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author | debashisdeb | 2014-06-20 15:42:42 +0530 |
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committer | debashisdeb | 2014-06-20 15:42:42 +0530 |
commit | 83c1bfceb1b681b4bb7253b47491be2d8b2014a1 (patch) | |
tree | f54eab21dd3d725d64a495fcd47c00d37abed004 /Hydraulics | |
parent | a78126bbe4443e9526a64df9d8245c4af8843044 (diff) | |
download | Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.gz Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.bz2 Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.zip |
removing problem statements
Diffstat (limited to 'Hydraulics')
-rw-r--r-- | Hydraulics/Chapter_1.ipynb | 57 | ||||
-rw-r--r-- | Hydraulics/Chapter_2.ipynb | 17 | ||||
-rw-r--r-- | Hydraulics/Chapter_3.ipynb | 41 | ||||
-rw-r--r-- | Hydraulics/Chapter_4.ipynb | 34 | ||||
-rw-r--r-- | Hydraulics/Chapter_5.ipynb | 56 | ||||
-rw-r--r-- | Hydraulics/Chapter_6.ipynb | 45 |
6 files changed, 91 insertions, 159 deletions
diff --git a/Hydraulics/Chapter_1.ipynb b/Hydraulics/Chapter_1.ipynb index 558e6301..afe45972 100644 --- a/Hydraulics/Chapter_1.ipynb +++ b/Hydraulics/Chapter_1.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:64f6f7af2b4765d579e2e197e51bf5b0d4a46d9e2613b339c736b1f3c01726e3" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,7 +28,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find pressure of water\n", "\n", "#initialisation of variables\n", "h1 = 2 \t\t\t#in\n", @@ -68,11 +68,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "pressure difference in ft of water\n", - "reading of mercury\n", - "'''\n", + "\n", "\n", "#initialisation of variables\n", "a = 6 \t\t\t#ft\n", @@ -115,7 +111,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# FIND THE INTENSITY OF PRESSURE IN TERMS OF FT OF WATER AT POINTS A,B,C and D\n", "\n", "#initialisation of variables\n", "sm = 13.6\n", @@ -165,7 +160,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Reading of the pressure guage at the top of tank\n", "\n", "#initialisation of variables\n", "lm = 2 \t\t\t#ft\n", @@ -209,7 +203,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the pressure in lb/sq. in\n", + "\n", "\n", "#initialisation of variables\n", "h = 42 \t\t\t#in\n", @@ -244,7 +238,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the pressure exerted by a vertical column\n", + "\n", "\n", "#initialisation of variables\n", "h = 200 \t\t\t#ft\n", @@ -279,7 +273,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Total pressure\n", + "\n", "\n", "#initialisation of variables\n", "w = 62.4 \t\t\t#lbs/ft**3\n", @@ -316,7 +310,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Total pressure\n", + "\n", "\n", "import math \n", "\n", @@ -360,7 +354,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find total pressure\n", + "\n", "\n", "#initialisation of variables\n", "l = 2. \t\t\t#ft\n", @@ -399,12 +393,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "Total pressure\n", - "Depth\n", - "pressure in ft\n", - "'''\n", + "\n", "#initialisation of variables\n", "l = 6. \t\t\t#ft\n", "b = 4. \t\t\t#ft\n", @@ -449,11 +438,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "force exerted by the oil \n", - "position of centre of pressure\n", - "'''\n", + "\n", "\n", "import math \n", "\n", @@ -502,7 +487,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find level of water\n", "\n", "#initialisation of variables\n", "import math \n", @@ -546,7 +530,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Total comression in the promp CD\n", + "\n", "\n", "import math \n", "\n", @@ -591,11 +575,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "depth of centre of pressure\n", - "force F required to act horizontally at the top of gate\n", - "'''\n", + "\n", "\n", "import math \n", "\n", @@ -654,7 +634,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find magnitude and position of the resultant water pressure.\n", + "\n", "import math \n", "\n", "#initialisation of variables\n", @@ -710,12 +690,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "a) the resultant thrust on the base per ft length of dam\n", - "b) distribution of normal stress on base,\n", - "c) normal stress on the vertical plane at the base\n", - "'''\n", + "\n", "\n", "#initialisation of variables\n", "import math \n", @@ -774,7 +749,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Volume of concrete\n", + "\n", "\n", "#initialisation of variables\n", "W = 145. \t\t\t#lb/cu ft\n", @@ -813,7 +788,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find Depth necessary to just float the ship in river\n", + "\n", "\n", "#initialisation of variables\n", "W = 10000. \t\t\t#tons\n", diff --git a/Hydraulics/Chapter_2.ipynb b/Hydraulics/Chapter_2.ipynb index 66db0d7d..8353a544 100644 --- a/Hydraulics/Chapter_2.ipynb +++ b/Hydraulics/Chapter_2.