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| author | priyanka | 2015-06-24 15:03:17 +0530 |
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| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1151/CH3/EX3.6 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1151/CH3/EX3.6')
| -rwxr-xr-x | 1151/CH3/EX3.6/example6.sce | 5 |
1 files changed, 5 insertions, 0 deletions
diff --git a/1151/CH3/EX3.6/example6.sce b/1151/CH3/EX3.6/example6.sce new file mode 100755 index 000000000..49a69ac1b --- /dev/null +++ b/1151/CH3/EX3.6/example6.sce @@ -0,0 +1,5 @@ +//determine the type of following feedback system
+printf("a) G(s)=K/((s+10)*(s+5) \n solution : Since in denominator the power of s is zero i.e.m=0,henece its type zero system");
+printf("\n b) G(s)=20/(s*(0.05*s+1)*(0.1*s+1) \n solution : Since in denominator the power of s is one i.e.m=1,henece its type one system\n");
+printf("c) G(s)=20*(s+2)/(s^3*(s+2)*(s^2+5*s+5) \n solution : Since in denominator the power of s is three i.e.m=3,henece its type three system\n");
+printf("d) G(s)=K/(s*(s+1)*(s+2) \n solution : Since in denominator the power of s is one i.e.m=1,henece its type one system\n");
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