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-{
- "metadata": {
- "name": "",
- "signature": "sha256:f00e66b23ba11c1502ba60271f6e9b549183dbf77dfd61ae21a7394bb7c1f4ce"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 19 - Photochemistry"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - pg 488"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Overall transmittance\n",
- "#Initialization of variables\n",
- "r1=0.727\n",
- "r2=0.407\n",
- "#calculations\n",
- "r3=r1*r2\n",
- "#results\n",
- "print '%s %.3f' %(\"Overall transmittance = \",r3)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Overall transmittance = 0.296\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - pg 488"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Extinction coefficient\n",
- "import math\n",
- "#Initialization of variables\n",
- "r=0.450\n",
- "c=0.02 #M\n",
- "l=4 #cm\n",
- "#calculations\n",
- "e=-math.log10(r) /(c*l)\n",
- "#results\n",
- "print '%s %.2f %s' %(\"Extinction coefficient =\",e,\"litres mole^-1 cm^-1\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Extinction coefficient = 4.33 litres mole^-1 cm^-1\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3 - pg 488"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Transmittance of the solution\n",
- "#Initialization of variables\n",
- "import math\n",
- "from math import log10\n",
- "r1=0.850\n",
- "r2=0.50\n",
- "#calculations\n",
- "Da=-log10(r1)\n",
- "Db=-log10(r2)\n",
- "D=Da+Db\n",
- "r3=10**(-D)\n",
- "#results\n",
- "print '%s %.3f' %(\"Transmittance of solution =\",r3)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Transmittance of solution = 0.425\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4 - pg 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Extinction coefficient\n",
- "#Initialization of variables\n",
- "c=0.000025 #M\n",
- "l=2 #cm\n",
- "D=0.417\n",
- "#calculations\n",
- "e=D/(c*l)\n",
- "#result\n",
- "print '%s %d %s' %(\"Extinction coefficient =\",e,\" liters mole^-1 cm^-1\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Extinction coefficient = 8340 liters mole^-1 cm^-1\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5 - pg 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Kc for dissociation\n",
- "#Initialization of variables\n",
- "c=0.5 #M\n",
- "c1=0.000025 #M\n",
- "D2=0.280\n",
- "D1=0.417\n",
- "#calculations\n",
- "c2=D2*c1/(D1)\n",
- "dC=c1-c2\n",
- "SCN=c- 6*c2 -4*dC\n",
- "K=dC*SCN**2 /c2\n",
- "#results\n",
- "print '%s %.2f %s' %(\"Kc for dissociation =\",K,\" M^2\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Kc for dissociation = 0.12 M^2\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6 - pg 492"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the value of m\n",
- "#Initialization of variables\n",
- "import math\n",
- "from math import log\n",
- "D2=0.249\n",
- "D1=0.172\n",
- "a2=0.00752\n",
- "a1=0.00527\n",
- "#calculations\n",
- "m=(log(D2) -log(D1))/(log(a2) - log(a1))\n",
- "#results\n",
- "print '%s %.2f' %(\"m = \",m)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "m = 1.04\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7 - pg 495"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Increase in optical density\n",
- "#Initialization of variables\n",
- "c=0.1 #M\n",
- "V=100 #ml\n",
- "v1=25 #ml\n",
- "D=0.980\n",
- "d1=0.090\n",
- "d2=0.150\n",
- "#calculations\n",
- "a=v1*c/V\n",
- "b=(V-v1)*c/V\n",
- "Da=a*d1/c\n",
- "Db=b*d2/c\n",
- "Ddash=Da+Db\n",
- "dD=D-Ddash\n",
- "#results\n",
- "print '%s %.3f' %(\"Increase in optical density =\",dD)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Increase in optical density = 0.845\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8 - pg 496"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the value of lambda for the reaction to occur\n",
- "#Initialization of variables\n",
- "E=50000. #cal/mol\n",
- "#calculations\n",
- "lam=2.8593/E\n",
- "#results\n",
- "print '%s %d %s' %(\"For the reaction to occur lambda <\",lam*10**8,\"A\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "For the reaction to occur lambda < 5718 A\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 9 - pg 497"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Amount of reactant disappeared\n",
- "#Initialization of variables\n",
- "lam=3000*10**-8 #cm\n",
- "ield=0.420\n",
- "Et=70000 #cal\n",
- "#calculations\n",
- "E=2.8593/lam\n",
- "n=ield*Et/E\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Amount of reactant disappeared =\",n,\" mol\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Amount of reactant disappeared = 0.308 mol\n"
- ]
- }
- ],
- "prompt_number": 10
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file