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diff --git a/Basic_Principles_And_Calculations_In_Chemical_Engineering/ch5.ipynb b/Basic_Principles_And_Calculations_In_Chemical_Engineering/ch5.ipynb new file mode 100644 index 00000000..5023ef53 --- /dev/null +++ b/Basic_Principles_And_Calculations_In_Chemical_Engineering/ch5.ipynb @@ -0,0 +1,239 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Chapter 5 : Pressure" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 5.1 Page no.109\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Pressure Conversion\n", + "# Solution\n", + "\n", + "# Variables\n", + "P = 60 ; #[Gpa]\n", + "\n", + "# Calculation and Results\n", + "#(a)\n", + "p_atm = (P*(10**6))/101.3 ; #[atm]\n", + "print '(a) Pressure in atmospheres is %.2e atm'%p_atm\n", + "\n", + "#(b)\n", + "p_s = (P*(10**6)*14.696)/101.3 ; #[psia]\n", + "print ' (b) Pressure in psia is %.2e psia'%p_s\n", + "\n", + "# (c)\n", + "p_in = (P*(10**6)*29.92)/101.3 ; #[inches of Hg]\n", + "print ' (c) Pressure in inches of Hg is %.2e in. Hg'%p_in\n", + "\n", + "# (d)\n", + "p_mm = (P*(10**6)*760)/101.3 ; #[mm of Hg]\n", + "print ' (d) Pressure in mm of Hg is %.2e mm Hg'%p_mm" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(a) Pressure in atmospheres is 5.92e+05 atm\n", + " (b) Pressure in psia is 8.70e+06 psia\n", + " (c) Pressure in inches of Hg is 1.77e+07 in. Hg\n", + " (d) Pressure in mm of Hg is 4.50e+08 mm Hg" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + " Example 5.2 Page no. 110\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Pressure Conversion\n", + "# Solution\n", + "\n", + "# Variable\n", + "b_rd = 28.0 ; #[in. Hg]\n", + "p_rd = 51.0 ; #[psia]\n", + "\n", + "# calculation\n", + "p_atm = b_rd*14.7/29.92 ; # [psia]\n", + "p_tnk = p_atm+p_rd ; #[psia]\n", + "\n", + "# Result\n", + "print ' Pressure in tank in psia is %.1f psia'%p_tnk" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " Pressure in tank in psia is 64.8 psia\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + " Example 5.3 Page no. 111\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Vacuum Pressure Reading\n", + "# Solution\n", + "\n", + "# Variables\n", + "b_rd = 100.0 ; #[kPa]\n", + "gp = 64.5*101.3/76.0 ; #[kPa]\n", + "\n", + "# Calculations\n", + "p_tnk = b_rd-gp ; #[kPa]\n", + "\n", + "# Results\n", + "print ' Absolute Pressure in tank in is %.1f kPa'%p_tnk\n", + "print ' Since absolute pressure in tank(%.1f kPa) is less than 20 kPa , the \\\n", + " mice probably will not survive. '%p_tnk" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " Absolute Pressure in tank in is 14.0 kPa\n", + " Since absolute pressure in tank(14.0 kPa) is less than 20 kPa , the mice probably will not survive. \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + " Example 5.4 Page no. 115\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Calculation of Pressure Difference\n", + "# Solution\n", + "\n", + "# Variables\n", + "df = 1.10*10**3 ; #[kg/m**3]\n", + "d = 1.0*10**3 ; #[kg/m**3]\n", + "g = 9.8 ; #[m/s**2]\n", + "h = 22.0 ; #[mm]\n", + "\n", + "# Calculation\n", + "dP = (df-d)*g*(h*10**(-3)) ; #[Pa]\n", + "\n", + "# Result\n", + "print 'Pressure difference across the orifice plate is %.1f Pa.'%dP" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Pressure difference across the orifice plate is 21.6 Pa.\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + " Example 5.5 Page no. 117\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Pressure Conversion\n", + "# Solution\n", + "\n", + "# Variables\n", + "p_atm=730.0*29.92/760.0 ; #[in. Hg]\n", + "gp= (4.0*29.92)/(2.54*12*33.91) ; #[in. Hg]\n", + "\n", + "# Calculation\n", + "p_air=p_atm-gp ; #[in. Hg]\n", + "\n", + "# Result\n", + "print ' Pressure of the air is %.1f in. Hg.'%p_air" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " Pressure of the air is 28.6 in. Hg.\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "code", + "collapsed": true, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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