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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1092/CH13/EX13.7 | |
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| -rwxr-xr-x | 1092/CH13/EX13.7/Example13_7.sce | 29 |
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diff --git a/1092/CH13/EX13.7/Example13_7.sce b/1092/CH13/EX13.7/Example13_7.sce new file mode 100755 index 000000000..710731bf6 --- /dev/null +++ b/1092/CH13/EX13.7/Example13_7.sce @@ -0,0 +1,29 @@ +// Electric Machinery and Transformers
+// Irving L kosow
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 13: RATINGS,SELECTION,AND MAINTENANCE OF ELECTRIC MACHINERY
+// Example 13-7
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+P_o = 200 ; // Power rating of the test motor in hp
+t1 = 5 ; // time duration in minutes for which test motor is operated at 200 hp
+t2 = 5 ; // time duration in minutes for which test motor is operated at 20 hp
+t3 = 10 ; // time duration in minutes for which test motor is operated at 100 hp
+
+// Calculation
+rms_hp = sqrt( ( (200^2)*t1 + (20^2)*t2 + (100^2)*t3 )/(t1 + t2 + t3 + 10/3) );
+// Horsepower required for intermittent varying load
+
+// Display the results
+disp("Example 13-7 Solution : ");
+printf(" \n Horsepower required for intermittent varying load is : ");
+printf(" \n rms hp = %.f hp \n ",rms_hp);
+
+printf(" \n A 125 hp motor would be selected because that is the nearest larger");
+printf(" \n commercial standard rating.This means that the motor would operate ");
+printf(" \n with a 160 percent overload (at 200 hp) for 5 minutes,or 1/6th of ")
+printf(" \n its total duty cycle.");
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