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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1271/CH14/EX14.38/example14_38.sce | |
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diff --git a/1271/CH14/EX14.38/example14_38.sce b/1271/CH14/EX14.38/example14_38.sce new file mode 100755 index 000000000..9bae2e9f7 --- /dev/null +++ b/1271/CH14/EX14.38/example14_38.sce @@ -0,0 +1,17 @@ +clc +// Given that +E1 = 500 // kinetic energy of electron in first case in eV +E2 = 50 // kinetic energy of electron in second case in eV +E3 = 1 // kinetic energy of electron in third case in eV +h = 6.62e-34 // Planck constant in J-sec +e = 1.6e-19 // charge on an electron in C +m = 9.1e-31 // mass of electron in kg +// Sample Problem 38 on page no. 14.36 +printf("\n # PROBLEM 38 # \n") +printf("Standard formula used \n ") +printf(" lambda = h/(2*m*E)^1/2.\n") +lambda1 = h / sqrt(2 * m * E1 * e) +lambda2 = h / sqrt(2 * m * E2 * e) +lambda3 = h / sqrt(2 * m * E3 * e) +printf("\n de-Broglie wavelength of electron - (1) In first case is %f A. \n (2) In second case is %f A. \n (3) In third is %f A.",lambda1*1e10,lambda2*1e10,lambda3*1e10) + |