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:e77c0ecf71b6b19d4b74c1b5653eedac5bf7ec259a0d03cbae3bef3229b3cdac" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,7 +28,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge in gal per min and also average velocities at the two sections\n", "\n", "#initialisation of variables\n", "\n", @@ -76,7 +76,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the pressure\n", "\n", "#initialisation of variables\n", "import math \n", @@ -122,7 +121,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge in gpm.\n", + "\n", "\n", "#initialisation of variables\n", "import math \n", @@ -169,7 +168,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the water pressure\n", + "\n", "\n", "#initialisation of variables\n", "\n", @@ -216,7 +215,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# calculate the flow of water in gallons per hour.\n", + "\n", "\n", "#initialisation of variables\n", "\n", @@ -264,7 +263,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find rate of flow\n", + "\n", "\n", "#initialisation of variables\n", "import math \n", @@ -310,7 +309,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the speed of the submarine\n", + "\n", "\n", "#initialisation of variables\n", "\n", @@ -349,7 +348,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the volume of air flowing \n", + "\n", "\n", "#initialisation of variables\n", "\n", diff --git a/Hydraulics/Chapter_3.ipynb b/Hydraulics/Chapter_3.ipynb index 52d98bab..6b36939a 100644 --- a/Hydraulics/Chapter_3.ipynb +++ b/Hydraulics/Chapter_3.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:97f449fad397b42ecb1501f787392dc6e0950fafed8997a70fb14e2a9c19a198" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,7 +28,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the hydraulic co-efficients.\n", "\n", "\n", "#initialisation of variables\n", @@ -81,7 +81,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Determine coefficients of velocity and contraction and discharge of the jet.\n", + "\n", "\n", "import math \n", "\n", @@ -137,12 +137,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "a) Head lost due to shock\n", - "b) pressure in the larger part of pipe\n", - "c) work done in forcing the water through the enlargement.\n", - "'''\n", + "\n", "\n", "#initialisation of variables\n", "\n", @@ -192,12 +187,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "a) discharge in cusecs\n", - "b) co-efficient of discharge\n", - "c) absolute pressure \n", - "'''\n", + "\n", "\n", "#initialisation of variables\n", "\n", @@ -245,9 +235,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "#find discharge per second\n", "\n", - "#initialisation of variables\n", "\n", "import math \n", "H = 4. \t\t\t#ft\n", @@ -284,7 +272,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the rate of discharge in gpm\n", + "\n", "\n", "import math \n", "\n", @@ -333,7 +321,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Find time required to lower the water level\n", + "\n", "\n", "import math \n", "\n", @@ -380,7 +368,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the time required to empty.\n", + "\n", "import math \n", "#initialisation of variables\n", "D = 10. \t\t\t#ft\n", @@ -421,7 +409,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find minutes will the mouthpiece empty the boiler\n", + "\n", "\n", "import math \n", "\n", @@ -461,7 +449,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the time of emptying the bath when co-efficient \n", "\n", "import math \n", "\n", @@ -504,7 +491,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find time required to reduce the difference of water levels\n", + "\n", "import math \n", "#initialisation of variables\n", "H1 = 9. \t\t\t#ft\n", @@ -544,7 +531,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "#Determine the size of a square orifice placed below the tail water level.\n", + "\n", "\n", "#initialisation of variables\n", "import math \n", @@ -584,7 +571,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find How much water will escape through the orifice d\n", + "\n", "\n", "#initialisation of variables\n", "import math \n", @@ -631,7 +618,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge in cu\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -672,7 +659,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find appropriate discharge in cu ft/sec.\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", diff --git a/Hydraulics/Chapter_4.ipynb b/Hydraulics/Chapter_4.ipynb index 9cf88603..60ede3c8 100644 --- a/Hydraulics/Chapter_4.ipynb +++ b/Hydraulics/Chapter_4.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:7c51eb85c2f5974253c21c1966c99eb7233e433431ba178d1ba6aaccb3adc83a" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,7 +28,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the length of the weir\n", + "\n", "import math\n", "#initialisation of variables\n", "p = 70. \t\t\t#per cent\n", @@ -67,7 +68,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the theoretical horse power\n", + "\n", "\n", "import math \n", "\n", @@ -111,7 +112,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge per second\n", "\n", "import math \n", "#initialisation of variables\n", @@ -166,7 +166,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find K and n\n", "\n", "import math \n", "#initialisation of variables\n", @@ -208,9 +207,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find the rate of discharge\n", - "'''\n", + "\n", "import math \n", "#initialisation of variables\n", "g = 32.2 \t\t\t#ft/sec**2\n", @@ -260,7 +257,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the length of the waste weir required.