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@@ -1,434 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:9350c41424c136ffdcb61a367641cc78b39d6999ad3a13b8f61c623099d55d5b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 6: The Ideal Gas"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.1, page no. 101"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import scipy.integrate\n",
-      "\n",
-      "#intialization of variables\n",
-      "T1 = 40+460.0                        #temperature(R)\n",
-      "T2 = 340+460.0                       #temperature(R)\n",
-      "\n",
-      "#calculation\n",
-      "def Cv(T):\n",
-      "\tcv = 0.162+0.00046*T\n",
-      "\treturn cv\n",
-      "\t\n",
-      "du = scipy.integrate.quadrature(Cv, T1, T2)[0]\n",
-      "\n",
-      "#result\n",
-      "print \"Change in specific internal energy = %.1f B/lbm\" %du"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Change in specific internal energy = 138.3 B/lbm\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.2, page no. 103"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "#initialization\n",
-      "\n",
-      "cp = 0.24                   #B/lbm F\n",
-      "R = 53.3                    #ft-lb/lbm F\n",
-      "\n",
-      "#calculation\n",
-      "cv = cp-R/778.0\n",
-      "\n",
-      "#result\n",
-      "print \"Specific heat at constant volume = %.3f B/lbm F\" %cv"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Specific heat at constant volume = 0.171 B/lbm F\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.3, page no. 104"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import scipy.integrate\n",
-      "\n",
-      "#initialization\n",
-      "T1 = 1400+460.0                         #temperature(R)\n",
-      "T2 = 1200+460.0                         #temperature(R)\n",
-      "\n",
-      "#calculation\n",
-      "def Cp(T):\n",
-      "\tcp = 0.317- 1.2*100/T + 4*10**4/T**2\n",
-      "\treturn cp\n",
-      "\n",
-      "dh = scipy.integrate.quadrature(Cp, T1, T2)[0]\n",
-      "\n",
-      "#result\n",
-      "print \"Change in stagnation enthalpy = %.1f B/lbm\" %dh"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Change in stagnation enthalpy = -52.3 B/lbm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.4, page no. 106"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import scipy.integrate\n",
-      "\n",
-      "#initialization\n",
-      "T1 = 100+460.0                       #temperature(R)\n",
-      "T2 = 300+460.0                       #temperature(R)\n",
-      "P1 = 15.0                            #pressure(lb/in^2)\n",
-      "P2 = 30.0                            #pressure(lb/in^2)\n",
-      "Cp = 0.3                             #constant pressure(B/lbm F)\n",
-      "R = 40.0                             #gas constant(ft-lb/lbm R)\n",
-      "\n",
-      "#calculation\n",
-      "def fun(f):\n",
-      "\ts=Cp/f\n",
-      "\treturn s\n",
-      "def fun1(f):\n",
-      "\ts2=R/(f*778)\n",
-      "\treturn s2\n",
-      "\n",
-      "ds1 = scipy.integrate.quadrature(fun, T1, T2)[0]\n",
-      "ds2 = scipy.integrate.quadrature(fun1, P1, P2)[0]\n",
-      "ds = ds1 - ds2\n",
-      "\n",
-      "#result\n",
-      "print \"Change in entropy = %.4f B/lbm R\" %ds"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Change in entropy = 0.0560 B/lbm R\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.5, page no. 108"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "#initialization\n",
-      "\n",
-      "T1 = 40+460.0                          #temperature(R)\n",
-      "T2 = 340+460.0                         #temperature(R)\n",
-      "P1 = 15.0                              #pressure(lb/in^2)\n",
-      "cp = 0.24\n",
-      "cv = 0.171\n",
-      "\n",
-      "#calculation\n",
-      "gamma=cp/cv\n",
-      "P2=P1 *((T2/T1)**(gamma/(gamma-1)))\n",
-      "\n",
-      "#result\n",
