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author | hardythe1 | 2014-07-28 14:01:58 +0530 |
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committer | hardythe1 | 2014-07-28 14:01:58 +0530 |
commit | 7876eeaf85f7c020ec1f3530963928cd2bc26a66 (patch) | |
tree | 67f4da564402aeb9869eaaf6f1e83ec7f1f75aa9 /Material_Science_In_Engineering/ch17.ipynb | |
parent | 1c1ea29e3e213559fef5f928df109b7d17c21f24 (diff) | |
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diff --git a/Material_Science_In_Engineering/ch17.ipynb b/Material_Science_In_Engineering/ch17.ipynb new file mode 100755 index 00000000..87b2a98d --- /dev/null +++ b/Material_Science_In_Engineering/ch17.ipynb @@ -0,0 +1,104 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 17 : Ceramics and Plastics" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 17.1 pageno : 467" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "mc = 12.;\t\t\t#mol wt of carbon\n", + "mh = 1.;\t\t\t#mol wt of hydrogen\n", + "m = 8.*(mc+mh);\t\t\t#mol wt of C8H8\n", + "DOP = 10000.;\t\t\t#degree of polarization , given\n", + "\n", + "# Calculations\n", + "mp = DOP*m;\n", + "\n", + "# Results\n", + "print \"Molecualr weight of Styrene polymer = %.2e \"%mp\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Molecualr weight of Styrene polymer = 1.04e+06 \n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 17.2 pageno : 468" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "DOP = 100000.;\n", + "mc = 12.;\t\t\t#mol wt of carbon\n", + "mf = 19.;\t\t\t#mol wt of fluorine\n", + "\n", + "# Calculations\n", + "m = (2*mc)+(4*mf);\t\t\t#mol wt of teflon monomer\n", + "mp = DOP*m;\n", + "mh = 1.;\t\t\t#mol wt of hydrogen\n", + "m1 = (2*mc)+(4*mh);\t\t\t#mol wt of polyethylene\n", + "#for same DOP\n", + "x = m/m1;\t\t\t#ratio of molecular weights\n", + "\n", + "# Results\n", + "print \"Molecualr weight of Teflon polymer = %e\"%mp\n", + "print \"Ratio of molecualr weights of Teflon and Polyethylene = %.2f\"%x\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Molecualr weight of Teflon polymer = 1.000000e+07\n", + "Ratio of molecualr weights of Teflon and Polyethylene = 3.57\n" + ] + } + ], + "prompt_number": 6 + } + ], + "metadata": {} + } + ] +}
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