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Diffstat (limited to 'A_Comprehensive_Textbook_Of_Applied_Physics_')
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| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter2.ipynb | 342 | ||||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter3.ipynb | 606 | ||||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter4.ipynb | 1115 | ||||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb | 1043 | ||||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/README.txt | 10 | ||||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/screenshots/k1.png | bin | 0 -> 16503 bytes | |||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/screenshots/k2.png | bin | 0 -> 18858 bytes | |||
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/screenshots/k3.png | bin | 0 -> 14827 bytes |
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diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter1.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter1.ipynb new file mode 100644 index 00000000..a1a29ec8 --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter1.ipynb @@ -0,0 +1,503 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "UNIT-1:Waves & Vibrations"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.1,Page no:11"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Velocity of sound \n",
+ "\n",
+ "#Variable declaration\n",
+ "n=512 #frequency in Hz\n",
+ "l=67 #wavelength in cm\n",
+ "\n",
+ "#Calculation\n",
+ "v=n*l #calculating velocity\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity = \",v,\" cm/sec\" \n",
+ "print\"NOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity = 34304 cm/sec\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.2,Page no:11"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Frequency of tuning fork \n",
+ "\n",
+ "#Variable declaration\n",
+ "v=340 #velocity in m/sec\n",
+ "l=0.68 #wavelength in m\n",
+ "\n",
+ "#Calculation\n",
+ "n=v/l #calculating frequency\n",
+ "\n",
+ "#Result\n",
+ "print\"Frequency\",n,\"Hz\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Frequency 500.0 Hz\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.3,Page no:12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Wavelength of wave \n",
+ "\n",
+ "#Variable declaration\n",
+ "v=3*10**8 #velocity in m/sec\n",
+ "n=500*10**3 #frequency in Hz\n",
+ "\n",
+ "#Calculation\n",
+ "l=v/n #calculating wavelength\n",
+ "\n",
+ "#Result\n",
+ "print\"Wavelength=\",l,\"m\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Wavelength= 600 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.4,Page no:12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Distance by sound in air \n",
+ "\n",
+ "#Variable declaration\n",
+ "v=330 #velocity in m/sec\n",
+ "n=560.0 #frequency in Hz\n",
+ "\n",
+ "#Calculation\n",
+ "lamda=v/n #calculating wavelength\n",
+ "\n",
+ "#Result\n",
+ "print\"lambda=\",round(lamda,3),\"m\"\n",
+ "print\"Distance travelled in 30 vibrations in m = \",round(lamda*30,2),\"m\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "lambda= 0.589 m\n",
+ "Distance travelled in 30 vibrations in m = 17.68 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.5,Page no:12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Sound,when stone dropped from height\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "s=90.0 #distance in m\n",
+ "u=0 #initial velocity in m/sec\n",
+ "\n",
+ "#Calculation\n",
+ "t=math.sqrt(90/4.9) #calculating time using kinematical equation\n",
+ "later=4.56 #Time after which sound is heard\n",
+ "t1=later-t #calculating time taken by sound to travel\n",
+ "t1=round(t1,2)\n",
+ "v=s/t1 #calculating velocity\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity in m/sec = \",round(v,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity in m/sec = 333.33 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.6,Page no:13"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Velocity in different medium \n",
+ "\n",
+ "#Variable declaration\n",
+ "l1=1.5 #wavelength in m\n",
+ "l2=2 #wavelength in m\n",
+ "v1=120 #velocity in m/sec\n",
+ "\n",
+ "#Calculation\n",
+ "n=v1/l1 #calculating frequency\n",
+ "v2=n*l2 #calculating velocity\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity in m/sec = \",v2,\"m/sec\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity in m/sec = 160.0 m/sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.7,Page no:14"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Frequency of green light \n",
+ "\n",
+ "#Variable declaration\n",
+ "l=5641*10**-10 #wavelength in m\n",
+ "c=3*10**8 #velocity in m/sec\n",
+ "u=1.58 #refractive index of glass\n",
+ "\n",
+ "#Calculation\n",
+ "n=c/l #calculating frequency\n",
+ "cg=c/u #calculating velocity of light in glass\n",
+ "l1=cg/n #calculating wavelegth in glass\n",
+ "\n",
+ "#Result\n",
+ "print\"Wavelength in glass in Angstrom =\",l1*10**10,\"Angstrom\" \n",
+ "print\"\\n\\nNOTE:Calculation ambiguity in book,value of cg is taken as 1.9*10**8 ,Therefore final answer is changed\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Wavelength in glass in Angstrom = 3570.25316456 Angstrom\n",
+ "\n",
+ "\n",
+ "NOTE:Calculation ambiguity in book,value of cg is taken as 1.9*10**8 ,Therefore final answer is changed\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.8,Page no:15"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Wavelength of raio station \n",
+ "\n",
+ "#Variable declaration\n",
+ "n=12*10**6 #frequency in Hz\n",
+ "v=3*10**8 #velocity in m/sec\n",
+ "\n",
+ "#Calculation\n",
+ "l=v/n #calculating wavelength\n",
+ "\n",
+ "#Result\n",
+ "print\"Wavelength in m = \",l,\"m\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Wavelength in m = 25 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.9,Page no:15"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Wavelength of sound \n",
+ "\n",
+ "#Variable declaration\n",
+ "n=400 #frequency in Hz\n",
+ "v=300.0 #velocity in m/sec\n",
+ "\n",
+ "#Calculation\n",
+ "l=v/n #calculating wavelength\n",
+ "\n",
+ "#Result\n",
+ "print\"Wavelength=\",l,\"m\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Wavelength= 0.75 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.10,Page no:22"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Equation of SHM\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "a=20 #amplitude in cm\n",
+ "n=6 #frequency per second\n",
+ "\n",
+ "#Calculation\n",
+ "w=2*(math.pi)*n #omega in radians/sec\n",
+ "\n",
+ "#Result\n",
+ "print\"Omega in radians/sec = \",round(w,1),\"rad/sec\" \n",
+ "print\"y=\",a,\"sin\",round(w,1),\"t\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Omega in radians/sec = 37.7 rad/sec\n",
+ "y= 20 sin 37.7 t\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.11,Page no:23"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#SHM by a body \n",
+ "\n",
+ "#Variable declaration\n",
+ "a=6 #amplitude in cm\n",
+ "n=9 #frequency in Hz.\n",
+ "\n",
+ "#Calculation\n",
+ "vmax=2*(math.pi)*n*6 #calculating velocity in cm/sec\n",
+ "acc=-((18*(math.pi))**2)*6 #calculating acc. in m/sec square\n",
+ "\n",
+ "#Result\n",
+ "print\"Maximum velocity in cm/sec = \",round(vmax,2),\"cm/sec\" \n",
+ "print\"Velocity at extreme position = 0\" \n",
