{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 15: Refrigeration and Air Conditioning" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exa 15.1" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Joule-Thomson coefficient (C/bar) = 1.61\n", "press enter key to exit\n" ] }, { "data": { "text/plain": [ "''" ] }, "execution_count": 1, "metadata": {}, "output_type": "execute_result" } ], "source": [ "#Estimate how much the temperature is lowered when the steam at 7 bar and \n", "#260C is throttled to 1.4 bar. What is the approximate Joule-Thomson \n", "#initialisation of variables\n", "P= 7. \t\t\t\t#bar\n", "P1= 1.4 \t\t\t#bar\n", "T= 260. \t\t\t#C\n", "T1= 251. \t\t\t#C\n", "h= 2974.9 \t\t\t#J/gm\n", "#CALCULATIONS\n", "dT= T-T1 \t\t\t#Change in Temp. \n", "Mj= dT/(P-P1) \t\t#Joule-Thomson coefficient\n", "#RESULTS\n", "print '%s %.2f' % ('Joule-Thomson coefficient (C/bar) = ',Mj)\n", "raw_input('press enter key to exit')" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exa 15.2" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Refrigerating effect (Btu/lbm) = 44.80\n", " \n", " Coffecient of performnance= 3.54\n", " \n", " Capacity of refrigeration in tons (ton) = 0.67\n", "press enter key to exit\n" ] }, { "data": { "text/plain": [ "''" ] }, "execution_count": 2, "metadata": {}, "output_type": "execute_result" } ], "source": [ "#A vapor compression refrigiration system, using Refrigirant 12, works between\n", "#n evaporator temperature of 10F and a condenser temp. of 110F. The pumping\n", "#rate for the refrigrant is 180 lbm/hr. Determine (a) the refrigirating \n", "#effect, (b) the coefficient of performance,and (c) the capacity of refrigiration\n", "#in tons\n", "#initialisation of variables\n", "T= 10. \t\t\t\t\t\t#F\n", "T1= 110. \t\t\t\t\t#F\n", "Pr= 180. \t\t\t\t\t#lbm/hr\n", "h1= 78.335 \t\t\t\t\t#Btu/lbm\n", "h3= 33.531 \t\t\t\t\t#Btu/lbm\n", "h2= 91. \t\t\t\t\t#Btu/lbm\n", "L= 12000. \t\t\t\t\t#Btu/hr per ton\n", "#CALCULATIONS\n", "h4= h3\n", "QL= h1-h4 \t\t\t\t\t#Refrigerating effect\n", "W= h2-h1 \t\t\t\t\t#Work done\n", "COP= QL/W \t\t\t\t\t#Coffecient of performnance\n", "C= QL*Pr/L \t\t\t\t\t#Capacity of refrigeration in tons\n", "#RESULTS\n", "print '%s %.2f' % ('Refrigerating effect (Btu/lbm) = ',QL)\n", "print '%s %.2f' % (' \\n Coffecient of performnance= ',COP)\n", "print '%s %.2f' % (' \\n Capacity of refrigeration in tons (ton) = ',C)\n", "raw_input('press enter key to exit')" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.6" } }, "nbformat": 4, "nbformat_minor": 0 }