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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:29c2c55c7f92ba07b1426c985419398b6baf83f563e8d0219eeaa4d84ad525c8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 2 : Fluid Statics"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1 Page No : 44"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "h1 = 1.5 \t\t\t#m\n",
+      "h2 = 2. \t\t\t#m\n",
+      "g1 = 800. \t\t\t#kg/m**3\n",
+      "g2 = 1000. \t\t\t#kg/m**3\n",
+      "g = 9.81\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "P = h1*g*g1 + h2*g*g2\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Pressure at the bottom of the vessel  =  %.2f kN/m**2\"%(P/1000)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure at the bottom of the vessel  =  31.39 kN/m**2\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.2 Page No : 44"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "depth = 8000. \t\t\t#m\n",
+      "sw = 10.06 \t\t\t#kN/m**3\n",
+      "BM = 2.05*10**9 \t\t\t#N/m**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "g = sw*10**3 /(1- sw*10**3 *depth/BM)\n",
+      "Ph = 2.3*BM*math.log10(BM/(BM-depth*9.81*1025))\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Specific weight  =  %.2f kN/m**2\"%(g/1000)\n",
+      "print \" Pressure at depth h  =  %.2f MN/m**2\"%(Ph/10**6)\n",
+      "\n",
+      "# note : rounding off error."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Specific weight  =  10.47 kN/m**2\n",
+        " Pressure at depth h  =  81.97 MN/m**2\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.3 Page No : 55"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "Patm = 101.3/9.81 \t\t\t#m of water\n",
+      "x1 = 0.45 \t\t\t#m\n",
+      "x2 = 0.3 \t\t\t#m\n",
+      "s1 = 920. \t\t\t#Kg/m**3\n",
+      "s2 = 13.6 \t\t\t#Kg/m**3\n",
+      "g = 9.81 \t\t\t#m/s**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "Pa = (s1*x1*g + s2*x2*g)/1000\n",
+      "Pa2 = Pa*10**3/(1000*g)\n",
+      "Pa3 = Pa/(s2)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Pressure at A  =  %.1f kPa\"%Pa\n",
+      "print \" Pressure at A  =  %.3f m of water\"%(Pa2)\n",
+      "print \" Pressure at A  =  %.3f m of mercury\"%(Pa3)\n",
+      "print \" Pressure at A  =  %.1f m of water absolute\"%(Pa/1000 +101.3)\n",
+      "print \" Pressure at A  =  %.3f m of mercury\"%(Pa2+10.3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure at A  =  4.1 kPa\n",
+        " Pressure at A  =  0.418 m of water\n",
+        " Pressure at A  =  0.302 m of mercury\n",
+        " Pressure at A  =  101.3 m of water absolute\n",
+        " Pressure at A  =  10.718 m of mercury\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.4 Page No : 55"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "sg = 1.25           # gravity\n",
+      "d = 0.5 \t\t\t#m\n",
+      "d2 = 13.5*10**-2\t#m\n",
+      "sw = 9.81 \t\t\t#specific weight of water - kN/m**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "sl = sg*sw          #specific weight of liquid\n",
+      "sm = 13.6*sw        #specfic weight of mercury\n",
+      "Pa = sl*d - sm*d2\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Pressure at A  =  %.2f kN/m**2 vacuum \"%(-Pa)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure at A  =  11.88 kN/m**2 vacuum \n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.5 Page No : 56"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "#Following values are ontained from the figure 2.17\n",
+      "s1 = 0.85\n",
+      "s2 = 13.6\n",
+      "z1 = 30\n",
+      "z2 = 15\n",
+      "z3 = 20\n",
+      "z4 = 35\n",
+      "z5 = 60\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "dHa = s1*(z1+z5+z3-z4) +s2*z4 -z3+s2*z2-s1*(z1+z2)        #Ha-Hb\n",
+      "Pd = 1000*9.81*dHa/100                                    #Pa-Pb\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Pressure difference  =  %.2f kN/m**2\"%(Pd/1000)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure difference  =  67.25 kN/m**2\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.6 Page No : 57"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "P = 450 \t\t\t#pressure - kN/m**2\n",
+      "alt = 2000 \t\t\t#altitude - m\n",
+      "r = 610 \t\t\t#atmospheric pressure - mm of mercury\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "Pat = 760-r\n",
+      "Pat2 = Pat*13.6*9.81*10**-3\n",
