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authorkinitrupti2017-05-12 18:40:35 +0530
committerkinitrupti2017-05-12 18:40:35 +0530
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-{
- "metadata": {
- "name": "",
- "signature": "sha256:3c3856bc217e5f495e078375001a6745906e09c45dfca2c5d1fe105500ef94b8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 16 : Machinery and Equipment"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.2 Page No : 16-11"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\t\n",
- "#initialisation of variables\n",
- "p = 500\t#ft\n",
- "p1 = 6\t#in\n",
- "t = 500\t#cfm\n",
- "p2 = 7\t#psig\n",
- "P = p2+14.7\t#psia\n",
- "T = 520*(P/14.7)**0.283\t#F\n",
- "f = 0.048*p1**0.027/(t)**0.148\t#in\n",
- "\t\n",
- "#CALCULATIONS\n",
- "delP = 20.*10**-3*p*T*(t)**2/(38*10**3*P*p1**5)\t#psia\n",
- "\t\n",
- "#RESULTS\n",
- "print 'the pressure drop = %.2f psia'%(delP)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the pressure drop = 0.23 psia\n"
- ]
- }
- ],
- "prompt_number": 1
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file