+ "print\"Accelaration at mean position = 0\" \n",
+ "print\"Accelaration at extreme position = \",round(acc,1),\"m/sec^2\" \n",
+ "print\"\\n\\nNOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum velocity in cm/sec = 339.29 cm/sec\n",
+ "Velocity at extreme position = 0\n",
+ "Accelaration at mean position = 0\n",
+ "Accelaration at extreme position = -19186.5 m/sec^2\n",
+ "\n",
+ "\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:1.12,Page no:26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Weight of body suspended fro spring \n",
+ "\n",
+ "#Variable declaration\n",
+ "g=9.8 #gravitational constant\n",
+ "m=50 #mass in kg\n",
+ "l=0.2 #length in m\n",
+ "T=0.6 #time period\n",
+ "\n",
+ "#Calculation\n",
+ "k=(m*g)/l #calculating constant\n",
+ "m=2450*((T/(2*(math.pi)))**2) #calcualting mass using given time period\n",
+ "\n",
+ "#Result\n",
+ "print\"Mass of body= \",round(m,2),\"kg\" \n",
+ "print\"Weight of suspended body=\",round(m,2)*g,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Mass of body= 22.34 kg\n",
+ "Weight of suspended body= 218.932 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter2.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter2.ipynb new file mode 100644 index 00000000..7c9499cb --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter2.ipynb @@ -0,0 +1,342 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "UNIT-2:Application of Sound Waves"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.1,Page no:41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate reverberation time\n",
+ "\n",
+ "#Variable declaration\n",
+ "v=3000 #volume in metre cube.\n",
+ "theta=0.2 #theta in owu(open window unit).\n",
+ "s=1850 #area in metre cube.\n",
+ "\n",
+ "#Calculation\n",
+ "a=theta*s #calculating total absorbtion of surface.\n",
+ "T=(0.165*v)/a #calculating T using Sabine formula\n",
+ "\n",
+ "#Result\n",
+ "print\"Reverberation time of Room = \",round(T,2) ,\"sec\" \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Reverberation time of Room = 1.34 sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.2,Page no:41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate average absorbing power\n",
+ "\n",
+ "#Variable declaration\n",
+ "v=120000 #volume in metre cube.\n",
+ "t=1.5 #time in second.\n",
+ "s=25000 #area in metre cube.\n",
+ "\n",
+ "#Calculation\n",
+ "a=(0.16*v)/(t*s) #using Sabine formula for calculating a\n",
+ "\n",
+ "#Variable declaration\n",
+ "print\"Average Absorbing Power of Surface = \",a,\"o w u\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Average Absorbing Power of Surface = 0.512 o w u\n"
+ ]
+ }
+ ],
+ "prompt_number": 39
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.3,Page no:42"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Reverberation time of cinema hall\n",
+ "\n",
+ "#Variable declaration\n",
+ "v=6000.0 #Volume in metre cube.\n",
+ "a=20.0 #surface absorbtion in owu(open window unit).\n",
+ "\n",
+ "#Calculation\n",
+ "T=(0.165*v)/(a) #calculating T using Sabine Formula.\n",
+ "\n",
+ "#Result\n",
+ "print\"Reverberation Time = \",T,\"sec\"\n",
+ "print\"\\nNOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Reverberation Time = 49.5 sec\n",
+ "\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 37
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.4,Page no:42"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Reverberation time with persons\n",
+ "\n",
+ "#Variable declaration\n",
+ "v=3500 #volume in metre cube.\n",
+ "n1=370-300 #no. of audience on wooden seats.\n",
+ "n2=300-70 #no. of empty wooden seats.\n",
+ "\n",
+ "#Calculation\n",
+ "a1s1=0.04*60 #absorption due to wooden doors.\n",
+ "a2s2=0.03*700 #absorption due to plastered walls.\n",
+ "a3s3=0.06*50 #absorption due to glass work.\n",
+ "a4s4=4.2*370 #absorption due to audience on spungy and wooden \n",
+ "#seats.\n",
+ "a5s5=2*230 #absorption due to empty seats.\n",
+ "sum=a1s1+a2s2+a3s3+a4s4+a5s5 #total absorption of cinema hall.\n",
+ "T=(0.165*v)/sum #calculating T using Sabine Formula.\n",
+ "\n",
+ "#Result\n",
+ "print\"Reverberation Time = \",round(T,2),\"sec\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Reverberation Time = 0.28 sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 40
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.5,Page no:49"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Frequency of ultrasonics\n",
+ "\n",
+ "import math\n",
+ "\n",
+ "#Variable declaration\n",
+ "l=10 #length in centimetres.\n",
+ "Y=20*10**11 #Young's Modulus in dyne/cm square.\n",
+ "R=8 #Density in gram/cc\n",
+ "\n",
+ "#Calculation\n",
+ "n=(1.0/(2*l))*math.sqrt(Y/R) #calculating frequency of vibration using \n",
+ "#young's modulus.\n",
+ "\n",
+ "#Result\n",
+ "print\"Frequency of vibration=\",n,\"Hz\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Frequency of vibration= 25000.0 Hz\n"
+ ]
+ }
+ ],
+ "prompt_number": 28
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.6,Page no:50"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Fundamental frequency of vibration\n",
+ "\n",
+ "import math\n",
+ "\n",
+ "#Variable declaration\n",
+ "t=0.1 #thickness in centimetre.\n",
+ "Y=8.75*10**11 #Young's Modulus in dyne/cm square.\n",
+ "R=2.654 #Density in gram/cm square.\n",
+ "\n",
+ "#Calculation\n",
+ "n=(1/(2*t))*math.sqrt(Y/R) #calculating frequency using Young's modulus.\n",
+ "\n",
+ "#Result\n",
+ "print\"Frequency of Vibration=\",round(n),\"Hz\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Frequency of Vibration= 2870936.0 Hz\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.7,Page no:50"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Speed of sound wave in water\n",
+ "\n",
+ "#Variable declaration\n",
+ "K=2.026*10**9 #Bulk Modulus in N/m square.\n",
+ "R=10**3 #Density in Kg/m cube.\n",
+ "\n",
+ "#Calculation\n",
+ "V=math.sqrt(K/R) #Calculating speed using Bulk Modulus.\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity of sound waves in water = \",round(V,2),\"m/sec\" \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity of sound waves in water = 1423.38 m/sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:2.8,Page no:51"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Speed of ultrasonic wave in air\n",
+ "\n",
+ "import math\n",
+ "\n",
+ "#Variable declaration\n",
+ "Y=1.41 #Young's Modulus.\n",
+ "R=1.293*10**-3 #Density of air in g/centimetre cube.\n",
+ "P=76*13.6*980 #atmospheric pressure in dyne/cm square.\n",
+ "\n",
+ "#Calculation\n",
+ "V=math.sqrt((Y*P)/R) #calculating speed using young's modulus.\n",
+ "\n",
+ "#Result\n",
+ "print\"Speed of ultrasonic wave in air at n.t.p=\",round(V*10**-2,1),\"m/sec\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Speed of ultrasonic wave in air at n.t.p= 332.4 m/sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter3.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter3.ipynb new file mode 100644 index 00000000..e8c1b701 --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter3.ipynb @@ -0,0 +1,606 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "UNIT-3:Principle of Optics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.1,Page no:69"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Distance of object from lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "f=15.0 #focal length in cm\n",
