Added(A)/Deleted(D) following books

 A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter10_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter12_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter13_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter14_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter15_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter16_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter1_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter2_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter6_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter7_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter8_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter9_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:01:00_1.png
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:01:25_1.png
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:02:44_1.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/chapter1.ipynb
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/chapter3.ipynb
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/1.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/2.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/3.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter10_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter11_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter12_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter13_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter14_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter15_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter1_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter2_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter3_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter4_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter5_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter6_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter7_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:50:16.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:52:27.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:53:23.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch1.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch10.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch11.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch12.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch2.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch3.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch4.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch5.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch6.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch7.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch8.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch9.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/Ch9MolFracNMolVol.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/Ch9_molarFracNMolVol.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/ch10_consistency.png
A  Machine_Design_by_T._H._Wentzell,_P._E/README.txt
A  Microwaves_and_Radar_Principles_and_Applications_by_A._K._Maini/README.txt
A  Network_Analysis_and_Synthesis_by_B_R_Gupta/README.txt

1 files changed, 580 insertions, 0 deletions

diff --git a/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch8.ipynb b/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch8.ipynb
new file mode 100644
index 00000000..c35a6a24
--- /dev/null
+++ b/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch8.ipynb
@@ -0,0 +1,580 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 8 - Refrigeration and liquifaction processes"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.1 Page: 297"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.1 - Page: 297\n",
+      "\n",
+      "\n",
+      "The coeffecient of performance of the cycle is 7.91\n",
+      "\n",
+      "The power required is 3.79 kW\n",
+      "\n",
+      "The rate of heat rejection in the room is 33.79 kW\n"
+     ]
+    }
+   ],
+   "source": [
+    "from __future__ import division\n",
+    "print \"Example: 8.1 - Page: 297\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Tl = 273 - 4## [K]\n",
+    "Th = 273 + 30## [K]\n",
+    "Ql = 30## [kW]\n",
+    "#*************\n",
+    "\n",
+    "# Solution (a)\n",
+    "COP = Tl/(Th - Tl)#\n",
+    "print \"The coeffecient of performance of the cycle is %.2f\\n\"%(COP)\n",
+    "\n",
+    "# Solution (b)\n",
+    "Wnet = Ql/COP## [kW]\n",
+    "print \"The power required is %.2f kW\\n\"%(Wnet)\n",
+    "\n",
+    "# Solution (c)\n",
+    "Qh = Wnet + Ql## [kW]\n",
+    "print \"The rate of heat rejection in the room is %.2f kW\"%(Qh)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.2 Page: 298"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.2 - Page: 298\n",
+      "\n",
+      "\n",
+      "The power consumption is 0.735 kW\n",
