Added(A)/Deleted(D) following books

A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/README.txt A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch2_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch3_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch4_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch5_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch6_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch7_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch8_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/ch9_1.ipynb A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/screenshots/ch2_1.png A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/screenshots/ch7_1.png A A_Course_In_Mechanical_Measurements_And_Instrumentation_by_A._K._Sawhney_And_P._Sawhney/screenshots/kVSv5.png A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/CHAPTER2_1.ipynb A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/CHAPTER4_2.ipynb A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/CHAPTER5_2.ipynb A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/CHAPTER6_2.ipynb A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/CHAPTER7_2.ipynb A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/README.txt A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/screenshots/CHAP2.png A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/screenshots/CHAP4.png A A_First_Course_on_Electrical_Drives_by_S._K._Pillai/screenshots/CHAP5.png D A_First_course_in_Programming_with_C/Chapter14.ipynb M A_First_course_in_Programming_with_C_by_T_Jeyapoovan/Chapter14_2.ipynb A A_First_course_in_Programming_with_C_by_T_Jeyapoovan/README.txt A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1.2.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1.3.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1.7.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1_2.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1_3.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT1_7.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.10.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.11.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.13.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.14.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.15.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.16.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.17.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.18.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.2.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.3.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.4.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.5.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.6.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.7.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.8.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2.9.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2_10.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2_11.ipynb A A_Textbook_on_Power_System_Engineering_by_A_Chakrabarti,_M_L_Soni,_P_V_Gupta,_U_S_Bhatnagar/CHAPT2_13.ipynb A 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Internal_Combustion_Engines_by_H._B._Keswani/screenshots/ch9.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter10_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter10_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter10_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter10_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter11_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter11_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter11_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter11_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter12_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter12_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter12_3.ipynb A 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Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter3_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter3_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter3_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter3_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter4_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter4_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter4_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter4_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter5_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter5_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter5_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter5_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter6_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter6_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter6_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter6_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter7_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter7_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter7_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter7_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter8_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter8_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter8_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter8_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter9_1.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter9_2.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter9_3.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/Chapter9_4.ipynb A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/README.txt A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter10_1.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter10_2.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter10_3.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter10_4.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter3_1.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter3_2.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter3_3.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter3_4.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter4_1.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter4_2.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter4_3.png A Introduction_To_Fluid_Mechanics_by_R._W._Fox_And_A._T._McDonald/screenshots/chapter4_4.png A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter1.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter2(PartB).ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter2.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter3(partB).ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter3.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter4(PartB).ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter4.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter5.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter6.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/Chapter7.ipynb A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/screenshots/chapter1.png A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/screenshots/chapter2.png A Introduction_To_Mechanical_Engineering_by_S._Chandra_And_O._Singh/screenshots/chapter3.png A Introduction_to_Electric_Drives_by_J._S._Katre/AppendixB.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/AppendixB_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter10.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter10_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter10_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter1_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter1_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter2_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter2_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter3.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter3_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter3_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter5.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter5_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter5_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter6.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter6_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter6_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter8.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter8_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter8_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter9.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter9_1.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/chapter9_2.ipynb A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_VLdc_VLrms.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_VLdc_VLrms_1.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_VLdc_VLrms_2.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_variation_of_RF_FF.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_variation_of_RF_FF_1.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch6_variation_of_RF_FF_2.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch_3_variation_avg_rms_load_V.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch_3_variation_avg_rms_load_V_1.png A Introduction_to_Electric_Drives_by_J._S._Katre/screenshots/ch_3_variation_avg_rms_load_V_2.png A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/Chapter9.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter1.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter2.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter3.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter4.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter6.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter7.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter8.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter_5.ipynb A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex1.2.png A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex3.13.png A Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex6.7.png A Linear_Integrated_Circuits_by_J._B._Gupta/README.txt A Linear_Integrated_Circuits_by_J._B._Gupta/chapter01_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter01_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter02_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter02_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter03_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter03_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter04_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter04_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter05_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter05_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter06_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter06_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter07_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter07_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter08_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter08_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter09_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter09_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter10_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter10_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter11_1.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/chapter11_2.ipynb A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/5_14.png A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/5_14_1.png A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/5_15.png A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/5_15_1.png A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/per_error_1.png A Linear_Integrated_Circuits_by_J._B._Gupta/screenshots/per_error_2.png A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER10.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER13.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER14.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER15.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER16.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER18.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER19.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER2.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER21.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER23.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER24_.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER26.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER30.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER31.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER33.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER36.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/CHAPTER9.ipynb A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/screenshots/CHAP10.png A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/screenshots/CHAP16.png A Manufacturing_Engineering_&_Technology_by__S._Kalpakjian_and_S._R._Schmid/screenshots/CHAP19.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch2.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch2_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch3.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch3_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch4.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch4_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch5.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch5_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch6.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch6_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch7.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/ch7_1.ipynb A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/FricCoeff.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/FricCoeff_1.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/fillingtime.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/fillingtime_1.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/millPOwer.png A Manufacturing_Science_by_A._Ghosh_And_A._K._Mallik/screenshots/millPOwer_1.png A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter10.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter11.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter12.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter13.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter14.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter15.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter16.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter17.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter2.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter3.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter4.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter5.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter6.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter7.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter8.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/Chapter9.ipynb A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/screenshots/Chapter10.png A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/screenshots/Chapter11.png A Materials_Science_and_Engineering_-_A_First_Course_by_V._Raghavan/screenshots/Chapter12.png A Materials_Science_by_Dr._M._Arumugam/Chapter10_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter12_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter1_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter2_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter3_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter4_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter5_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter6_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter7_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter8_1.ipynb A Materials_Science_by_Dr._M._Arumugam/Chapter9_1.ipynb A Materials_Science_by_Dr._M._Arumugam/README.txt A Materials_Science_by_Dr._M._Arumugam/screenshots/11.png A Materials_Science_by_Dr._M._Arumugam/screenshots/22.png A Materials_Science_by_Dr._M._Arumugam/screenshots/33.png A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_2_Generalized_Configurations_and_Functional_Descriptions_of_Measuring_Instruments.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_3_Generalized_Performance_Characteristics_of_Instruments.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_4_Relative_Velocity_Translational_and_Rotational.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_5_Force_Torque_and_Shaft_power_Measurement.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_6_Pressure_and_Sound_Measurement.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_7_Flow_Measurement.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/Chapter_8_Temperature_and_Heat-Flux_Measurement.ipynb A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/screenshots/cha3.png A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/screenshots/cha4.png A Measurement_Systems_by_E._O._Doebelin_And_D._N._Manik/screenshots/cha5.png A Mechanical_Metallurgy_by_George_E._Dieter/README.txt A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/AppendixA.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/AppendixA_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/AppendixA_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/AppendixA_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_10.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_11.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_12.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_13.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_14.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_4.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_5.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_6.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_7.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_8.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter01_9.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter02.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter02_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter02_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter02_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter03.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter03_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter03_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter03_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter04.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter04_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter04_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter04_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter05.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter05_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter05_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter05_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter06.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter06_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter06_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter06_3.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter07.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter07_1.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter07_2.ipynb A Mechanics_of_Materials_by_Pytel_and_Kiusalaas/Chapter07_3.ipynb A 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Special_Electrical_Machines_by_S.P._Burman/chapter03.ipynb A Special_Electrical_Machines_by_S.P._Burman/chapter04.ipynb A Special_Electrical_Machines_by_S.P._Burman/screenshots/ResolShaftSpeed3.png A Special_Electrical_Machines_by_S.P._Burman/screenshots/TorqLossEff1.png A Special_Electrical_Machines_by_S.P._Burman/screenshots/Torq_Speed1.png A Strength_Of_Materials_by_B_K_Sarkar/Chapter01.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter02.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter03.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter04.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter05.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter06.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter07.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter08.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter09.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter10.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter11.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter12.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter13.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter14.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter15.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter16.ipynb A Strength_Of_Materials_by_B_K_Sarkar/Chapter17.ipynb A Strength_Of_Materials_by_B_K_Sarkar/README.txt A Strength_Of_Materials_by_B_K_Sarkar/chapter_10_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_10_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_11_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_11_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_12_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_12_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_13_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_13_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_14_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_14_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_15_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_15_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_16_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_16_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_17_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_17_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_1_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_1_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_2_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_2_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_3_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_3_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_4_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_4_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_5_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_5_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_6_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_6_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_7_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_7_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_8_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_8_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_9_som.ipynb A Strength_Of_Materials_by_B_K_Sarkar/chapter_9_som_1.ipynb A Strength_Of_Materials_by_B_K_Sarkar/screenshots/B.M.D_1.JPG A Strength_Of_Materials_by_B_K_Sarkar/screenshots/B.M.D_2.JPG A Strength_Of_Materials_by_B_K_Sarkar/screenshots/BMD2.png A Strength_Of_Materials_by_B_K_Sarkar/screenshots/S.F.D_1.jpg A Strength_Of_Materials_by_B_K_Sarkar/screenshots/S.F.D_1_1.jpg A Strength_Of_Materials_by_B_K_Sarkar/screenshots/S.F.D_2.jpg A Strength_Of_Materials_by_B_K_Sarkar/screenshots/S.F.D_4.jpg A Strength_Of_Materials_by_B_K_Sarkar/screenshots/SFD.png A Strength_Of_Materials_by_B_K_Sarkar/screenshots/SFD3.png M The_C_Book/Chapter2.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/README.txt R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch10.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch10.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch10_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch2.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch2.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch2_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch3.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch3.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch3_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch4.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch4.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch4_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch5.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch5.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch5_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch6.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch6.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch6_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch7.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch7.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch7_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch8.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch8.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch8_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch9.ipynb -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch9.ipynb A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/ch9_1.ipynb R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same3_7.png -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same3_7.png A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same3_7_1.png R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same7.png -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same7.png A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/same7_1.png R _Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/shearAndBendingMoment7.png -> Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/shearAndBendingMoment7.png A Vector_Mechanics_for_Engineers:_Stastics_And_Dynamics_by_F._P._Beer,_E._R._Johnston,_D._F._Mazurek,_P._J._Cornwell_And_E._R._Eisenberg/screenshots/shearAndBendingMoment7_1.png A Wireless_Communications_and_Networking_by_V._Garg/README.txt A Wireless_Communications_and_Networking_by_V._Garg/ch10_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch11_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch12_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch13_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch14_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch17_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch19_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch21_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch2_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch3_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch4_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch5_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch6_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch8_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/ch9_1.ipynb A Wireless_Communications_and_Networking_by_V._Garg/screenshots/EbbyNo_1.png A Wireless_Communications_and_Networking_by_V._Garg/screenshots/comparision_of_models_1.png A Wireless_Communications_and_Networking_by_V._Garg/screenshots/multiplexing_1.png A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/README.txt A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch10_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch11_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch12_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch1_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch2_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch3_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch4_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch5_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch6_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch7_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch8_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/ch9_1.ipynb A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/screenshots/energy_stored3_1.png A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/screenshots/magnetic_flux12_1.png A _Electric_Machinery_And_Transformers_by_B._S._Guru_And_H._R._Hiziroglu/screenshots/pitch_factor7_1.png A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_10_Solid_Solutions_and_Phase_Equilibrium_2.ipynb A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_10_Solid_Solutions_and_Phase_Equilibrium_3.ipynb A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_11_Dispertion_Strengthening_and_Eutectic_Phase_Diagrams_2.ipynb A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_11_Dispertion_Strengthening_and_Eutectic_Phase_Diagrams_3.ipynb A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_12_Dispersion_Strengthening__by_Phase_Transmission_and_Heat_Treatment_2.ipynb A _Essentials_of_Materials_Science_and_Engineering_by__D._R._Askeland_and_P._P._Phule/Chapter_12_Dispersion_Strengthening__by_Phase_Transmission_and_Heat_Treatment_3.ipynb A 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author: FOSSEE SysAds 2015-12-08 15:04:13 +0600
