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diff --git a/Engineering_Physics/chapter8_2.ipynb b/Engineering_Physics/chapter8_2.ipynb new file mode 100644 index 00000000..c344140a --- /dev/null +++ b/Engineering_Physics/chapter8_2.ipynb @@ -0,0 +1,133 @@ +{ + "metadata": { + "name": "chapter8" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": "Physics of Nano Materials" + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 8.1, Page number 320" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=5; #radius in m\npi=3.14;\n\n#Calculation \nSA=4*pi*r**2; #surface area of sphere in m^2\nV=(4/3)*pi*r**3; #volume of sphere in m^3\nR=SA/V; #ratio\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "('surface area to volume ratio of sphere in m-1 is', 0.6)\n" + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 8.2, Page number 321" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nd=26; #distance in m\nr=d/2; #radius in m\npi=3.14;\n\n#Calculation\nSA=4*pi*r**2; #surface area of sphere in m^2\nV=(4/3)*pi*r**3; #volume of sphere in m^3\nR=SA/V; #ratio\nR=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "('surface area to volume ratio of sphere in m-1 is', 0.231)\n" + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 8.3, Page number 321" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "# To calculate the volume of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=1; #radius in m\nh=1; #height in m\npi=3.14\n\n#Calculation\nV=(1/3)*pi*(r**2)*h;\nV=math.ceil(V*10**2)/10**2; #rounding off to 2 decimals\n\n#Result\nprint(\"volume of cone in m^3 is\",V); ", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "('volume of cone in m^3 is', 1.05)\n" + } + ], + "prompt_number": 11 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 8.4, Page number 321" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "# To calculate the total surface area of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=3; # radius in m\nh=4; # height in m\npi=3.14\n\n#Calculation\nSA=pi*r*math.sqrt((r**2)+(h**2));\nTSA=SA+(pi*r**2);\n\n#Result\nprint(\"total surface area of cone in m^2 is\",TSA);\n", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "('total surface area of cone in m^2 is', 75.36)\n" + } + ], + "prompt_number": 16 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 8.5, Page number 322" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "# To calculate the height of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nV=100; #volume of cone in cubic inches\nr=5; #radius of cone in inches\npi=3.14;\n\n#Calculation\nr_m=r*0.0254; #radius of cone in m\n#volume V=(1/3)*pi*(r**2)*h\n#therefore h = (3*V)/(pi*r**2)\nh=(3*V)/(pi*r**2); #height in inches\nR=3/r_m;\nh=math.ceil(h*10**3)/10**3; #rounding off to 3 decimals\n\n#Result\nprint(\"height of the cone in inches is\",h);\nprint(\"surface area to volume ratio in m-1 is\",R);\n\n#answer for the surface area to volume ratio given in the book is wrong", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "('height of the cone in inches is', 3.822)\n('surface area to volume ratio in m-1 is', 23.62204724409449)\n" + } + ], + "prompt_number": 18 + }, + { + "cell_type": "code", + "collapsed": false, + "input": "", + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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