+ "v=10.0 #image distance in cm\n",
+ "\n",
+ "#Calculation\n",
+ "u=1/((1/v)-(1/f)) #calculating u using (1/f)=(1/v)-(1/u)\n",
+ "\n",
+ "#Result\n",
+ "print\"Object Distance ,u= \",u,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Object Distance ,u= 30.0 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.2,Page no:70"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Power of lens\n",
+ "\n",
+ "#Variable declaration\n",
+ "f=80.0 #focal length in cm\n",
+ "f1=20.0 #focallength of first lens in cm\n",
+ "\n",
+ "#Calculation\n",
+ "f2=1/((1/f)-(1/f1)) #using (1/F)=(1/f1)+(1/f2)\n",
+ "P=(100.0/f) #power in D\n",
+ "P1=100.0/20 #power of first lens\n",
+ "P2=P1-P #power in D\n",
+ "\n",
+ "#Variable declaration\n",
+ "print\"Power= \",P2,\"D\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Power= 3.75 D\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.3,Page no:71"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Focal length and nature of lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "P=2.5 #Power in D\n",
+ "\n",
+ "#Calculation\n",
+ "f=-(1/P) #calculating f in m\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length =\",f,\"m\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length = -0.4 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.4,Page no:72"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find object and image distance\n",
+ "\n",
+ "#Variable declaration \n",
+ "m=4 #magnigication\n",
+ "f=20 #focal length in cm\n",
+ "\n",
+ "#Calculation\n",
+ "u=(20*3)/(4) #on simplifying (1/f)=(1/v)-(1/u)\n",
+ "v=(4*u) #calculating v in cm\n",
+ "\n",
+ "#Result\n",
+ "print\"Object distance,u= \",u,\"cm\" \n",
+ "print\"Image distance,v= \",v,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Object distance,u= 15 cm\n",
+ "Image distance,v= 60 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.5,Page no:72"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Describe image produced by lens\n",
+ "\n",
+ "from scipy.optimize import fsolve \n",
+ "\n",
+ "#Variable declaration\n",
+ "u=14.0 #object distance in cm\n",
+ "f=-21.0 #focal distance in cm\n",
+ "\n",
+ "#Calculation\n",
+ "v=1/((1/f)-(1/u))\n",
+ "I=(3.0*v)/(-u) #using m=(1/0)=(v/u) \n",
+ "\n",
+ "#Result\n",
+ "print\"Image distance= \",v,\"cm\" \n",
+ "print\"I= \",I,\"cm\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Image distance= -8.4 cm\n",
+ "I= 1.8 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.6,Page no:79"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate magnifying power of glass\n",
+ "\n",
+ "#Variable declaration \n",
+ "fe=5 #focal length in cm\n",
+ "D=25 #distance od distinct vision in cm\n",
+ "\n",
+ "#Calculation\n",
+ "m=1+(D/fe) #calculating magnifying power\n",
+ "\n",
+ "#Result\n",
+ "print\"magnifying Power = \",m "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "magnifying Power = 6\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.7,Page no:80"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate magnification produced by objectives\n",
+ "\n",
+ "#Variable declaration \n",
+ "fe=5 #focal length in cm\n",
+ "D=25 #distance od distinct vision in cm\n",
+ "\n",
+ "#Calculation\n",
+ "mo=30/(1+(D/fe)) #calculating magnification of objective lens\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnification produced by objective lens = \",mo "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnification produced by objective lens = 5\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.8,Page no:80"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Magnifying power of microscope\n",
+ "\n",
+ "#Variable declaration \n",
+ "u=-6.0 #object distance in cm\n",
+ "fo=4.0 #focal distance in cm\n",
+ "fe=6.0 #focal length in cm\n",
+ "D=25.0 #distance of distinct vision in cm\n",
+ "\n",
+ "#Calculation\n",
+ "v=1/((1/u)+(1/fo)) #using (1/f)=(1/v)-(1/u)\n",
+ "m=(v/u)*(1+(D/fe)) #calculating m\n",
+ "\n",
+ "#Result\n",
+ "print\"Image distance in cm = \",v,\"cm\" \n",
+ "print\"Magnifying Power = \",round(-m,2) "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Image distance in cm = 12.0 cm\n",
+ "Magnifying Power = 10.33\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.9,Page no:81"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Magnification of lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "D=25.0 #distance of distinct vision\n",
+ "u=-9.0 #object distance in cm\n",
+ "fe=10.0 #focal length in cm\n",
+ "\n",
+ "#Calculation\n",
+ "v=1/((1/fe)+(1/u)) #using (1/f)=(1/v)-(1/u)\n",
+ "m=(v/u) #calculating m\n",
+ "M=D/u #calculating Magnifying power of lens\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnification of lens = \",m \n",
+ "print\"Magnifying Power = \",round(-M,1) "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnification of lens = 10.0\n",
+ "Magnifying Power = 2.8\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.10,Page no:82"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate focal length of eye lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "fo=0.5 #focal length of eye lens\n",
+ "D=25 #distance of distinct vision\n",
+ "L=15 #length in cm\n",
+ "m=375 #magnification\n",
+ "\n",
+ "#Calculation\n",
+ "fe=(-L*D)/(fo*((L/fo)-m)) #calculating fe\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length of eye lens= \",round(fe,1),\"cm\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length of eye lens= 2.2 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 33
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.11,Page no:86"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Focal length of astronomical lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "m=5 #magnifying power\n",
+ "L=24 #length in cm\n",
+ "fe=4 #focal length in cm\n",
+ "\n",
+ "#Calculation\n",
+ "fo=5*fe #calculating fo\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length of lens = \",fo,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length of lens = 20 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.12,Page no:87"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate magnifying power of telescope\n",
+ "\n",
+ "#Variable declaration \n",
+ "D=25.0 #distance of distinct vision in cm\n",
+ "fo=140.0 #focal length of eye lens\n",
+ "fe=5.0 #focal length in cm\n",
+ "\n",
+ "#Calculation\n",
+ "m=-(fo/fe) #calculating magnifying power\n",
+ "m1=-(fo/fe)*(1+(fe/D)) #calculating magnifying power\n",
+ "\n",
+ "#Result\n",
+ "print\"(a):Magnifying power at normal adjustment = \",m\n",
+ "print\"(b):Magnifying power atleast distance of distinct vision = \",m1"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a):Magnifying power at normal adjustment = -28.0\n",
+ "(b):Magnifying power atleast distance of distinct vision = -33.6\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.13,Page no:88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find focal length of eye lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "M=5 #Magnifying power\n",
+ "fo=10 #focal length of eye lens\n",
+ "\n",
+ "#Calculation\n",
