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| author | debashisdeb | 2014-06-20 15:42:42 +0530 |
|---|---|---|
| committer | debashisdeb | 2014-06-20 15:42:42 +0530 |
| commit | 83c1bfceb1b681b4bb7253b47491be2d8b2014a1 (patch) | |
| tree | f54eab21dd3d725d64a495fcd47c00d37abed004 /Materials_science_and_engineering_an_introduction/CH20.ipynb | |
| parent | a78126bbe4443e9526a64df9d8245c4af8843044 (diff) | |
| download | Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.gz Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.bz2 Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.zip | |
removing problem statements
Diffstat (limited to 'Materials_science_and_engineering_an_introduction/CH20.ipynb')
| -rw-r--r-- | Materials_science_and_engineering_an_introduction/CH20.ipynb | 13 |
1 files changed, 0 insertions, 13 deletions
diff --git a/Materials_science_and_engineering_an_introduction/CH20.ipynb b/Materials_science_and_engineering_an_introduction/CH20.ipynb index c410a6ac..b3d2e8d5 100644 --- a/Materials_science_and_engineering_an_introduction/CH20.ipynb +++ b/Materials_science_and_engineering_an_introduction/CH20.ipynb @@ -27,9 +27,7 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "# Calculation of saturation magnetisation and flux density for Nickel\n",
"\n",
- "#Given\n",
"b_m=9.27*10**-24 #ampere*m**2 (Bohr Magneton)\n",
"Na=6.023*10**23 #atoms/mol (Avogadro's No.)\n",
"d=8.9*10**6 #g/m**3 (density)\n",
@@ -37,13 +35,9 @@ "A=58.71 #g/mol (Atomic weigth of Nickel)\n",
"N=d*Na/A #No. of atoms per cubic meter\n",
"\n",
- "#Calculation\n",
- "# M is saturation magnetisation\n",
"M=0.6*b_m*N #0.6= Bohr Magneton/atom\n",
- "#B = Saturation Flux Density\n",
"B=uo*M\n",
"\n",
- "#Result\n",
"print\"Saturation Magnetisation is \",M,\"A/m\"\n",
"print\"Saturation Flux Density is \",round(B,2),\"Tesla\"\n"
],
@@ -73,14 +67,11 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "# Calculation of saturation magnetisation of Fe3O4\n",
"\n",
- "#Given\n",
"a=0.839*10**-9 #a is edge length in m\n",
"b_m=9.27*10**-24 #ampere*m**2 (Bohr Magneton)\n",
"nb=8*4 #8 is no. of Fe++ ions per unit cell\n",
" #4 is Bohr magnetons per Fe++ ion\n",
- "#Calculation\n",
"M=nb*b_m/a**3 #M is Saturation magnetisation\n",
"\n",
"print\"Saturation Magnetisation is \",round(M,0),\"A/m\"\n",
@@ -111,21 +102,17 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "#Design Example 20.1: Designing a cubic mixed-ferrite magnetic material\n",
"\n",
- "#Given\n",
"Ms_Fe=5.25*10**5 #Required saturation Magnetisation\n",
"b_m=9.27*10**-24 #ampere*m**2 (Bohr Magneton)\n",
"a=0.839*10**-9 #a is edge length in m\n",
"M=5*10**5 #From previous question result\n",
"\n",
- "#Calculation\n",
"nb=Ms_Fe*a**3/b_m\n",
"i=8 # No of Divalent ions per unit cell\n",
"j=4 #4 is Bohr magnetons per Mn++ ion\n",
"n=nb/(i)-j \n",
" \n",
- "#Result\n",
"print\"Replacing percent of Fe++ with Mn++ would produce the required saturation magnetisation\",round(n*100,2)\n",
"\n"
],
|