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// Scilab code Ex5.8: Current carrying conductor in magnetic field: Pg 153 (2008)
clc; clear;
phi = 2.5e-03; // Flux, Wb
l = 0.05; // Effective length of pole, m
d = 0.03; // Effective width of pole, m
F = 1.25; // Force exerted on conductor, N
A = l*d; // Cross-sectional area of pole face, m^2
B = phi/A; // Flux density, T
theta = (%pi/2); // Angle, degrees
// Since F = B*I*l*sin(theta), solving for I
I = F/(B*l*sin(theta)); // Current in conductor, A
theta_2 = (%pi/4); // New angle, degrees
F_2 = B*I*l*sin(theta_2); // Force exerted on conductor, N
printf("\nThe value of the current = %2g A", I);
printf("\nThe force exerted on conductor when placed at 45 degrees to the field = %5.3f newton", F_2);
// Result
// The value of the current = 14 A
// The force exerted on conductor when placed at 45 degrees to the field = 0.884 N
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