-      "print \"Final pressure = %.1f lb/in^2\" %P2"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Final pressure = 76.9 lb/in^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.6, page no. 110"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "#initialization\n",
-      "P1 = 16.0                   #lb/in^2\n",
-      "P2 = 14.0                   #lb/in^2\n",
-      "Tt = 83+460.0               #R\n",
-      "gamma = 1.4\n",
-      "cp = 0.24                   #B/lbm F\n",
-      "\n",
-      "#calculation\n",
-      "T = Tt *(P2/P1)**((gamma-1)/gamma)\n",
-      "dh = cp*(Tt-T)\n",
-      "V = math.sqrt(2*32.2*778*dh)\n",
-      "\n",
-      "#result\n",
-      "print \"Actual temperature in the flow = %d R\" %T\n",
-      "print \"Flow velocity = %d ft/sec\" %V\n",
-      "\n",
-      "#difference in answeres is due to internal rounding off in Python"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Actual temperature in the flow = 522 R\n",
-        "Flow velocity = 494 ft/sec\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.7, page no. 111"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "import scipy.integrate\n",
-      "\n",
-      "#initialization\n",
-      "T1 = 400.0+460.0                      #R\n",
-      "P1 = 100.0                          #lb/in^2\n",
-      "P2 = 20.0                           #lb/in^2\n",
-      "T2 = 140.0+460.0                      #R\n",
-      "Cp = 50.0\n",
-      "\n",
-      "#calculation\n",
-      "Pratio = P1/P2\n",
-      "Tratio = T1/T2\n",
-      "C = math.log(Tratio)/math.log(Pratio)\n",
-      "n=1/(1-C)\n",
-      "v1=Cp*T1/(144*P1)\n",
-      "v2=Cp*T2/(144*P2)\n",
-      "w=144*P1*v1**n\n",
-      "def fun(v):\n",
-      "\tp=w/v**n\n",
-      "\treturn p\n",
-      "\n",
-      "Work = scipy.integrate.quadrature(fun, v1, v2)[0]\n",
-      "\n",
-      "#result\n",
-      "print \"Work done = %f ft-lb/lbm\" %Work"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Work done = 45118.149895 ft-lb/lbm\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.8, page no. 113"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "#initialization\n",
-      "P1 = 15.0                     #lb/in^2\n",
-      "P2 = 20.0                     #lb/in^2\n",
-      "T1 = 40+460                   #R\n",
-      "T2 = 540+460                  #R\n",
-      "\n",
-      "#calculation\n",
-      "#From table 6 at the two temperatures\"\n",
-      "phi1 = 0.58233\n",
-      "phi2 = 0.75042\n",
-      "ds = phi2-phi1-53.3*math.log(P2/P1)/778.0\n",
-      "\n",
-      "#result\n",
-      "print \"Entropy change = %.5f B/lbm R\" %ds"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy change = 0.14838 B/lbm R\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6.9, page no. 115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "#part a\n",
-      "\n",
-      "P2 = 1460.0                #pressure 2\n",
-      "P1 = 1900.0                #pressure 1\n",
-      "V2 = 1900.0                #volume 1\n",
-      "V1 = 1460.0                #volume 2\n",
-      "\n",
-      "pratio = (P2/P1)**3.5\n",
-      "vratio = (V2/V1)**2.5\n",
-      "\n",
-      "print \"Pressure ratio is \", round(pratio,2)\n",
-      "print \"Volume ratio is \", round(vratio,2)\n",
-      "\n",
-      "#part b\n",
-      "#from table 6\n",
-      "Pr2 = 50.34                #pressure 2\n",
-      "Pr1 = 141.51                #pressure 1\n",
-      "Vr2 = 10.743                #volume 1\n",
-      "Vr1 = 4.974                #volume 2\n",
-      "\n",
-      "pratio = (Pr2/Pr1)\n",
-      "vratio = (Vr2/Vr1)\n",
-      "\n",
-      "print \"Pressure ratio is \", round(pratio,2)\n",
-      "print \"Volume ratio is \", round(vratio,2)"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Pressure ratio is  0.4\n",
-        "Volume ratio is  1.93\n",
-        "Pressure ratio is  0.36\n",
-        "Volume ratio is  2.16\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
\ No newline at end of file