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diff --git a/Engineering_Physics/chapter8_2.ipynb b/Engineering_Physics/chapter8_2.ipynb
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+{
+ "metadata": {
+  "name": "chapter8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": "Physics of Nano Materials"
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 8.1, Page number 320"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=5;    #radius in m\npi=3.14;\n\n#Calculation \nSA=4*pi*r**2;    #surface area of sphere in m^2\nV=(4/3)*pi*r**3;   #volume of sphere in m^3\nR=SA/V;    #ratio\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "('surface area to volume ratio of sphere in m-1 is', 0.6)\n"
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 8.2, Page number 321"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nd=26;   #distance in m\nr=d/2;  #radius in m\npi=3.14;\n\n#Calculation\nSA=4*pi*r**2;      #surface area of sphere in m^2\nV=(4/3)*pi*r**3;   #volume of sphere in m^3\nR=SA/V;    #ratio\nR=math.ceil(R*10**3)/10**3;   #rounding off to 3 decimals\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "('surface area to volume ratio of sphere in m-1 is', 0.231)\n"
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 8.3, Page number 321"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "# To calculate the volume of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=1;   #radius in m\nh=1;   #height in m\npi=3.14\n\n#Calculation\nV=(1/3)*pi*(r**2)*h;\nV=math.ceil(V*10**2)/10**2;   #rounding off to 2 decimals\n\n#Result\nprint(\"volume of cone in m^3 is\",V); ",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "('volume of cone in m^3 is', 1.05)\n"
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 8.4, Page number 321"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "# To calculate the total surface area of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=3;   # radius in m\nh=4;   # height in m\npi=3.14\n\n#Calculation\nSA=pi*r*math.sqrt((r**2)+(h**2));\nTSA=SA+(pi*r**2);\n\n#Result\nprint(\"total surface area of cone in m^2 is\",TSA);\n",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "('total surface area of cone in m^2 is', 75.36)\n"
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 8.5, Page number 322"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "# To calculate the height of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nV=100;   #volume of cone in cubic inches\nr=5;   #radius of cone in inches\npi=3.14;\n\n#Calculation\nr_m=r*0.0254;    #radius of cone in m\n#volume V=(1/3)*pi*(r**2)*h\n#therefore h = (3*V)/(pi*r**2)\nh=(3*V)/(pi*r**2);   #height in inches\nR=3/r_m;\nh=math.ceil(h*10**3)/10**3;   #rounding off to 3 decimals\n\n#Result\nprint(\"height of the cone in inches is\",h);\nprint(\"surface area to volume ratio in m-1 is\",R);\n\n#answer for the surface area to volume ratio given in the book is wrong",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "('height of the cone in inches is', 3.822)\n('surface area to volume ratio in m-1 is', 23.62204724409449)\n"
+      }
+     ],
+     "prompt_number": 18
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "",
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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