committer: FOSSEE SysAds 2015-12-08 15:04:13 +0600
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diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap10.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap10.ipynb
new file mode 100755
index 00000000..b41e5bfd
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap10.ipynb
@@ -0,0 +1,138 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:09b7d26869b043c328670d7c0075696a10aa47c91999b0d80eca2e92e801eeab"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 10 Measuring instruments"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.1 Page no 289"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=600                                         #pf\n",
+      "C2=100                                         #pf\n",
+      "f1=2                                           #MHz\n",
+      "f2=4                                           #MHz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Cs=(C1-4*C2)/3.0\n",
+      "L=1/(4*(math.pi)**2*f1**2*(C1+Cs))\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of distributed capacitance is \",round(Cs,2),\"pf\",\"and inductance is \",round(L*10**6,3),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of distributed capacitance is  66.67 pf and inductance is  9.499 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.2 Page no 290"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=500                             #pf\n",
+      "C2=110                               #pf2\n",
+      "f1=1                                 #MHz\n",
+      "f2=2                                   #MHz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Cs=(C1-4*C2)/3.0\n",
+      "L=1/(4*(math.pi)**2*f1**2*(C1+Cs))\n",
+      "\n",
+      "#Result\n",
+      "print\"The distributed capacitance is \",Cs ,\"pf\",\"and Value of L is \",round(L*10**6,3),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The distributed capacitance is  20.0 pf and Value of L is  48.712 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 33
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.3 Page no 290"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "f1=2                                  #MHz\n",
+      "C1=500                                   #pf\n",
+      "f2=6                                  #MHz\n",
+      "C2=50                                  #pf\n",
+      "\n",
+      "#Calculation \n",
+      "Cs=(C1-9*C2)/8.0\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of self capacitance is \", Cs,\"pf\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of self capacitance is  6.25 pf\n"
+       ]
+      }
+     ],
+     "prompt_number": 36
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap10_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap10_1.ipynb
new file mode 100755
index 00000000..a5622574
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap10_1.ipynb
@@ -0,0 +1,138 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7d03652ecc470b7ccb201edf24672d9dd74a5f784da6cca21dd0403d0615224a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 10 Measuring Instruments"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.1 Page no 289"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=600                                         #pf\n",
+      "C2=100                                         #pf\n",
+      "f1=2                                           #MHz\n",
+      "f2=4                                           #MHz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Cs=(C1-4*C2)/3.0\n",
+      "L=1/(4*(math.pi)**2*f1**2*(C1+Cs))\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of distributed capacitance is \",round(Cs,2),\"pf\",\"and inductance is \",round(L*10**6,3),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of distributed capacitance is  66.67 pf and inductance is  9.499 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.2 Page no 290"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=500                             #pf\n",
+      "C2=110                               #pf2\n",
+      "f1=1                                 #MHz\n",
+      "f2=2                                   #MHz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Cs=(C1-4*C2)/3.0\n",
+      "L=1/(4*(math.pi)**2*f1**2*(C1+Cs))\n",
+      "\n",
+      "#Result\n",
+      "print\"The distributed capacitance is \",Cs ,\"pf\",\"and Value of L is \",round(L*10**6,3),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The distributed capacitance is  20.0 pf and Value of L is  48.712 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 33
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.3 Page no 290"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "f1=2                                  #MHz\n",
+      "C1=500                                   #pf\n",
+      "f2=6                                  #MHz\n",
+      "C2=50                                  #pf\n",
+      "\n",
+      "#Calculation \n",
+      "Cs=(C1-9*C2)/8.0\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of self capacitance is \", Cs,\"pf\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of self capacitance is  6.25 pf\n"
+       ]
+      }
+     ],
+     "prompt_number": 36
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap11.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap11.ipynb
new file mode 100755
index 00000000..39ebbba6
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap11.ipynb
@@ -0,0 +1,1005 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:3733f4bc277677bc2f9c52d22638fa67f4c2b3f988678afdd8082febee12d607"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 11 Bridges"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.1 Page no 323"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=15*10**3                      #ohm\n",
+      "R3=40*10**3                      #ohm\n",
+      "R1=10.0*10**3                      #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "\n",
+      "#Result \n",
+      "print\"Value of unknown resistance is \",Rx*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of unknown resistance is  60.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.2 Page no 325"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "E=6                             #Volts\n",
+      "R1=1.0*10**3                      #ohm\n",
+      "R2=2.5*10**3                    #ohm\n",
+      "R3=3.5*10**3                    #ohm\n",
+      "R4=10*10**3                     #ohm\n",
+      "Rg=300.0                          #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Eth=E*((R4/(R2+R4))-(R3/(R1+R3)))\n",
+      "Rth=((R1*R3)/(R1+R3))+((R2*R4)/(R2+R4))\n",
+      "Ig=Eth/(Rth+Rg)\n",
+      "\n",
+      "#Result\n",
+      "print\"Current through galvanometer is \", round(Ig*10**6,0),\"micro A\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Current through galvanometer is  43.0 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.3 Page no 327"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "E=10                              #Volts\n",
+      "r=35\n",
+      "R=700                             #ohm\n",
+      "Rth=700                            #ohm\n",
+      "Rg=125                              #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Eth=E*r/(4.0*R)\n",
+      "Ig=Eth/(Rth+Rg)\n",
+      "print\"current through the galvanometer is \", round(Ig*10**6,1),\"micro A\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "current through the galvanometer is  151.5 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.4 Page no 331"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=5                                   #ohm\n",
+      "Rb=1                                   #ohm\n",
+      "Ra=1000.0                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R2=R1/0.5\n",
+      "Rx=(Rb*R2)/Ra\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of Rx is \",Rx,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of Rx is  0.01 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 33
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.5 Page no 333"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=5.0*10**3                                 #ohm\n",
+      "R2=5.0*10**3                                  #ohm\n",
+      "R3=5.0*10**3                                  #ohm\n",
+      "E=6                                         #Volts\n",
+      "RV=4.5*10**3                                #ohm\n",
+      "r=500\n",
+      "\n",
+      "#Calculation\n",
+      "Rv=(R2*R3)/R1\n",
+      "es=E*((R3/(R1+R3))-(RV/(R2+RV)))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The bridge is balanced when the temperature is 80 degree.\"\n",
+      "print\"The amplitude of the error signal at 60 degree \", round(es,3),\"V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The bridge is balanced when the temperature is 80 degree.\n",
+        "The amplitude of the error signal at 60 degree  0.158 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.6 (a) Page no 337"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=10*10**3                                   #ohm\n",
+      "R2=50*10**3                                    #ohm\n",
+      "R3=100*10**3                                     #ohm\n",
+      "C3=100*10**-6                              #farad\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Cx=(R1*C3)/R2\n",
+      "\n",
+      "#Result\n",
+      "print\"The unknown capacitance is \", Cx*10**6,\"micro F\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The unknown capacitance is  20.0 micro F\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.6 (b) Page no 338"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=2000.0                        #ohm\n",
+      "R2=2850.0                        #ohm\n",
+      "R4=52                          #ohm\n",
+      "C4=0.4*10**-6                   #Farad\n",
+      "f=400                           #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=(R1*R4)/R2\n",
+      "Cx=(R2*C4)/R1\n",
+      "A=2*math.pi*f*Cx*Rx\n",
+      "\n",
+      "#Result\n",
+      "print\"Loss angle of capacitor is \", round(A,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Loss angle of capacitor is  0.052\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.7 Page no 339"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "L3=10*10**-3                      #H\n",
+      "R1=10.0*10**3                        #ohm\n",
+      "R2=40*10**3                        #ohm\n",
+      "R3=100*10**3                        #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Lx=(R2*L3)/R1\n",
+      "\n",
+      "#Result\n",
+      "print\"Equivalent unknown resistance is \", Lx*10**3,\"mH\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Equivalent unknown resistance is  40.0 mH\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.8 (a) Page no 341"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.01*10**-6                               #Farad\n",
+      "R1=470.0*10**3                                 #ohm\n",
+      "R2=5.1*10**3                                 #ohm\n",
+      "R3=100*10**3                                 #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Lx=R2*R3*C1\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of unknown impedence \", Lx,\"H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of unknown impedence  5.1 H\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.8 (b) Page no 341"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=32.7                           #ohm\n",
+      "L1=50*10**-3                       #H\n",
+      "R2=1.36                            #ohm\n",
+      "R3=100.0                             #ohm\n",
+      "R4=100                             #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "r=((R4*R1)/R3)-R2\n",
+      "L2=L1*(R4/R3)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistance of the coil is \",r,\"ohm \\nInductance of the coil is \" ,L2*10**3,\"mH\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistance of the coil is  31.34 ohm \n",
+        "Inductance of the coil is  50.0 mH\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (a) Page no 343"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "w=3000                              #rad/s\n",
+      "R2=10*10**3                         #ohm\n",
+      "R1=2*10**3                          #ohm\n",
+      "C1=1*10**-6                         #farad\n",
+      "R3=1*10**3                          #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(w**2*R1*R2*R3*C1**2)/(1+w**2*R1**2*C1**2)\n",
+      "Lx=(R2*R3*C1)/(1+w**2*R1**2*C1**2)\n",
+      "\n",
+      "#Result\n",
+      "print\" series equivalent impedence is \", round(Lx*10**3,0),\"mH\",\"\\n Series equivqlent resistance is \",round(Rx*10**-3,2),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " series equivalent impedence is  270.0 mH \n",
+        " Series equivqlent resistance is  4.86 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 27
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (b) Page no 343"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=1000                          #ohm\n",
+      "R3=16500                         #ohm\n",
+      "R4=800                           #ohm\n",
+      "C4=2*10**-6                      #F\n",
+      "f=50                             #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "w=2*math.pi*f\n",
+      "Lx=(R2*R3*C4)/(1+(w**2*C4**2*R4**2))\n",
+      "Rx=(w**2*C4**2*R4*R2*R3)/(1+w**2*C4**2*R4**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistance of the coil is \", round(Rx*10**-3,1),\"Kohm\"\n",
+      "print\"Inductance of the coil is \",round(Lx,1),\"H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistance of the coil is  4.2 Kohm\n",
+        "Inductance of the coil is  26.3 H\n"
+       ]
+      }
+     ],
+     "prompt_number": 35
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (c) Page no 345"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C4=1*10**-6                        #F\n",
+      "R2=1000                            #ohm\n",
+      "w=314                              #rad/s\n",
+      "R3=1000\n",
+      "R4=1000\n",
+      "\n",
+      "#Calculation\n",
+      "L1=(R3*R4*C4)/(1+(w**2*C4**2*R4**2))\n",
+      "Rx=(w**2*C4**2*R4*R2*R3)/(1+w**2*C4**2*R4**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"unknown resistance is\" ,round(L1,2),\"H\"\n",
+      "print\"unknown inductance is\", round(Rx,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "unknown resistance is 0.91 H\n",
+        "unknown inductance is 89.75 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (a) Page no 346 "
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.5*10**-6                          #farad\n",
+      "C3=0.5*10**-6                          #farad\n",
+      "R2=2*10**3                             #ohm\n",
+      "R1=1*10**3                              #ohm\n",
+      "f=1000                                  #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=(C1*R2)/C3\n",
+      "Cx=(R1*C3)/R2\n",
+      "D=2*math.pi*f*Cx*Rx\n",
+      "\n",
+      "#Result\n",
+      "print\" The unknown capacitance is \",Cx*10**6,\"micro farad\", \"\\n Dissipation factor is \",round(D,4)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " The unknown capacitance is  0.25 micro farad \n",
+        " Dissipation factor is  3.1416\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (b) Page no 347"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R3=100.0                                   #ohm\n",
+      "R4=300                                     #ohm\n",
+      "C4=0.5*10**-6                              #F\n",
+      "C2=100.0                                   #pf\n",
+      "f=50                                       #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "R1=(C4/C2)*R3\n",
+      "Pf=W*R4*C4\n",
+      "\n",
+      "#Result\n",
+      "print\"Capacitance is \", C1,\"pF\"\n",
+      "print\"Equivalent series resistance is \",R1*10**6,\"Mohm\"\n",
+      "print\"PF of insulation is \",round(Pf,4)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Capacitance is  300.0 pF\n",
+        "Equivalent series resistance is  0.5 Mohm\n",
+        "PF of insulation is  0.0471\n"
+       ]
+      }
+     ],
+     "prompt_number": 19
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (c) Page no 348"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R4=100                          #ohm\n",
+      "C4=0.1                   #micro F\n",
+      "C2=500                    #pf\n",
+      "R3=300.0                     #ohm\n",
+      "f=50                         #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4*10**-5\n",
+      "\n",
+      "#Result\n",
+      "print\"The Capacitance is \",round(C1,1),\"pF\" \n",
+      "print\"Dielectric loss of angle is \",round(A*180/3.14,1),\"degree\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The Capacitance is  166.7 pF\n",
+        "Dielectric loss of angle is  1.8 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 40
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (d) Page no 348"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "d=4.5*10**-3\n",
+      "f=50                    #Hz\n",
+      "C2=105*10**-12\n",
+      "C4=0.5*10**-6               #F\n",
+      "R3=260.0                   #ohm\n",
+      "R4=1000/3.14\n",
+      "K0=8.854*10**-12\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4\n",
+      "a=math.pi*(6*10**-2)**2\n",
+      "K=(C1*d)/(K0*a)\n",
+      "\n",
+      "#Result\n",
+      "print\"The capacitance is \",round(C1*10**12,1),\"pF\"\n",
+      "print\"Value of PF is \",round(A,3)\n",
+      "print\"Relative permittivity is \",round(K,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The capacitance is  128.6 pF\n",
+        "Value of PF is  0.05\n",
+        "Relative permittivity is  5.78\n"
+       ]
+      }
+     ],
+     "prompt_number": 63
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (e) Page no 349"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R3=100               #ohm\n",
+      "R4=300               #ohm\n",
+      "C2=100.0                #pF\n",
+      "C4=0.5                #micro F\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "C1=(R4/R3)*C2\n",
+      "r1=R3*(C4/C2)\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4*10**-6\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of capacitor is \",C1,\"pF\"\n",
+      "print\"PF of the capacitor is \",round(A,4)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of capacitor is  300.0 pF\n",
+        "PF of the capacitor is  0.0471\n"
+       ]
+      }
+     ],
+     "prompt_number": 71
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (f) Page no 350"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=300                    #ohm\n",
+      "R2=100.0                    #ohm\n",
+      "C1=0.6*10**-6                   # F\n",
+      "C3=100.0*10**-12                   #F\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=R2*(C1/C3)\n",
+      "C=(R1/R2)*C3\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of series resistance is \", Rx*10**-5,\"Mohm\"\n",
+      "print\"The value of capacitance is \",C*10**12,\"pF\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of series resistance is  6.0 Mohm\n",
+        "The value of capacitance is  300.0 pF\n"
+       ]
+      }
+     ],
+     "prompt_number": 80
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (g) Page no 350"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.1*10**-6                    #F\n",
+      "C2=0.25*10**-6                    #F\n",
+      "R2=5000.0                           #ohm\n",
+      "C3=0.25*10**-6                    #F\n",
+      "f=2000                           #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=R2*(C1/C2)\n",
+      "C=(R1/R2)*C3\n",
+      "W=2*math.pi*f\n",
+      "A=W*C*Rx*10**-6\n",
+      "#Result\n",
+      "print\"The value of capacitance is \", round(C*10**7,1),\"micro F\"\n",
+      "print\"Dissipation factor is \", round(A*10**7,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of capacitance is  0.1 micro F\n",
+        "Dissipation factor is  3.77\n"
+       ]
+      }
+     ],
+     "prompt_number": 102
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.11 Page no 352"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=4.7*10**3                                     #ohm\n",
+      "R2=20*10**3                                      #ohm\n",
+      "R3=10*10**3                                      #ohm\n",
+      "R4=100*10**3                                     #ohm\n",
+      "C1=5*10**-9                                      #farad\n",
+      "C3=10*10**-9                                     #farad\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "f=1/(2.0*math.pi*(math.sqrt(C1*R1*R3*C3)))\n",
+      "print\"Frequency of the circuit is \", round(f*10**-3,3),\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Frequency of the circuit is  3.283 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.12 Page no 353"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=3.1*10**3                                       #ohm\n",
+      "C1=5.2*10**-6                                      #farad\n",
+      "R2=25.0*10**3                                        #ohm\n",
+      "f=2.5*10**3                                        #ohm\n",
+      "R4=100.0*10**3                                       #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "w=2*math.pi*f\n",
+      "R3=R4/R2*(R1+(1/w**2*R1*C1**2))\n",
+      "C3=R2/R4*(C1/(1+w**2*R1**2*C1**2))\n",
+      "\n",
+      "#CResult\n",
+      "print\" Equivalent parallel resistance is \",R3*10**-3,\"Kohm \",\"\\n Equivalent parallel capaciatnce is \", round(C3*10**12,1),\"pf\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Equivalent parallel resistance is  12.4 Kohm  \n",
+        " Equivalent parallel capaciatnce is  20.3 pf\n"
+       ]
+      }
+     ],
+     "prompt_number": 20
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.13 Page no 353"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.5*10**-6                           #farad\n",
+      "R1=800.0                                  #ohm\n",
+      "C2=1.0*10**-6                            #farad\n",
+      "R2=400                                   #ohm\n",
+      "R4=1000                                  #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "f=1/(2.0*math.pi*math.sqrt(R1*C1*R2*C2))\n",
+      "R3=R4/((R2/R1)+(C1/C2))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of frequency for which the bridge is balanced \", round(f*10**-3,3),\"KHz\"\n",
+      "print\"(ii) The value of R required to produce balance \",R3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of frequency for which the bridge is balanced  0.398 KHz\n",
+        "(ii) The value of R required to produce balance  1000.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.14 Page no 359"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=200                                 #ohm\n",
+      "R3=1000                                  #ohm\n",
+      "R4=1000.0\n",
+      "C=10*10**-6                              #Farad\n",
+      "r=496\n",
+      "\n",
+      "#Calculation\n",
+      "R1=(R2*R3)/R4\n",
