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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 21, Problem 26
+clc;
+V1=320; //primary voltage
+V2=250; //secondary voltage
+Rg=20e3; //rating
+I1=Rg/V1; //primary current
+I2=Rg/V2; //secondary current
+I=I2-I1; //current in common part of the winding
+printf("Primary current = %.1f A\n\nSecondary current = %d A\n\n\n",I1,I2);
+printf("Hence current in common part of the winding = %.1f A",I);