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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//CHAPTER 6- MAGNETIC CIRCUITS
+//Example 2
+
+disp("CHAPTER 6");
+disp("EXAMPLE 2");
+
+//VARIABLE INITIALIZATION
+dr=25/100; //diameter of steel ring in m
+ds=3/100; //diameter of circular section in m
+lg=1.5/1000; //length of air-gap in m
+N=700; //number of turns
+mu0=4*%pi*10^(-7); //absolute permeability in Henry/m
+I=2; //in Amperes
+
+//SOLUTION
+
+//solution (i)
+mmf=N*I;
+disp(sprintf("(i) MMF is %d AT", mmf));
+
+//solution (ii)
+netMMF=(mmf-(0.35*mmf)); //mmf taken by iron path is 35% of total mmf
+b=(mu0*netMMF)/lg; //phi=b*area, r=lg/(mu0*area) & mmf=phi*r => mmf=(b*lg)/mu0 => b=(mmf*mu0)/lg
+disp(sprintf("(ii) The flux density of the air gap is %E Wb/m^2", b));
+
+//solution (iii)
+ar=%pi*((ds/2)^2); //area of cross-section of circular section
+phi=ar*b;
+disp(sprintf("(iii) The magnetic flux is %E Wb",phi));
+
+//solution (iv)
+rt=mmf/phi;
+disp(sprintf("(iv) The total reluctance is %E AT/wb",rt));
+
+//solution (v)
+rg=lg/(mu0*ar); //reluctance of air gap
+rs=rt-rg; //reluctance of steel
+lr=%pi*dr; //circumference of ring
+mur=lr/(mu0*rs*ar);
+disp(sprintf("(v) The relative permeability of the steel ring is %E",mur));
+
+//solution (vi)
+disp(sprintf("(vi) Reluctance of steel is %E AT/Wb",rs));
+
+//END
+
+
+
+
+