+      "L1=(C*R3/R4)*(r*R4+R2*R4+r*R2)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of inductance is \", L1,\"H\"\n",
+      "print\"The value of resistance is \",R1,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of inductance is  7.952 H\n",
+        "The value of resistance is  200.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 108
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap11_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap11_1.ipynb
new file mode 100755
index 00000000..39ebbba6
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap11_1.ipynb
@@ -0,0 +1,1005 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:3733f4bc277677bc2f9c52d22638fa67f4c2b3f988678afdd8082febee12d607"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 11 Bridges"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.1 Page no 323"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=15*10**3                      #ohm\n",
+      "R3=40*10**3                      #ohm\n",
+      "R1=10.0*10**3                      #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "\n",
+      "#Result \n",
+      "print\"Value of unknown resistance is \",Rx*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of unknown resistance is  60.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.2 Page no 325"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "E=6                             #Volts\n",
+      "R1=1.0*10**3                      #ohm\n",
+      "R2=2.5*10**3                    #ohm\n",
+      "R3=3.5*10**3                    #ohm\n",
+      "R4=10*10**3                     #ohm\n",
+      "Rg=300.0                          #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Eth=E*((R4/(R2+R4))-(R3/(R1+R3)))\n",
+      "Rth=((R1*R3)/(R1+R3))+((R2*R4)/(R2+R4))\n",
+      "Ig=Eth/(Rth+Rg)\n",
+      "\n",
+      "#Result\n",
+      "print\"Current through galvanometer is \", round(Ig*10**6,0),\"micro A\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Current through galvanometer is  43.0 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.3 Page no 327"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "E=10                              #Volts\n",
+      "r=35\n",
+      "R=700                             #ohm\n",
+      "Rth=700                            #ohm\n",
+      "Rg=125                              #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Eth=E*r/(4.0*R)\n",
+      "Ig=Eth/(Rth+Rg)\n",
+      "print\"current through the galvanometer is \", round(Ig*10**6,1),\"micro A\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "current through the galvanometer is  151.5 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.4 Page no 331"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=5                                   #ohm\n",
+      "Rb=1                                   #ohm\n",
+      "Ra=1000.0                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R2=R1/0.5\n",
+      "Rx=(Rb*R2)/Ra\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of Rx is \",Rx,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of Rx is  0.01 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 33
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.5 Page no 333"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=5.0*10**3                                 #ohm\n",
+      "R2=5.0*10**3                                  #ohm\n",
+      "R3=5.0*10**3                                  #ohm\n",
+      "E=6                                         #Volts\n",
+      "RV=4.5*10**3                                #ohm\n",
+      "r=500\n",
+      "\n",
+      "#Calculation\n",
+      "Rv=(R2*R3)/R1\n",
+      "es=E*((R3/(R1+R3))-(RV/(R2+RV)))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The bridge is balanced when the temperature is 80 degree.\"\n",
+      "print\"The amplitude of the error signal at 60 degree \", round(es,3),\"V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The bridge is balanced when the temperature is 80 degree.\n",
+        "The amplitude of the error signal at 60 degree  0.158 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.6 (a) Page no 337"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=10*10**3                                   #ohm\n",
+      "R2=50*10**3                                    #ohm\n",
+      "R3=100*10**3                                     #ohm\n",
+      "C3=100*10**-6                              #farad\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Cx=(R1*C3)/R2\n",
+      "\n",
+      "#Result\n",
+      "print\"The unknown capacitance is \", Cx*10**6,\"micro F\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The unknown capacitance is  20.0 micro F\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.6 (b) Page no 338"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=2000.0                        #ohm\n",
+      "R2=2850.0                        #ohm\n",
+      "R4=52                          #ohm\n",
+      "C4=0.4*10**-6                   #Farad\n",
+      "f=400                           #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=(R1*R4)/R2\n",
+      "Cx=(R2*C4)/R1\n",
+      "A=2*math.pi*f*Cx*Rx\n",
+      "\n",
+      "#Result\n",
+      "print\"Loss angle of capacitor is \", round(A,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Loss angle of capacitor is  0.052\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.7 Page no 339"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "L3=10*10**-3                      #H\n",
+      "R1=10.0*10**3                        #ohm\n",
+      "R2=40*10**3                        #ohm\n",
+      "R3=100*10**3                        #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Lx=(R2*L3)/R1\n",
+      "\n",
+      "#Result\n",
+      "print\"Equivalent unknown resistance is \", Lx*10**3,\"mH\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Equivalent unknown resistance is  40.0 mH\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.8 (a) Page no 341"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.01*10**-6                               #Farad\n",
+      "R1=470.0*10**3                                 #ohm\n",
+      "R2=5.1*10**3                                 #ohm\n",
+      "R3=100*10**3                                 #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(R2*R3)/R1\n",
+      "Lx=R2*R3*C1\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of unknown impedence \", Lx,\"H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of unknown impedence  5.1 H\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.8 (b) Page no 341"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=32.7                           #ohm\n",
+      "L1=50*10**-3                       #H\n",
+      "R2=1.36                            #ohm\n",
+      "R3=100.0                             #ohm\n",
+      "R4=100                             #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "r=((R4*R1)/R3)-R2\n",
+      "L2=L1*(R4/R3)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistance of the coil is \",r,\"ohm \\nInductance of the coil is \" ,L2*10**3,\"mH\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistance of the coil is  31.34 ohm \n",
+        "Inductance of the coil is  50.0 mH\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (a) Page no 343"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "w=3000                              #rad/s\n",
+      "R2=10*10**3                         #ohm\n",
+      "R1=2*10**3                          #ohm\n",
+      "C1=1*10**-6                         #farad\n",
+      "R3=1*10**3                          #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=(w**2*R1*R2*R3*C1**2)/(1+w**2*R1**2*C1**2)\n",
+      "Lx=(R2*R3*C1)/(1+w**2*R1**2*C1**2)\n",
+      "\n",
+      "#Result\n",
+      "print\" series equivalent impedence is \", round(Lx*10**3,0),\"mH\",\"\\n Series equivqlent resistance is \",round(Rx*10**-3,2),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " series equivalent impedence is  270.0 mH \n",
+        " Series equivqlent resistance is  4.86 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 27
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (b) Page no 343"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=1000                          #ohm\n",
+      "R3=16500                         #ohm\n",
+      "R4=800                           #ohm\n",
+      "C4=2*10**-6                      #F\n",
+      "f=50                             #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "w=2*math.pi*f\n",
+      "Lx=(R2*R3*C4)/(1+(w**2*C4**2*R4**2))\n",
+      "Rx=(w**2*C4**2*R4*R2*R3)/(1+w**2*C4**2*R4**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistance of the coil is \", round(Rx*10**-3,1),\"Kohm\"\n",
+      "print\"Inductance of the coil is \",round(Lx,1),\"H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistance of the coil is  4.2 Kohm\n",
+        "Inductance of the coil is  26.3 H\n"
+       ]
+      }
+     ],
+     "prompt_number": 35
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.9 (c) Page no 345"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C4=1*10**-6                        #F\n",
+      "R2=1000                            #ohm\n",
+      "w=314                              #rad/s\n",
+      "R3=1000\n",
+      "R4=1000\n",
+      "\n",
+      "#Calculation\n",
+      "L1=(R3*R4*C4)/(1+(w**2*C4**2*R4**2))\n",
+      "Rx=(w**2*C4**2*R4*R2*R3)/(1+w**2*C4**2*R4**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"unknown resistance is\" ,round(L1,2),\"H\"\n",
+      "print\"unknown inductance is\", round(Rx,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "unknown resistance is 0.91 H\n",
+        "unknown inductance is 89.75 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (a) Page no 346 "
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.5*10**-6                          #farad\n",
+      "C3=0.5*10**-6                          #farad\n",
+      "R2=2*10**3                             #ohm\n",
+      "R1=1*10**3                              #ohm\n",
+      "f=1000                                  #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=(C1*R2)/C3\n",
+      "Cx=(R1*C3)/R2\n",
+      "D=2*math.pi*f*Cx*Rx\n",
+      "\n",
+      "#Result\n",
+      "print\" The unknown capacitance is \",Cx*10**6,\"micro farad\", \"\\n Dissipation factor is \",round(D,4)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " The unknown capacitance is  0.25 micro farad \n",
+        " Dissipation factor is  3.1416\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (b) Page no 347"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R3=100.0                                   #ohm\n",
+      "R4=300                                     #ohm\n",
+      "C4=0.5*10**-6                              #F\n",
+      "C2=100.0                                   #pf\n",
+      "f=50                                       #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "R1=(C4/C2)*R3\n",
+      "Pf=W*R4*C4\n",
+      "\n",
+      "#Result\n",
+      "print\"Capacitance is \", C1,\"pF\"\n",
+      "print\"Equivalent series resistance is \",R1*10**6,\"Mohm\"\n",
+      "print\"PF of insulation is \",round(Pf,4)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Capacitance is  300.0 pF\n",
+        "Equivalent series resistance is  0.5 Mohm\n",
+        "PF of insulation is  0.0471\n"
+       ]
+      }
+     ],
+     "prompt_number": 19
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (c) Page no 348"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R4=100                          #ohm\n",
+      "C4=0.1                   #micro F\n",
+      "C2=500                    #pf\n",
+      "R3=300.0                     #ohm\n",
+      "f=50                         #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4*10**-5\n",
+      "\n",
+      "#Result\n",
+      "print\"The Capacitance is \",round(C1,1),\"pF\" \n",
+      "print\"Dielectric loss of angle is \",round(A*180/3.14,1),\"degree\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The Capacitance is  166.7 pF\n",
+        "Dielectric loss of angle is  1.8 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 40
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (d) Page no 348"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "d=4.5*10**-3\n",
+      "f=50                    #Hz\n",
+      "C2=105*10**-12\n",
+      "C4=0.5*10**-6               #F\n",
+      "R3=260.0                   #ohm\n",
+      "R4=1000/3.14\n",
+      "K0=8.854*10**-12\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4\n",
+      "a=math.pi*(6*10**-2)**2\n",
+      "K=(C1*d)/(K0*a)\n",
+      "\n",
+      "#Result\n",
+      "print\"The capacitance is \",round(C1*10**12,1),\"pF\"\n",
+      "print\"Value of PF is \",round(A,3)\n",
+      "print\"Relative permittivity is \",round(K,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The capacitance is  128.6 pF\n",
+        "Value of PF is  0.05\n",
+        "Relative permittivity is  5.78\n"
+       ]
+      }
+     ],
+     "prompt_number": 63
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (e) Page no 349"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R3=100               #ohm\n",
+      "R4=300               #ohm\n",
+      "C2=100.0                #pF\n",
+      "C4=0.5                #micro F\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "C1=(R4/R3)*C2\n",
+      "r1=R3*(C4/C2)\n",
+      "W=2*math.pi*f\n",
+      "C1=(R4/R3)*C2\n",
+      "A=W*C4*R4*10**-6\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of capacitor is \",C1,\"pF\"\n",
+      "print\"PF of the capacitor is \",round(A,4)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of capacitor is  300.0 pF\n",
+        "PF of the capacitor is  0.0471\n"
+       ]
+      }
+     ],
+     "prompt_number": 71
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (f) Page no 350"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=300                    #ohm\n",
+      "R2=100.0                    #ohm\n",
+      "C1=0.6*10**-6                   # F\n",
+      "C3=100.0*10**-12                   #F\n",
+      "\n",
+      "#Calculation\n",
+      "Rx=R2*(C1/C3)\n",
+      "C=(R1/R2)*C3\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of series resistance is \", Rx*10**-5,\"Mohm\"\n",
+      "print\"The value of capacitance is \",C*10**12,\"pF\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of series resistance is  6.0 Mohm\n",
+        "The value of capacitance is  300.0 pF\n"
+       ]
+      }
+     ],
+     "prompt_number": 80
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.10 (g) Page no 350"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.1*10**-6                    #F\n",
+      "C2=0.25*10**-6                    #F\n",
+      "R2=5000.0                           #ohm\n",
+      "C3=0.25*10**-6                    #F\n",
+      "f=2000                           #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "Rx=R2*(C1/C2)\n",
+      "C=(R1/R2)*C3\n",
+      "W=2*math.pi*f\n",
+      "A=W*C*Rx*10**-6\n",
+      "#Result\n",
+      "print\"The value of capacitance is \", round(C*10**7,1),\"micro F\"\n",
+      "print\"Dissipation factor is \", round(A*10**7,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of capacitance is  0.1 micro F\n",
+        "Dissipation factor is  3.77\n"
+       ]
+      }
+     ],
+     "prompt_number": 102
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.11 Page no 352"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=4.7*10**3                                     #ohm\n",
+      "R2=20*10**3                                      #ohm\n",
+      "R3=10*10**3                                      #ohm\n",
+      "R4=100*10**3                                     #ohm\n",
+      "C1=5*10**-9                                      #farad\n",
+      "C3=10*10**-9                                     #farad\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "f=1/(2.0*math.pi*(math.sqrt(C1*R1*R3*C3)))\n",
+      "print\"Frequency of the circuit is \", round(f*10**-3,3),\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Frequency of the circuit is  3.283 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.12 Page no 353"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=3.1*10**3                                       #ohm\n",
+      "C1=5.2*10**-6                                      #farad\n",
+      "R2=25.0*10**3                                        #ohm\n",
+      "f=2.5*10**3                                        #ohm\n",
+      "R4=100.0*10**3                                       #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "w=2*math.pi*f\n",
+      "R3=R4/R2*(R1+(1/w**2*R1*C1**2))\n",
+      "C3=R2/R4*(C1/(1+w**2*R1**2*C1**2))\n",
+      "\n",
+      "#CResult\n",
+      "print\" Equivalent parallel resistance is \",R3*10**-3,\"Kohm \",\"\\n Equivalent parallel capaciatnce is \", round(C3*10**12,1),\"pf\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Equivalent parallel resistance is  12.4 Kohm  \n",
+        " Equivalent parallel capaciatnce is  20.3 pf\n"
+       ]
+      }
+     ],
+     "prompt_number": 20
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.13 Page no 353"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C1=0.5*10**-6                           #farad\n",
+      "R1=800.0                                  #ohm\n",
+      "C2=1.0*10**-6                            #farad\n",
+      "R2=400                                   #ohm\n",
+      "R4=1000                                  #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "f=1/(2.0*math.pi*math.sqrt(R1*C1*R2*C2))\n",
+      "R3=R4/((R2/R1)+(C1/C2))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of frequency for which the bridge is balanced \", round(f*10**-3,3),\"KHz\"\n",
+      "print\"(ii) The value of R required to produce balance \",R3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of frequency for which the bridge is balanced  0.398 KHz\n",
+        "(ii) The value of R required to produce balance  1000.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 11.14 Page no 359"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R2=200                                 #ohm\n",
+      "R3=1000                                  #ohm\n",
+      "R4=1000.0\n",
+      "C=10*10**-6                              #Farad\n",
+      "r=496\n",
+      "\n",
+      "#Calculation\n",
+      "R1=(R2*R3)/R4\n",
+      "L1=(C*R3/R4)*(r*R4+R2*R4+r*R2)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of inductance is \", L1,\"H\"\n",
+      "print\"The value of resistance is \",R1,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of inductance is  7.952 H\n",
+        "The value of resistance is  200.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 108
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap12.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap12.ipynb
new file mode 100755
index 00000000..b3715c64
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap12.ipynb
@@ -0,0 +1,95 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7af0495b58ca6c852d68e4365d49889cd4f3d900affcfb795083ae4f78ea1db8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 12 Recorders"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 12.1 Page no 373"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "t=5                                    #second\n",
+      "s=40.0                                    #cycle\n",
+      "\n",
+      "#Calculation\n",
+      "p=t/s\n",
+      "f=1/p\n",
+      "\n",
+      "#Result\n",
+      "print\"The frequency of the signal is \", f,\"cycle/sec.\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The frequency of the signal is  8.0 cycle/sec.\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 12.2 Page no 373"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "f=20.0                                       #Hz\n",
+      "t=5                                         #mm\n",
+      "\n",
+      "#Calculation\n",
+      "p=1/f\n",
+      "s=t/p\n",
+      "\n",
+      "#Result\n",
+      "print\"The chart speed isn\", s,\"mm/s\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The chart speed isn 100.0 mm/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap12_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap12_1.ipynb
new file mode 100755
index 00000000..b3715c64
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap12_1.ipynb
@@ -0,0 +1,95 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7af0495b58ca6c852d68e4365d49889cd4f3d900affcfb795083ae4f78ea1db8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 12 Recorders"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 12.1 Page no 373"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "t=5                                    #second\n",
+      "s=40.0                                    #cycle\n",
+      "\n",
+      "#Calculation\n",
+      "p=t/s\n",
+      "f=1/p\n",
+      "\n",
+      "#Result\n",
+      "print\"The frequency of the signal is \", f,\"cycle/sec.\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The frequency of the signal is  8.0 cycle/sec.\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 12.2 Page no 373"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "f=20.0                                       #Hz\n",
+      "t=5                                         #mm\n",
+      "\n",
+      "#Calculation\n",
+      "p=1/f\n",
+      "s=t/p\n",
+      "\n",
+      "#Result\n",
+      "print\"The chart speed isn\", s,\"mm/s\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The chart speed isn 100.0 mm/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap13.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap13.ipynb
new file mode 100755
index 00000000..58b2b2dc
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap13.ipynb
@@ -0,0 +1,405 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:0022da94b1d3ec30a76a501a1e2a864424059045ea34a0bef2657a4e00b24747"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 13 Transducers"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.1 Page no 412"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=5*10**3                                 #ohm\n",
+      "a=0.9                                     #in.\n",
+      "b=3.0                                      #in.\n",
+      "R2=1500                                    #ohm\n",
+      "Vt=5                                       #volts\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(a*R)/b\n",
+      "V0=(R2/R)*Vt\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of output resistance is \", V0,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of output resistance is  1.5 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.2 Page no 413"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "a=3\n",
+      "b=5.0           \n",
+      "R=5*10**3                                     #ohm\n",
+      "Vt=5                                           #volts\n",
+      "R4=2.5*10**3                                   #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(a*R)/b\n",
+      "Ve=((R2/R)*Vt-(R4/R)*Vt)\n",
+      "\n",
+      "#Results\n",
+      "print\"The value of Ve is \",Ve,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of Ve is  0.5 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.3 Page no 417"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "K=2\n",
+      "R=130                               #ohm\n",
+      "l=1*10**-6\n",
+      "\n",
+      "#Calculation\n",
+      "R1=K*R*l\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of change in resistance is \", R1*10**6,\"micro ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of change in resistance is  260.0 micro ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.4 Page no 427"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Vt=15                                 #Volts\n",
+      "R1=4000.0                              #ohm\n",
+      "R2=17.0                                 #ohm\n",
+      "R3=3.0                                   #ohm\n",
+      "R4=950                                   #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "I=Vt/(R1+R2+R3)\n",
+      "I1=Vt/(R2+R3+R4)\n",
+      "\n",
+      "#Result\n",
+      "print\" Meter reading at 77 degree F is \", round(I*10**3,2),\"mA\",\"\\n Meter reading at 150 degree F is \",round(I1*10**3,1),\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Meter reading at 77 degree F is  3.73 mA \n",
+        " Meter reading at 150 degree F is  15.5 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 29
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.5 Page no 432"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "L=2500                          #F\n",
+      "a=1\n",
+      "b=0.04\n",
+      "\n",
+      "#Calculation\n",
+      "c=a-b\n",
+      "Lt=L*(1/c)\n",
+      "Ld=Lt-L\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of inductance is \", round(Ld,0),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of inductance is  104.0 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.6 Page no 437"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=6.3                                     #volts\n",
+      "V2=5.2                                     #Volts\n",
+      "a=-0.5                                       #in.\n",
+      "b=-0.30\n",
+      "c=-5.2\n",
+      "d=-0.25\n",
+      "\n",
+      "#Calculation\n",
+      "V0=(b*c)/a\n",
+      "V=(d*c)/a\n",
+      "\n",
+      "#Result\n",
+      "print\"(i)  The output voltage is \", V0,\"Volts\"\n",
+      "print\"(ii) The output voltage is \", V,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i)  The output voltage is  -3.12 Volts\n",
+        "(ii) The output voltage is  -2.6 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 43
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.7 Page no 450"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "K=0.32\n",
+      "a=7.06*10**-3                                   #J\n",
+      "\n",
+      "#Calculation\n",
