From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 1319/CH12/EX12.11/i_11.sce | 46 ++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 46 insertions(+)
 create mode 100644 1319/CH12/EX12.11/i_11.sce

(limited to '1319/CH12/EX12.11/i_11.sce')

diff --git a/1319/CH12/EX12.11/i_11.sce b/1319/CH12/EX12.11/i_11.sce
new file mode 100644
index 000000000..0fd86f5b4
--- /dev/null
+++ b/1319/CH12/EX12.11/i_11.sce
@@ -0,0 +1,46 @@
+// To find the value of the unknown resitance in the series of resistances in a circuit.
+
+clc;
+clear;
+
+R1=20;
+
+V=220;
+
+P=50;
+
+R=poly([0 1],'R','c');
+Rt=R1+R;
+
+I=V/Rt;
+
+A=(I^2)*R;// To get the characteristic eqaution to find R. 
+B=A-50;
+C=B(2);
+
+rts=roots(C);// To find the two resistances
+
+R=round(10000.*rts)./10000;// Rounding off to four decimal points.
+
+Rt=R1+R;// Total resistance
+
+I=V./Rt;// Currents
+
+pow=(I.^2)*(R)';
+
+power=diag(pow);
+
+disp(B(2),'The Characteristic polynomial to find resistance R equated to zero is')
+
+disp('ohms',R,'The solution of the above equation yields two resistances')
+
+disp('Now to check which resistance is suitable by finding out the power dissipated by each of them')
+
+disp('watts',power,'The Power dissipated by both the resistors are')
+
+disp('ohms',R(1),'From comparison with the given value (50 watts), We find that the suitable resistance is')
+
+// The higher resistance is preferred because it limits the amount of current, ( Please see the current ratings of the resistors (Heating effect)) 
+
+
+
-- 
cgit