+ "fe=fo/M #calculating fe\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length of eye lens= \",fe,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length of eye lens= 2 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.14,Page no:88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find magnifying power of telescope\n",
+ "\n",
+ "#Variable declaration \n",
+ "fo=75.0 #focal length of eye lens\n",
+ "D=25.0 #distance of distinct vision\n",
+ "fe=5.0 #focal of eye lens in cm\n",
+ "\n",
+ "#Calculation\n",
+ "M=-(fo/fe)*(1+(fe/D)) #calculating M\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnifying power = \",M"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnifying power = -18.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:3.15,Page no:88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Focal length of two thin lens\n",
+ "\n",
+ "#Variable declaration \n",
+ "M=7 #magnifying power\n",
+ "L=40 #length\n",
+ "\n",
+ "#Calculation\n",
+ "fe=(L/(M+1)) #focal length of eye lens in cm\n",
+ "fo=(M*fe) #calculating focal length\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal Length of lens=\",fo,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal Length of lens= 35 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter4.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter4.ipynb new file mode 100644 index 00000000..a7b1202f --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter4.ipynb @@ -0,0 +1,1115 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "UNIT-4:Electrostatics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.1,Page no:103"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Coulomb or charge of an electron\n",
+ "\n",
+ "#Variable declaration \n",
+ "q=1.0 #no of coulomb\n",
+ "e=1.6*10**-19 #charge on an electron\n",
+ "\n",
+ "#Calculation\n",
+ "n=(q/e) #calculating no of electrons\n",
+ "\n",
+ "#Result\n",
+ "print\"No of electrons =\",n\n",
+ "print\"NOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "No of electrons = 6.25e+18\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 32
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.2,Page no:103"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calcuate charge in equal sized spheres\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "g=9.8\n",
+ "m=4.5 #Massin [kg]\n",
+ "r=0.03 #radius in [m]\n",
+ "\n",
+ "#Calculation\n",
+ "F=m*g #in Newton\n",
+ "q=math.sqrt(((r**2)*m*g)/(9*10**9)) #calculating q using F=(1/4*3.14*eo)*((q1*q2)/(r**2))\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge = \",q,\"C\"\n",
+ "print\"\\nNOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge = 2.1e-06 C\n",
+ "\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 36
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.3,Page no:103"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calcuate force between small spheres\n",
+ "\n",
+ "#Variable declaration \n",
+ "q1=2*10**-7 #charge in C\n",
+ "q2=3*10**-7 #charge in C\n",
+ "r=30*10**-2 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
+ "\n",
+ "#Result\n",
+ "print\"Force = %.e\"%F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force = 6e-03 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 70
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.4,Page no:104"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate force between two charges in vacuum\n",
+ "\n",
+ "#Variable declaration \n",
+ "q1=1 #charge in C\n",
+ "q2=1 #charge in C\n",
+ "r=1 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
+ "\n",
+ "#Result\n",
+ "print\"Force = %.e\"%F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force = 9e+09 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 71
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.5,Page no:104"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#No of electrons trasnferred when polythene is rubbed\n",
+ "\n",
+ "#Variable declaration \n",
+ "m=9*10**-31 #mass of electron in kg\n",
+ "q=-3.2*10**-7 #charge in C\n",
+ "e=-1.6*10**-19 #charge on electron in C\n",
+ "\n",
+ "#Calculation\n",
+ "n=(q/e) #calculating n\n",
+ "M=n*m #calculating mass transfered\n",
+ "\n",
+ "#Result\n",
+ "print\"(a):No. of electrons = \",n\n",
+ "print\"(b):Mass transfered to polythene= \",M,\"kg\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a):No. of electrons = 2e+12\n",
+ "(b):Mass transfered to polythene= 1.8e-18 kg\n"
+ ]
+ }
+ ],
+ "prompt_number": 50
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.6,Page no:105"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Compare force between electron and proton\n",
+ "\n",
+ "#Variable declaration \n",
+ "q1=1.6*10**-19 #charge in C\n",
+ "q2=-1.6*10**-19 #charge in C\n",
+ "r=10**-9 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
+ "\n",
+ "#Result\n",
+ "print\"Force=\",F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force= -2.304e-10 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 54
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.7,Page no:110"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find the value of voltage\n",
+ "\n",
+ "#Variable declaration \n",
+ "Va=-10 #voltage in volts\n",
+ "W=100 #work in Joule\n",
+ "q=2 #charge in Coulomb\n",
+ "\n",
+ "#Calculation\n",
+ "v=(Va)+(W/q) #calculating v\n",
+ "\n",
+ "#Result\n",
+ "print\"Voltage = \",v,\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Voltage = 40 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 55
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.8,Page no:111"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate magnitude of point charge for fixed electric field\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "eo=(8.854*10**-12) #constant\n",
+ "E=2 #magnitude of electric field in N/C\n",
+ "r=0.5 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "q=E*4*(math.pi)*(eo)*(r**2) #calculating charge\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge= %.2e\"%q,\"C\"\n",
+ "print\"\\nNOTE:Calcualtion mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge= 5.56e-11 C\n",
+ "\n",
+ "NOTE:Calcualtion mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 73
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.9,Page no:111"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate work done to move electron in capacitor\n",
+ "\n",
+ "#Variable declaration \n",
+ "e=-1.6*10**-19 #charge on electron in Coulomb\n",
+ "q=20*10**-6 #charge in Coulomb\n",
+ "r1=0.1 #r1 in m\n",
+ "r2=0.05 #r2 in m\n",
+ "\n",
+ "#Calculation\n",
+ "Va=9*10**9*(q/r1) #calculating voltage at A\n",
+ "Vb=9*10**9*(q/r2) #calculating voltage at B\n",
+ "V=Va-Vb #potential difference\n",
+ "W=V*e #calculating work done in joule\n",
+ "\n",
+ "#Result\n",
+ "print\"Work done to take the electron from A to B = \",W,\"Joule\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Work done to take the electron from A to B = 2.88e-13 Joule\n"
+ ]
+ }
+ ],
+ "prompt_number": 69
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.10,Page no:112"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Potential at the centre of the square\n",
+ "\n",
+ "#Variable declaration \n",
+ "q1=(2.0*10**-8) #charge in coulomb\n",
+ "q2=(-2.0*10**-8) #charge in coulomb\n",
+ "q3=(3.0*10**-8) #charge in coulomb\n",
+ "q4=(6.0*10**-8) #charge in coulomb\n",
+ "s=1.0 #side in m\n",
+ "\n",
+ "#Calculation\n",
+ "V=(9.0*10**9)*(1.0/s)*(q1+q2+q3+q4) #calculating voltage\n",