+      "E=a/K\n",
+      "\n",
+      "#Result\n",
+      "print\"Electric energy is \", round(E*10**3,2),\"mJ\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Electric energy is  22.06 mJ\n"
+       ]
+      }
+     ],
+     "prompt_number": 49
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.8 (a) Page no 453"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=30                                    #Volts\n",
+      "I=10*10**-3                             #A\n",
+      "Rcell=1000                                   #ohm\n",
+      "R1=100*10**3                                 #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R=(V/I)-Rcell\n",
+      "I1=V/(R+R1)\n",
+      "\n",
+      "#Result \n",
+      "print\"(i) The required series resistance is \", R*10**-3,\"Kohm\"\n",
+      "print\"(ii) Dark current level is \",round(I1*10**3,1),\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The required series resistance is  2.0 Kohm\n",
+        "(ii) Dark current level is  0.3 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 62
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.8 (b) Page no 460"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R0=180\n",
+      "a=0.00392\n",
+      "T1=60                         #degree\n",
+      "T2=20                         #degree\n",
+      "\n",
+      "#Calculation\n",
+      "R=R0*(1-(a*(T1-T2)))\n",
+      "\n",
+      "#Result\n",
+      "print\"The resistance is \", round(R,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resistance is  151.78 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.9 Page no 460"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R0=100.0\n",
+      "a=0.00392\n",
+      "T1=50                          #degree\n",
+      "T2=25                         #degree\n",
+      "R=200                          #ohm\n",
+      "\n",
+      "R=R0*(1+a*(T1-T2))\n",
+      "t2=(((R/R0)-1)/a)+T2\n",
+      "print t2"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "50.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap13_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap13_1.ipynb
new file mode 100755
index 00000000..58b2b2dc
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap13_1.ipynb
@@ -0,0 +1,405 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:0022da94b1d3ec30a76a501a1e2a864424059045ea34a0bef2657a4e00b24747"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 13 Transducers"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.1 Page no 412"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=5*10**3                                 #ohm\n",
+      "a=0.9                                     #in.\n",
+      "b=3.0                                      #in.\n",
+      "R2=1500                                    #ohm\n",
+      "Vt=5                                       #volts\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(a*R)/b\n",
+      "V0=(R2/R)*Vt\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of output resistance is \", V0,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of output resistance is  1.5 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.2 Page no 413"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "a=3\n",
+      "b=5.0           \n",
+      "R=5*10**3                                     #ohm\n",
+      "Vt=5                                           #volts\n",
+      "R4=2.5*10**3                                   #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(a*R)/b\n",
+      "Ve=((R2/R)*Vt-(R4/R)*Vt)\n",
+      "\n",
+      "#Results\n",
+      "print\"The value of Ve is \",Ve,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of Ve is  0.5 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.3 Page no 417"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "K=2\n",
+      "R=130                               #ohm\n",
+      "l=1*10**-6\n",
+      "\n",
+      "#Calculation\n",
+      "R1=K*R*l\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of change in resistance is \", R1*10**6,\"micro ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of change in resistance is  260.0 micro ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.4 Page no 427"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Vt=15                                 #Volts\n",
+      "R1=4000.0                              #ohm\n",
+      "R2=17.0                                 #ohm\n",
+      "R3=3.0                                   #ohm\n",
+      "R4=950                                   #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "I=Vt/(R1+R2+R3)\n",
+      "I1=Vt/(R2+R3+R4)\n",
+      "\n",
+      "#Result\n",
+      "print\" Meter reading at 77 degree F is \", round(I*10**3,2),\"mA\",\"\\n Meter reading at 150 degree F is \",round(I1*10**3,1),\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Meter reading at 77 degree F is  3.73 mA \n",
+        " Meter reading at 150 degree F is  15.5 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 29
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.5 Page no 432"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "L=2500                          #F\n",
+      "a=1\n",
+      "b=0.04\n",
+      "\n",
+      "#Calculation\n",
+      "c=a-b\n",
+      "Lt=L*(1/c)\n",
+      "Ld=Lt-L\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of inductance is \", round(Ld,0),\"micro H\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of inductance is  104.0 micro H\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.6 Page no 437"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=6.3                                     #volts\n",
+      "V2=5.2                                     #Volts\n",
+      "a=-0.5                                       #in.\n",
+      "b=-0.30\n",
+      "c=-5.2\n",
+      "d=-0.25\n",
+      "\n",
+      "#Calculation\n",
+      "V0=(b*c)/a\n",
+      "V=(d*c)/a\n",
+      "\n",
+      "#Result\n",
+      "print\"(i)  The output voltage is \", V0,\"Volts\"\n",
+      "print\"(ii) The output voltage is \", V,\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i)  The output voltage is  -3.12 Volts\n",
+        "(ii) The output voltage is  -2.6 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 43
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.7 Page no 450"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "K=0.32\n",
+      "a=7.06*10**-3                                   #J\n",
+      "\n",
+      "#Calculation\n",
+      "E=a/K\n",
+      "\n",
+      "#Result\n",
+      "print\"Electric energy is \", round(E*10**3,2),\"mJ\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Electric energy is  22.06 mJ\n"
+       ]
+      }
+     ],
+     "prompt_number": 49
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.8 (a) Page no 453"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=30                                    #Volts\n",
+      "I=10*10**-3                             #A\n",
+      "Rcell=1000                                   #ohm\n",
+      "R1=100*10**3                                 #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R=(V/I)-Rcell\n",
+      "I1=V/(R+R1)\n",
+      "\n",
+      "#Result \n",
+      "print\"(i) The required series resistance is \", R*10**-3,\"Kohm\"\n",
+      "print\"(ii) Dark current level is \",round(I1*10**3,1),\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The required series resistance is  2.0 Kohm\n",
+        "(ii) Dark current level is  0.3 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 62
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.8 (b) Page no 460"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R0=180\n",
+      "a=0.00392\n",
+      "T1=60                         #degree\n",
+      "T2=20                         #degree\n",
+      "\n",
+      "#Calculation\n",
+      "R=R0*(1-(a*(T1-T2)))\n",
+      "\n",
+      "#Result\n",
+      "print\"The resistance is \", round(R,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resistance is  151.78 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 13.9 Page no 460"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R0=100.0\n",
+      "a=0.00392\n",
+      "T1=50                          #degree\n",
+      "T2=25                         #degree\n",
+      "R=200                          #ohm\n",
+      "\n",
+      "R=R0*(1+a*(T1-T2))\n",
+      "t2=(((R/R0)-1)/a)+T2\n",
+      "print t2"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "50.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap14.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap14.ipynb
new file mode 100755
index 00000000..a2b4154b
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap14.ipynb
@@ -0,0 +1,143 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:22e515cfdcb31a0dc094c823dd4160ebc2cdde6bfeeb65b5dbdb65b6ac7c27a6"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 14 Signal conditioning"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.2 Page no 508"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Va=2                                   #Volts\n",
+      "Vb=1                                   #Volts\n",
+      "Vc=3                                   #Volts\n",
+      "R=3000.0                                 #ohm\n",
+      "Rf=1000                                #ohm\n",
+      "Rom=270                                #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "V0=-(Rf/R)*(Va+Vb+Vc)\n",
+      "\n",
+      "#Result\n",
+      "print\"The output voltage is \", V0,\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The output voltage is  -2.0 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.3 Page no 519"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=2.2*10**3                                 #ohm\n",
+      "Rf=10*10**3                                  #ohm\n",
+      "R=120.0*10**3                                   #ohm\n",
+      "E=5                                           #volts\n",
+      "a=-1000                                          \n",
+      "T1=-25                                        #degree C\n",
+      "T=100                                         #degree C\n",
+      "\n",
+      "#Calculation\n",
+      "R0=a*T1\n",
+      "V0=-((R0*E)/(2.0*(2*R+R0)))*(Rf/R1)\n",
+      "R2=a*(T+T1)\n",
+      "V1=-((R2*E)/(2.0*(2*R+R2)))*(Rf/R1)\n",
+      "\n",
+      "#Result\n",
+      "print\" The output voltage is at 0 degree C is \", round(V0,2),\"Volts\",\"\\n The output Voltage at 100 Degree C is \",round(V1,2),\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " The output voltage is at 0 degree C is  -1.07 Volts \n",
+        " The output Voltage at 100 Degree C is  5.17 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.4 Page no 521"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V0=1.5                                   #Volts\n",
+      "E=10                                     #Volts\n",
+      "R=100                                     #ohm\n",
+      "Rf=100                                    #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R0=(V0*R)/(E*Rf)\n",
+      "\n",
+      "#Result\n",
+      "print\"The change in resistance of each gauge element is \", R0,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The change in resistance of each gauge element is  0.15 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap14_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap14_1.ipynb
new file mode 100755
index 00000000..a2b4154b
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap14_1.ipynb
@@ -0,0 +1,143 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:22e515cfdcb31a0dc094c823dd4160ebc2cdde6bfeeb65b5dbdb65b6ac7c27a6"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 14 Signal conditioning"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.2 Page no 508"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Va=2                                   #Volts\n",
+      "Vb=1                                   #Volts\n",
+      "Vc=3                                   #Volts\n",
+      "R=3000.0                                 #ohm\n",
+      "Rf=1000                                #ohm\n",
+      "Rom=270                                #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "V0=-(Rf/R)*(Va+Vb+Vc)\n",
+      "\n",
+      "#Result\n",
+      "print\"The output voltage is \", V0,\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The output voltage is  -2.0 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.3 Page no 519"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=2.2*10**3                                 #ohm\n",
+      "Rf=10*10**3                                  #ohm\n",
+      "R=120.0*10**3                                   #ohm\n",
+      "E=5                                           #volts\n",
+      "a=-1000                                          \n",
+      "T1=-25                                        #degree C\n",
+      "T=100                                         #degree C\n",
+      "\n",
+      "#Calculation\n",
+      "R0=a*T1\n",
+      "V0=-((R0*E)/(2.0*(2*R+R0)))*(Rf/R1)\n",
+      "R2=a*(T+T1)\n",
+      "V1=-((R2*E)/(2.0*(2*R+R2)))*(Rf/R1)\n",
+      "\n",
+      "#Result\n",
+      "print\" The output voltage is at 0 degree C is \", round(V0,2),\"Volts\",\"\\n The output Voltage at 100 Degree C is \",round(V1,2),\"volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " The output voltage is at 0 degree C is  -1.07 Volts \n",
+        " The output Voltage at 100 Degree C is  5.17 volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 14.4 Page no 521"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V0=1.5                                   #Volts\n",
+      "E=10                                     #Volts\n",
+      "R=100                                     #ohm\n",
+      "Rf=100                                    #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R0=(V0*R)/(E*Rf)\n",
+      "\n",
+      "#Result\n",
+      "print\"The change in resistance of each gauge element is \", R0,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The change in resistance of each gauge element is  0.15 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap15.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap15.ipynb
new file mode 100755
index 00000000..8a106854
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap15.ipynb
@@ -0,0 +1,428 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:fc6706355245368084174ebaf68c877ff8fa2581b1104eec814db836f65c5c69"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 15 Filters"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "Example 15.1 Page no 547"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fH=2000                         #Hz\n",
+      "C=0.01*10**-6                   #F\n",
+      "Af=2                            #gain\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2.0*math.pi*fH*C)\n",
+      "Rf=Af-1\n",
+      "\n",
+      "#Result\n",
+      "print\"In this case R1=Rf=10 Kohm is selected.\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "In this case R1=Rf=10 Kohm is selected.\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.2 Page no 547"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "wc=20.0                          #K radian/s\n",
+      "C=0.01                          #micro F\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/(wc*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of resistance is \", R,\"K ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of resistance is  5.0 K ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.3 Page no 550"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fh=2000                         #Hz\n",
+      "C2=0.0033*10**-6                #F\n",
+      "C3=0.0033*10**-6                #F\n",
+      "R0=0.586                        #ohm\n",
+      "R1=10000                        #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2*math.pi*fh*C2)\n",
+      "Rf=R0*R1\n",
+      "\n",
+      "#Result\n",
+      "print\" R2=R3=\",round(R*10**-3,0),\"Kohm \\n C2=C3=\",C2 ,\"micro F \\n Rf=\",Rf*10**-3,\"Kohm \\n R1=\",R1*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " R2=R3= 24.0 Kohm \n",
+        " C2=C3= 3.3e-09 micro F \n",
+        " Rf= 5.86 Kohm \n",
+        " R1= 10.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 18
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.4 Page no 553"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=47*10**3                      #ohm\n",
+      "C=0.0022*10**-6                 #F\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "fl=1/(2.0*math.pi*R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The cutoff frequency is \", round(fl*10**-3,2),\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The cutoff frequency is  1.54 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.5 Page no 557"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01*10**-6                         #f\n",
+      "fh=1000                                #Hz\n",
+      "fl=100\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/(2.0*math.pi*fh*C)\n",
+      "R1=1/(2.0*math.pi*fl*C)\n",
+      "fc=math.sqrt(fl*fh)\n",
+      "Q=fc/(fh-fl)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resistance is \", round(R1*10**-3,0),\"Kohm\"\n",
+      "print\"(ii) The value of Q is \",round(Q,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resistance is  159.0 Kohm\n",
+        "(ii) The value of Q is  0.35\n"
+       ]
+      }
+     ],
+     "prompt_number": 35
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.6 Page no 561"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01                          #F\n",
+      "Q=5\n",
+      "Fc=1000                              #Hz\n",
+      "Av0=8\n",
+      "a=1000                             #Hz\n",
+      "b=1.5*10**3                         #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R1=Q/(2.0*math.pi*C*Av0)\n",
+      "R2=(Q/(2.0*math.pi*Fc*C*(2*Q**2-Av0)))*10**3\n",
+      "R3=Q/(math.pi*Fc*C)\n",
+      "Rk=R2*((a/b)**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resistances are \\n R1=\",round(R1,0),\"Kohm \\n R2=\",round(R2,0),\"Kohm \\n R3=\",round(R3*10**3,0),\"Kohm\"\n",
+      "print\"(ii) The value of resistance is \", round(Rk*10**3,0),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resistances are \n",
+        " R1= 10.0 Kohm \n",
+        " R2= 2.0 Kohm \n",
+        " R3= 159.0 Kohm\n",
+        "(ii) The value of resistance is  842.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 67
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.7 Page no 563"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fl=100                            #Hz\n",
+      "fh=1000                            #Hz\n",
+      "R=159                       #Kohm, for low pass filter\n",
+      "C=0.1                     #micro F , for low pass filter\n",
+      "R1=15.9                      # K ohm, for high pass filter\n",
+      "C1=0.01                   #micro F ,  for high pass filter\n",
+      "R2=10.0                        #K ohm\n",
+      "R3=10.0                     #K ohm\n",
+      "R4=10.0                        #K ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rom=(R2*R3*R4)/(R2+R3+R4)*10**-1\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of resistance is \", round(Rom,1),\"Kohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of resistance is  3.3 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.8 Page no 564"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.047                   #micro F\n",
+      "fn=50                             #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2.0*math.pi*fn*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of resistance is \", round(R*10**3,0),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of resistance is  68.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.9 Page no 566"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01                      #micro F\n",
+      "R=15                        #K ohm\n",
+      "f=2.5                        #K ohm\n",
+      "\n",
+      "import math\n",
+      "b=2*math.pi*f*C*R\n",
+      "a=-(2*math.atan(b)*180/3.14)\n",
+      "\n",
+      "#Result\n",
+      "print\"Phase angle is \", round(a,0)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Phase angle is  -134.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 26
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.10 Page no 570"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=316.0                 #ohm\n",
+      "a=10.0\n",
+      "R1=100                              #ohm\n",
+      "F1=1.5 *10**3                       #Hz\n",
+      "c=5.03*10**7\n",
+      "R6=1.8*10**3\n",
+      "\n",
+      "#Calculation\n",
+      "R2=R/a\n",
+      "R3=R1/(R*a-1)\n",
+      "R4=c/F1\n",
+      "R7=6*R6 \n",
+      "R8=(R6*R7)/(R6+R7)\n",
+      "\n",
+      "print\"value of external component are \\n R2=\",R2,\"Kohm \\n R3=\",round(R3*10**2,1),\"Kohm \\n R4=R5=\", round(R4*10**-3,2)\n",
+      "print\" R7=\",R7*10**-3,\"Kohm \\n R8=\", round(R8*10**-3,3),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "value of external component are \n",
+        " R2= 31.6 Kohm \n",
+        " R3= 3.2 Kohm \n",
+        " R4=R5= 33.53\n",
+        " R7= 10.8 Kohm \n",
+        " R8= 1.543 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap15_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap15_1.ipynb
new file mode 100755
index 00000000..f0a780cd
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap15_1.ipynb
@@ -0,0 +1,426 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:eb4b10e7f9c8c3f627f67e212344cd57fc6c1ddf81e7bbc925101a5b8d063fd2"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 15 Filters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.1 Page no 547"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fH=2000                         #Hz\n",
+      "C=0.01*10**-6                   #F\n",
+      "Af=2                            #gain\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2.0*math.pi*fH*C)\n",
+      "Rf=Af-1\n",
+      "\n",
+      "#Result\n",
+      "print\"In this case R1=Rf=10 Kohm is selected.\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "In this case R1=Rf=10 Kohm is selected.\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.2 Page no 547"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "wc=20.0                          #K radian/s\n",
+      "C=0.01                          #micro F\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/(wc*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of resistance is \", R,\"K ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of resistance is  5.0 K ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.3 Page no 550"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fh=2000                         #Hz\n",
+      "C2=0.0033*10**-6                #F\n",
+      "C3=0.0033*10**-6                #F\n",
+      "R0=0.586                        #ohm\n",
+      "R1=10000                        #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2*math.pi*fh*C2)\n",
+      "Rf=R0*R1\n",
+      "\n",
+      "#Result\n",
+      "print\" R2=R3=\",round(R*10**-3,0),\"Kohm \\n C2=C3=\",C2 ,\"micro F \\n Rf=\",Rf*10**-3,\"Kohm \\n R1=\",R1*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " R2=R3= 24.0 Kohm \n",
+        " C2=C3= 3.3e-09 micro F \n",
+        " Rf= 5.86 Kohm \n",
+        " R1= 10.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 18
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.4 Page no 553"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=47*10**3                      #ohm\n",
+      "C=0.0022*10**-6                 #F\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "fl=1/(2.0*math.pi*R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The cutoff frequency is \", round(fl*10**-3,2),\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The cutoff frequency is  1.54 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.5 Page no 557"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01*10**-6                         #f\n",
+      "fh=1000                                #Hz\n",
+      "fl=100\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/(2.0*math.pi*fh*C)\n",
+      "R1=1/(2.0*math.pi*fl*C)\n",
+      "fc=math.sqrt(fl*fh)\n",
+      "Q=fc/(fh-fl)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resistance is \", round(R1*10**-3,0),\"Kohm\"\n",
+      "print\"(ii) The value of Q is \",round(Q,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resistance is  159.0 Kohm\n",
+        "(ii) The value of Q is  0.35\n"
+       ]
+      }
+     ],
+     "prompt_number": 35
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.6 Page no 561"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01                          #F\n",
+      "Q=5\n",
+      "Fc=1000                              #Hz\n",
+      "Av0=8\n",
+      "a=1000                             #Hz\n",
+      "b=1.5*10**3                         #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R1=Q/(2.0*math.pi*C*Av0)\n",
+      "R2=(Q/(2.0*math.pi*Fc*C*(2*Q**2-Av0)))*10**3\n",
+      "R3=Q/(math.pi*Fc*C)\n",
+      "Rk=R2*((a/b)**2)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resistances are \\n R1=\",round(R1,0),\"Kohm \\n R2=\",round(R2,0),\"Kohm \\n R3=\",round(R3*10**3,0),\"Kohm\"\n",
+      "print\"(ii) The value of resistance is \", round(Rk*10**3,0),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resistances are \n",
+        " R1= 10.0 Kohm \n",
+        " R2= 2.0 Kohm \n",
+        " R3= 159.0 Kohm\n",
+        "(ii) The value of resistance is  842.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 67
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.7 Page no 563"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fl=100                            #Hz\n",
+      "fh=1000                            #Hz\n",
+      "R=159                       #Kohm, for low pass filter\n",
+      "C=0.1                     #micro F , for low pass filter\n",
