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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1535/CH3/EX3.7 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1535/CH3/EX3.7')
| -rwxr-xr-x | 1535/CH3/EX3.7/Ch03Ex7.sci | 10 |
1 files changed, 10 insertions, 0 deletions
diff --git a/1535/CH3/EX3.7/Ch03Ex7.sci b/1535/CH3/EX3.7/Ch03Ex7.sci new file mode 100755 index 000000000..8f7d3fda4 --- /dev/null +++ b/1535/CH3/EX3.7/Ch03Ex7.sci @@ -0,0 +1,10 @@ +// Scilab Code Ex3.7 : Page-72 (2010)
+D4 = 0.4; // Diameter of 4th dark ring, cm
+D12 = 0.7; // Diameter of 12th dark ring, cm
+// We have dn_puls_k^2-Dn^2 = 4*k*R*lambda, so
+// D12^2-D4^2 = 32*R*lambda and D20^2-D12^2 = 32*R*lambda for k = 8, solving for D20
+D20 = sqrt(2*D12^2-D4^2); // Diameter of 20th dark ring, cm
+printf("\nThe diameter of 20th dark ring = %6.4f cm", D20);
+
+// Result
+// The diameter of 20th dark ring = 0.9055 cm
\ No newline at end of file |