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authorpriyanka2015-06-24 15:03:17 +0530
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-rwxr-xr-x1541/CH3/EX3.1/Chapter3_Example1.sce19
-rwxr-xr-x1541/CH3/EX3.2/Chapter3_Example2.sce20
-rwxr-xr-x1541/CH3/EX3.3/Chapter3_Example3.sce19
-rwxr-xr-x1541/CH3/EX3.4/Chapter3_Example4.sce23
-rwxr-xr-x1541/CH3/EX3.5/Chapter3_Example5.sce27
-rwxr-xr-x1541/CH3/EX3.6/Chapter3_Example6.sce24
-rwxr-xr-x1541/CH3/EX3.7/Chapter3_Example7.sce23
7 files changed, 155 insertions, 0 deletions
diff --git a/1541/CH3/EX3.1/Chapter3_Example1.sce b/1541/CH3/EX3.1/Chapter3_Example1.sce
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+//Chapter-3, Example 3.1, Page 3.6
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+N=900;//Rotor speed in rpm
+f=50;//Power supply frequency in Hz
+P=6;//No. of poles
+
+//CALCULATIONS
+Ns=(120*f)/P;//Synchronous speed in rpm
+s=((Ns-N)/Ns)*100;//%slip
+f1=(s*f)/100;//Frequency of rotor current in Hz
+
+//OUTPUT
+mprintf('Slip of a 3 phase motor is %i percent\nFrequency of rotor current is %i Hz',s,f1)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.2/Chapter3_Example2.sce b/1541/CH3/EX3.2/Chapter3_Example2.sce
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+//Chapter-3, Example 3.2, Page 3.6
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+N=600;//Speed of 12 pole 3 phase alternator in rpm
+P=12;//No. of poles of alternator
+n=6;//No. of poles in induction motor
+s=2.5;//slip of the motor in %
+
+//CALCULATIONS
+f=(N*P)/120;//Alternator supply frequency in Hz
+Ns=(120*f)/n;//Synchronous speed in rpm
+N1=(Ns-((s*Ns)/100));//Full load speed of the motor when the slip is 2.5%
+
+//OUTPUT
+mprintf('Full load speed of the motor when the slip is 2.5 percent = %irpm',N1)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.3/Chapter3_Example3.sce b/1541/CH3/EX3.3/Chapter3_Example3.sce
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+//Chapter-3, Example 3.3, Page 3.7
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+P=6;//Number of poles
+f=50;//Supply frequency in Hz
+f1=3;//Rotor current frequency in Hz
+
+//CALCULATIONS
+s=(f1/f)*100;//Slip of the motor in %
+Ns=(120*f)/P;//Synchronous speed in rpm
+N=(Ns-((s*Ns)/100));//Speed of the motor in rpm
+
+//OUTPUT
+mprintf('Slip of the motor is %i percent\nSpeed of the motor is %i rpm',s,N)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.4/Chapter3_Example4.sce b/1541/CH3/EX3.4/Chapter3_Example4.sce
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+//Chapter-3, Example 3.4, Page 3.12
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+VL=440;//Supply line voltage in V
+P=4;//Number of poles
+IL=75;//Line current in A
+cosx=0.8;//Power factor
+n=0.8;//Efficiency of the motor
+s=0.03;//slip of the motor
+f=50;//Frequency in Hz
+
+//CALCULATIONS
+Pm=(sqrt(3)*VL*IL*cosx*n);//Output power in W
+Ns=(120*f)/P;//Synchronous speed in rpm
+N=(1-s)*Ns;//Actual speed in rpm
+
+//OUTPUT
+mprintf('Shaft output power is %3.0f W\nActual speed is %i rpm',Pm,N)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.5/Chapter3_Example5.sce b/1541/CH3/EX3.5/Chapter3_Example5.sce
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+//Chapter-3, Example 3.5, Page 3.13
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+P=6;//Number of poles
+f=50;//Supply frequency in Hz
+Tm=120;//Shaft torque in N.m
+f1=2;//Rotor current frequency in Hz
+L=5;//Amount of constant losses in N.m
+C=500;//Amount of core losses in W
+
+//CALCULATIONS
+Ns=(120*f)/P;//Synchronous speed in rpm
+s=(f1/f);//Slip of the motor
+N=(1-s)*Ns;//Actual speed in rpm
+P=(2*3.14*N*Tm)/60;//Shaft power in W
+Pm=(2*3.14*N*(Tm+L))/60000;//Mechanical power output in kW
+R=(s*Pm)/(1-s);//Rotor copper losses in kW
+I=(Pm+R+(L/10));//Motor input in kW
+n=(Pm/I)*100;//Machine efficiency
+
+//OUTPUT
+mprintf('a)Mechanical power output is %3.3f kW\nb)Rotor copper losses is %3.2fkW\nc)Motor input is %3.3f kW\nd)Machine efficiency is %3.1f percent',Pm,R,I,n)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.6/Chapter3_Example6.sce b/1541/CH3/EX3.6/Chapter3_Example6.sce
new file mode 100755
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+//Chapter-3, Example 3.6, Page 3.17
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+VL=11000;//Supply line voltage in V
+P=12;//Number of poles
+f=50;//Supply frequency in Hz
+R2=0.2;//Rotor resistance in ohm
+X2=1.2;//Rotor reactance at stand still in ohm
+N=480;//Full load speed in rpm
+
+//CALCULATIONS
+s=(R2/X2);//Slip at maximum torque
+Ns=(120*f)/P;//Synchronous speed in rpm
+s1=(Ns-N)/Ns;//Slip at full load
+T=((R2^2+(s1^2*X2^2))/((2*X2)*(s1*R2)));//Ratio of maximum and full load torque
+T1=((R2^2+X2^2)/(2*X2*R2));//Ratio of maximum and starting torque
+
+//OUTPUT
+mprintf('a)Slip at maximum torque is %3.2f \nb)Ratio of maximum and full load torque is %3.2f \nc)Ratio of maximum and starting torque is %3.2f',s,T,T1)
+
+//=================================END OF PROGRAM==============================
diff --git a/1541/CH3/EX3.7/Chapter3_Example7.sce b/1541/CH3/EX3.7/Chapter3_Example7.sce
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+//Chapter-3, Example 3.7, Page 3.18
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+P=6;//Number of poles
+f=50;//Supply frequency in Hz
+R2=0.4;//Rotor reisitance in ohm
+X2=4;//Rotor standstill reactance in ohm
+T1=2;//Ratio of maximum torque to starting torque
+
+//CALCULATIONS
+Ns=(120*f)/P;//Synchronous speed in rpm
+Sm=(R2/X2);//Slip at maximum torque
+NTM=(Ns*(1-Sm));//Speed of the motor at maximum torque in rpm
+T=((R2^2+X2^2)/(2*R2*X2));//Ratio of maximum torque to starting torque
+Rext=(sqrt(X2^2/((2*T1)-1))-R2);//Additional resistance required for the ratio of maximum torque to the statring torque to be 2 in ohm
+
+//OUTPUT
+mprintf('a)Speed of the motor at maximum torque is %i rpm \n b)Ratio of maximum torque to starting torque is %3.2f \n c)Additional resistance required for the ratio of maximum torque to the starting torque to be 2 is %3.1f ohm',NTM,T,Rext)
+
+//=================================END OF PROGRAM==============================