+      "R1=15.9                      # K ohm, for high pass filter\n",
+      "C1=0.01                   #micro F ,  for high pass filter\n",
+      "R2=10.0                        #K ohm\n",
+      "R3=10.0                     #K ohm\n",
+      "R4=10.0                        #K ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Rom=(R2*R3*R4)/(R2+R3+R4)*10**-1\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of resistance is \", round(Rom,1),\"Kohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of resistance is  3.3 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.8 Page no 564"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.047                   #micro F\n",
+      "fn=50                             #Hz\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "R=1/(2.0*math.pi*fn*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of resistance is \", round(R*10**3,0),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of resistance is  68.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.9 Page no 566"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "C=0.01                      #micro F\n",
+      "R=15                        #K ohm\n",
+      "f=2.5                        #K ohm\n",
+      "\n",
+      "import math\n",
+      "b=2*math.pi*f*C*R\n",
+      "a=-(2*math.atan(b)*180/3.14)\n",
+      "\n",
+      "#Result\n",
+      "print\"Phase angle is \", round(a,0)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Phase angle is  -134.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 26
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 15.10 Page no 570"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=316.0                 #ohm\n",
+      "a=10.0\n",
+      "R1=100                              #ohm\n",
+      "F1=1.5 *10**3                       #Hz\n",
+      "c=5.03*10**7\n",
+      "R6=1.8*10**3\n",
+      "\n",
+      "#Calculation\n",
+      "R2=R/a\n",
+      "R3=R1/(R*a-1)\n",
+      "R4=c/F1\n",
+      "R7=6*R6 \n",
+      "R8=(R6*R7)/(R6+R7)\n",
+      "\n",
+      "print\"value of external component are \\n R2=\",R2,\"Kohm \\n R3=\",round(R3*10**2,1),\"Kohm \\n R4=R5=\", round(R4*10**-3,2)\n",
+      "print\" R7=\",R7*10**-3,\"Kohm \\n R8=\", round(R8*10**-3,3),\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "value of external component are \n",
+        " R2= 31.6 Kohm \n",
+        " R3= 3.2 Kohm \n",
+        " R4=R5= 33.53\n",
+        " R7= 10.8 Kohm \n",
+        " R8= 1.543 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap16.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap16.ipynb
new file mode 100755
index 00000000..876e1901
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap16.ipynb
@@ -0,0 +1,58 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:f0d106cb20e4ff801816370dc6f9b81f6c99454631c6ab3d945167ce9fa7c469"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 16 Measurment set-up"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 16.1 Page no 619"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fd=75                   #KHz\n",
+      "fm=5.0                    #KHz\n",
+      "\n",
+      "#Calculation\n",
+      "Mi=fd/fm\n",
+      "\n",
+      "#Result\n",
+      "print\"Modulation index is \", Mi"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Modulation index is  15.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap16_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap16_1.ipynb
new file mode 100755
index 00000000..ec1414f3
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap16_1.ipynb
@@ -0,0 +1,58 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:ff974df8ce9486ee9f772d0135b1a24d04773e3e5aa89510038bd431059e4876"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 16 Measurement set-up"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 16.1 Page no 619"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "fd=75                   #KHz\n",
+      "fm=5.0                    #KHz\n",
+      "\n",
+      "#Calculation\n",
+      "Mi=fd/fm\n",
+      "\n",
+      "#Result\n",
+      "print\"Modulation index is \", Mi"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Modulation index is  15.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap17.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap17.ipynb
new file mode 100755
index 00000000..cf85c902
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap17.ipynb
@@ -0,0 +1,78 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:8031d2b3be7285338d4c75ced4c49e8240652de917ff83e30f4a9fa6859d2b74"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 17 Data acquisition system"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 17.1 Page no 640"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "n=5                     #bit\n",
+      "a=10\n",
+      "b=20\n",
+      "c=30\n",
+      "\n",
+      "#Calculation\n",
+      "Wlsb=-(1/2.0**n-1)\n",
+      "Wlsb2=(2/2.0**n)\n",
+      "Wlsb3=(4/2.0**n)\n",
+      "V1=a/(2.0**n-1)\n",
+      "V2=b/(2.0**n-1)\n",
+      "V3=c/(2.0**n-1)\n",
+      "Va=(a*2**4+a*2**3+0*2**2+a*2**1+a*2**0)/(2.0**5-1)\n",
+      "Vb=(a*2**4+0*2**3+a*2**2+a*2**1+0*2**0)/(2.0**5-1)\n",
+      "#Result\n",
+      "print\"(1) The LSB Weight is \", round(Wlsb,2)\n",
+      "print\"(2) The 2nd LSB Weight is \", round(Wlsb2,2),\"And 2rd LSB weight is \",Wlsb3\n",
+      "print\"(3) Ist LSB causes a change in output voltage is \", round(V1,1)\n",
+      "print\"    2nd LSB causes a change in output voltage is \", round(V2,1)\n",
+      "print\"    3rdLSB causes a change in output voltage is \", round(V1,1)\n",
+      "print\"(4) Output voltage for 11011 is \" ,round(Va,2),\"Volt\"\n",
+      "print\"    Output voltage for 10110 is \" ,round(Vb,2),\"Volt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(1) The LSB Weight is  0.97\n",
+        "(2) The 2nd LSB Weight is  0.06 And 2rd LSB weight is  0.125\n",
+        "(3) Ist LSB causes a change in output voltage is  0.3\n",
+        "    2nd LSB causes a change in output voltage is  0.6\n",
+        "    3rdLSB causes a change in output voltage is  0.3\n",
+        "(4) Output voltage for 11011 is  8.71 Volt\n",
+        "    Output voltage for 10110 is  7.1 Volt\n"
+       ]
+      }
+     ],
+     "prompt_number": 23
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap17_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap17_1.ipynb
new file mode 100755
index 00000000..cf85c902
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap17_1.ipynb
@@ -0,0 +1,78 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:8031d2b3be7285338d4c75ced4c49e8240652de917ff83e30f4a9fa6859d2b74"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 17 Data acquisition system"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 17.1 Page no 640"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "n=5                     #bit\n",
+      "a=10\n",
+      "b=20\n",
+      "c=30\n",
+      "\n",
+      "#Calculation\n",
+      "Wlsb=-(1/2.0**n-1)\n",
+      "Wlsb2=(2/2.0**n)\n",
+      "Wlsb3=(4/2.0**n)\n",
+      "V1=a/(2.0**n-1)\n",
+      "V2=b/(2.0**n-1)\n",
+      "V3=c/(2.0**n-1)\n",
+      "Va=(a*2**4+a*2**3+0*2**2+a*2**1+a*2**0)/(2.0**5-1)\n",
+      "Vb=(a*2**4+0*2**3+a*2**2+a*2**1+0*2**0)/(2.0**5-1)\n",
+      "#Result\n",
+      "print\"(1) The LSB Weight is \", round(Wlsb,2)\n",
+      "print\"(2) The 2nd LSB Weight is \", round(Wlsb2,2),\"And 2rd LSB weight is \",Wlsb3\n",
+      "print\"(3) Ist LSB causes a change in output voltage is \", round(V1,1)\n",
+      "print\"    2nd LSB causes a change in output voltage is \", round(V2,1)\n",
+      "print\"    3rdLSB causes a change in output voltage is \", round(V1,1)\n",
+      "print\"(4) Output voltage for 11011 is \" ,round(Va,2),\"Volt\"\n",
+      "print\"    Output voltage for 10110 is \" ,round(Vb,2),\"Volt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(1) The LSB Weight is  0.97\n",
+        "(2) The 2nd LSB Weight is  0.06 And 2rd LSB weight is  0.125\n",
+        "(3) Ist LSB causes a change in output voltage is  0.3\n",
+        "    2nd LSB causes a change in output voltage is  0.6\n",
+        "    3rdLSB causes a change in output voltage is  0.3\n",
+        "(4) Output voltage for 11011 is  8.71 Volt\n",
+        "    Output voltage for 10110 is  7.1 Volt\n"
+       ]
+      }
+     ],
+     "prompt_number": 23
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap20.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap20.ipynb
new file mode 100755
index 00000000..6483ad2a
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap20.ipynb
@@ -0,0 +1,129 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:188a137b5dad28c9242953d4ba18308d43530d869157a87980207688e00b52f5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 20 Measurment of power"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.1 Page no 721"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=20                            #volts\n",
+      "V2=30                            #Volts\n",
+      "R1=100                           #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "p=(V2**2-V1**2)/(4.0*R1)\n",
+      "\n",
+      "#Result\n",
+      "print\"RF test power is \", p,\"Watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "RF test power is  1.25 Watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.2 Page no 725"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "m=200                           #gm\n",
+      "sp=1                             #cal/gm degree C\n",
+      "T1=30                            #degree C\n",
+      "T2=40                            #degree C\n",
+      "\n",
+      "#Calculation\n",
+      "P=4.18*m*sp*(T2-T1)\n",
+      "\n",
+      "#Result\n",
+      "print\"The power is \",round(P*10**-3,1),\"K watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The power is  8.4 K watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.3 Page no 728"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "V1=8.0                               #Volts\n",
+      "V2=2.0                                #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "SWR=(V1+V2)/(V1-V2)\n",
+      "print\"The standing wave ratio is \", round(SWR,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The standing wave ratio is  1.67\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap20_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap20_1.ipynb
new file mode 100755
index 00000000..6483ad2a
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap20_1.ipynb
@@ -0,0 +1,129 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:188a137b5dad28c9242953d4ba18308d43530d869157a87980207688e00b52f5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 20 Measurment of power"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.1 Page no 721"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=20                            #volts\n",
+      "V2=30                            #Volts\n",
+      "R1=100                           #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "p=(V2**2-V1**2)/(4.0*R1)\n",
+      "\n",
+      "#Result\n",
+      "print\"RF test power is \", p,\"Watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "RF test power is  1.25 Watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.2 Page no 725"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "m=200                           #gm\n",
+      "sp=1                             #cal/gm degree C\n",
+      "T1=30                            #degree C\n",
+      "T2=40                            #degree C\n",
+      "\n",
+      "#Calculation\n",
+      "P=4.18*m*sp*(T2-T1)\n",
+      "\n",
+      "#Result\n",
+      "print\"The power is \",round(P*10**-3,1),\"K watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The power is  8.4 K watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 20.3 Page no 728"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "V1=8.0                               #Volts\n",
+      "V2=2.0                                #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "SWR=(V1+V2)/(V1-V2)\n",
+      "print\"The standing wave ratio is \", round(SWR,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The standing wave ratio is  1.67\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap7.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap7.ipynb
new file mode 100755
index 00000000..55d579f9
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap7.ipynb
@@ -0,0 +1,94 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:c42ad53e71f05c7daed7df58d8caaed6d1cdccf89baa99b8fd442bc5fe5611d6"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Cahpter 7 oscilloscope"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 7.1 Page no 222"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=0.5                               #Volts\n",
+      "n=3\n",
+      "\n",
+      "#Calculation\n",
+      "V1=V*n\n",
+      "\n",
+      "#Result\n",
+      "print\"Peak to peak amplitude of the signal is \", V1,\"Vp-p\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Peak to peak amplitude of the signal is  1.5 Vp-p\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 7.2 Page no 223"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "t=2*10**-6                           #s\n",
+      "n=4\n",
+      "\n",
+      "#Calculation\n",
+      "T=t*n\n",
+      "f=(1/T)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Frequency of the signal is \", f,\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Frequency of the signal is  125.0 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/Chap7_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/Chap7_1.ipynb
new file mode 100755
index 00000000..ccfcbb02
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/Chap7_1.ipynb
@@ -0,0 +1,94 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:953d26fb666c1230bc683887cd7369146814cb5c3509af93cb69a75904089e3f"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 7 oscilloscope"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 7.1 Page no 222"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=0.5                               #Volts\n",
+      "n=3\n",
+      "\n",
+      "#Calculation\n",
+      "V1=V*n\n",
+      "\n",
+      "#Result\n",
+      "print\"Peak to peak amplitude of the signal is \", V1,\"Vp-p\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Peak to peak amplitude of the signal is  1.5 Vp-p\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 7.2 Page no 223"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "t=2*10**-6                           #s\n",
+      "n=4\n",
+      "\n",
+      "#Calculation\n",
+      "T=t*n\n",
+      "f=(1/T)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Frequency of the signal is \", f,\"KHz\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Frequency of the signal is  125.0 KHz\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/README.txt b/electronic_instrumentation_by_H_S_Kalsi/README.txt
new file mode 100755
index 00000000..4a166aa3
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/README.txt
@@ -0,0 +1,10 @@
+Contributed By: Ruchi Mittal
+Course: others
+College/Institute/Organization: aggarwal public school
+Department/Designation: commerce
+Book Title: electronic instrumentation
+Author: H S Kalsi
+Publisher: Tata McGraw hill education private limited
+Year of publication: 1995
+Isbn: ISBN-13: 9780070702066, ISBN-10: 0070702063
+Edition: third
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap1.ipynb
new file mode 100755
index 00000000..602a3854
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap1.ipynb
@@ -0,0 +1,496 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:2624a2ba41f12934f33163ef62780c9504a218c824a031aeca0eae58b845a3fc"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 1 Qualities of measurments"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1 (a) Page no 3"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=80.0                             #expected value of voltage in Volts\n",
+      "V1=79                            #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "E=V-V1\n",
+      "E1=((V-V1)/V)*100\n",
+      "E2=1-((V-V1)/V)\n",
+      "A=100*E2\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Absolute error is \",E,\"V\"\n",
+      "print\"(ii) percent error is \", E1,\"%\"\n",
+      "print\"(iii) reletive error is \", E2\n",
+      "print\"(iv) percent of accuracy is \", A,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Absolute error is  1.0 V\n",
+        "(ii) percent error is  1.25 %\n",
+        "(iii) reletive error is  0.9875\n",
+        "(iv) percent of accuracy is  98.75 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1 (b) Page no 3"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Yn=20.0                             #mA\n",
+      "Xn=18                             #mA\n",
+      "\n",
+      "#Calculation\n",
+      "e=Yn-Xn\n",
+      "E=(e/Yn)*100\n",
+      "A=1-(e/Yn)\n",
+      "a=A*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Absolute error is \", e,\"mA\"\n",
+      "print\"(ii) Percent error is \",E,\"%\"\n",
+      "print\"(iii) Relative accuracy is \",A\n",
+      "print\"(iv) Percent accuracy is \",a,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Absolute error is  2.0 mA\n",
+        "(ii) Percent error is  10.0 %\n",
+        "(iii) Relative accuracy is  0.9\n",
+        "(iv) Percent accuracy is  90.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.2 Page no 4"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=98\n",
+      "x2=101\n",
+      "x3=102\n",
+      "x4=97\n",
+      "x5=101\n",
+      "x6=100\n",
+      "x7=103\n",
+      "x8=98\n",
+      "x9=106\n",
+      "x10=99\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10.0\n",
+      "P=(x6/X)\n",
+      "\n",
+      "#Result\n",
+      "print\"Precision of the 6th measurment is \",round(P,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Precision of the 6th measurment is  0.995\n"
+       ]
+      }
+     ],
+     "prompt_number": 26
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3(a) Page no 6"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "V=80                                  #milliammeter readings\n",
+      "I=10.0                                  #mA\n",
+      "V1=150                                 #Volts\n",
+      "R1=1000                                #ohm/volt\n",
+      "\n",
+      "#Calculation\n",
+      "R=V/I\n",
+      "Rv=R1*V1\n",
+      "Rx=(R*V1)/(V1-R)\n",
+      "E=((Rx-R)/Rx)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Apparent resistance of the unknown resistance \",R,\"K ohm\"\n",
+      "print \"(ii) Actual resistance of the unknown resistance is \",round(Rx,2),\"K ohm\"\n",
+      "print \"(iii) Error due to the loading effet of the voltmeter \",round(E,1),\"%\" "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Apparent resistance of the unknown resistance  8.0 K ohm\n",
+        "(ii) Actual resistance of the unknown resistance is  8.45 K ohm\n",
+        "(iii) Error due to the loading effet of the voltmeter  5.3 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3(b) Page no 7"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=30                             #Volts\n",
+      "V1=150                           #Volts\n",
+      "I=0.6                            #A\n",
+      "R1=1000                          #ohm/volts\n",
+      "\n",
+      "#Calculation\n",
+      "R=V/I\n",
+      "Rv=(R1*V1)\n",
+      "Rx=(R*Rv)/(Rv-R)\n",
+      "E=((Rx-R)/Rx)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) total circuit resistance is \", R,\"ohm\"\n",
+      "print \"(ii) The voltmeter resistance is \",round(Rx,2)\n",
+      "print\"(iii) Error due to loading effect of voltmeter \", round(E,3),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) total circuit resistance is  50.0 ohm\n",
+        "(ii) The voltmeter resistance is  50.02\n",
+        "(iii) Error due to loading effect of voltmeter  0.033 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 113
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.4 Page no 12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=49.7\n",
+      "x2=50.1\n",
+      "x3=50.2\n",
+      "x4=49.6\n",
+      "x5=49.7\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5)/5.0\n",
+      "d1=x1-X\n",
+      "d2=x2-X\n",
+      "d3=x3-X\n",
+      "d4=x4-X\n",
+      "d5=x5-X\n",
+      "dtotal=(d1+d2+d3+d4+d5)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Arithmetic mean is \", X\n",
+      "print\"(ii) derivations from each value are\"\n",
+      "print \"d1=\",d1,\"\\nd2=\",d2,\"\\nd3=\",d3,\"\\nd4=\",d4,\"\\nd5=\",d5\n",
+      "print\"(iii) The algebric sum of derivative is \",round(dtotal,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Arithmetic mean is  49.86\n",
+        "(ii) derivations from each value are\n",
+        "d1= -0.16 \n",
+        "d2= 0.24 \n",
+        "d3= 0.34 \n",
+        "d4= -0.26 \n",
+        "d5= -0.16\n",
+        "(iii) The algebric sum of derivative is  0.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 77
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.5 Page no 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=49.7\n",
+      "x2=50.1\n",
+      "x3=50.2\n",
+      "x4=49.6\n",
+      "x5=49.7\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5)/5.0\n",
+      "d1=x1-X\n",
+      "d2=x2-X\n",
+      "d3=x3-X\n",
+      "d4=x4-X\n",
+      "d5=x5-X\n",
+      "dtotal=(d1+d2+d3+d4+d5)/5.0\n",
+      "\n",
+      "#Result\n",
+      "print\"The average deviation is \",round(dtotal*10**14,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The average deviation is  0.284\n"
+       ]
+      }
+     ],
+     "prompt_number": 86
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.6 Page no 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "d1= -0.16 \n",
+      "d2= 0.24 \n",
+      "d3= 0.34 \n",
+      "d4= -0.26 \n",
+      "d5= -0.16\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "D=math.sqrt((d1**2+d2**2+d3**2+d4**2+d5**2)/4.0)\n",
+      "\n",
+      "#Result\n",
+      "print\"The standard deviation is \",round(D,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The standard deviation is  0.27\n"
+       ]
+      }
+     ],
+     "prompt_number": 90
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.7 Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=600                         #Volts\n",
+      "V1=250.0                       #Volts\n",
+      "a=0.02\n",
+      "\n",
+      "#Calculation\n",
+      "M=a*V\n",
+      "E=(M/V1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"The limited error is \", E,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The limited error is  4.8 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 94
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8 (a) Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "a=0.02\n",
+      "I=500                           #mA\n",
+      "I1=300.0                         #mA\n",
+      "\n",
+      "#Calculation\n",
+      "M1=I*a\n",
+      "M2=(M1/I1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"Limiting error is \", round(M2,1),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Limiting error is  3.3 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 20
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8 (b) Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=70.0                        #Volts\n",
+      "V1=100                      #Volts\n",
+      "I=80.0                        #mA\n",
+      "I1=150                      #mA\n",
+      "a=0.015\n",
+      "\n",
+      "#calculation\n",
+      "M=a*V1\n",
+      "E=(M/V)*100\n",
+      "E1=a*I1\n",
+      "E2=(E1/I)*100\n",
+      "E3=E+E2\n",
+      "\n",
+      "#Result\n",
+      "print\"limiting error is \",round (E3,3),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "limiting error is  4.955 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 102
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap1_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap1_1.ipynb
new file mode 100755
index 00000000..40d6bd4d
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap1_1.ipynb
@@ -0,0 +1,496 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:51d805a6704370d51c8924e78b695ede1f2e0cf7db8506765ce19861dd684c21"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 1 Qualities of measurements"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1 (a) Page no 3"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=80.0                             #expected value of voltage in Volts\n",
+      "V1=79                            #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "E=V-V1\n",
+      "E1=((V-V1)/V)*100\n",
+      "E2=1-((V-V1)/V)\n",
+      "A=100*E2\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Absolute error is \",E,\"V\"\n",
+      "print\"(ii) percent error is \", E1,\"%\"\n",
+      "print\"(iii) reletive error is \", E2\n",
+      "print\"(iv) percent of accuracy is \", A,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Absolute error is  1.0 V\n",
+        "(ii) percent error is  1.25 %\n",
+        "(iii) reletive error is  0.9875\n",
+        "(iv) percent of accuracy is  98.75 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1 (b) Page no 3"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Yn=20.0                             #mA\n",
+      "Xn=18                             #mA\n",
+      "\n",
+      "#Calculation\n",
+      "e=Yn-Xn\n",
+      "E=(e/Yn)*100\n",
+      "A=1-(e/Yn)\n",
+      "a=A*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Absolute error is \", e,\"mA\"\n",
+      "print\"(ii) Percent error is \",E,\"%\"\n",
+      "print\"(iii) Relative accuracy is \",A\n",
+      "print\"(iv) Percent accuracy is \",a,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Absolute error is  2.0 mA\n",
+        "(ii) Percent error is  10.0 %\n",
+        "(iii) Relative accuracy is  0.9\n",
+        "(iv) Percent accuracy is  90.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.2 Page no 4"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=98\n",
