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authorpriyanka2015-06-24 15:03:17 +0530
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+//example 2
+//Total Differential versus Partial Differential
+clear
+clc
+R=0.287 //Universal gas constant kPa-m3/kg-K
+v=(0.86+0.87)/2 //average value m^3/kg
+T=(300+302)/2 //average temp. in kelvins
+dT=302-300 //change in tep. in K
+dv=0.87-0.86 //change in volume in m^3/kg
+dP=R*dT/v-R*T*dv/v^2 //Change in the pressure in kPa
+printf("\n Hence, the change in the pressure of air is = %.3f kPa. \n",dP); \ No newline at end of file