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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      "Chapter 5 : Pressure"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      "Example 5.1 Page no.109\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Pressure Conversion\n",
+      "# Solution\n",
+      "\n",
+      "# Variables\n",
+      "P = 60 ;         #[Gpa]\n",
+      "\n",
+      "# Calculation and Results\n",
+      "#(a)\n",
+      "p_atm = (P*(10**6))/101.3 ;           #[atm]\n",
+      "print '(a) Pressure in atmospheres is %.2e atm'%p_atm\n",
+      "\n",
+      "#(b)\n",
+      "p_s = (P*(10**6)*14.696)/101.3 ;      #[psia]\n",
+      "print ' (b) Pressure in psia is %.2e psia'%p_s\n",
+      "\n",
+      "# (c)\n",
+      "p_in = (P*(10**6)*29.92)/101.3 ;      #[inches of Hg]\n",
+      "print ' (c) Pressure in inches of Hg is %.2e in. Hg'%p_in\n",
+      "\n",
+      "# (d)\n",
+      "p_mm = (P*(10**6)*760)/101.3 ;        #[mm of Hg]\n",
+      "print ' (d) Pressure in mm of Hg is %.2e mm Hg'%p_mm"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(a) Pressure in atmospheres is 5.92e+05 atm\n",
+        " (b) Pressure in psia is 8.70e+06 psia\n",
+        " (c) Pressure in inches of Hg is 1.77e+07 in. Hg\n",
+        " (d) Pressure in mm of Hg is 4.50e+08 mm Hg"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      " Example 5.2 Page no. 110\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Pressure Conversion\n",
+      "# Solution\n",
+      "\n",
+      "# Variable\n",
+      "b_rd = 28.0 ;       #[in. Hg]\n",
+      "p_rd = 51.0 ;       #[psia]\n",
+      "\n",
+      "# calculation\n",
+      "p_atm = b_rd*14.7/29.92 ;       # [psia]\n",
+      "p_tnk  =  p_atm+p_rd ;          #[psia]\n",
+      "\n",
+      "# Result\n",
+      "print ' Pressure in tank in psia is %.1f psia'%p_tnk"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Pressure in tank in psia is 64.8 psia\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      " Example 5.3 Page no. 111\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Vacuum Pressure Reading\n",
+      "# Solution\n",
+      "\n",
+      "# Variables\n",
+      "b_rd = 100.0 ;             #[kPa]\n",
+      "gp =  64.5*101.3/76.0 ;    #[kPa]\n",
+      "\n",
+      "# Calculations\n",
+      "p_tnk = b_rd-gp ;          #[kPa]\n",
+      "\n",
+      "# Results\n",
+      "print ' Absolute Pressure in tank in is %.1f kPa'%p_tnk\n",
+      "print '  Since absolute pressure in tank(%.1f kPa) is less than 20 kPa , the \\\n",
+      " mice probably will not survive. '%p_tnk"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Absolute Pressure in tank in is 14.0 kPa\n",
+        "  Since absolute pressure in tank(14.0 kPa) is less than 20 kPa , the  mice probably will not survive. \n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      " Example 5.4 Page no. 115\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Calculation of Pressure Difference\n",
+      "# Solution\n",
+      "\n",
+      "# Variables\n",
+      "df = 1.10*10**3 ;              #[kg/m**3]\n",
+      "d = 1.0*10**3 ;                #[kg/m**3]\n",
+      "g = 9.8 ;                      #[m/s**2]\n",
+      "h = 22.0 ;                     #[mm]\n",
+      "\n",
+      "# Calculation\n",
+      "dP = (df-d)*g*(h*10**(-3)) ;   #[Pa]\n",
+      "\n",
+      "# Result\n",
+      "print 'Pressure difference across the orifice plate is %.1f Pa.'%dP"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure difference across the orifice plate is 21.6 Pa.\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 3,
+     "metadata": {},
+     "source": [
+      " Example 5.5 Page no. 117\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Pressure Conversion\n",
+      "# Solution\n",
+      "\n",
+      "# Variables\n",
+      "p_atm=730.0*29.92/760.0 ;            #[in. Hg]\n",
+      "gp= (4.0*29.92)/(2.54*12*33.91) ;    #[in. Hg]\n",
+      "\n",
+      "# Calculation\n",
+      "p_air=p_atm-gp ;                     #[in. Hg]\n",
+      "\n",
+      "# Result\n",
+      "print ' Pressure of the air is %.1f in. Hg.'%p_air"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Pressure of the air is 28.6 in. Hg.\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "code",
+     "collapsed": true,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file