+      "x2=101\n",
+      "x3=102\n",
+      "x4=97\n",
+      "x5=101\n",
+      "x6=100\n",
+      "x7=103\n",
+      "x8=98\n",
+      "x9=106\n",
+      "x10=99\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10.0\n",
+      "P=(x6/X)\n",
+      "\n",
+      "#Result\n",
+      "print\"Precision of the 6th measurment is \",round(P,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Precision of the 6th measurment is  0.995\n"
+       ]
+      }
+     ],
+     "prompt_number": 26
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3(a) Page no 6"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "V=80                                  #milliammeter readings\n",
+      "I=10.0                                  #mA\n",
+      "V1=150                                 #Volts\n",
+      "R1=1000                                #ohm/volt\n",
+      "\n",
+      "#Calculation\n",
+      "R=V/I\n",
+      "Rv=R1*V1\n",
+      "Rx=(R*V1)/(V1-R)\n",
+      "E=((Rx-R)/Rx)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Apparent resistance of the unknown resistance \",R,\"K ohm\"\n",
+      "print \"(ii) Actual resistance of the unknown resistance is \",round(Rx,2),\"K ohm\"\n",
+      "print \"(iii) Error due to the loading effet of the voltmeter \",round(E,1),\"%\" "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Apparent resistance of the unknown resistance  8.0 K ohm\n",
+        "(ii) Actual resistance of the unknown resistance is  8.45 K ohm\n",
+        "(iii) Error due to the loading effet of the voltmeter  5.3 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3(b) Page no 7"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=30                             #Volts\n",
+      "V1=150                           #Volts\n",
+      "I=0.6                            #A\n",
+      "R1=1000                          #ohm/volts\n",
+      "\n",
+      "#Calculation\n",
+      "R=V/I\n",
+      "Rv=(R1*V1)\n",
+      "Rx=(R*Rv)/(Rv-R)\n",
+      "E=((Rx-R)/Rx)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) total circuit resistance is \", R,\"ohm\"\n",
+      "print \"(ii) The voltmeter resistance is \",round(Rx,2)\n",
+      "print\"(iii) Error due to loading effect of voltmeter \", round(E,3),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) total circuit resistance is  50.0 ohm\n",
+        "(ii) The voltmeter resistance is  50.02\n",
+        "(iii) Error due to loading effect of voltmeter  0.033 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 113
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.4 Page no 12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=49.7\n",
+      "x2=50.1\n",
+      "x3=50.2\n",
+      "x4=49.6\n",
+      "x5=49.7\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5)/5.0\n",
+      "d1=x1-X\n",
+      "d2=x2-X\n",
+      "d3=x3-X\n",
+      "d4=x4-X\n",
+      "d5=x5-X\n",
+      "dtotal=(d1+d2+d3+d4+d5)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Arithmetic mean is \", X\n",
+      "print\"(ii) derivations from each value are\"\n",
+      "print \"d1=\",d1,\"\\nd2=\",d2,\"\\nd3=\",d3,\"\\nd4=\",d4,\"\\nd5=\",d5\n",
+      "print\"(iii) The algebric sum of derivative is \",round(dtotal,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Arithmetic mean is  49.86\n",
+        "(ii) derivations from each value are\n",
+        "d1= -0.16 \n",
+        "d2= 0.24 \n",
+        "d3= 0.34 \n",
+        "d4= -0.26 \n",
+        "d5= -0.16\n",
+        "(iii) The algebric sum of derivative is  0.0\n"
+       ]
+      }
+     ],
+     "prompt_number": 77
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.5 Page no 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "x1=49.7\n",
+      "x2=50.1\n",
+      "x3=50.2\n",
+      "x4=49.6\n",
+      "x5=49.7\n",
+      "\n",
+      "#Calculation\n",
+      "X=(x1+x2+x3+x4+x5)/5.0\n",
+      "d1=x1-X\n",
+      "d2=x2-X\n",
+      "d3=x3-X\n",
+      "d4=x4-X\n",
+      "d5=x5-X\n",
+      "dtotal=(d1+d2+d3+d4+d5)/5.0\n",
+      "\n",
+      "#Result\n",
+      "print\"The average deviation is \",round(dtotal*10**14,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The average deviation is  0.284\n"
+       ]
+      }
+     ],
+     "prompt_number": 86
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.6 Page no 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "d1= -0.16 \n",
+      "d2= 0.24 \n",
+      "d3= 0.34 \n",
+      "d4= -0.26 \n",
+      "d5= -0.16\n",
+      "\n",
+      "#Calculation\n",
+      "import math\n",
+      "D=math.sqrt((d1**2+d2**2+d3**2+d4**2+d5**2)/4.0)\n",
+      "\n",
+      "#Result\n",
+      "print\"The standard deviation is \",round(D,2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The standard deviation is  0.27\n"
+       ]
+      }
+     ],
+     "prompt_number": 90
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.7 Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=600                         #Volts\n",
+      "V1=250.0                       #Volts\n",
+      "a=0.02\n",
+      "\n",
+      "#Calculation\n",
+      "M=a*V\n",
+      "E=(M/V1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"The limited error is \", E,\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The limited error is  4.8 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 94
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8 (a) Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "a=0.02\n",
+      "I=500                           #mA\n",
+      "I1=300.0                         #mA\n",
+      "\n",
+      "#Calculation\n",
+      "M1=I*a\n",
+      "M2=(M1/I1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"Limiting error is \", round(M2,1),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Limiting error is  3.3 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 20
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8 (b) Page no 14"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=70.0                        #Volts\n",
+      "V1=100                      #Volts\n",
+      "I=80.0                        #mA\n",
+      "I1=150                      #mA\n",
+      "a=0.015\n",
+      "\n",
+      "#calculation\n",
+      "M=a*V1\n",
+      "E=(M/V)*100\n",
+      "E1=a*I1\n",
+      "E2=(E1/I)*100\n",
+      "E3=E+E2\n",
+      "\n",
+      "#Result\n",
+      "print\"limiting error is \",round (E3,3),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "limiting error is  4.955 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 102
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap2.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap2.ipynb
new file mode 100755
index 00000000..96e1d472
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap2.ipynb
@@ -0,0 +1,103 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:25c836d1606fcfdd3be702967e2c46de8c90c4ed0ada91a05ae2508868159a1c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 2 Indicators and display devices"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1 (a) Page no 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "N=100\n",
+      "W=20*10**-3                                #Width of the coil in m\n",
+      "A=30*10**-3                               #Depth of the coil in mm\n",
+      "B=0.1                                     #flux density in wb/m**2\n",
+      "I=10*10**-3                                 #current in A\n",
+      "K=2.0*10**-6                                #Nm/degree\n",
+      "\n",
+      "#Calculation\n",
+      "T=B*A*W*I*N\n",
+      "x=T/K\n",
+      "\n",
+      "#Result\n",
+      "print\"The deflection torque is \",T,\"m\"\n",
+      "print\"The deflection is \", x,\"degree\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The deflection torque is  6e-05 m\n",
+        "The deflection is  30.0 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1 (b) Page no 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "N=100\n",
+      "A=20*10**-3                               #m\n",
+      "d=30*10**-3                               #m\n",
+      "D=0.1                                     #Wb/m**2\n",
+      "t=30*10**-6                               #Nm\n",
+      "\n",
+      "#Calculation\n",
+      "I=(t/(D*d*A*N))*10**3\n",
+      "\n",
+      "#Result\n",
+      "print\"The current through the moving coil is \", I,\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The current through the moving coil is  5.0 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap2_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap2_1.ipynb
new file mode 100755
index 00000000..96e1d472
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap2_1.ipynb
@@ -0,0 +1,103 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:25c836d1606fcfdd3be702967e2c46de8c90c4ed0ada91a05ae2508868159a1c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 2 Indicators and display devices"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1 (a) Page no 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "N=100\n",
+      "W=20*10**-3                                #Width of the coil in m\n",
+      "A=30*10**-3                               #Depth of the coil in mm\n",
+      "B=0.1                                     #flux density in wb/m**2\n",
+      "I=10*10**-3                                 #current in A\n",
+      "K=2.0*10**-6                                #Nm/degree\n",
+      "\n",
+      "#Calculation\n",
+      "T=B*A*W*I*N\n",
+      "x=T/K\n",
+      "\n",
+      "#Result\n",
+      "print\"The deflection torque is \",T,\"m\"\n",
+      "print\"The deflection is \", x,\"degree\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The deflection torque is  6e-05 m\n",
+        "The deflection is  30.0 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1 (b) Page no 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "N=100\n",
+      "A=20*10**-3                               #m\n",
+      "d=30*10**-3                               #m\n",
+      "D=0.1                                     #Wb/m**2\n",
+      "t=30*10**-6                               #Nm\n",
+      "\n",
+      "#Calculation\n",
+      "I=(t/(D*d*A*N))*10**3\n",
+      "\n",
+      "#Result\n",
+      "print\"The current through the moving coil is \", I,\"mA\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The current through the moving coil is  5.0 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap3.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap3.ipynb
new file mode 100755
index 00000000..f0592fc1
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap3.ipynb
@@ -0,0 +1,195 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:607025d5b183f599aab55f55aee44964f766dd94a0ecfa331fb5c9e733e05bf7"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 3 Ammeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.1 (a) Page no 65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100                               #ohm\n",
+      "Im=1*10**-3                          #A\n",
+      "I=100*10**-3\n",
+      "\n",
+      "#Calculation\n",
+      "Rsh=Im*R/(I-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of shunt resistance is \", round(Rsh,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of shunt resistance is  1.01 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.1 (b) Page no 65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=100.0*10**-6                         #A\n",
+      "Rm=500                                  #ohm\n",
+      "I=100*10**-3                            #A\n",
+      "\n",
+      "#calculation\n",
+      "n=I/Im\n",
+      "Rsh=Rm/(n-1)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of required shunt is \", round(Rsh,2),\"ohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of required shunt is  0.5 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.2 Page no  66"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=10.0*10**-3                             #A\n",
+      "Im=1.0*10**-3                             #A\n",
+      "Rm=100                                    #ohm\n",
+      "I1=20.0*10**-3\n",
+      "I2=50.0*10**-3\n",
+      "\n",
+      "#Calculation\n",
+      "# For the range of 0-10 mA\n",
+      "Rsh1=(Im*Rm)/(I-Im) \n",
+      "\n",
+      "# For the range of 0-20 mA\n",
+      "Rsh2=(Im*Rm)/(I1-Im) \n",
+      "\n",
+      "# For the range of 0-50 mA\n",
+      "Rsh3=(Im*Rm)/(I2-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of the shunt resistance required for the range 0-10 mA\", round(Rsh1,2),\"ohm\"\n",
+      "print\"The value of the shunt resistance required for the range 0-20 mA\", round(Rsh2,1),\"ohm\"\n",
+      "print\"The value of the shunt resistance required for the range 0-50 mA\", round(Rsh3,3),\"ohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of the shunt resistance required for the range 0-10 mA 11.11 ohm\n",
+        "The value of the shunt resistance required for the range 0-20 mA 5.3 ohm\n",
+        "The value of the shunt resistance required for the range 0-50 mA 2.041 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.3 page no 67"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10.0*10**-3                          #A\n",
+      "Rm=500                                  #ohm\n",
+      "I=1000.0*10**-3                         #A\n",
+      "I1=5000.0*10**-3                        #A\n",
+      "I2=10000.0*10**-3                       #A\n",
+      "\n",
+      "#Calculation\n",
+      "# For the range of 0-1A, i.e, 1000mA\n",
+      "Rsh1=(Im*Rm)/(I-Im)  \n",
+      "\n",
+      "# For the range of 0-5A, i.e, 5000mA\n",
+      "Rsh2=(Im*Rm)/(I1-Im) \n",
+      "\n",
+      "# For the range of 0-10A, i.e, 10000mA\n",
+      "Rsh3=(Im*Rm)/(I2-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of shunt resistance for the range 0-1A\", round(Rsh1,2),\"ohm\"\n",
+      "print\"The value of shunt resistance for the range 0-5A\", round(Rsh2,3),\"ohm\"\n",
+      "print\"The value of shunt resistance for the range 0-10A\", round(Rsh3*10**-1,3),\"ohm\"\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of shunt resistance for the range 0-1A 5.05 ohm\n",
+        "The value of shunt resistance for the range 0-5A 1.002 ohm\n",
+        "The value of shunt resistance for the range 0-10A 0.05 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap3_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap3_1.ipynb
new file mode 100755
index 00000000..f0592fc1
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap3_1.ipynb
@@ -0,0 +1,195 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:607025d5b183f599aab55f55aee44964f766dd94a0ecfa331fb5c9e733e05bf7"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 3 Ammeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.1 (a) Page no 65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100                               #ohm\n",
+      "Im=1*10**-3                          #A\n",
+      "I=100*10**-3\n",
+      "\n",
+      "#Calculation\n",
+      "Rsh=Im*R/(I-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of shunt resistance is \", round(Rsh,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of shunt resistance is  1.01 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.1 (b) Page no 65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=100.0*10**-6                         #A\n",
+      "Rm=500                                  #ohm\n",
+      "I=100*10**-3                            #A\n",
+      "\n",
+      "#calculation\n",
+      "n=I/Im\n",
+      "Rsh=Rm/(n-1)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of required shunt is \", round(Rsh,2),\"ohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of required shunt is  0.5 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.2 Page no  66"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=10.0*10**-3                             #A\n",
+      "Im=1.0*10**-3                             #A\n",
+      "Rm=100                                    #ohm\n",
+      "I1=20.0*10**-3\n",
+      "I2=50.0*10**-3\n",
+      "\n",
+      "#Calculation\n",
+      "# For the range of 0-10 mA\n",
+      "Rsh1=(Im*Rm)/(I-Im) \n",
+      "\n",
+      "# For the range of 0-20 mA\n",
+      "Rsh2=(Im*Rm)/(I1-Im) \n",
+      "\n",
+      "# For the range of 0-50 mA\n",
+      "Rsh3=(Im*Rm)/(I2-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of the shunt resistance required for the range 0-10 mA\", round(Rsh1,2),\"ohm\"\n",
+      "print\"The value of the shunt resistance required for the range 0-20 mA\", round(Rsh2,1),\"ohm\"\n",
+      "print\"The value of the shunt resistance required for the range 0-50 mA\", round(Rsh3,3),\"ohm\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of the shunt resistance required for the range 0-10 mA 11.11 ohm\n",
+        "The value of the shunt resistance required for the range 0-20 mA 5.3 ohm\n",
+        "The value of the shunt resistance required for the range 0-50 mA 2.041 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3.3 page no 67"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10.0*10**-3                          #A\n",
+      "Rm=500                                  #ohm\n",
+      "I=1000.0*10**-3                         #A\n",
+      "I1=5000.0*10**-3                        #A\n",
+      "I2=10000.0*10**-3                       #A\n",
+      "\n",
+      "#Calculation\n",
+      "# For the range of 0-1A, i.e, 1000mA\n",
+      "Rsh1=(Im*Rm)/(I-Im)  \n",
+      "\n",
+      "# For the range of 0-5A, i.e, 5000mA\n",
+      "Rsh2=(Im*Rm)/(I1-Im) \n",
+      "\n",
+      "# For the range of 0-10A, i.e, 10000mA\n",
+      "Rsh3=(Im*Rm)/(I2-Im)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of shunt resistance for the range 0-1A\", round(Rsh1,2),\"ohm\"\n",
+      "print\"The value of shunt resistance for the range 0-5A\", round(Rsh2,3),\"ohm\"\n",
+      "print\"The value of shunt resistance for the range 0-10A\", round(Rsh3*10**-1,3),\"ohm\"\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of shunt resistance for the range 0-1A 5.05 ohm\n",
+        "The value of shunt resistance for the range 0-5A 1.002 ohm\n",
+        "The value of shunt resistance for the range 0-10A 0.05 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap4.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap4.ipynb
new file mode 100755
index 00000000..c74b96bf
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap4.ipynb
@@ -0,0 +1,1235 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:6894c833baa0eedea1946bb8c106382f5457dd2d09fc25376fba7e033019797b"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 4 Voltmeters and multimeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.1 Page no 80"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=200.0*10**-6                               # A\n",
+      "\n",
+      "#calculation\n",
+      "s=(1/I)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Sensitivity is \", s,\"Kohm/V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Sensitivity is  5.0 Kohm/V\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.2 (a) Page no 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=10                               #Volt\n",
+      "Im=50.0*10**-6                       #A\n",
+      "Rm=500                             #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R=((V/Im)-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Reading of resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Reading of resistance is  199.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.2 (b) Page no 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=500.0*10**-6                       #A\n",
+      "V=50                                  #Volts\n",
+      "Rm=1*10**3                            #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/Im\n",
+      "Rs=(S*V)-Rm\n",
+      "\n",
+      "\n",
+      "print\"The value of multiplier resistance is \", Rs*10**-3,\"K ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  99.0 K ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.3 Page no 82"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "Im=50.0*10**-6                   #A\n",
+      "Rm=500.0                         #ohm\n",
+      "V=20                           #Volts\n",
+      "V1=50                          #volts\n",
+      "V2=100                         #volts\n",
+      "\n",
+      "#Calculation\n",
+      "# For range 0-20 V\n",
+      "Rs=V/(Im)-Rm\n",
+      "\n",
+      "# for range 0-50 V\n",
+      "Rs1=V1/(Im)-Rm\n",
+      "\n",
+      "# for the range of 0-100 V\n",
+      "Rs2=V2/(Im)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier required for 0-20 V is \", Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-50 V is \", Rs1*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-100 V is \", Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier required for 0-20 V is  399.5 Kohm\n",
+        "The value of multiplier required for 0-50 V is  999.5 Kohm\n",
+        "The value of multiplier required for 0-100 V is  1999.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.4 Page no 82"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10*10**-3                       #A\n",
+      "Rm=500                             #ohm\n",
+      "V=20                           #Volts\n",
+      "V1=50                          #volts\n",
+      "V2=100                         #volts\n",
+      "\n",
+      "#Calculation\n",
+      "# For range 0-20 V\n",
+      "Rs=V/(Im)-Rm\n",
+      "\n",
+      "# for range 0-50 V\n",
+      "Rs1=V1/(Im)-Rm\n",
+      "\n",
+      "# for the range of 0-100 V\n",
+      "Rs2=V2/(Im)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier required for 0-20 V is \", Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-50 V is \", Rs1*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-100 V is \", Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier required for 0-20 V is  1.5 Kohm\n",
+        "The value of multiplier required for 0-50 V is  4.5 Kohm\n",
+        "The value of multiplier required for 0-100 V is  9.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 25
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.5 Page no 83"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10.0*10**-3                                #A\n",
+      "Rm=100                                      #ohm\n",
+      "V=5                                         #Volts\n",
+      "V1=50                                       #Volts\n",
+      "V2=100                                      #volts\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=V/Im\n",
+      "R3=Rt-Rm\n",
+      "Rt1=V1/Im\n",
+      "R2=Rt1-(R3+Rm)\n",
+      "Rt2=V2/Im\n",
+      "R1=Rt2-(R2+R3+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\" R1= \", R1*10**-3,\"Kohm\",\"\\n R2= \",R2*10**-3,\"Kohm\",\"\\n R3= \",R3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " R1=  5.0 Kohm \n",
+        " R2=  4.5 Kohm \n",
+        " R3=  400.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 39
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.6 Page no 83"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=10                                #Volts\n",
+      "I=2.0*10**-3                          #A\n",
+      "Rm=50                                #ohm\n",
+      "V1=50                               #Volts\n",
+      "V2=100                              #Volts\n",
+      "V3=250                              #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=(V/I)\n",
+      "R4=(Rt-Rm)\n",
+      "Rt1=V1/I\n",
+      "R3=Rt1-(R4+Rm)\n",
+      "Rt2=V2/I\n",
+      "R2=Rt2-(R3+R4+Rm)\n",
+      "Rt3=V3/I\n",
+      "R1=Rt3-(R2+R3+R4+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistances are  R1=\", R1*10**-3,\"Kohm \",\"\\n R2=\",R2*10**-3,\"Kohm\",\"\\n R3=\",R3*10**-3,\"Kohm\",\"\\n R4=\",R4,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistances are  R1= 75.0 Kohm  \n",
+        " R2= 25.0 Kohm \n",
+        " R3= 20.0 Kohm \n",
+        " R4= 4950.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.7 Page no 85"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=200.0*10**-6                               #A\n",
+      "V=50                                         #v\n",
+      "Rm=100                                       #ohm\n",
+      "\n",
+      "#Calculation \n",
+      "S=(1/I)\n",
+      "Rs=((S*V)-Rm)*10**-3\n",
+      "\n",
+      "#Result \n",
+      "print\"The value of multiplier resistance is \", Rs,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  249.9 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 48
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.8 Page no 85"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=50.0*10**-6                                     #A\n",
+      "V=5                                              #Volts\n",
+      "Rm=1000                                          #ohm\n",
+      "V1=10                                             #volts\n",
+      "V2=50\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/I\n",
+      "# for 5 volt range\n",
+      "Rs1=((S*V)-Rm)*10**-3\n",
+      "\n",
+      "# for 10 volt range \n",
+      "Rs2=((S*V1)-Rm)*10**-3\n",
+      "\n",
+      "# for 50 volt range\n",
+      "Rs3=((S*V2)-Rm)*10**-3\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs1,\"Kohm\"\n",
+      "print\"The value of multiplier resistance is \", Rs2,\"Kohm\"\n",
+      "print\"The value of multiplier resistance is \", Rs3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  99.0 Kohm\n",
+        "The value of multiplier resistance is  199.0 Kohm\n",
+        "The value of multiplier resistance is  999.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.9 Page no 86"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=50.0*10**-6                             #A\n",
+      "V=3                                        #volts\n",
+      "V1=10                                      #Volts\n",
+      "V2=30                                      #Volts\n",
+      "Rm=1000                                    #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/Im\n",
+      "Rs=S*V-Rm\n",
