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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
treedbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1586/CH6
parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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diff --git a/1586/CH6/EX6.2/EXP6_2.jpg b/1586/CH6/EX6.2/EXP6_2.jpg
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+clc;funcprot(0);//EXAMPLE 6.2
+// Initialisation of Variables
+F=45000;.......//Force applied on an aluminum rod in lb
+e=25000;.......//the maximum allowable stress on the rod in psi
+l2=150;.......//the minimum length of the rod in in
+e1=0.0025;......//The strain appiled on rod
+sigma=16670;.........//Stress applied on rod in psi
+L=0.25;........//The maximum allowable elastic deformation in in
+//CALCULATIONS
+Ao1=F/e;........//The required crosssectional area of the rod
+d=sqrt((Ao1*4)/%pi);......//Diameter of rod in in
+l1=e1*L;...........//The maximum length of the rod in in
+e2=L/e1;...........//The minimum strain allowed on rod
+Ao2=F/sigma;........//The minimum cross-sectional area in in^2
+disp(Ao1,"The required crosssectional area of the rod in in^2:")
+disp(d,"Diameter of rod in in:")
+disp(l1,"The maximum length of the rod in in:")
+disp(e2,"The minimum strain allowed on rod:")
+disp(Ao2,"The minimum cross-sectional area in in^2:")
diff --git a/1586/CH6/EX6.3/EXP6_3.jpg b/1586/CH6/EX6.3/EXP6_3.jpg
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+clc;funcprot(0);//EXAMPLE 6.2
+// Initialisation of Variables
+sigma1=35000;.......//Stress applied of aluminum alloy in psi from table 6-1
+e1=0.0035;........//Strain applied of aluminum alloy from table 6-1
+sigma2=30000;.......//Stress applied of aluminum alloy in psi
+Lo=50;.........//initial length of aluminum alloy
+//CALCULATIONS
+E=sigma1/e1;........//Modulus of elasticity of aluminum alloy
+e2=sigma2/E;.......//Strain applied of aluminum alloy
+L=Lo+(e2*Lo);......//The length after deformation of bar in in
+disp(E,"Modulus of elasticity of aluminum alloy from table 6-1:")
+disp(L,"The length after deformation of bar in in")
+disp(e2,"Strain applied of aluminum alloy:")
diff --git a/1586/CH6/EX6.4/EXP6_4.jpg b/1586/CH6/EX6.4/EXP6_4.jpg
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+clc;funcprot(0);//EXAMPLE 6.4
+// Initialisation of Variables
+Lf=2.195;........//Final length after failure
+d1=0.505;.......//Diameter of alluminum alloy in in
+d2=0.398;......//Final diameter of alluminum alloy in in
+Lo=2;..........//Initial length of alluminum alloy
+//CALCULATIONS
+A0=(%pi/4)*d1^2;........//Area of original of alluminum alloy
+Af=(%pi/4)*d2^2;........//Area of final of alluminum alloy
+%E=((Lf-Lo)/Lo)*100;.....//Percentage of Elongation
+%R=((A0-Af)/A0)*100;......//Percentage of Reduction in area
+disp(%E,"Percentage of Elongation:")
+disp(%R,"Percentage of Reduction in area:")
+printf("The final length is less than 2.205 in because, after fracture, the elastic strain is recovered.")
diff --git a/1586/CH6/EX6.5/EXP6_5.jpg b/1586/CH6/EX6.5/EXP6_5.jpg
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+clc;funcprot(0);//EXAMPLE 6.5
+// Initialisation of Variables
+F=8000;.......//Load applied for the aluminum alloy in lb
+F2=7600;......//Load applied for the aluminum alloy in lb at fracture
+dt1=0.505;.......//diameter of for the aluminum alloy in in
+dt2=0.497;.......//The diameter at maximum load
+Lt=2.120;..........//Final length at maxium load
+Lot=2;.............//Initial length of alluminum alloy
+Ff=7600;.........//Load applied for the aluminum alloy after fracture in lb
+df=0.398;.......//The diameter at maximum load after fracture
+Lf=0.205;.......//Final length at fracture
+//CALCULATIONS
+Es=F/((%pi/4)*dt1^2);.....//Engineering stress in psiAt the tensile or maximum load
+Ts=F/((%pi/4)*dt2^2);.....//True stress in psi At the tensile or maximum load
+Ee=(Lt-Lot)/Lot;........//Engineering strain At the tensile or maximum load
+Te=log(Lt/Lot);........//True strain At the tensile or maximum load
+Es2=F2/((%pi/4)*dt1^2);......//Engineering stress At fracture:
+Ts2=F2/((%pi/4)*df^2);......//True stress At fracture:
+Ee2=Lf/Lot;..........//Engineering strain At fracture:
+Te2=log(((%pi/4)*dt1^2)/((%pi/4)*df^2));.......//True strain At fracture:
+disp(Es,"Engineering stress in psiAt the tensile or maximum load")
+disp(Ts,"True stress in psi At the tensile or maximum load")
+disp(Ee,"Engineering strain At the tensile or maximum load")
+disp(Te,"True strain At the tensile or maximum load")
+disp(Es2,"Engineering stress At fracture:")
+disp(Ts2,"True stress At fracture")
+disp(Ee2,"Engineering strain At fracture:")
+disp(Te2,"True strain At fracture:")
diff --git a/1586/CH6/EX6.6/EXP6_6.jpg b/1586/CH6/EX6.6/EXP6_6.jpg
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+clc;funcprot(0);//EXAMPLE 6.6
+// Initialisation of Variables
+Fs=45000;.......//The flexural strength of a composite material in psi
+Fm=18*10^6;........//The flexural modulus of composite material in psi
+w=0.5;.......//wide of sample in in
+h=0.375;......//Height of sample in in
+l=5;..........//Length of sample in in
+//CALCULATIONS
+F=Fs*2*w*h^2/(3*l);......//The force required to fracture the material in lb
+delta=(l^3)*F/(Fm*4*w*h^3);.......//The deflection of the sample at fracture
+disp(F,"The force required to fracture the material in lb:")
+disp(delta,"The deflection of the sample at fracture in in")