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authorkinitrupti2017-05-12 18:40:35 +0530
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-{
- "metadata": {
- "name": "",
- "signature": "sha256:f0bae5619ed9c3242b82c3fadf724693800c27dd8d5dc8811bfb1cb1c626c969"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter14-Thermionic Generation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4.1-pg738"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##Ex.14.4.1.;Calculate the efficiency of the generator and also compare with the carnot efficiency\n",
- "import math\n",
- "##cathode work funtion \n",
- "flux_c=2.5;##unit=volts\n",
- "##anode work funtion \n",
- "flux_a=2.;##unit=volts\n",
- "##Temp. of cathode\n",
- "Tc=2000.;##unit=degree k\n",
- "##Temp. of surrounding\n",
- "Ts=1000.;##unit=degree k\n",
- "##plasma potentail drop\n",
- "flux_p=0.1;##unit=volts\n",
- "##Net output voltage\n",
- "V=flux_c-flux_a-flux_p\n",
- "print'%s %.2f %s'%(\" V=\",V,\" volt\");\n",
- "##charge of an electron\n",
- "e=1.6*10**-19;##unit=coulomb\n",
- "##boltzmann constant\n",
- "k=1.38*10**-23;##unit=joule/degree kelvin\n",
- "A=1.20*10**6;\n",
- "##one electron volt=1.6*10**-19 joule\n",
- "##The net current in the generator J=J_cathode-J_anode\n",
- "##let EC=e**(-flux_c/k*Tc)\n",
- "EC=math.e**(-(1.6*10**-19*flux_c)/(k*Tc));\n",
- "J_cathode=A*(Tc*Tc)*EC##J_cathode=A*Tc**2*e**(-flux_c/k*Tc)\n",
- "print'%s %.2f %s'%(\"\\n J_cathode=\",J_cathode,\" amp/m^2\");\n",
- "##let EA=e**(-flux_c/k*Ts)\n",
- "EA=math.e**(-(1.6*10**-19*flux_a)/(k*Ts));\n",
- "J_anode=A*(Ts**2)*EA;##J_cathode=A*Ts**2*e**(-flux_c/k*Ts)\n",
- "print'%s %.2f %s'%(\"\\n J_anode=\",J_anode,\" amp/m^2\");\n",
- "##The net current can be taken =Jc,as Ja can be neglected in comparison with Jc\n",
- "J=J_cathode;\n",
- "print'%s %.2f %s'%(\"\\n J=\",J,\" amp/m^2\");\n",
- "##The heat supplied to the cathode Qc/Ac=J(flux_c+((2*k*Tc)/e))+samestion of sigma*(Tc**4-Ts**4)\n",
- "##let QA=Qc/Ac; and\n",
- "a=2.5+((2*1.38*10**-23*2000.)/(1.6*10**-19));\n",
- "b=J*a;\n",
- "c=(0.2*5.67*(10**-12)*(10**-4)*((2000**4)-(1000**4)));\n",
- "##therefore\n",
- "QA=b+c; ##since: QA=(J*(2.5+((2*(1.38*10**-23)*2000*)/(1.6*10**-19))))+(0.2*5.67*(10**-12)*(10**-4)*((2000**4)-(1000**4)))\n",
- "print'%s %.2f %s'%(\"\\n The heat supplied to the cathode Qc/Ac=\",QA,\" watt/m^2\");\n",
- "##efficiency of the generator\n",
- "ng=((J*V)/(7.026*10**6))*100.;\n",
- "print'%s %.2f %s'%(\"\\n ng=\",ng,\" persent\");\n",
- "##carnot efficiency this device\n",
- "T1=2000;\n",
- "T2=1000;\n",
- "T=2000;\n",
- "nc=((T1-T2)/T)*100;\n",
- "print'%s %.2f %s'%(\"\\n nc=\",nc,\" persent\");\n",
- "\n",
- "\n",
- "##Value of \"The heat supplied to the cathode Qc/Ac\" is given wrong\n",
- "##value of charge e is taken wrong;corrected by giving value 1.6*10**-19\n",
- "##value of J anode is differ from calculated value. \n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " V= 0.40 volt\n",
- "\n",
- " J_cathode= 2438475.02 amp/m^2\n",
- "\n",
- " J_anode= 102.00 amp/m^2\n",
- "\n",
- " J= 2438475.02 amp/m^2\n",
- "\n",
- " The heat supplied to the cathode Qc/Ac= 6937461.44 watt/m^2\n",
- "\n",
- " ng= 13.88 persent\n",
- "\n",
- " nc= 0.00 persent\n"
- ]
- }
- ],
- "prompt_number": 2
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file