+      "Rs1=S*V1-Rm\n",
+      "Rs2=S*V2-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \",\"\\n Rs1= \", Rs*10**-3,\"Kohm \\n Rs2= \",Rs1*10**-3,\"Kohm \\n Rs3= \",Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  \n",
+        " Rs1=  59.0 Kohm \n",
+        " Rs2=  199.0 Kohm \n",
+        " Rs3=  599.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.10 Page no 86"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given \n",
+      "Im=20.0*10**-3                               #A\n",
+      "v=100*10**-3                               #volts\n",
+      "I=50000*10**3                               #A\n",
+      "V=500                                       #Volts\n",
+      "\n",
+      "Rm=v/Im\n",
+      "Rsh=(Im*Rm)/(I-Im)\n",
+      "Rsh1=(V/Im)-Rm\n",
+      "P=V*Im\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Shunt resistance is \", round(Rsh1*10**-3,0),\"Kohm\"\n",
+      "print\"(ii) Power dissipation is \",P,\"Watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Shunt resistance is  25.0 Kohm\n",
+        "(ii) Power dissipation is  10.0 Watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.11 Page no 87"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=100                                            #Volts\n",
+      "s=1000                                            #ohm/V\n",
+      "R=10.0*10**3                                    #kohm\n",
+      "R1=10.0*10**3                                      #kohm\n",
+      "s2=20000                                          #ohm/V\n",
+      "\n",
+      "#Calculation\n",
+      "V2=(R/(R1+R))*V\n",
+      "\n",
+      "#case 1\n",
+      "R2=V2*s\n",
+      "Req=(R*R2)/(R+R2)\n",
+      "V1=(Req/(R1+Req))*V\n",
+      "\n",
+      "#case 2\n",
+      "R3=V2*s2\n",
+      "Req2=(R1*R3)/(R1+R3)\n",
+      "V12=(Req2/(R1+Req2))*V\n",
+      "\n",
+      "#Result\n",
+      "print\"(a) voltmeter indicates \", round(V1,2),\"V\"\n",
+      "print\"(b) Voltmeter will read \",round(V12,2),\"V\"\n",
+      "print\"This example shows that a high sensitivity voltmeter Should be used to get accurate reading\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(a) voltmeter indicates  45.45 V\n",
+        "(b) Voltmeter will read  49.75 V\n",
+        "This example shows that a high sensitivity voltmeter Should be used to get accurate reading\n"
+       ]
+      }
+     ],
+     "prompt_number": 39
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.12 Page no 88"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "s=1*10**3                                  #ohm/V\n",
+      "Rm=0.2*10**3                         #ohm\n",
+      "V=10                                 #Volts\n",
+      "s1=20*10**3                           #ohm/volt\n",
+      "Rm1=1.5*10**3                           #ohm\n",
+      "R0=5.0*10**3                              #ohm\n",
+      "R1=25.0*10**3                             #ohm\n",
+      "V1=30                                   #Volt\n",
+      "\n",
+      "#Calculation\n",
+      "VRb=(R0/(R1+R0))*V1\n",
+      "Rm2=s*V\n",
+      "Req=(R0*Rm2)/(R0+Rm2)\n",
+      "VRb2=Req/(Req+R1)*V1\n",
+      "Rm3=s1*V\n",
+      "Req2=(R0*Rm3)/(R0+Rm3)\n",
+      "VRb3=(Req2/(R1+Req2))*V1\n",
+      "E1=((VRb-3.33)/VRb)*100\n",
+      "E2=((VRb-VRb3)/VRb)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Voltage across Rb without any meter across it \", VRb,\"Volt\"\n",
+      "print\"(ii) Voltage across Rb when the meter 1 is used \", round(VRb2,2),\"Volt\"\n",
+      "print\"(iii) voltage across arb when the meter 2 is used \", round(VRb3,1),\"Volts\"\n",
+      "print\"(iv) Error in voltmeter when meter 1 is used \", E1,\"%\"\n",
+      "print\"     Error in voltmeter when meter 2 is used \",round(E2,0),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Voltage across Rb without any meter across it  5.0 Volt\n",
+        "(ii) Voltage across Rb when the meter 1 is used  3.53 Volt\n",
+        "(iii) voltage across arb when the meter 2 is used  4.9 Volts\n",
+        "(iv) Error in voltmeter when meter 1 is used  33.4 %\n",
+        "     Error in voltmeter when meter 2 is used  2.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.13 Page no 89"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=5.0                          #Volt \n",
+      "V2=10                         #Volt\n",
+      "V3=30                         #Volt\n",
+      "S=20*10**3                    #ohm/V\n",
+      "Rb=5.0*10**3                    #ohm\n",
+      "Ra=45.0*10**3                   #ohm\n",
+      "V=50                          #Volt\n",
+      "\n",
+      "#Calculation\n",
+      "VRb=Rb/(Ra+Rb)*V\n",
+      "Rm=S*V1\n",
+      "Req=(Rm*Rb)/(Rm+Rb)\n",
+      "VRb1=Req/(Ra+Req)*V\n",
+      "E=((V1-VRb1)/V1)*100\n",
+      "Rm1=S*V2\n",
+      "Req1=(Rm1*Rb)/(Rm1+Rb)\n",
+      "VRb2=(Req1/(Req1+Ra))*V\n",
+      "E1=((V1-VRb2)/V1)*100\n",
+      "Rm2=S*V3\n",
+      "Req2=(Rm2*Rb)/(Rm2+Rb)\n",
+      "VRb3=Req2/(Req2+Ra)*V\n",
+      "E2=((V1-VRb3)/V1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Voltage reading with a voltmeter on 5 volt \" ,round(VRb1,3),\"Volts\",\"\\n percent error is \",round(E,2),\"%\"\n",
+      "print\"(ii) Voltage reading with a voltmeter on 10 volt\", round(VRb2,2),\"Volts\",\"\\n percent error is \",round(E1,2),\"%\"\n",
+      "print\"(iii) Voltage reading with a voltmeter on 10 volt\", round(VRb3,2),\"Volts\",\"\\n percent error is \",round(E,2),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Voltage reading with a voltmeter on 5 volt  4.785 Volts \n",
+        " percent error is  4.31 %\n",
+        "(ii) Voltage reading with a voltmeter on 10 volt 4.89 Volts \n",
+        " percent error is  2.2 %\n",
+        "(iii) Voltage reading with a voltmeter on 10 volt 4.96 Volts \n",
+        " percent error is  1.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 90
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.14 Page no 90"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=1000                              #ohm\n",
+      "R2=1000.0                             #ohm\n",
+      "R3=1000.0                              #ohm\n",
+      "Rm=100                               #ohm\n",
+      "I=1                                  #A\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=(R1)+((R2*R3)/(R2+R3)) \n",
+      "Im=(((Rt)/(Rt+Rm))*I)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"Percent reading due to ammeter loading \", round(Im,1),\"%\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Percent reading due to ammeter loading  93.8 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.15 Page no 100"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=1.0*10**-3                         #A\n",
+      "Erms=10                              #Volts\n",
+      "V=0.45                               #Volts\n",
+      "Rm=200                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/I\n",
+      "R=(S*V*Erms-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of multiplier resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of multiplier resistance is  4.3 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 98
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.16 Page no 101"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100.0*10**-6                           #A\n",
+      "V=0.45                                    #Volts\n",
+      "Rm=500                                    #ohm\n",
+      "Erms=100\n",
+      "\n",
+      "#calculation\n",
+      "Sdc=1/Ifsd\n",
+      "Rs=(Sdc*V*100)-Rm\n",
+      "Rs1=((0.45*Erms)/Ifsd)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs1*10**-3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  449.5 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.17 Page no 102"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100.0*10**-6                              #A\n",
+      "Rm=100                                       #ohm\n",
+      "V=50                                           #Vrms\n",
+      "\n",
+      "#Calculation\n",
+      "Sdc=1/Ifsd\n",
+      "Sac=0.9*Sdc\n",
+      "Rs=Sac*V-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  449.9 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.18 Page no 102"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=1.0*10**-3                                #A\n",
+      "V=10                                 #volts\n",
+      "Rm=250                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Sdc=1/I\n",
+      "Sac=0.9*Sdc\n",
+      "R=(Sac*V-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of multiplier resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of multiplier resistance is  8.75 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 103
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.19 Page no 103"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100*10**-6                              #A\n",
+      "V=10.0                                         #Volts\n",
+      "R2=10.0*10**3                                 #ohm\n",
+      "Rm=100*10**3                                #ohm\n",
+      "R1=10.0*10**3                                 #ohm\n",
+      "\n",
+      "Sdc=1/Ifsd\n",
+      "Rs=Sdc*V\n",
+      "Req=(R2*Rm)/(R2+Rm)\n",
+      "ER2=Req/(R1+Req)\n",
+      "Shw=0.45*Sdc\n",
+      "Rs1=Shw*V\n",
+      "Req1=(R2*Rs1)/(R2+Rs1)\n",
+      "E=Req1/(R1+Req1)\n",
+      "Sfw=(0.90*Sdc)\n",
+      "Rs2=Sfw*V\n",
+      "Req2=(R2*Rs2)/(R2+Rs2)\n",
+      "E=(Req2/(R1+Req2))*V\n",
+      "\n",
+      "#Result\n",
+      "print\"Sensitivity is \",Sdc*10**-3,\"Kohm/volt\"\n",
+      "print\"Multiplier resistance is \",Rs*10**-3,\"Kohm\"\n",
+      "print\"The voltage across R2 is \",round(ER2*10**1,2),\"Volts\"\n",
+      "print\"Resistance using Half wave rectifier \",Rs1*10**-3,\"Kohm\"\n",
+      "print\"Voltage by AC voltmeter is \",round(E,2),\"Volts\"\n",
+      "print\"Resistance using full wave rectifier \",Rs2*10**-3,\"Kohm\"\n",
+      "print\"Voltage by DC voltmeter is \",round(E,2),\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Sensitivity is  10.0 Kohm/volt\n",
+        "Multiplier resistance is  100.0 Kohm\n",
+        "The voltage across R2 is  4.76 Volts\n",
+        "Resistance using Half wave rectifier  45.0 Kohm\n",
+        "Voltage by AC voltmeter is  4.74 Volts\n",
+        "Resistance using full wave rectifier  90.0 Kohm\n",
+        "Voltage by DC voltmeter is  4.74 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.20 Page no 113"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=1*10**-3                        #A\n",
+      "Rm=100                             #ohm\n",
+      "Rh=1*10**3                         #ohm\n",
+      "V=3.0                               #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R1=Rh-(Im*Rm*Rh)/V\n",
+      "R2=(Im*Rm*Rh)/(V-Im*Rh)\n",
+      "V1=3-0.09\n",
+      "R21=(Im*Rm*Rh)/(V1-Im*Rh)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1= \",round(R1,2),\"ohm\",\" \\n    Value of R2= \",round(R2,2),\"ohm\"\n",
+      "print\"(ii) Maximum value of R2 to compensate for a 3% Drop in Battery Voltage \",round(R21,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1=  966.67 ohm  \n",
+        "    Value of R2=  50.0 ohm\n",
+        "(ii) Maximum value of R2 to compensate for a 3% Drop in Battery Voltage  52.36 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.21 Page no 113"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Rh=2000.0                       #ohm\n",
+      "Ifsd=1*10**-3                   #A\n",
+      "Rm=100                        #ohm\n",
+      "V=3.0                            #Volts\n",
+      "V1=2.58                           #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R1=Rh-((Ifsd*Rm*Rh)/V)\n",
+      "R2=(Ifsd*Rm*Rh)/(V-(Ifsd*Rh))\n",
+      "R21=(Ifsd*Rm*Rh)/(V1-(Ifsd*Rh))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1=\",round(R1,1),\"Ohm and Value of R2=\",R2,\"Ohm\" \n",
+      "print\"The maximum value of R2 is \",round(R21,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1= 1933.3 Ohm and Value of R2= 200.0 Ohm\n",
+        "The maximum value of R2 is  344.83 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.22 Page no 114"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=3                      #volts\n",
+      "Im=1.0*10**-3               #A\n",
+      "Rm=100                    #ohm\n",
+      "P=0.2 \n",
+      "P1=0.4\n",
+      "P2=0.5 \n",
+      "P3=0.75\n",
+      "P4=0.9\n",
+      "P5=1\n",
+      "\n",
+      "#calculation\n",
+      "Rs=(V/Im)-Rm\n",
+      "Rx=((Rs+Rm)/P)-(Rs+Rm)\n",
+      "Rx1=((Rs+Rm)/P1)-(Rs+Rm)\n",
+      "Rx2=((Rs+Rm)/P2)-(Rs+Rm)\n",
+      "Rx3=((Rs+Rm)/P3)-(Rs+Rm)\n",
+      "Rx4=((Rs+Rm)/P4)-(Rs+Rm)\n",
+      "Rx5=((Rs+Rm)/P5)-(Rs+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of Rs is \",Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 20% detection is \",Rx*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 40% detection is \",Rx1*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 50% detection is \",Rx2*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 75% detection is \",Rx3*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 90% detection is \",round(Rx4*10**-3,3),\"Kohm\"\n",
+      "print\"The value of Rx with 100% detection is \",Rx5*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of Rs is  2.9 Kohm\n",
+        "The value of Rx with 20% detection is  12.0 Kohm\n",
+        "The value of Rx with 40% detection is  4.5 Kohm\n",
+        "The value of Rx with 50% detection is  3.0 Kohm\n",
+        "The value of Rx with 75% detection is  1.0 Kohm\n",
+        "The value of Rx with 90% detection is  0.333 Kohm\n",
+        "The value of Rx with 100% detection is  0.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 40
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.23 Page no 115"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=3.0                       #Volts\n",
+      "I=1.0*10**-3                #A\n",
+      "V1=2.8\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=V/I\n",
+      "Rt1=V1/I\n",
+      "E=((V-V1)/V)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"The resulting error is \", round(E,2),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resulting error is  6.67 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 47
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.24 Page no 116"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=1*10**-3                    #A\n",
+      "Rm=100.0                         #ohm\n",
+      "Rh=2000                        #ohm\n",
+      "V=3.0                            #Volts\n",
+      "V1=2.7                            #Volts\n",
+      "V2=3.1                            #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(Im*Rh*Rm)/(V-Im*Rh)\n",
+      "R1=Rh-R2*Rm/R2+Rm\n",
+      "R21=(Im*Rh*Rm)/(V1-Im*Rh)\n",
+      "R22=(Im*Rh*Rm)/(V2-Im*Rh)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1=\",R1-66.6,\"ohm and the value of R2=\",R2,\"ohm\"\n",
+      "print\"(ii) The value of R2 when battery is 2.7 V is \",round(R21,0),\"ohm\"\n",
+      "print\"     The value of R2 when battery is 3.1 V is \",round(R22,0),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1= 1933.4 ohm and the value of R2= 200.0 ohm\n",
+        "(ii) The value of R2 when battery is 2.7 V is  286.0 ohm\n",
+        "     The value of R2 when battery is 3.1 V is  182.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 72
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.25 Page no 118"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=0.5                          #mA\n",
+      "Im=10                          #mA\n",
+      "Rm=50                          #ohm\n",
+      "Rh=10.0                          #ohm\n",
+      "V=3                              #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "Ih=I*Im\n",
+      "Vm=Ih*Rm\n",
+      "Ix=Vm/Rh\n",
+      "Ish=Ix-Ih\n",
+      "Rsh=Vm/Ish\n",
+      "It=Ix+Ih+Ish\n",
+      "V1=V-Vm*10**-3\n",
+      "R1=V1/It\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of shunt resistance is \", Rsh,\"ohm\"\n",
+      "print\"(ii) Value of current limiting resistance is \", R1*10**3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of shunt resistance is  12.5 ohm\n",
+        "(ii) Value of current limiting resistance is  55.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 93
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.26 Page no 119"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=3\n",
+      "R1=10.0                   #ohm\n",
+      "R2=20.0                    #ohm\n",
+      "R3=30.0*10**3                #ohm\n",
+      "R11=100.0                  #ohm\n",
+      "R22=200.0                   #ohm\n",
+      "R12=1000                    #ohm\n",
+      "R21=2000.0                   #ohm\n",
+      "\n",
+      "V=I*(R1/(R1+R2))\n",
+      "Im=V/R3\n",
+      "V1=I*(R11/(R11+R22))\n",
+      "Im1=V1/R3\n",
+      "V2=I*(R12/(R12+R21))\n",
+      "Im2=V2/R3\n",
+      "print\"(a) Current through the micrometer is \", round(Im*10**6,1),\"micro A\"\n",
+      "print\"(b) The current flows through the meter movement when a 200 ohm resistor is measured \",round (Im1*10**6,1),\"micro A\"\n",
+      "print\"(b) The current flows through the meter movement when a 2 Kohm resistor is measured\",round (Im1*10**6,1),\"micro A\" "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(a) Current through the micrometer is  33.3 micro A\n",
+        "(b) The current flows through the meter movement when a 200 ohm resistor is measured  33.3 micro A\n",
+        "(b) The current flows through the meter movement when a 2 Kohm resistor is measured 33.3 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 114
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap4_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap4_1.ipynb
new file mode 100755
index 00000000..c74b96bf
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap4_1.ipynb
@@ -0,0 +1,1235 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:6894c833baa0eedea1946bb8c106382f5457dd2d09fc25376fba7e033019797b"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 4 Voltmeters and multimeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.1 Page no 80"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=200.0*10**-6                               # A\n",
+      "\n",
+      "#calculation\n",
+      "s=(1/I)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Sensitivity is \", s,\"Kohm/V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Sensitivity is  5.0 Kohm/V\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.2 (a) Page no 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=10                               #Volt\n",
+      "Im=50.0*10**-6                       #A\n",
+      "Rm=500                             #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "R=((V/Im)-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Reading of resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Reading of resistance is  199.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.2 (b) Page no 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=500.0*10**-6                       #A\n",
+      "V=50                                  #Volts\n",
+      "Rm=1*10**3                            #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/Im\n",
+      "Rs=(S*V)-Rm\n",
+      "\n",
+      "\n",
+      "print\"The value of multiplier resistance is \", Rs*10**-3,\"K ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  99.0 K ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.3 Page no 82"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "Im=50.0*10**-6                   #A\n",
+      "Rm=500.0                         #ohm\n",
+      "V=20                           #Volts\n",
+      "V1=50                          #volts\n",
+      "V2=100                         #volts\n",
+      "\n",
+      "#Calculation\n",
+      "# For range 0-20 V\n",
+      "Rs=V/(Im)-Rm\n",
+      "\n",
+      "# for range 0-50 V\n",
+      "Rs1=V1/(Im)-Rm\n",
+      "\n",
+      "# for the range of 0-100 V\n",
+      "Rs2=V2/(Im)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier required for 0-20 V is \", Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-50 V is \", Rs1*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-100 V is \", Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier required for 0-20 V is  399.5 Kohm\n",
+        "The value of multiplier required for 0-50 V is  999.5 Kohm\n",
+        "The value of multiplier required for 0-100 V is  1999.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.4 Page no 82"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10*10**-3                       #A\n",
+      "Rm=500                             #ohm\n",
+      "V=20                           #Volts\n",
+      "V1=50                          #volts\n",
+      "V2=100                         #volts\n",
+      "\n",
+      "#Calculation\n",
+      "# For range 0-20 V\n",
+      "Rs=V/(Im)-Rm\n",
+      "\n",
+      "# for range 0-50 V\n",
+      "Rs1=V1/(Im)-Rm\n",
+      "\n",
+      "# for the range of 0-100 V\n",
+      "Rs2=V2/(Im)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier required for 0-20 V is \", Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-50 V is \", Rs1*10**-3,\"Kohm\"\n",
+      "print\"The value of multiplier required for 0-100 V is \", Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier required for 0-20 V is  1.5 Kohm\n",
+        "The value of multiplier required for 0-50 V is  4.5 Kohm\n",
+        "The value of multiplier required for 0-100 V is  9.5 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 25
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.5 Page no 83"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=10.0*10**-3                                #A\n",
+      "Rm=100                                      #ohm\n",
+      "V=5                                         #Volts\n",
+      "V1=50                                       #Volts\n",
+      "V2=100                                      #volts\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=V/Im\n",
+      "R3=Rt-Rm\n",
+      "Rt1=V1/Im\n",
+      "R2=Rt1-(R3+Rm)\n",
+      "Rt2=V2/Im\n",
+      "R1=Rt2-(R2+R3+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\" R1= \", R1*10**-3,\"Kohm\",\"\\n R2= \",R2*10**-3,\"Kohm\",\"\\n R3= \",R3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " R1=  5.0 Kohm \n",
+        " R2=  4.5 Kohm \n",
+        " R3=  400.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 39
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.6 Page no 83"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=10                                #Volts\n",
+      "I=2.0*10**-3                          #A\n",
+      "Rm=50                                #ohm\n",
+      "V1=50                               #Volts\n",
+      "V2=100                              #Volts\n",
+      "V3=250                              #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=(V/I)\n",
+      "R4=(Rt-Rm)\n",
+      "Rt1=V1/I\n",
+      "R3=Rt1-(R4+Rm)\n",
+      "Rt2=V2/I\n",
+      "R2=Rt2-(R3+R4+Rm)\n",
+      "Rt3=V3/I\n",
+      "R1=Rt3-(R2+R3+R4+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\"Resistances are  R1=\", R1*10**-3,\"Kohm \",\"\\n R2=\",R2*10**-3,\"Kohm\",\"\\n R3=\",R3*10**-3,\"Kohm\",\"\\n R4=\",R4,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Resistances are  R1= 75.0 Kohm  \n",
+        " R2= 25.0 Kohm \n",
+        " R3= 20.0 Kohm \n",
+        " R4= 4950.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.7 Page no 85"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=200.0*10**-6                               #A\n",
+      "V=50                                         #v\n",
+      "Rm=100                                       #ohm\n",
+      "\n",
+      "#Calculation \n",
+      "S=(1/I)\n",
+      "Rs=((S*V)-Rm)*10**-3\n",
+      "\n",
+      "#Result \n",
+      "print\"The value of multiplier resistance is \", Rs,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  249.9 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 48
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.8 Page no 85"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=50.0*10**-6                                     #A\n",
+      "V=5                                              #Volts\n",
+      "Rm=1000                                          #ohm\n",
+      "V1=10                                             #volts\n",
+      "V2=50\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/I\n",
+      "# for 5 volt range\n",
+      "Rs1=((S*V)-Rm)*10**-3\n",
+      "\n",
+      "# for 10 volt range \n",
+      "Rs2=((S*V1)-Rm)*10**-3\n",
+      "\n",
+      "# for 50 volt range\n",
+      "Rs3=((S*V2)-Rm)*10**-3\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs1,\"Kohm\"\n",
+      "print\"The value of multiplier resistance is \", Rs2,\"Kohm\"\n",
+      "print\"The value of multiplier resistance is \", Rs3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  99.0 Kohm\n",
+        "The value of multiplier resistance is  199.0 Kohm\n",
+        "The value of multiplier resistance is  999.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.9 Page no 86"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=50.0*10**-6                             #A\n",
+      "V=3                                        #volts\n",
+      "V1=10                                      #Volts\n",
+      "V2=30                                      #Volts\n",
+      "Rm=1000                                    #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/Im\n",
+      "Rs=S*V-Rm\n",
+      "Rs1=S*V1-Rm\n",
+      "Rs2=S*V2-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \",\"\\n Rs1= \", Rs*10**-3,\"Kohm \\n Rs2= \",Rs1*10**-3,\"Kohm \\n Rs3= \",Rs2*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  \n",
+        " Rs1=  59.0 Kohm \n",
+        " Rs2=  199.0 Kohm \n",