+      "\n",
+      "Cooling Effect produced is 2.862 kW\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.2 - Page: 298\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Tl = -10 + 273## [K]\n",
+    "Th = 45 + 273## [K]\n",
+    "Ql = 1## [ton]\n",
+    "#*************\n",
+    "\n",
+    "# Solution (a)\n",
+    "COP = Tl/(Th - Tl)#\n",
+    "Wnet = Ql*3.516/COP## [kW]\n",
+    "print \"The power consumption is %.3f kW\\n\"%(Wnet)\n",
+    "\n",
+    "# Solution (b)\n",
+    "Tl = -20 + 273## [K]\n",
+    "Th = 45 + 273## [K]\n",
+    "COP = Tl/(Th - Tl)#\n",
+    "Ql = Wnet*COP## [kW]\n",
+    "print \"Cooling Effect produced is %.3f kW\\n\"%(Ql)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.3 Page: 298"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.3 - Page: 298\n",
+      "\n",
+      "\n",
+      "Increase in percentage of work output is 22.97 %\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.3 - Page: 298\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "# From Example 8.2:\n",
+    "\n",
+    "# For refrigerated space:\n",
+    "# Wnet = Ql/4.78 = 0.209*Ql\n",
+    "\n",
+    "# For freezer box.\n",
+    "# Wnet = Ql/3.89 = 0.257*Ql\n",
+    "\n",
+    "percent = ((0.257 - 0.209)/0.209)*100#\n",
+    "print \"Increase in percentage of work output is %.2f %%\"%(percent)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.4 Page: 299"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.4 - Page: 299\n",
+      "\n",
+      "\n",
+      "Coeffecient of performance of Carnot Heat Pump is 12.38\n",
+      "\n",
+      "Power input can be estimated as 2.02 kW\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.4 - Page: 299\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Th = 273 + 24## [K]\n",
+    "Tl = 0 + 273## [K]\n",
+    "Qh = 25## [kW]\n",
+    "#*************\n",
+    "\n",
+    "COP = Th/(Th - Tl)#\n",
+    "Wnet = Qh/COP## [kW]\n",
+    "print \"Coeffecient of performance of Carnot Heat Pump is %.2f\\n\"%(COP)#\n",
+    "print \"Power input can be estimated as %.2f kW\\n\"%(Wnet)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.5 Page: 299"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.5 - Page: 299\n",
+      "\n",
+      "\n",
+      "Minimum Power input required is 1.669 kW\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.5 - Page: 299\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Tl = -2 + 273## [K]\n",
+    "Th = 20 + 273## [K]\n",
+    "Qh = 80000## [kJ/h]\n",
+    "#*************\n",
+    "\n",
+    "Ql = Qh*Tl/Th## [kJ/h]\n",
+    "Wnet = Qh - Ql## [kJ/h]\n",
+    "print \"Minimum Power input required is %.3f kW\\n\"%(Wnet/3600)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.6 Page: 303"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.6 - Page: 303\n",
+      "\n",
+      "\n",
+      "Enthalpy of saturated vapour is 6.65\n",
+      "\n",
+      "Refrigerating Effect is 113 kJ/kg\n",
+      "\n",
+      "The COP of an ideal Carnot refrigerator is 6.83\n",
+      "\n",
+      "Work done by the compression is 17.00 kJ/kg\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.6 - Page: 303\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Tl = 273## [K]\n",
+    "Th = 313## [K]\n",
+    "H1 = 187## [Enthalpy of saturated vapour at 273 K, kJ/kg]\n",
+    "H3 = 74## [Enthalpy of saturated liquid at 313 K,kJ/kg]\n",
+    "H4 = H3## [kJ/kg]\n",
+    "H2 = 204## [Enthalpy of Supersaturated Vapour at 273 K, kJ/kg]\n",
+    "#****************\n",
+    "\n",
+    "# Solution (i)\n",
+    "# COP = Ql/Wnet#\n",
+    "COP = ((H1 - H4)/(H2 - H1))#\n",
+    "print \"Enthalpy of saturated vapour is %.2f\\n\"%(COP)\n",
+    "\n",
+    "# Solution (ii)\n",
+    "Ref_Effect = H1 - H4## [kJ/kg]\n",
+    "print \"Refrigerating Effect is %d kJ/kg\\n\"%(Ref_Effect)\n",
+    "\n",
+    "# Solution (iii)\n",
+    "COP = Tl/(Th - Tl)#\n",
+    "print \"The COP of an ideal Carnot refrigerator is %.2f\\n\"%(COP)\n",
+    "\n",
+    "# Solution (iv)\n",
+    "W = H2 - H1## [kJ/kg]\n",
+    "print \"Work done by the compression is %.2f kJ/kg\\n\"%(W)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.7 Page: 304"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.7 - Page: 304\n",
+      "\n",
+      "\n",
+      "Amount of heat removed from cold space is 9.18 kW\n",
+      "\n",
+      "THe power input required is 1.92 kW\n",
+      "\n",
+      "COP of refrigeration of cycle is 4.77\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.7 - Page: 304\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "P1 = 0.18## [MPa]\n",
+    "T1 = -10 + 273## [K]\n",
+    "mdot = 0.06## [kg/s]\n",
+    "P2 = 1## [MPa]\n",
+    "T2 = 45 + 273## [K]\n",
+    "T = 273 + 29## [K]\n",
+    "P = 0.75## [MPa]\n",
+    "H1 = 245.16## [Enthalpy of superheated vapour at -10 OC & 0.18 MPa, kJ/kg]\n",
+    "H2 = 277.2## [Enthalpy of superheated vapour at 45 OC & 1 MPa, kJ/kg]\n",
+    "H3 = 92.22## [Enthalpy of saturated liquid at 29 OC & 0.75 MPa, kJ/kg]\n",