+ "\n",
+ "#Result\n",
+ "print\"Voltage in Volts = \",V,\"Volts\"\n",
+ "print\"\\nNOTE:Calculation mistake in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Voltage in Volts = 810.0 Volts\n",
+ "\n",
+ "NOTE:Calculation mistake in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.11,Page no:123"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Electrical flux through gaussian surface\n",
+ "\n",
+ "#Variable declaration \n",
+ "eo=8.85*10**-12 #constant\n",
+ "q=2*10**-6 #charge in coulomb\n",
+ "l=9 #length in cm\n",
+ "\n",
+ "#Calculation\n",
+ "fi=(q/eo) #calcualting flux in (N m square)/c\n",
+ "\n",
+ "#Result\n",
+ "print\"Flux through the surface=%2e\"%fi,\"N m^2/c\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Flux through the surface=2.259887e+05 N m^2/c\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.12,Page no:124"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate charge on spherical capacitor\n",
+ "\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "eo=8.85*10**-12 #constant\n",
+ "r=1.2 #r in m\n",
+ "t=80*10**-6 #surface sharge density in c/m square\n",
+ "\n",
+ "#Calculation\n",
+ "q=t*4*(math.pi)*(r**2) #calculating charge\n",
+ "fi=q/eo #calculating flux\n",
+ "\n",
+ "#Result\n",
+ "print\"Flux=%g\"%fi,\"N c^-1 m^2\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Flux=1.63576e+08 N c^-1 m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.13,Page no:124"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate linear charge density\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "eo=8.85*10**-12 #constant\n",
+ "E=9*10**4 #Electric field in N/C\n",
+ "r=2*10**-2 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "L=2*(math.pi)*E*eo*r #calculating linear charge density\n",
+ "\n",
+ "#Result\n",
+ "print\"Linear charge density = \",round(L,7),\"cm^-1\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Linear charge density = 1e-07 cm^-1\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.14,Page no:125"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Electrical intensity of plates\n",
+ "\n",
+ "#Variable declaration \n",
+ "o=17*10**-22 #surface charge density in cm**-2\n",
+ "eo=8.85*10**-12 #constant\n",
+ "\n",
+ "#Calculation\n",
+ "E=o/eo #calculating electric intensity in region III\n",
+ "\n",
+ "#Result\n",
+ "print\"Electric Intensity in regions I and II = 0\" \n",
+ "print\"Electric Intensity in region III = \",round(E,12),\"N/C\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Electric Intensity in regions I and II = 0\n",
+ "Electric Intensity in region III = 1.92e-10 N/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.15,Page no:125"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Intensity of electric field of point charge\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "r=0.05 # in m\n",
+ "eo=8.85*10**-12 #constant\n",
+ "q=10.0**-9 #charge at point P in Coulomb\n",
+ "\n",
+ "#Calculation\n",
+ "E=q/(4*(math.pi)*eo*(r**2)) #calculating electric field\n",
+ "r1=0.2 #in m\n",
+ "V1=q/(4*(math.pi)*eo*r1) #calculating potential difference\n",
+ "\n",
+ "#Result\n",
+ "print\"Electric field= \",round(E),\"v/m\"\n",
+ "print\"\\nNOTE:Approximate answer is calculated in book\\n\\n\"\n",
+ "print\"Potential difference between two points = \",round(V1),\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Electric field= 3597.0 v/m\n",
+ "\n",
+ "NOTE:Approximate answer is calculated in book\n",
+ "\n",
+ "\n",
+ "Potential difference between two points = 45.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 65
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.16,Page no:126"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Charge on the sphere and electric flux\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "eo=8.85*10**-12 #constant\n",
+ "o=80.0*10**-6 #surface charge density in c/ square\n",
+ "r=1.2 #in m\n",
+ "\n",
+ "#Calculation\n",
+ "q=o*(math.pi)*(r**2) #calculating charge in Coulomb\n",
+ "fi=q/eo #calculating electric flux\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge= \",q,\"C\"\n",
+ "print\"Electric flux = \",fi,\"N m^2/c\"\n",
+ "print\"\\nNOTE:Wrong answers in book\\n\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge= 0.000361911473694 C\n",
+ "Electric flux = 40893951.8298 N m^2/c\n",
+ "\n",
+ "NOTE:Wrong answers in book\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 19
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.17,Page no:138"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Charge on plates of capacitor\n",
+ "\n",
+ "#Variable declaration \n",
+ "V=250 #potential difference in Volt\n",
+ "C=10**-11 #capacitance in farad\n",
+ "\n",
+ "#Calculation\n",
+ "q=C*V #calculating charge\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge = \",q,\"C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge = 2.5e-09 C\n"
+ ]
+ }
+ ],
+ "prompt_number": 68
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.18,Page no:138"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate capacitance of earth\n",
+ "\n",
+ "#Variable declaration \n",
+ "r=6.4*10**6 #in m\n",
+ "\n",
+ "#Calculation\n",
+ "C=r/(9*10**9) #calculating charge\n",
+ "\n",
+ "#Result\n",
+ "print\"Capacitance = \",round(C*10**6),\"mu F\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Capacitance = 711.0 mu F\n"
+ ]
+ }
+ ],
+ "prompt_number": 67
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.19,Page no:138"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Area of capacitor plate\n",
+ "\n",
+ "#Variable declaration \n",
+ "C=2 #capacitance in Farad\n",
+ "d=0.5*10**-2 #distance in m\n",
+ "eo=8.85*10**-12 #constant\n",
+ "\n",
+ "#Calculation\n",
+ "A=(C*d)/(eo) #calculating area\n",
+ "\n",
+ "#Result\n",
+ "print\"Area=%.2e\"%A,\"m^2\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Area=1.13e+09 m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 66
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.20,Page no:139"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Spherical and plate capacitor\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "A=0.02 #area in m square\n",
+ "r=0.5 #r in m\n",
+ "\n",
+ "#Calculation\n",
+ "d=(A/(4*(math.pi)*r)) #calculating distance\n",
+ "\n",
+ "#Result\n",
+ "print\"Distance between the plates = \",round(d*1000,2),\"mm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Distance between the plates = 3.18 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.21,Page no:139"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Capacitance of parallel plate capacitor\n",
+ "\n",
+ "#Variable declaration \n",
+ "eo=8.85*10**-12 #constant\n",
+ "A=1 #area in m square\n",
+ "d=2*10**-3 #r in m\n",
+ "K=4 #constant\n",
+ "\n",
+ "#Calculation\n",
+ "C=(K*eo*A)/d #calculating capacitance\n",
+ "\n",
+ "#Result\n",
+ "print\"Capacitance = \",C,\"Farad\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Capacitance = 1.77e-08 Farad\n"
+ ]
+ }
+ ],
+ "prompt_number": 21
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.22,Page no:140"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Capacity with air between plates\n",
+ "\n",
+ "#Variable declaration \n",
+ "cm=10*10**-6 #capacitance in Farad\n",
+ "K=2 #constant\n",
+ "\n",
+ "#Calculation\n",
+ "co=cm/K #calculating co\n",
