{
 "metadata": {
  "name": "El5"
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 5: Junction Properties (Continued)"
     ]
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 5.1 Page No 191"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Exa 5.1\n",
      "#Estimate the junction width in two cases.\n",
      "\n",
      "#given data\n",
      "import math\n",
      "ND=10**17           #in atoms/cm**3\n",
      "NA=0.5*10**16       #in atoms/cm**3\n",
      "Vo=0.7              #in Volts\n",
      "V=-10.0               #in Volts\n",
      "ND=ND*10**6         #in atoms/m**3\n",
      "NA=NA*10**6         #in atoms/m**3\n",
      "epsilon=8.85*10**-11  #in F/m\n",
      "e=1.6*10**-19         #coulamb\n",
      "\n",
      "#Calculation\n",
      "#part (i)\n",
      "#print \"When no external voltage is applied i.e. V=0\"\n",
      "#print\"VB = 0.7 volts\"\n",
      "VB=0.7               #in Volts\n",
      "W1=math.sqrt(2*epsilon*VB*(1/NA+1/ND)/e)         #in m\n",
      "\n",
      "#part (ii)\n",
      "#print\"When external voltage of -10 volt is applied\"\n",
      "#print\"VB = Vo-V volts\"\n",
      "VB=Vo-V              #in Volts\n",
      "W2=math.sqrt(2*epsilon*VB*(1/NA+1/ND)/e)    #in m\n",
      "\n",
      "#result\n",
      "print \"When no external voltage is applied, Junction width is \",round(W1,8),\"m\"\n",
      "print\"When external voltage of -10 Volt is applied, Junction width is \",round(W2,7),\"m\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "When no external voltage is applied, Junction width is  3.9e-07 m\n",
        "When external voltage of -10 Volt is applied, Junction width is  1.5e-06 m\n"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 5.3 Page No 195"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Exa 5.3\n",
      "#Determine the junction capacitance\n",
      "\n",
      "#given data\n",
      "CTzero=50            #in pF\n",
      "VR=8                 #in Volt\n",
      "VK=0.7               #in Volt\n",
      "n=1/3.0                #for Si\n",
      "\n",
      "#calculation\n",
      "CT=CTzero/((1+VR/VK)**n)   #in pF\n",
      "\n",
      "#result\n",
      "print\"Junction capacitance is\",round(CT,2),\"pF\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Junction capacitance is 21.59 pF\n"
       ]
      }
     ],
     "prompt_number": 17
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 5.4 Page No.196"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Example 5.4\n",
      "#Determine the tuning range of the circuit\n",
      "\n",
      "#Given\n",
      "L=12.5*10**-3          #mH inductance\n",
      "C1=4.0                 #pF Capacitance\n",
      "C2=40.0                #pF Capacitance\n",
      "\n",
      "#Calculation\n",
      "Ctmin=(C1*C1)/(C1+C1)     #Min value of total Capacitance\n",
      "Ctmax=(C2*C2)/(C2+C2)     #Max value of total Capacitance\n",
      "Fmax=1/(2*math.pi*math.sqrt(L*Ctmin*10**-12))\n",
      "Fmin=1/(2*math.pi*math.sqrt(L*Ctmax*10**-12))\n",
      "\n",
      "#result\n",
      "print\"The tuning range of circuit lies between\",round(Fmin/1000,2),\"khz and\",round(Fmax/1000,0),\"Mhz\"\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The tuning range of circuit lies between 318.31 khz and 1007.0 Mhz\n"
       ]
      }
     ],
     "prompt_number": 22
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}