+      "Pg = Pat2+P\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Gauge reading  =  %.2f kN/m**2\"%(Pg)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Gauge reading  =  470.01 kN/m**2\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.7 Page No : 62"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "g = 9.81 \t\t\t#kN/m**2\n",
+      "hc = 16.25 \t\t\t#m\n",
+      "w = 1.5 \t\t\t#width - m\n",
+      "b = 2.5 \t\t\t#depth - m\n",
+      "f = 0.3             #coefficient of friction\n",
+      "Pi = 50. \t\t\t#weight of gate - kN\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "P = g*hc*w*b\n",
+      "Preq = Pi+f*P\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Force required to lift the gate  =  %.2f kN\"%(Preq)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Force required to lift the gate  =  229.34 kN\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.8 Page No : 62"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "a = 6. \t\t\t#m\n",
+      "b = 8. \t\t\t#m\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "Ixy = 9./32 *b**4 /4\n",
+      "xp =  Ixy/(2./3 *b *1./2 *a*b)\n",
+      "ICG = 1./36 *a*b**3\n",
+      "yp = 2./3*b + ICG/(2./3 *b* 1./2 *a*b )\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"The coordinates of centre of pressure are %.2f,%d\"%(xp,yp)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The coordinates of centre of pressure are 2.25,6\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.9 Page No : 63"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "z = 1.2 \t\t\t#m\n",
+      "y = 1. \t\t\t#m\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "hp = 0.6 + 1./12 *y*z**3 /(0.6*y*z)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Position of hinge  =  %.1f m\"%(hp)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Position of hinge  =  0.8 m\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.10 Page No : 64"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "from sympy import *\n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "r = 0.75 \t\t\t#radius of plane - m\n",
+      "gam = 8. \t\t\t#specific weight of fluid - kN/m**3\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "P = gam*2./3 *r**3\n",
+      "hp = Symbol('hp')\n",
+      "hp = 4*r/(3*math.pi) + (math.pi/gam - gam/(9*math.pi)) * r**4/(4*r/(3*math.pi) * 1./2*math.pi*r**3)\n",
+      "\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \" Total pressure  =  %.2f kN\"%(P)\n",
+      "print \"Total pressure location  =  %.3f m\"%(hp)\n",
+      "\n",
+      "# note : answer is slightly different because of rounding off error. please check."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Total pressure  =  2.25 kN\n",
+        "Total pressure location  =  0.483 m\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.11 Page No : 65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "B = 3. \t\t\t#m\n",
+      "b = 2. \t\t\t#m\n",
+      "h1 = 0.75 \t\t\t#m\n",
+      "h2 = 1. \t\t\t#m\n",
+      "sg = 0.9        #specific gravity\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "IP = sg*9.81*h2\n",
+      "F1 = 0.5*IP*h2\n",
+      "F2 = IP*h1\n",
+      "F3 = 0.5*(9.81*h1)*h1\n",
+      "F = B*(F1+F2+F3)\n",
+      "ybar =  (F1*(h1+ 1./3) + F2* h1/2 + F3* h1/3)/(F1+F2+F3)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Total force  =  %.2f kN\"%(F)\n",
+      "print \"Location  =  %.3f m  from the base\"%(ybar)\n",
+      "\n",
+      "# note : rounding off error."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Total force  =  41.39 kN\n",
+        " Location  =  0.577 m  from the base\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.12 Page No : 67"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "from scipy.integrate import quad\n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "g = 1000*9.81 \t\t\t#kg/m**3\n",
+      "hc = 20. \t\t\t#m\n",
+      "Ax = 40.*1 \t\t\t#m**2\n",
+      "y1 = 0. \t\t\t#m\n",
+      "y2 = 40. \t\t\t#m\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "Fx = g*hc*Ax\n",
+      "def fy(y):\n",
+      "    return (12*y)**(1./3)\n",
+      "\n",
+      "Fy = quad(fy,y1,y2)\n",
+      "Fy = g*Fy[0]\n",
+      "F = math.sqrt(Fx**2 +Fy**2)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Net force  =  %d kN\"%(F/1000)\n",
+      "#The answer is a bit different due to rounding off error in the textbook"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Net force  =  8179 kN\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.13 Page No : 68"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "g = 9.81 \t\t\t#kN/m**2\n",