+ "\n",
+ "#Result\n",
+ "print\"capacity of capacitor with air between the plates= \",co*10**6,\"muF\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "capacity of capacitor with air between the plates= 5.0 muF\n"
+ ]
+ }
+ ],
+ "prompt_number": 37
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.23,Page no:140"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Capacitance of combination of capacitors\n",
+ "\n",
+ "#Variable declaration \n",
+ "v=100.0 #v in volt\n",
+ "c1=8.0*10**-6 #capacitance in Farad\n",
+ "c2=12.0*10.0**-6 #capacitance in Farad\n",
+ "c3=24.0*10.0**-6 #capacitance in Farad\n",
+ "cs=4.0/(10.0**6) #calculating series capacitance\n",
+ "\n",
+ "#Calculation\n",
+ "cp=(c1+c2+c3) #calculating parallel capacitance\n",
+ "qs=cs*v #calculating charge\n",
+ "\n",
+ "#Result\n",
+ "print\"Equivalent Series capacitance,C= \",cs*10**6,\"muF\"\n",
+ "print\"Equivalent parallel capacitance,Cp= \",cp*10**6,\"muF\" \n",
+ "print\"charge on plate=%.e\"%qs,\"C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Equivalent Series capacitance,C= 4.0 muF\n",
+ "Equivalent parallel capacitance,Cp= 44.0 muF\n",
+ "charge on plate=4e-04 C\n"
+ ]
+ }
+ ],
+ "prompt_number": 48
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.24,Page no:141"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Electrical energy stored by capacitor\n",
+ "\n",
+ "#Variable declaration \n",
+ "C=9*10**-10 #capacitance in farad\n",
+ "V=100.0 #in volt\n",
+ "\n",
+ "#Calculation\n",
+ "U=(1/2.0)*(C*(V**2)) #calculating energy stored\n",
+ "\n",
+ "#Result\n",
+ "print\"Energy stored = \",U,\"J\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy stored = 4.5e-06 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 50
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.25,Page no:141"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate electrical energy stored by the capacitor\n",
+ "\n",
+ "#Variable declaration \n",
+ "eo=8.85*10**-12 #constant\n",
+ "A=90.0*10**-4 #area in m square\n",
+ "d=2.5*10**-3 #distance in m\n",
+ "V=400.0 #in volt\n",
+ "\n",
+ "#Calculation\n",
+ "C=(eo*A)/d #calculating capacitance\n",
+ "W=(1/2.0)*(C*(V**2)) #calculating electrical energy stored\n",
+ "\n",
+ "#Result\n",
+ "print\"Capacitance = \",C,\"Farad\"\n",
+ "print\"Electrical Energy stored in capacitor =%.2e\"%W,\"J\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Capacitance = 3.186e-11 Farad\n",
+ "Electrical Energy stored in capacitor =2.55e-06 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 56
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.26,Page no:142"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Time the capacity after parallel\n",
+ "#Variable declaration \n",
+ "v=100 #v in volt\n",
+ "c1=1*10**-6 #capacitance in Farad\n",
+ "c2=2*10**-6 #capacitance in Farad\n",
+ "c3=3*10**-6 #capacitance in Farad\n",
+ "cs=6/11.0 #calculating series capacitance\n",
+ "\n",
+ "#Calculation\n",
+ "cp=(c1+c2+c3) #calculating parallel capacitance\n",
+ "\n",
+ "#Result\n",
+ "print\"Equivalent Series capacitance = \",cs,\"muF\"\n",
+ "print\"Equivalent parallel capacitance= \",cp*10**6,\"muF\"\n",
+ "print\"Therefore Cp=(11*Cs)\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Equivalent Series capacitance = 0.545454545455 muF\n",
+ "Equivalent parallel capacitance= 6.0 muF\n",
+ "Therefore Cp=(11*Cs)\n"
+ ]
+ }
+ ],
+ "prompt_number": 60
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:4.27,Page no:143"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate work done by battery\n",
+ "#Variable declaration \n",
+ "eo=8.85*10**-12 #constant\n",
+ "V=6 #v in volt\n",
+ "A=25*10**-4 #area in m square\n",
+ "d=10**-3 #distance in m\n",
+ "\n",
+ "#Calculation\n",
+ "q=(eo*A*V)/d #calculating charge\n",
+ "W=q*V #calculating work done\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge through battery =%.3g\"%q,\"C\"\n",
+ "print\"Work done by Battery=%.e\"%W,\"J\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge through battery =1.33e-10 C\n",
+ "Work done by Battery=8e-10 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 63
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb new file mode 100644 index 00000000..53a08905 --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb @@ -0,0 +1,1043 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "UNIT-5 Electricity"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.1,Page no:152"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate current flowing through a conductor\n",
+ "\n",
+ "#Variable declaration \n",
+ "n=10**6 #no. of electrons\n",
+ "e=1.6*10**-19 #charge on an electron in C\n",
+ "\n",
+ "#Calculation\n",
+ "q=n*e #calculating total charge\n",
+ "t=10**-3 #time in second\n",
+ "I=q/t #calculating current\n",
+ "\n",
+ "#Result\n",
+ "print\"Current flowing = \",I,\"Ampere\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current flowing = 1.6e-10 Ampere\n"
+ ]
+ }
+ ],
+ "prompt_number": 71
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.2,Page no:152"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#No of electrons passing through a lamp\n",
+ "\n",
+ "#Variable declaration \n",
+ "I=300*10**-3 #current n Ampere\n",
+ "t=60 #time in second\n",
+ "e=1.6*10**-19 #chatge on electron in C\n",
+ "\n",
+ "#Calculation\n",
+ "q=I*t #calculating charge\n",
+ "n=q/e #calculating no of electrons\n",
+ "\n",
+ "#Result\n",
+ "print\"No. of electrons = \",n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "No. of electrons = 1.125e+20\n"
+ ]
+ }
+ ],
+ "prompt_number": 20
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.3,Page no:154"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Frequency of electrons across a conductor\n",
+ "\n",
+ "#Variable declaration \n",
+ "V=200 #voltage in volt\n",
+ "R=100 #resistance in Ohm\n",
+ "e=1.6*10**-19 #charge on an electron in C\n",
+ "\n",
+ "#Calculation\n",
+ "I=V/R #Ohm's law\n",
+ "t=1 #time in second\n",
+ "q=I*t #calculating charge\n",
+ "n=q/e #calculating no of electrons\n",
+ "\n",
+ "#Result\n",
+ "print\"No. of electrons = \",n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "No. of electrons = 1.25e+19\n"
+ ]
+ }
+ ],
+ "prompt_number": 72
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.4,Page no:156"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Resistivity of small wire\n",
+ "\n",
+ "#Variable declaration \n",
+ "l=15 #length in m\n",
+ "A=6*10**-7 #area in m square\n",
+ "R=5 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "p=(A*R)/l #calculating resistivity\n",
+ "\n",
+ "#Result\n",
+ "print\"Resistivity= \",p,\"Ohm metre\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistivity= 2e-07 Ohm metre\n"
+ ]
+ }
+ ],
+ "prompt_number": 73
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.5,Page no:157"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Resistivity of a normal wire\n",
+ "\n",
+ "#Variable declaration \n",
+ "l=0.1 #length in m\n",
+ "A=10**-4 #area in m square\n",
+ "R=0.01 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "p=(A*R)/l #calculating resistivity\n",
+ "\n",
+ "#Result\n",
+ "print\"Resistivity = \",p,\"Ohm metre\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistivity = 1e-05 Ohm metre\n"
+ ]
+ }
+ ],
+ "prompt_number": 74
