removing problem statements

1 files changed, 0 insertions, 33 deletions

diff --git a/Materials_science_and_engineering_an_introduction/CH6.ipynb b/Materials_science_and_engineering_an_introduction/CH6.ipynb
index e04ca9e8..490f5d5d 100644
--- a/Materials_science_and_engineering_an_introduction/CH6.ipynb
+++ b/Materials_science_and_engineering_an_introduction/CH6.ipynb
@@ -27,17 +27,13 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Elongation (Elastic) Computation\n",

       "\n",

       "E=110*10**3  #Young's modulus of Copper in MPa\n",

       "sigma=276.0    #Applied stress in MPa\n",

       "lo=305.0       #Original length in mm\n",

       "\n",

-      "#Calculation\n",

-      "#Deformation\n",

       "dl=sigma*lo/E\n",

       "\n",

-      "#Result\n",

       "print\"Elongation obtained is  \",round(dl,2),\"mm\"\n",

       "\n"

      ],

@@ -66,21 +62,17 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Computation of Load to Produce Specified Diameter Change\n",

       "\n",

-      "#Given\n",

       "del_d=-2.5*10**-3  #Deformation in dia  in mm\n",

       "d0=10.0             #Initial dia  in mm\n",

       "v=0.34           #Poisson ratio for brass\n",

       "\n",

-      "#Calculation\n",

       "ex=del_d/d0\n",

       "ez=-ex/v\n",

       "E=97*10**3        #Modulus of elasticity in MPa\n",

       "sigma=ez*E\n",

       "F=sigma*math.pi*(d0**2)/4.0\n",

       "\n",

-      "#Result\n",

       "print\"Applied force is \",round(F,0),\"N\"\n",

       "\n"

      ],

@@ -109,30 +101,22 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#From draph in the question\n",

-      "#stress and strain can be obtained\n",

       "\n",

-      "#Given\n",

       "si2=150           # in MPa\n",

       "si1=0\n",

       "e2=0.0016\n",

       "e1=0\n",

       "d0=12.8*10**-3    #Initial Diameter in m\n",

       "\n",

-      "#Calculation\n",

-      "#(a)Young's Modulus = stress/strain\n",

       "E=(si2-si1)/(e2-e1)\n",

       "\n",

       "A0=math.pi*d0**2/4.0\n",

       "sig=450*10**6     #tensile strength in MPa\n",

       "F=sig*A0\n",

-      "#From stress-strain curve\n",

-      "#Strain corresponding to stress of 345 MPa is 0.06\n",

       "l0=250     #Initial lengt in mm\n",

       "e=0.06     #strain\n",

       "dl=e*l0\n",

       "\n",

-      "#Result\n",

       "print\"Modulus of elasticity is \",round(E/10**3,1),\"GPa\"\n",

       "print\"From the graph the Yield strength is\",l0,\"MPa\"\n",

       "print\"Maximum load sustained is \",round(F,0),\"N/n\"\n",

@@ -168,17 +152,12 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Ductility\n",

       "\n",

-      "#Given\n",

       "di=12.8     #Initial dia in mm\n",

       "df=10.7     #Final dia  in mm\n",

       "\n",

-      "#Calculation\n",

       "import math\n",

-      "#Ductility in terms of Reduction Area \n",

       "RA = ((di**2-df**2)/di**2)*100\n",

-      "#True-Stress-At-Fracture Computations\n",

       "Ao=math.pi*di**2*10**-6/4.0\n",

       "sig=460*10**6    #Tensile strength\n",

       "\n",

@@ -187,7 +166,6 @@
       "Af=math.pi*df**2/4.0\n",

       "sig_t=F/Af\n",

       "\n",

-      "#Result\n",

       "print\"percent reduction in area is \",round(RA,0),\"%\"\n",

       "print\"True stress is \",round(sig_t,1),\"MPa\"\n",

       "\n"

@@ -218,16 +196,13 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Calculation of Strain-Hardening Exponent\n",

       "\n",

       "sig_t=415       #True stress in MPa\n",

       "et=0.1          #True strain\n",

       "K=1035.0         # In MPa\n",

       "\n",

-      "#Calculation\n",

       "n=(math.log(sig_t)-math.log(K))/math.log(et)\n",

       "\n",

-      "#Result\n",

       "print\"Strain - hardening coefficient is \",round(n,2)\n",

       "\n"

      ],

@@ -256,20 +231,16 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Average Computations\n",

       "\n",

-      "#Tensile strength at 4 points\n",

       "n=4.0        #No of points\n",

       "T1=520\n",

       "T2=512\n",

       "T3=515\n",

       "T4=522\n",

       "\n",

-      "#Calculation\n",

       "Tav=(T1+T2+T3+T4)/n\n",

       "s=(((T1-Tav)**2+(T2-Tav)**2+(T3-Tav)**2+(T4-Tav)**2)/(n-1))**(0.5)\n",

       "\n",

-      "#Result\n",

       "print\"The average Tensile strength is\",round(Tav,0),\"MPa\"\n",

       "print\"The standard deviation  is\",round(s,1),\"MPa\""

      ],

@@ -299,18 +270,14 @@
      "cell_type": "code",

      "collapsed": false,

      "input": [

-      "#Specification of Support Post Diameter\n",

       "\n",

-      "#Given\n",

       "sig_y=310.0      #Minimum yield strength in MPa\n",

       "N=5.0            # Conservative factor of safety\n",

       "\n",

-      "#Calculation\n",

       "F=220000/2.0    #Two rods must support half of the total force\n",

       "sig_w=sig_y/N\n",

       "d=2*math.sqrt(F/(math.pi*sig_w))\n",

       "\n",

-      "#Result\n",

       "print\"Diameter of each of the two rods is \",round(d,1),\"mm\"\n",

       "\n"

      ],