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Diffstat (limited to 'electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb')
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diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb new file mode 100755 index 00000000..f4f36010 --- /dev/null +++ b/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb @@ -0,0 +1,247 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:2471290ece4efb00967c01c588e1982987585cc7ba4f2523bc3d651b33c25fb9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 5 Digital voltmeters"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.1 Page no 134"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "R=100.0*10**3 #ohm\n",
+ "C=1.0*10**-6 #Farad\n",
+ "ei=1\n",
+ "t1=1 #second \n",
+ "\n",
+ "#Calculation\n",
+ "E=(ei*t1)/(R*C)\n",
+ "\n",
+ "#Result\n",
+ "print\"Voltage present at the output of the integrator after 1s is \", E,\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Voltage present at the output of the integrator after 1s is 10.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.2 Page no 134"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "e1=1\n",
+ "er=5.0 #Volts\n",
+ "t1=1 #Second\n",
+ "\n",
+ "#Calculation\n",
+ "t2=ei*t1/er\n",
+ "\n",
+ "#Result\n",
+ "print\"Time interval of t2 is \", t2,\"s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Time interval of t2 is 0.2 s\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.3 Page no 134"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "R=100.0*10**3 #ohm\n",
+ "C=2.0*10**-6 #farad\n",
+ "e1=2 #volts\n",
+ "t1=2 #S\n",
+ "\n",
+ "#Calculation\n",
+ "e0=(e1*t1)/(R*C)\n",
+ "\n",
+ "#Result\n",
+ "print\"The output of the integrator is \", e0,\"Volts\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The output of the integrator is 20.0 Volts\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.4 Page no 134"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "e1=2 #Volts\n",
+ "t1=2 #second\n",
+ "e2=10.0 #Volts\n",
+ "\n",
+ "t2=(e1*t1)/e2\n",
+ "print\"Time interval is \",t2,\"second\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Time interval is 0.4 second\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.5 Page no 141"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "n=3\n",
+ "\n",
+ "#Calculation\n",
+ "R=1/10.0**n\n",
+ "\n",
+ "#Result\n",
+ "print\"The resolution is \", R"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The resolution is 0.001\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.6 Page no 141"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given \n",
+ "n=5\n",
+ "V=12.98 #Volts\n",
+ "V1=1 #Volts\n",
+ "V2=10 #volts\n",
+ "\n",
+ "#Calculation\n",
+ "R=1/10.0**n\n",
+ "R1=V1*R\n",
+ "R2=V2*R\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Resolution is \", R\n",
+ "print\"(ii) Any reading upto 4th decimal can be displayed. \\n Hence this will be displayed as 0.6973\"\n",
+ "print\"(iii) Resolution is \",R2,\"\\n Hence decimal upto 3rd decimal place can be displayed\"\n",
+ "print\"therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Resolution is 1e-05\n",
+ "(ii) Any reading upto 4th decimal can be displayed. \n",
+ " Hence this will be displayed as 0.6973\n",
+ "(iii) Resolution is 0.0001 \n",
+ " Hence decimal upto 3rd decimal place can be displayed\n",
+ "therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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