+    "H4 = H3## [kJ/kg]\n",
+    "#*************\n",
+    "\n",
+    "# Solution (a)\n",
+    "Ql = mdot*(H1 - H4)## [kW]\n",
+    "print \"Amount of heat removed from cold space is %.2f kW\\n\"%(Ql)\n",
+    "\n",
+    "# Solution (b)\n",
+    "Wnet = mdot*(H2 - H1)## [kW]\n",
+    "print \"THe power input required is %.2f kW\\n\"%(Wnet)\n",
+    "\n",
+    "# Solution (c)\n",
+    "COP = Ql/Wnet#\n",
+    "print \"COP of refrigeration of cycle is %.2f\\n\"%(COP)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.8 Page: 305"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.8 - Page: 305\n",
+      "\n",
+      "\n",
+      "Mass flow rate of the refrigerant is 0.1546 kg/s\n",
+      "\n",
+      "Power consumption in the compression is 4.57 kW\n",
+      "\n",
+      "The amount of heat rejected in the condenser is 22.15 kW\n",
+      "\n",
+      "Relative COP is 0.78\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.8 - Page: 305\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Ql = 5## [tons]\n",
+    "Tl = -10 + 273## [K]\n",
+    "Th = 35 + 273## [K]\n",
+    "eta = 0.85#\n",
+    "H1 = 183.2## [Enthalpy of saturated vapour at 263 K, kJ/kg]\n",
+    "H2 = 208.3## [Enthalpy of superheated vapour, kJ/kg]\n",
+    "H3 = 69.5## [Enthalpy of saturated vapour at 308 K, kJ/kg]\n",
+    "H4 = H3## [kJ/kg]\n",
+    "#***************\n",
+    "\n",
+    "# Solution (a)\n",
+    "# Mass flow rate:\n",
+    "Ql = Ql*3.516## [kW]\n",
+    "mdot = Ql/(H1 - H4)## [kW]\n",
+    "print \"Mass flow rate of the refrigerant is %.4f kg/s\\n\"%(mdot)\n",
+    "\n",
+    "# Solution (b)\n",
+    "W = H2 - H1## [kJ/kg]\n",
+    "Wnet = W*mdot/eta## [kW]\n",
+    "print \"Power consumption in the compression is %.2f kW\\n\"%(Wnet)\n",
+    "\n",
+    "# Solution (c)\n",
+    "Qh = Ql + Wnet## [kW]\n",
+    "print \"The amount of heat rejected in the condenser is %.2f kW\\n\"%(Qh)\n",
+    "\n",
+    "# Solution (d)\n",
+    "COP_VapourCompression = (H1 - H4)/(H2 - H1)#\n",
+    "COP_Carnot = Tl/(Th - Tl)#\n",
+    "COP_relative = COP_VapourCompression/COP_Carnot#\n",
+    "print \"Relative COP is %.2f\\n\"%(COP_relative)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.9 Page: 308"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 10,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.9 - Page: 308\n",
+      "\n",
+      "\n",
+      "Claim is Valid and reasonable\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.9 - Page: 308\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Th = 273 + 125## [K]\n",
+    "Tl = 273 - 5## [K]\n",
+    "Ts = 273 + 28## [K]\n",
+    "COP = 2#\n",
+    "#*************\n",
+    "\n",
+    "COP_absorption = (Tl/(Ts - Tl))*((Th - Ts)/Th)#\n",
+    "if ((COP - 0.1) < COP_absorption) or ((COP + 0.1) > COP_absorption):\n",
+    "    print \"Claim is Valid and reasonable\"\n",
+    "else:\n",
+    "    print \"Claim is not Valid\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 8.10 Page: 313"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 11,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 8.10 - Page: 313\n",
+      "\n",
+      "\n",
+      "COP of Air Refrigeration System is 2.06\n",
+      "\n",
+      "Mass flow rate of the refrigerant is 1279.07 kg/h\n",
+      "\n",
+      "The work of Compression is 26.13 kW\n",
+      "\n",
+      "The work of expansion is 17.58 kW\n",
+      "\n",
+      "Net work of the system is 8.55 kW\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 8.10 - Page: 313\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data******#\n",
+    "Q = 5## [tons]\n",
+    "T1 = 253## [Temperature of the working fluid leaving the evaporator, K]\n",
+    "T2 = 303## [Temperature of the working fluid leaving the evaporator, K]\n",
+    "T3 = 303## [K]\n",
+    "Pressure_Ratio = 4#\n",
+    "C = 1.008## [kJ/kg]\n",
+    "gama = 1.4#\n",
+    "#**************\n",
+    "\n",
+    "# Solution (a)\n",
+    "T2 = T1*((Pressure_Ratio)**((gama - 1)/gama))## [K]\n",
+    "T2 = T1*(Pressure_Ratio)**((gama - 1)/gama)## [K]\n",
+    "T4 = T3/((Pressure_Ratio)**((gama - 1)/gama))## [K]\n",
+    "COP = T1/(T2 - T1)#\n",
+    "print \"COP of Air Refrigeration System is %.2f\\n\"%(COP)\n",
+    "\n",
+    "# Solution (b)\n",
+    "mdot = Q*12660/(C*(T1 - T4))## [kg/h]\n",
+    "print \"Mass flow rate of the refrigerant is %.2f kg/h\\n\"%(mdot)\n",
+    "\n",
+    "# Solution (c)\n",
+    "Wcompression = mdot*C*(T2 - T3)## [kJ/h]\n",
+    "print \"The work of Compression is %.2f kW\\n\"%(Wcompression/3600)\n",
+    "\n",
+    "# Solution (d)\n",
+    "Wexpansion = mdot*C*(T1 - T4)## [kJ/h]\n",
+    "print \"The work of expansion is %.2f kW\\n\"%(Wexpansion/3600)\n",
+    "\n",
+    "# Solution (e)\n",
+    "Wnet = Wcompression - Wexpansion## [kJ/h]\n",
+    "print \"Net work of the system is %.2f kW\\n\"%(Wnet/3600)#"
+   ]
+  }
+ ],
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