1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
|
{
"metadata": {
"name": "El5"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 5: Junction Properties (Continued)"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 5.1 Page No 191"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Exa 5.1\n",
"#Estimate the junction width in two cases.\n",
"\n",
"#given data\n",
"import math\n",
"ND=10**17 #in atoms/cm**3\n",
"NA=0.5*10**16 #in atoms/cm**3\n",
"Vo=0.7 #in Volts\n",
"V=-10.0 #in Volts\n",
"ND=ND*10**6 #in atoms/m**3\n",
"NA=NA*10**6 #in atoms/m**3\n",
"epsilon=8.85*10**-11 #in F/m\n",
"e=1.6*10**-19 #coulamb\n",
"\n",
"#Calculation\n",
"#part (i)\n",
"#print \"When no external voltage is applied i.e. V=0\"\n",
"#print\"VB = 0.7 volts\"\n",
"VB=0.7 #in Volts\n",
"W1=math.sqrt(2*epsilon*VB*(1/NA+1/ND)/e) #in m\n",
"\n",
"#part (ii)\n",
"#print\"When external voltage of -10 volt is applied\"\n",
"#print\"VB = Vo-V volts\"\n",
"VB=Vo-V #in Volts\n",
"W2=math.sqrt(2*epsilon*VB*(1/NA+1/ND)/e) #in m\n",
"\n",
"#result\n",
"print \"When no external voltage is applied, Junction width is \",round(W1,8),\"m\"\n",
"print\"When external voltage of -10 Volt is applied, Junction width is \",round(W2,7),\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"When no external voltage is applied, Junction width is 3.9e-07 m\n",
"When external voltage of -10 Volt is applied, Junction width is 1.5e-06 m\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 5.3 Page No 195"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Exa 5.3\n",
"#Determine the junction capacitance\n",
"\n",
"#given data\n",
"CTzero=50 #in pF\n",
"VR=8 #in Volt\n",
"VK=0.7 #in Volt\n",
"n=1/3.0 #for Si\n",
"\n",
"#calculation\n",
"CT=CTzero/((1+VR/VK)**n) #in pF\n",
"\n",
"#result\n",
"print\"Junction capacitance is\",round(CT,2),\"pF\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Junction capacitance is 21.59 pF\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 5.4 Page No.196"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 5.4\n",
"#Determine the tuning range of the circuit\n",
"\n",
"#Given\n",
"L=12.5*10**-3 #mH inductance\n",
"C1=4.0 #pF Capacitance\n",
"C2=40.0 #pF Capacitance\n",
"\n",
"#Calculation\n",
"Ctmin=(C1*C1)/(C1+C1) #Min value of total Capacitance\n",
"Ctmax=(C2*C2)/(C2+C2) #Max value of total Capacitance\n",
"Fmax=1/(2*math.pi*math.sqrt(L*Ctmin*10**-12))\n",
"Fmin=1/(2*math.pi*math.sqrt(L*Ctmax*10**-12))\n",
"\n",
"#result\n",
"print\"The tuning range of circuit lies between\",round(Fmin/1000,2),\"khz and\",round(Fmax/1000,0),\"Mhz\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The tuning range of circuit lies between 318.31 khz and 1007.0 Mhz\n"
]
}
],
"prompt_number": 22
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|