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{
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"source": [
"# Chapter 15: Refrigeration and Air Conditioning"
]
},
{
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"metadata": {},
"source": [
"## Exa 15.1"
]
},
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"execution_count": 1,
"metadata": {
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"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Joule-Thomson coefficient (C/bar) = 1.61\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 1,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#Estimate how much the temperature is lowered when the steam at 7 bar and \n",
"#260C is throttled to 1.4 bar. What is the approximate Joule-Thomson \n",
"#initialisation of variables\n",
"P= 7. \t\t\t\t#bar\n",
"P1= 1.4 \t\t\t#bar\n",
"T= 260. \t\t\t#C\n",
"T1= 251. \t\t\t#C\n",
"h= 2974.9 \t\t\t#J/gm\n",
"#CALCULATIONS\n",
"dT= T-T1 \t\t\t#Change in Temp. \n",
"Mj= dT/(P-P1) \t\t#Joule-Thomson coefficient\n",
"#RESULTS\n",
"print '%s %.2f' % ('Joule-Thomson coefficient (C/bar) = ',Mj)\n",
"raw_input('press enter key to exit')"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Exa 15.2"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Refrigerating effect (Btu/lbm) = 44.80\n",
" \n",
" Coffecient of performnance= 3.54\n",
" \n",
" Capacity of refrigeration in tons (ton) = 0.67\n",
"press enter key to exit\n"
]
},
{
"data": {
"text/plain": [
"''"
]
},
"execution_count": 2,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#A vapor compression refrigiration system, using Refrigirant 12, works between\n",
"#n evaporator temperature of 10F and a condenser temp. of 110F. The pumping\n",
"#rate for the refrigrant is 180 lbm/hr. Determine (a) the refrigirating \n",
"#effect, (b) the coefficient of performance,and (c) the capacity of refrigiration\n",
"#in tons\n",
"#initialisation of variables\n",
"T= 10. \t\t\t\t\t\t#F\n",
"T1= 110. \t\t\t\t\t#F\n",
"Pr= 180. \t\t\t\t\t#lbm/hr\n",
"h1= 78.335 \t\t\t\t\t#Btu/lbm\n",
"h3= 33.531 \t\t\t\t\t#Btu/lbm\n",
"h2= 91. \t\t\t\t\t#Btu/lbm\n",
"L= 12000. \t\t\t\t\t#Btu/hr per ton\n",
"#CALCULATIONS\n",
"h4= h3\n",
"QL= h1-h4 \t\t\t\t\t#Refrigerating effect\n",
"W= h2-h1 \t\t\t\t\t#Work done\n",
"COP= QL/W \t\t\t\t\t#Coffecient of performnance\n",
"C= QL*Pr/L \t\t\t\t\t#Capacity of refrigeration in tons\n",
"#RESULTS\n",
"print '%s %.2f' % ('Refrigerating effect (Btu/lbm) = ',QL)\n",
"print '%s %.2f' % (' \\n Coffecient of performnance= ',COP)\n",
"print '%s %.2f' % (' \\n Capacity of refrigeration in tons (ton) = ',C)\n",
"raw_input('press enter key to exit')"
]
}
],
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