updated the code

1 files changed, 8 insertions, 8 deletions

diff --git a/1445/CH8/EX8.18/Ex8_18.sce b/1445/CH8/EX8.18/Ex8_18.sce
index 10b37b947..fb5a399e9 100644
--- a/1445/CH8/EX8.18/Ex8_18.sce
+++ b/1445/CH8/EX8.18/Ex8_18.sce
@@ -1,27 +1,27 @@
 //CHAPTER 8- DIRECT CURRENT MACHINES
 //Example 18
 
+clc;
 disp("CHAPTER 8");
 disp("EXAMPLE 18");
 
-//460 V 10 HP motor 
 //VARIABLE INITIALIZATION
 v_t=460;                     //in Volts
 p_o=10*736;                  //in Watts (1 metric H.P=735.5 W)
 ratio=85/100;                //as given in the question 
-eff=84/100;                  // efficiency
+eff=84/100; 
 I_f=1.1;                     //in Amperes
 r_a=0.2;                     //in Ohms
 
 //SOLUTION
-p_i=p_o/eff;                //power input
-I_l=p_i/v_t;                //line current
-I_a=I_l-I_f;                // armature current
-E1=v_t-(I_a*r_a);           //back emf
+p_i=p_o/eff;
+I_l=p_i/v_t;
+I_a=I_l-I_f;
+E1=v_t-(I_a*r_a);
 E2=E1*ratio;                 //E2:E1=N2:N1=ratio
 v=v_t-E2;                    //voltage drop across r_a and r_s (r_s is the series resistance to be inserted)
-r_s=(v/I_a)-r_a;            // series resistance
-disp(sprintf("The resistance required is %.2f Ω",r_s));
+r_s=(v/I_a)-r_a;
+disp(sprintf("The resistance required is %f Ω",r_s));
 
 //The answer is different because ratio equals 85/100 and not 75/100