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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1319/CH12/EX12.11/i_11.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '1319/CH12/EX12.11/i_11.sce')
| -rw-r--r-- | 1319/CH12/EX12.11/i_11.sce | 46 |
1 files changed, 46 insertions, 0 deletions
diff --git a/1319/CH12/EX12.11/i_11.sce b/1319/CH12/EX12.11/i_11.sce new file mode 100644 index 000000000..0fd86f5b4 --- /dev/null +++ b/1319/CH12/EX12.11/i_11.sce @@ -0,0 +1,46 @@ +// To find the value of the unknown resitance in the series of resistances in a circuit.
+
+clc;
+clear;
+
+R1=20;
+
+V=220;
+
+P=50;
+
+R=poly([0 1],'R','c');
+Rt=R1+R;
+
+I=V/Rt;
+
+A=(I^2)*R;// To get the characteristic eqaution to find R.
+B=A-50;
+C=B(2);
+
+rts=roots(C);// To find the two resistances
+
+R=round(10000.*rts)./10000;// Rounding off to four decimal points.
+
+Rt=R1+R;// Total resistance
+
+I=V./Rt;// Currents
+
+pow=(I.^2)*(R)';
+
+power=diag(pow);
+
+disp(B(2),'The Characteristic polynomial to find resistance R equated to zero is')
+
+disp('ohms',R,'The solution of the above equation yields two resistances')
+
+disp('Now to check which resistance is suitable by finding out the power dissipated by each of them')
+
+disp('watts',power,'The Power dissipated by both the resistors are')
+
+disp('ohms',R(1),'From comparison with the given value (50 watts), We find that the suitable resistance is')
+
+// The higher resistance is preferred because it limits the amount of current, ( Please see the current ratings of the resistors (Heating effect))
+
+
+
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