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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//example3.15
+clc
+x=250*800
+disp(x,"a)The output power at full load(in watt)=")
+disp("THe input power at full load =(200*10^3)/0.98135")
+disp("The total loss = Input-Output")
+t=((200*10^3)/0.98135)-200000
+format(8)
+disp(t,"= ")
+disp("Therefore, P_i + P_c = 3800.88 (i)")
+disp("where P_i= Iron loss ,P_c = Full load copper loss")
+p=125*800
+disp(p,"The power output at half load=125*10^3 *0.8=")
+disp("The power input at half load = (100*10^3)/0.97751")
+x=((100*10^3)/0.9775)
+disp(x,"Total loss = (100*10^3)/0.9775 - 100*10^3 =")
+disp("(P_i)+ (0.5^2)*(P_c) = 2300.74")
+disp("(P_i)+ (0.25)*(P_c) = 2300.74 (ii)")
+disp("From equations (i) and (ii),")
+disp("0.75*(P_i)=3800.88-2300.74")
+p=(3800.88-2300.74)/0.75
+disp(p,"Therefore, P_i(in watt)=")
+z=3800.88-2000.18
+disp(z,"P_c(in watt)=")