+      "hc = 1. \t\t\t#m\n",
+      "l = 3.   \t\t\t#m\n",
+      "b = 0.5 \t\t\t#m\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "Ax = l*b \t\t\t#m**2\n",
+      "Fx = g*hc*Ax\n",
+      "Fz = g*(0.5* math.pi/4 *b**2)*l\n",
+      "F = math.sqrt(Fx**2 + Fz**2)\n",
+      "theta = math.degrees(math.atan(Fz/Fx))\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Magintude of resultant force  =  %.3f kN\"%(F)\n",
+      "print \" Direction of the resultant force  =  %.1f deg\"%(theta)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Magintude of resultant force  =  14.996 kN\n",
+        " Direction of the resultant force  =  11.1 deg\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.14 Page No : 71"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "r1 = 920. \t\t\t#density of ice - kg/m**3\n",
+      "r2 = 1030. \t\t\t#density of sea water - kg/m**3\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "VtbyV2 = r2/r1\n",
+      "V1byV2 = VtbyV2-1\n",
+      "V1byVt = 1./(1+1/V1byV2)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"fraction  =  %.3f \"%(V1byVt)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "fraction  =  0.107 \n"
+       ]
+      }
+     ],
+     "prompt_number": 19
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.15 Page No : 72"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "d = 3. \t\t\t    #diameter of balloon - m\n",
+      "rh1 = 1.19 \t\t\t#density of air - kg/m**3\n",
+      "rh2 = 0.17 \t\t\t#density of helium - kg/m**3 \n",
+      "g = 9.81 \t\t\t#m/s**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "pay = (rh1-rh2)*g*math.pi/6 *d**3\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \" Pay load  =  %.2f N\"%(pay)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Pay load  =  141.46 N\n"
+       ]
+      }
+     ],
+     "prompt_number": 20
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.16 Page No : 76"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from numpy import roots\t\t\t\n",
+      "#calculations\n",
+      "y = [6,-6,1]\n",
+      "z = roots(y)\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"For stability, s must be greater than %.2f and less than %.2f and must be less than 1\"%(z[0],z[1])"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "For stability, s must be greater than 0.79 and less than 0.21 and must be less than 1\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.17 Page No : 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "ax = 1.5 \t\t\t#m/s**2\n",
+      "g = 9.81 \t\t\t#m/s**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "alpha = math.degrees(math.atan(ax/g))\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"The interface is inclined at %.f degrees with the horizontal\"%(alpha)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The interface is inclined at 9 degrees with the horizontal\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.18 Page No : 81"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "d = 10. \t\t\t#diameter - cm\n",
+      "h = 25. \t\t\t#height - cm\n",
+      "hw = 15. \t\t\t#cm\n",
+      "g = 9.81 \t\t\t#m/s**2\n",
+      "\t\t\t\n",
+      "#calculations\n",
+      "z = d**2 *d*2/d**2\n",
+      "w = math.sqrt(z*2*g/(d/2)**2 *100)\n",
+      "N = w/(2*math.pi) *60\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Speed of rotation  =  %d rpm\"%(N)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Speed of rotation  =  378 rpm\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.19 Page No : 82"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "from scipy.integrate import quad\n",
+      "\t\t\t\n",
+      "#Initialization of variables\n",
+      "dia = 1. \t\t\t#diameter - m\n",
+      "h = 3. \t\t\t    #height - m\n",
+      "rho = 1000. \t\t#kg/m**3\n",
+      "N = 80. \t\t\t#rpm\n",
+      "g = 9.81 \t\t\t#m/s**2\n",
+      "\n",
+      "#calculation\n",
+      "w = 2*math.pi*N/60\n",
+      "def  fun(r):\n",
+      "    return 0.5*rho*w**2 *r**3 *2*math.pi\n",
+      "\n",
+      "vec = quad(fun,0,dia/2)\n",
+      "Pt = vec[0] + math.pi/4 *dia**2 *(h-dia)*rho*g\n",
+      "\t\t\t\n",
+      "#results\n",
+      "print \"Total pressure on base  =  %.2f kN\"%(Pt/1000)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Total pressure on base  =  18.85 kN\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file