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+ # PROBLEM 38 #
+Standard formula used
+ lambda = h/(2*m*E)^1/2.
+
+ de-Broglie wavelength of electron - (1) In first case is 0.548627 A.
+ (2) In second case is 1.734911 A.
+ (3) In third is 12.267676 A.
diff --git a/1271/CH14/EX14.38/example14_38.sce b/1271/CH14/EX14.38/example14_38.sce
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+clc
+// Given that
+E1 = 500 // kinetic energy of electron in first case in eV
+E2 = 50 // kinetic energy of electron in second case in eV
+E3 = 1 // kinetic energy of electron in third case in eV
+h = 6.62e-34 // Planck constant in J-sec
+e = 1.6e-19 // charge on an electron in C
+m = 9.1e-31 // mass of electron in kg
+// Sample Problem 38 on page no. 14.36
+printf("\n # PROBLEM 38 # \n")
+printf("Standard formula used \n ")
+printf(" lambda = h/(2*m*E)^1/2.\n")
+lambda1 = h / sqrt(2 * m * E1 * e)
+lambda2 = h / sqrt(2 * m * E2 * e)
+lambda3 = h / sqrt(2 * m * E3 * e)
+printf("\n de-Broglie wavelength of electron - (1) In first case is %f A. \n (2) In second case is %f A. \n (3) In third is %f A.",lambda1*1e10,lambda2*1e10,lambda3*1e10)
+