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.6,Page no:157"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Resistivity of a long wire\n",
+ "\n",
+ "import math \n",
+ "\n",
+ "#Variable declaration\n",
+ "L=1 #length in m\n",
+ "r=0.2*10**-3 #radius in m\n",
+ "R=2 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "A=math.pi*(r)**2 #calculating area\n",
+ "P=(R*A)/L #calculating resistivity\n",
+ "\n",
+ "#Result\n",
+ "print\"Resistivity =%.2g\"%P,\"Ohm.metre\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistivity =2.5e-07 Ohm.metre\n"
+ ]
+ }
+ ],
+ "prompt_number": 38
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.7,Page no:158"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#New resistance of a wire after drawn out\n",
+ "\n",
+ "#Variable declaration \n",
+ "R1=5 #resisitance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "#A2=A/3\n",
+ "#R2/5=3l*3/A*A/l\n",
+ "#R2=9*5\n",
+ "\n",
+ "R2=9*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n",
+ "print\"Resisitance = \",R2,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resisitance = 45 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 75
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.8,Page no:159"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Change in resistance of a wire\n",
+ "\n",
+ "#Variable declaration \n",
+ "R1=5 #resisitance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "#A2=A/2\n",
+ "#R1=rho*l1/A1*R2\n",
+ "#R2=rho*l2/A2\n",
+ "#R2/R1=A1/l1\n",
+ "R2=4*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n",
+ "\n",
+ "#Result\n",
+ "print\"Resisitance= \",R2,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resisitance= 20 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 70
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.9,Page no:162"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Total resistance in parallel\n",
+ "\n",
+ "#Variable declaration \n",
+ "R1=2 #resisitance in Ohm\n",
+ "R2=4 #resistance in Ohm\n",
+ "R3=5 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "R=(R1**-1)+(R2**-1)+(R3**-1) #calculating parallel resistance\n",
+ "Rp=(1/R) \n",
+ "\n",
+ "#Result\n",
+ "print\"Resisitance = \",Rp,\"Ohm\"\n",
+ "print\"\\nNOTE:Incorrect answer in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resisitance = 1.05263157895 Ohm\n",
+ "\n",
+ "NOTE:Incorrect answer in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 39
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.10,Page no:163"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Series parallel combination resistance\n",
+ "\n",
+ "from scipy.optimize import fsolve \n",
+ "\n",
+ "#Variable declaration\n",
+ "Rs=40 #resisitance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "#R1+R2=40\n",
+ "#R1*R2=256\n",
+ "#R1=256/R2\n",
+ "#Putting this value in eq 1:\n",
+ "#(256/R2)+R2=40\n",
+ "from sympy import solve, symbols, pprint\n",
+ "R2= symbols('R2')\n",
+ "a=1\n",
+ "b=-40\n",
+ "c=256\n",
+ "f = a*R2**2 + b*R2 + c\n",
+ "solution = solve(f, R2)\n",
+ "\n",
+ "#Result\n",
+ "print\"When R2=\",solution[0],\"Ohm R1=\",solution[1],\"Ohm\"\n",
+ "print\"When R2=\",solution[1],\"Ohm R1=\",solution[0],\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "When R2= 8 Ohm R1= 32 Ohm\n",
+ "When R2= 32 Ohm R1= 8 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.11,Page no:164"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find the valueof current in fig\n",
+ "\n",
+ "#Variable declaration \n",
+ "V=2.0 #in volts\n",
+ "R1=30.0 #resisitance in Ohm\n",
+ "R2=60.0 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n",
+ "I=V/Rp #Ohm's law\n",
+ "\n",
+ "#Result\n",
+ "print\"Resisitance = \",Rp,\"Ohm\"\n",
+ "print\"Current = \",I,\"A\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resisitance = 20.0 Ohm\n",
+ "Current = 0.1 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.12,Page no:165"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Combine resistance to get an equivalent resistance\n",
+ "\n",
+ "#Variable declaration \n",
+ "R1=2.0 #resisitance in Ohm\n",
+ "R2=3.0 #resistance in Ohm\n",
+ "R3=1.0 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n",
+ "R=Rp+1.0 #1 Ohm in series\n",
+ "Rs=(R1+R2+R3) #series resistances\n",
+ "Rp=(1.0/R1)+(1.0/R2)+(1.0/R3) #calculating parallel resistance\n",
+ "\n",
+ "#Result\n",
+ "print\"(1)Equivalent Resisitance= \",R,\"Ohm\" \n",
+ "print\"(2)All resistances in series = \",Rs,\"Ohm\"\n",
+ "print\"(3)All in Parallel = \",(1/Rp),\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(1)Equivalent Resisitance= 2.2 Ohm\n",
+ "(2)All resistances in series = 6.0 Ohm\n",
+ "(3)All in Parallel = 0.545454545455 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 76
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.13,Page no:166"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Total resistor of combination\n",
+ "\n",
+ "#Variable declaration \n",
+ "V=20 #voltage in Volts\n",
+ "R1=2.0 #resisitance in Ohm\n",
+ "R2=4.0 #resistance in Ohm\n",
+ "R3=5.0 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Rp=(1/R1)+(1/R2)+(1/R3) #calculating parallel resistance\n",
+ "R=1/Rp #Parallel\n",
+ "I1=V/R1 #calculating current through R1\n",
+ "I2=V/R2 #calculating current through R2\n",
+ "I3=V/R3 #calculating current through R3\n",
+ "I=V/R #calculating total current\n",
+ "\n",
+ "\n",
+ "#Result\n",
+ "print\"(a)Equivalent Resisitance = \",R,\"Ohm\"\n",
+ "print\"Current through R1 = \",I1,\"Ampere\"\n",
+ "print\"Current through R2 = \",I2,\"Ampere\" \n",
+ "print\"Total current = \",I,\"Ampere\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)Equivalent Resisitance = 1.05263157895 Ohm\n",
+ "Current through R1 = 10.0 Ampere\n",
+ "Current through R2 = 5.0 Ampere\n",
+ "Total current = 19.0 Ampere\n"
+ ]
+ }
+ ],
+ "prompt_number": 30
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.14,Page no:166"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate no of resistors form total resistor\n",
+ "\n",
+ "#Variable declaration\n",
+ "R=7 #Total resistanc of combination\n",
+ "\n",
+ "#Calculation\n",
+ "def f(n):\n",
+ " Rp = 6*(1/n) #resistance in parallel\n",
+ " return(R-Rp-5)\n",
+ "n=fsolve(f,1)\n",
+ "\n",
+ "#Result\n",
+ "print\"n=\",n[0]"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "n= 3.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 33
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.15,Page no:173"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Voltage and current in figure\n",
+ "\n",
+ "#Variable declaration \n",
+ "R1=2 #resistance in Ohm\n",
+ "R2=6 #resistance in Ohm\n",
+ "R3=3 #resistance in Ohm\n",
+ "V=24 #voltage in volts\n",
+ "R=8 #resistance in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "I=V/R #Ohm's Law\n",
+ "V1=I*R1 #Ohm's Law\n",
+ "V2=I*R2 #Ohm's Law\n",
+ "V3=I*R3 #Ohm's Law\n",
+ "\n",
+ "#Result\n",
+ "print\"Current = \",I,\"Ampere\" \n",
+ "print\"Voltage drop across R1 = \",V1,\"Volts\"\n",
+ "print\"Voltage drop across R2 = \",V2,\"Volts\" \n",
+ "print\"Voltage drop across R3 = \",V3,\"Volts\"\n",
+ "print\"\\nNOTE:Wrong answer of R3 in book\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current = 3 Ampere\n",
+ "Voltage drop across R1 = 6 Volts\n",
+ "Voltage drop across R2 = 18 Volts\n",