+        " Rs3=  599.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.10 Page no 86"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given \n",
+      "Im=20.0*10**-3                               #A\n",
+      "v=100*10**-3                               #volts\n",
+      "I=50000*10**3                               #A\n",
+      "V=500                                       #Volts\n",
+      "\n",
+      "Rm=v/Im\n",
+      "Rsh=(Im*Rm)/(I-Im)\n",
+      "Rsh1=(V/Im)-Rm\n",
+      "P=V*Im\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Shunt resistance is \", round(Rsh1*10**-3,0),\"Kohm\"\n",
+      "print\"(ii) Power dissipation is \",P,\"Watt\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Shunt resistance is  25.0 Kohm\n",
+        "(ii) Power dissipation is  10.0 Watt\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.11 Page no 87"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=100                                            #Volts\n",
+      "s=1000                                            #ohm/V\n",
+      "R=10.0*10**3                                    #kohm\n",
+      "R1=10.0*10**3                                      #kohm\n",
+      "s2=20000                                          #ohm/V\n",
+      "\n",
+      "#Calculation\n",
+      "V2=(R/(R1+R))*V\n",
+      "\n",
+      "#case 1\n",
+      "R2=V2*s\n",
+      "Req=(R*R2)/(R+R2)\n",
+      "V1=(Req/(R1+Req))*V\n",
+      "\n",
+      "#case 2\n",
+      "R3=V2*s2\n",
+      "Req2=(R1*R3)/(R1+R3)\n",
+      "V12=(Req2/(R1+Req2))*V\n",
+      "\n",
+      "#Result\n",
+      "print\"(a) voltmeter indicates \", round(V1,2),\"V\"\n",
+      "print\"(b) Voltmeter will read \",round(V12,2),\"V\"\n",
+      "print\"This example shows that a high sensitivity voltmeter Should be used to get accurate reading\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(a) voltmeter indicates  45.45 V\n",
+        "(b) Voltmeter will read  49.75 V\n",
+        "This example shows that a high sensitivity voltmeter Should be used to get accurate reading\n"
+       ]
+      }
+     ],
+     "prompt_number": 39
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.12 Page no 88"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "s=1*10**3                                  #ohm/V\n",
+      "Rm=0.2*10**3                         #ohm\n",
+      "V=10                                 #Volts\n",
+      "s1=20*10**3                           #ohm/volt\n",
+      "Rm1=1.5*10**3                           #ohm\n",
+      "R0=5.0*10**3                              #ohm\n",
+      "R1=25.0*10**3                             #ohm\n",
+      "V1=30                                   #Volt\n",
+      "\n",
+      "#Calculation\n",
+      "VRb=(R0/(R1+R0))*V1\n",
+      "Rm2=s*V\n",
+      "Req=(R0*Rm2)/(R0+Rm2)\n",
+      "VRb2=Req/(Req+R1)*V1\n",
+      "Rm3=s1*V\n",
+      "Req2=(R0*Rm3)/(R0+Rm3)\n",
+      "VRb3=(Req2/(R1+Req2))*V1\n",
+      "E1=((VRb-3.33)/VRb)*100\n",
+      "E2=((VRb-VRb3)/VRb)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Voltage across Rb without any meter across it \", VRb,\"Volt\"\n",
+      "print\"(ii) Voltage across Rb when the meter 1 is used \", round(VRb2,2),\"Volt\"\n",
+      "print\"(iii) voltage across arb when the meter 2 is used \", round(VRb3,1),\"Volts\"\n",
+      "print\"(iv) Error in voltmeter when meter 1 is used \", E1,\"%\"\n",
+      "print\"     Error in voltmeter when meter 2 is used \",round(E2,0),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Voltage across Rb without any meter across it  5.0 Volt\n",
+        "(ii) Voltage across Rb when the meter 1 is used  3.53 Volt\n",
+        "(iii) voltage across arb when the meter 2 is used  4.9 Volts\n",
+        "(iv) Error in voltmeter when meter 1 is used  33.4 %\n",
+        "     Error in voltmeter when meter 2 is used  2.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.13 Page no 89"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V1=5.0                          #Volt \n",
+      "V2=10                         #Volt\n",
+      "V3=30                         #Volt\n",
+      "S=20*10**3                    #ohm/V\n",
+      "Rb=5.0*10**3                    #ohm\n",
+      "Ra=45.0*10**3                   #ohm\n",
+      "V=50                          #Volt\n",
+      "\n",
+      "#Calculation\n",
+      "VRb=Rb/(Ra+Rb)*V\n",
+      "Rm=S*V1\n",
+      "Req=(Rm*Rb)/(Rm+Rb)\n",
+      "VRb1=Req/(Ra+Req)*V\n",
+      "E=((V1-VRb1)/V1)*100\n",
+      "Rm1=S*V2\n",
+      "Req1=(Rm1*Rb)/(Rm1+Rb)\n",
+      "VRb2=(Req1/(Req1+Ra))*V\n",
+      "E1=((V1-VRb2)/V1)*100\n",
+      "Rm2=S*V3\n",
+      "Req2=(Rm2*Rb)/(Rm2+Rb)\n",
+      "VRb3=Req2/(Req2+Ra)*V\n",
+      "E2=((V1-VRb3)/V1)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Voltage reading with a voltmeter on 5 volt \" ,round(VRb1,3),\"Volts\",\"\\n percent error is \",round(E,2),\"%\"\n",
+      "print\"(ii) Voltage reading with a voltmeter on 10 volt\", round(VRb2,2),\"Volts\",\"\\n percent error is \",round(E1,2),\"%\"\n",
+      "print\"(iii) Voltage reading with a voltmeter on 10 volt\", round(VRb3,2),\"Volts\",\"\\n percent error is \",round(E,2),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Voltage reading with a voltmeter on 5 volt  4.785 Volts \n",
+        " percent error is  4.31 %\n",
+        "(ii) Voltage reading with a voltmeter on 10 volt 4.89 Volts \n",
+        " percent error is  2.2 %\n",
+        "(iii) Voltage reading with a voltmeter on 10 volt 4.96 Volts \n",
+        " percent error is  1.0 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 90
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.14 Page no 90"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R1=1000                              #ohm\n",
+      "R2=1000.0                             #ohm\n",
+      "R3=1000.0                              #ohm\n",
+      "Rm=100                               #ohm\n",
+      "I=1                                  #A\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=(R1)+((R2*R3)/(R2+R3)) \n",
+      "Im=(((Rt)/(Rt+Rm))*I)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"Percent reading due to ammeter loading \", round(Im,1),\"%\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Percent reading due to ammeter loading  93.8 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.15 Page no 100"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=1.0*10**-3                         #A\n",
+      "Erms=10                              #Volts\n",
+      "V=0.45                               #Volts\n",
+      "Rm=200                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "S=1/I\n",
+      "R=(S*V*Erms-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of multiplier resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of multiplier resistance is  4.3 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 98
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.16 Page no 101"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100.0*10**-6                           #A\n",
+      "V=0.45                                    #Volts\n",
+      "Rm=500                                    #ohm\n",
+      "Erms=100\n",
+      "\n",
+      "#calculation\n",
+      "Sdc=1/Ifsd\n",
+      "Rs=(Sdc*V*100)-Rm\n",
+      "Rs1=((0.45*Erms)/Ifsd)-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs1*10**-3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  449.5 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.17 Page no 102"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100.0*10**-6                              #A\n",
+      "Rm=100                                       #ohm\n",
+      "V=50                                           #Vrms\n",
+      "\n",
+      "#Calculation\n",
+      "Sdc=1/Ifsd\n",
+      "Sac=0.9*Sdc\n",
+      "Rs=Sac*V-Rm\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of multiplier resistance is \", Rs*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of multiplier resistance is  449.9 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.18 Page no 102"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=1.0*10**-3                                #A\n",
+      "V=10                                 #volts\n",
+      "Rm=250                               #ohm\n",
+      "\n",
+      "#Calculation\n",
+      "Sdc=1/I\n",
+      "Sac=0.9*Sdc\n",
+      "R=(Sac*V-Rm)*10**-3\n",
+      "\n",
+      "#Result\n",
+      "print\"Value of multiplier resistance is \", R,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of multiplier resistance is  8.75 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 103
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.19 Page no 103"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Ifsd=100*10**-6                              #A\n",
+      "V=10.0                                         #Volts\n",
+      "R2=10.0*10**3                                 #ohm\n",
+      "Rm=100*10**3                                #ohm\n",
+      "R1=10.0*10**3                                 #ohm\n",
+      "\n",
+      "Sdc=1/Ifsd\n",
+      "Rs=Sdc*V\n",
+      "Req=(R2*Rm)/(R2+Rm)\n",
+      "ER2=Req/(R1+Req)\n",
+      "Shw=0.45*Sdc\n",
+      "Rs1=Shw*V\n",
+      "Req1=(R2*Rs1)/(R2+Rs1)\n",
+      "E=Req1/(R1+Req1)\n",
+      "Sfw=(0.90*Sdc)\n",
+      "Rs2=Sfw*V\n",
+      "Req2=(R2*Rs2)/(R2+Rs2)\n",
+      "E=(Req2/(R1+Req2))*V\n",
+      "\n",
+      "#Result\n",
+      "print\"Sensitivity is \",Sdc*10**-3,\"Kohm/volt\"\n",
+      "print\"Multiplier resistance is \",Rs*10**-3,\"Kohm\"\n",
+      "print\"The voltage across R2 is \",round(ER2*10**1,2),\"Volts\"\n",
+      "print\"Resistance using Half wave rectifier \",Rs1*10**-3,\"Kohm\"\n",
+      "print\"Voltage by AC voltmeter is \",round(E,2),\"Volts\"\n",
+      "print\"Resistance using full wave rectifier \",Rs2*10**-3,\"Kohm\"\n",
+      "print\"Voltage by DC voltmeter is \",round(E,2),\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Sensitivity is  10.0 Kohm/volt\n",
+        "Multiplier resistance is  100.0 Kohm\n",
+        "The voltage across R2 is  4.76 Volts\n",
+        "Resistance using Half wave rectifier  45.0 Kohm\n",
+        "Voltage by AC voltmeter is  4.74 Volts\n",
+        "Resistance using full wave rectifier  90.0 Kohm\n",
+        "Voltage by DC voltmeter is  4.74 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 60
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.20 Page no 113"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=1*10**-3                        #A\n",
+      "Rm=100                             #ohm\n",
+      "Rh=1*10**3                         #ohm\n",
+      "V=3.0                               #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R1=Rh-(Im*Rm*Rh)/V\n",
+      "R2=(Im*Rm*Rh)/(V-Im*Rh)\n",
+      "V1=3-0.09\n",
+      "R21=(Im*Rm*Rh)/(V1-Im*Rh)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1= \",round(R1,2),\"ohm\",\" \\n    Value of R2= \",round(R2,2),\"ohm\"\n",
+      "print\"(ii) Maximum value of R2 to compensate for a 3% Drop in Battery Voltage \",round(R21,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1=  966.67 ohm  \n",
+        "    Value of R2=  50.0 ohm\n",
+        "(ii) Maximum value of R2 to compensate for a 3% Drop in Battery Voltage  52.36 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.21 Page no 113"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Rh=2000.0                       #ohm\n",
+      "Ifsd=1*10**-3                   #A\n",
+      "Rm=100                        #ohm\n",
+      "V=3.0                            #Volts\n",
+      "V1=2.58                           #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R1=Rh-((Ifsd*Rm*Rh)/V)\n",
+      "R2=(Ifsd*Rm*Rh)/(V-(Ifsd*Rh))\n",
+      "R21=(Ifsd*Rm*Rh)/(V1-(Ifsd*Rh))\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1=\",round(R1,1),\"Ohm and Value of R2=\",R2,\"Ohm\" \n",
+      "print\"The maximum value of R2 is \",round(R21,2),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1= 1933.3 Ohm and Value of R2= 200.0 Ohm\n",
+        "The maximum value of R2 is  344.83 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.22 Page no 114"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=3                      #volts\n",
+      "Im=1.0*10**-3               #A\n",
+      "Rm=100                    #ohm\n",
+      "P=0.2 \n",
+      "P1=0.4\n",
+      "P2=0.5 \n",
+      "P3=0.75\n",
+      "P4=0.9\n",
+      "P5=1\n",
+      "\n",
+      "#calculation\n",
+      "Rs=(V/Im)-Rm\n",
+      "Rx=((Rs+Rm)/P)-(Rs+Rm)\n",
+      "Rx1=((Rs+Rm)/P1)-(Rs+Rm)\n",
+      "Rx2=((Rs+Rm)/P2)-(Rs+Rm)\n",
+      "Rx3=((Rs+Rm)/P3)-(Rs+Rm)\n",
+      "Rx4=((Rs+Rm)/P4)-(Rs+Rm)\n",
+      "Rx5=((Rs+Rm)/P5)-(Rs+Rm)\n",
+      "\n",
+      "#Result\n",
+      "print\"The value of Rs is \",Rs*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 20% detection is \",Rx*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 40% detection is \",Rx1*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 50% detection is \",Rx2*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 75% detection is \",Rx3*10**-3,\"Kohm\"\n",
+      "print\"The value of Rx with 90% detection is \",round(Rx4*10**-3,3),\"Kohm\"\n",
+      "print\"The value of Rx with 100% detection is \",Rx5*10**-3,\"Kohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of Rs is  2.9 Kohm\n",
+        "The value of Rx with 20% detection is  12.0 Kohm\n",
+        "The value of Rx with 40% detection is  4.5 Kohm\n",
+        "The value of Rx with 50% detection is  3.0 Kohm\n",
+        "The value of Rx with 75% detection is  1.0 Kohm\n",
+        "The value of Rx with 90% detection is  0.333 Kohm\n",
+        "The value of Rx with 100% detection is  0.0 Kohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 40
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.23 Page no 115"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "V=3.0                       #Volts\n",
+      "I=1.0*10**-3                #A\n",
+      "V1=2.8\n",
+      "\n",
+      "#Calculation\n",
+      "Rt=V/I\n",
+      "Rt1=V1/I\n",
+      "E=((V-V1)/V)*100\n",
+      "\n",
+      "#Result\n",
+      "print\"The resulting error is \", round(E,2),\"%\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resulting error is  6.67 %\n"
+       ]
+      }
+     ],
+     "prompt_number": 47
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.24 Page no 116"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "Im=1*10**-3                    #A\n",
+      "Rm=100.0                         #ohm\n",
+      "Rh=2000                        #ohm\n",
+      "V=3.0                            #Volts\n",
+      "V1=2.7                            #Volts\n",
+      "V2=3.1                            #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "R2=(Im*Rh*Rm)/(V-Im*Rh)\n",
+      "R1=Rh-R2*Rm/R2+Rm\n",
+      "R21=(Im*Rh*Rm)/(V1-Im*Rh)\n",
+      "R22=(Im*Rh*Rm)/(V2-Im*Rh)\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of R1=\",R1-66.6,\"ohm and the value of R2=\",R2,\"ohm\"\n",
+      "print\"(ii) The value of R2 when battery is 2.7 V is \",round(R21,0),\"ohm\"\n",
+      "print\"     The value of R2 when battery is 3.1 V is \",round(R22,0),\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of R1= 1933.4 ohm and the value of R2= 200.0 ohm\n",
+        "(ii) The value of R2 when battery is 2.7 V is  286.0 ohm\n",
+        "     The value of R2 when battery is 3.1 V is  182.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 72
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.25 Page no 118"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=0.5                          #mA\n",
+      "Im=10                          #mA\n",
+      "Rm=50                          #ohm\n",
+      "Rh=10.0                          #ohm\n",
+      "V=3                              #Volts\n",
+      "\n",
+      "#Calculation\n",
+      "Ih=I*Im\n",
+      "Vm=Ih*Rm\n",
+      "Ix=Vm/Rh\n",
+      "Ish=Ix-Ih\n",
+      "Rsh=Vm/Ish\n",
+      "It=Ix+Ih+Ish\n",
+      "V1=V-Vm*10**-3\n",
+      "R1=V1/It\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) The value of shunt resistance is \", Rsh,\"ohm\"\n",
+      "print\"(ii) Value of current limiting resistance is \", R1*10**3,\"ohm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) The value of shunt resistance is  12.5 ohm\n",
+        "(ii) Value of current limiting resistance is  55.0 ohm\n"
+       ]
+      }
+     ],
+     "prompt_number": 93
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.26 Page no 119"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "I=3\n",
+      "R1=10.0                   #ohm\n",
+      "R2=20.0                    #ohm\n",
+      "R3=30.0*10**3                #ohm\n",
+      "R11=100.0                  #ohm\n",
+      "R22=200.0                   #ohm\n",
+      "R12=1000                    #ohm\n",
+      "R21=2000.0                   #ohm\n",
+      "\n",
+      "V=I*(R1/(R1+R2))\n",
+      "Im=V/R3\n",
+      "V1=I*(R11/(R11+R22))\n",
+      "Im1=V1/R3\n",
+      "V2=I*(R12/(R12+R21))\n",
+      "Im2=V2/R3\n",
+      "print\"(a) Current through the micrometer is \", round(Im*10**6,1),\"micro A\"\n",
+      "print\"(b) The current flows through the meter movement when a 200 ohm resistor is measured \",round (Im1*10**6,1),\"micro A\"\n",
+      "print\"(b) The current flows through the meter movement when a 2 Kohm resistor is measured\",round (Im1*10**6,1),\"micro A\" "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(a) Current through the micrometer is  33.3 micro A\n",
+        "(b) The current flows through the meter movement when a 200 ohm resistor is measured  33.3 micro A\n",
+        "(b) The current flows through the meter movement when a 2 Kohm resistor is measured 33.3 micro A\n"
+       ]
+      }
+     ],
+     "prompt_number": 114
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb
new file mode 100755
index 00000000..f4f36010
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb
@@ -0,0 +1,247 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:2471290ece4efb00967c01c588e1982987585cc7ba4f2523bc3d651b33c25fb9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 5 Digital voltmeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.1 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100.0*10**3                           #ohm\n",
+      "C=1.0*10**-6                            #Farad\n",
+      "ei=1\n",
+      "t1=1                                  #second \n",
+      "\n",
+      "#Calculation\n",
+      "E=(ei*t1)/(R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"Voltage present at the output of the integrator after 1s is \", E,\"V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Voltage present at the output of the integrator after 1s is  10.0 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.2 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "e1=1\n",
+      "er=5.0                                               #Volts\n",
+      "t1=1                                                 #Second\n",
+      "\n",
+      "#Calculation\n",
+      "t2=ei*t1/er\n",
+      "\n",
+      "#Result\n",
+      "print\"Time interval of t2 is \", t2,\"s\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Time interval of t2 is  0.2 s\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.3 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100.0*10**3                   #ohm\n",
+      "C=2.0*10**-6                   #farad\n",
+      "e1=2                           #volts\n",
+      "t1=2                           #S\n",
+      "\n",
+      "#Calculation\n",
+      "e0=(e1*t1)/(R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The output of the integrator is \", e0,\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The output of the integrator is  20.0 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.4 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "e1=2                              #Volts\n",
+      "t1=2                               #second\n",
+      "e2=10.0                             #Volts\n",
+      "\n",
+      "t2=(e1*t1)/e2\n",
+      "print\"Time interval is \",t2,\"second\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Time interval is  0.4 second\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.5 Page no 141"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "n=3\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/10.0**n\n",
+      "\n",
+      "#Result\n",
+      "print\"The resolution is \", R"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resolution is  0.001\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.6 Page no 141"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given \n",
+      "n=5\n",
+      "V=12.98                   #Volts\n",
+      "V1=1                      #Volts\n",
+      "V2=10                      #volts\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/10.0**n\n",
+      "R1=V1*R\n",
+      "R2=V2*R\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resolution is \", R\n",
+      "print\"(ii) Any reading upto 4th decimal can be displayed. \\n Hence this will be displayed as 0.6973\"\n",
+      "print\"(iii) Resolution is \",R2,\"\\n Hence decimal upto 3rd decimal place can be displayed\"\n",
+      "print\"therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resolution is  1e-05\n",
+        "(ii) Any reading upto 4th decimal can be displayed. \n",
+        " Hence this will be displayed as 0.6973\n",
+        "(iii) Resolution is  0.0001 \n",
+        " Hence decimal upto 3rd decimal place can be displayed\n",
+        "therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap5_1.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap5_1.ipynb
new file mode 100755
index 00000000..f4f36010
--- /dev/null
+++ b/electronic_instrumentation_by_H_S_Kalsi/chap5_1.ipynb
@@ -0,0 +1,247 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:2471290ece4efb00967c01c588e1982987585cc7ba4f2523bc3d651b33c25fb9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 5 Digital voltmeters"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.1 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100.0*10**3                           #ohm\n",
+      "C=1.0*10**-6                            #Farad\n",
+      "ei=1\n",
+      "t1=1                                  #second \n",
+      "\n",
+      "#Calculation\n",
+      "E=(ei*t1)/(R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"Voltage present at the output of the integrator after 1s is \", E,\"V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Voltage present at the output of the integrator after 1s is  10.0 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.2 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "e1=1\n",
+      "er=5.0                                               #Volts\n",
+      "t1=1                                                 #Second\n",
+      "\n",
+      "#Calculation\n",
+      "t2=ei*t1/er\n",
+      "\n",
+      "#Result\n",
+      "print\"Time interval of t2 is \", t2,\"s\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Time interval of t2 is  0.2 s\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.3 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "R=100.0*10**3                   #ohm\n",
+      "C=2.0*10**-6                   #farad\n",
+      "e1=2                           #volts\n",
+      "t1=2                           #S\n",
+      "\n",
+      "#Calculation\n",
+      "e0=(e1*t1)/(R*C)\n",
+      "\n",
+      "#Result\n",
+      "print\"The output of the integrator is \", e0,\"Volts\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The output of the integrator is  20.0 Volts\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.4 Page no 134"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "e1=2                              #Volts\n",
+      "t1=2                               #second\n",
+      "e2=10.0                             #Volts\n",
+      "\n",
+      "t2=(e1*t1)/e2\n",
+      "print\"Time interval is \",t2,\"second\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Time interval is  0.4 second\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.5 Page no 141"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#given\n",
+      "n=3\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/10.0**n\n",
+      "\n",
+      "#Result\n",
+      "print\"The resolution is \", R"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resolution is  0.001\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.6 Page no 141"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given \n",
+      "n=5\n",
+      "V=12.98                   #Volts\n",
+      "V1=1                      #Volts\n",
+      "V2=10                      #volts\n",
+      "\n",
+      "#Calculation\n",
+      "R=1/10.0**n\n",
+      "R1=V1*R\n",
+      "R2=V2*R\n",
+      "\n",
+      "#Result\n",
+      "print\"(i) Resolution is \", R\n",
+      "print\"(ii) Any reading upto 4th decimal can be displayed. \\n Hence this will be displayed as 0.6973\"\n",
+      "print\"(iii) Resolution is \",R2,\"\\n Hence decimal upto 3rd decimal place can be displayed\"\n",
+      "print\"therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i) Resolution is  1e-05\n",
+        "(ii) Any reading upto 4th decimal can be displayed. \n",
+        " Hence this will be displayed as 0.6973\n",
+        "(iii) Resolution is  0.0001 \n",
+        " Hence decimal upto 3rd decimal place can be displayed\n",
+        "therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
diff --git a/electronic_instrumentation_by_H_S_Kalsi/screenshots/image_1.png b/electronic_instrumentation_by_H_S_Kalsi/screenshots/image_1.png
new file mode 100755
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author	FOSSEE SysAds	2015-12-08 15:04:13 +0600
committer	FOSSEE SysAds	2015-12-08 15:04:13 +0600
commit	534e42c1dee8fefa92f28d4496f273f8c6e4bd94 (patch)
tree	2896915c480bcca6cfbe6432f3fa84e2166f589b /electronic_instrumentation_by_H_S_Kalsi
parent	3ed3fb328a5f4530eec6591d0ca6fe99c69b1013 (diff)
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