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+// Scilab code Ex5.8: Current carrying conductor in magnetic field: Pg 153 (2008)

+clc; clear; 

+phi = 2.5e-03;                             // Flux, Wb

+l = 0.05;                                  // Effective length of pole, m

+d = 0.03;                                  //  Effective width of pole, m

+F = 1.25;                                  // Force exerted on conductor, N

+A = l*d;                                   // Cross-sectional area of pole face, m^2

+B = phi/A;                                // Flux density, T

+theta = (%pi/2);                          // Angle, degrees

+// Since F = B*I*l*sin(theta), solving for I

+I = F/(B*l*sin(theta));                   // Current in conductor, A

+theta_2 = (%pi/4);                        // New angle, degrees

+F_2 = B*I*l*sin(theta_2);                  // Force exerted on conductor, N

+printf("\nThe value of the current = %2g A", I);

+printf("\nThe force exerted on conductor when placed at 45 degrees to the field = %5.3f newton", F_2);

+

+// Result

+// The value of the current = 14 A

+// The force exerted on conductor when placed at 45 degrees to the field = 0.884 N