+ "Voltage drop across R3 = 9 Volts\n",
+ "\n",
+ "NOTE:Wrong answer of R3 in book\n"
+ ]
+ }
+ ],
+ "prompt_number": 36
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.16,Page no:173"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Current through branches of circuit\n",
+ "\n",
+ "#Variable declaration \n",
+ "R=15 #resistance in Ohm\n",
+ "print\"KVL: 16I1+15I2=6 (1)\" #KVL equation\n",
+ "I1=-1.66 #from(1)\n",
+ "I2=2.17 #from (1)\n",
+ "#Calculation\n",
+ "V=(I1+I2)*R #calculating potential difference\n",
+ "\n",
+ "#Result\n",
+ "print\"Potential difference= \",V,\"Volt\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "KVL: 16I1+15I2=6 (1)\n",
+ "Potential difference= 7.65 Volt\n"
+ ]
+ }
+ ],
+ "prompt_number": 37
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.17,Page no:174"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine current in wheatstone bridge\n",
+ "\n",
+ "print\"3I1-I2-1=0 (1)\" #KVL equation\n",
+ "print\"3I1-I2+2I=2 (2)\" #KVL equation\n",
+ "print\"3I1-I1+2I=2 (3)\" #KVL equation\n",
+ "\n",
+ "#Variable declaration\n",
+ "I1=4/17.0 #from (1)(2)(3)through AB \n",
+ "I2=-2/17.0 #from (1)(2)(3)through BD\n",
+ "I=3*I1+I2 #from (1)(2)(3)through main circuit\n",
+ "\n",
+ "#Calculation\n",
+ "Ibc=I1-I2 #calculating current in BC\n",
+ "Iad=I-I1 #calculating current in AD\n",
+ "Idc=I-I1+I2 #calculating current in DC\n",
+ "\n",
+ "#Result\n",
+ "print\"Current in branch BC = \",Ibc,\"Ampere\"\n",
+ "print\"NOTE:Calculation mistake in book while calculating for BC\"\n",
+ "print\"Current in branch AD = \",Iad,\"Ampere\"\n",
+ "print\"Current in branch DC = \",Idc,\"Ampere\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "3I1-I2-1=0 (1)\n",
+ "3I1-I2+2I=2 (2)\n",
+ "3I1-I1+2I=2 (3)\n",
+ "Current in branch BC = 0.352941176471 Ampere\n",
+ "NOTE:Calculation mistake in book while calculating for BC\n",
+ "Current in branch AD = 0.352941176471 Ampere\n",
+ "Current in branch DC = 0.235294117647 Ampere\n"
+ ]
+ }
+ ],
+ "prompt_number": 77
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.18,Page no:176"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Current through a galvanometer in wheatstone bridge\n",
+ "\n",
+ "#Variable declaration \n",
+ "P=10 #Ohm\n",
+ "Q=3 #Ohm\n",
+ "R=12 #Ohm\n",
+ "S=6 #Ohm\n",
+ "G=20 #Ohm\n",
+ "\n",
+ "\n",
+ "#Calculation\n",
+ "print\"-12I+22I1+IgG=0 (1)\" #KVL\n",
+ "print\"6I-9I1+29Ig=0 (2)\" #KVL\n",
+ "print\"13I1-3Ig=2 (3)\" #KVL\n",
+ "#From above equations\n",
+ "import numpy as np\n",
+ "a = np.array([[-12,22,20],[6,-9,29],[0,13,-3]]) \n",
+ "b = np.array([[0],[0],[2]])\n",
+ "np.linalg.solve(a,b)\n",
+ "\n",
+ "\n",
+ "#Result\n",
+ "print\"Current through Galvanometer = \",round(Ig*1000,2),\"mA\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "-12I+22I1+IgG=0 (1)\n",
+ "6I-9I1+29Ig=0 (2)\n",
+ "13I1-3Ig=2 (3)\n",
+ "Current through Galvanometer = 7.8 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 78
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.19,Page no:179"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#% drop in heat in bulb\n",
+ "\n",
+ "#Variable declaration \n",
+ "P=500 #power in Watts\n",
+ "V=200 #voltage in Volts\n",
+ "V1=160 #voltage in Volts\n",
+ "\n",
+ "#Calculation\n",
+ "R=(V**2)/P #using P=V**2*R\n",
+ "P1=(V1**2)/R #calculating power\n",
+ "Dp=500-P1 #drop in heat\n",
+ "D=(Dp*100)/500 #percentage drop\n",
+ "\n",
+ "#Result\n",
+ "print\"Resistance= \",R,\"Ohm\"\n",
+ "print\"% Drop in heat production = \",D,\"%\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance= 80 Ohm\n",
+ "% Drop in heat production = 36 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 79
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.20,Page no:180"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Bulbs connected in parallel\n",
+ "\n",
+ "#Variable declaration\n",
+ "P1=100 #power in Watts\n",
+ "P2=500 #power in Watts\n",
+ "\n",
+ "#Calculation\n",
+ "P=P2/P1 #ratio\n",
+ "\n",
+ "#Result\n",
+ "print \"P=\",P\n",
+ "print\"P>0,I2=5I Therefore I2>I1\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "P= 5\n",
+ "P>0,I2=5I Therefore I2>I1\n"
+ ]
+ }
+ ],
+ "prompt_number": 80
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.21,Page no:181"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Heat and light energy produced by bulb on voltage drop\n",
+ "\n",
+ "#Variable declaration \n",
+ "t=1200 #time in second\n",
+ "P=100 #power in Watts\n",
+ "V=230 #voltage in Volts\n",
+ "\n",
+ "#Calculation\n",
+ "R=(V**2)/P #calculating resistance\n",
+ "V1=115 #supply voltage in Volts\n",
+ "E=((V1**2)*t)/R #calculating energy\n",
+ "\n",
+ "#Result\n",
+ "print\"Energy dissipated by bulb = \",E,\"J\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy dissipated by bulb = 30000 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 81
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.22,Page no:181"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate effeciency of transmission\n",
+ "\n",
+ "#Variable declaration\n",
+ "P=10**4 #power in Watts\n",
+ "V=250 #voltage in Volts\n",
+ "R=0.2 #resistance in ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Pl=((P/V)*(P/V))*R #calculating power loss\n",
+ "print P1\n",
+ "E=P/(Pl+P) #calculating efficiency\n",
+ "\n",
+ "#Result\n",
+ "print\"Percent Efficiency = \",round(E*100),\"%\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "100\n",
+ "Percent Efficiency = 97.0 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 56
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.23,Page no:182"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Resistance and current capacity of a lamp\n",
+ "\n",
+ "#Variable declaration \n",
+ "P=100.0 #power in Watts\n",
+ "V=220.0 #voltage in Volts\n",
+ "\n",
+ "#Calculation\n",
+ "I=P/V #Current in Ampere\n",
+ "R=V/I #resistance\n",
+ "\n",
+ "#Result\n",
+ "print\"Current = \",round(I,3),\"A\" \n",
+ "print\"Resistance=\",R,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current = 0.455 A\n",
+ "Resistance= 484.0 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 59
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example no:5.24,Page no:182"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Resistance of windings of electric motor\n",
+ "\n",
+ "#Variable declaration \n",
+ "V=50 #voltage in Volts\n",
+ "I=12 #Current in Ampere\n",
+ "\n",
+ "#Calculation\n",
+ "P=V*I #power\n",
+ "Pd=P*0.7 #power dissipated\n",
+ "R=(Pd/(I)**2) \n",
+ "\n",
+ "#Result\n",
+ "print\"Resistance = \",round(R,2),\"Ohm\" "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance = 2.92 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 82
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/README.txt b/A_Comprehensive_Textbook_Of_Applied_Physics_/README.txt new file mode 100644 index 00000000..121834de --- /dev/null +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/README.txt @@ -0,0 +1,10 @@ +Contributed By: Deepak Shakya +Course: btech +College/Institute/Organization: DCRUST +Department/Designation: Chemical Engg +Book Title: A Comprehensive Textbook Of Applied Physics +Author: M. Kumar +Publisher: Abhishek Publications,Chandigarh +Year of publication: 2009 +Isbn: 978-81-8247-226-6 +Edition: 1
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