\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -301,7 +298,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge of water \n", "\n", "import math \n", "#initialisation of variables\n", @@ -344,7 +340,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the percentage error in estimating the discharge\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -384,7 +380,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find time required to lower the level of a reservoir of superficial area\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -424,7 +420,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find depth of water through this notch.\n", "\n", "import math \n", "#initialisation of variables\n", @@ -464,7 +459,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find in each case the percentage error \n", + "\n", "import math \n", "#initialisation of variables\n", "V = 20. \t\t\t#litres\n", @@ -511,7 +506,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Estimate the discharge in the channel in gallons per minute\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -555,7 +550,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Determine the discharge \n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -599,7 +594,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find discharge over this weir in gallons per hour\n", + "\n", "import math \n", "#initialisation of variables\n", "L = 6 \t\t\t#ft\n", @@ -641,7 +636,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the height of an anicut \n", + "\n", "import math \n", "#initialisation of variables\n", "W = 100 \t\t\t#ft\n", @@ -685,7 +680,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find length\n", + "\n", "import math \n", "#initialisation of variables\n", "x = 6. \t\t\t#in\n", @@ -724,7 +719,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the number of siphons required\n", "\n", "import math \n", "#initialisation of variables\n", diff --git a/Hydraulics/Chapter_5.ipynb b/Hydraulics/Chapter_5.ipynb index 7fdc90dc..a400585d 100644 --- a/Hydraulics/Chapter_5.ipynb +++ b/Hydraulics/Chapter_5.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:fe74dcaff3035e39890b266fafcf015d3afee121cbb7baf09e89820b75888c5a" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,11 +28,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "a) a channel having bottom width\n", - "b) channel whose section is an arc of a circle\n", - "'''\n", + "\n", "import math\n", "import numpy \n", "#initialisation of variables\n", @@ -75,7 +72,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the head lost\n", "\n", "import math \n", "\n", @@ -120,7 +116,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the pressure difference between two points\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -169,7 +165,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge\n", "\n", "import math \n", "#initialisation of variables\n", @@ -209,7 +204,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the size of the supply main \n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -253,7 +248,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the critical velocities \n", + "\n", "\n", "import math \n", "\n", @@ -303,7 +298,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find pressure \n", + "\n", "import math \n", "#initialisation of variables\n", "p = 0.91 \t\t\t#units\n", @@ -351,7 +346,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the value of n\n", + "\n", "from math import log10\n", "#initialisation of variables\n", "h = 1.5 # H\n", @@ -391,7 +386,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the pressure \n", "\n", "import math \n", "#initialisation of variables\n", @@ -445,7 +439,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find rate of flow \n", + "\n", "import math \n", "#initialisation of variables\n", "d = 8. \t\t\t#in\n", @@ -492,7 +486,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find discharge when the syphone is running full\n", "\n", "import math \n", "#initialisation of variables\n", @@ -538,7 +531,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the necessary height of water surface\n", + "\n", "\n", "import math \n", "\n", @@ -583,7 +576,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "#find the diameter of uniform pipe \n", "\n", "import math \n", "#initialisation of variables\n", @@ -623,7 +615,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Find the diameter of the parallel mains\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -659,7 +651,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the increase in discharge\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -704,11 +696,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "Find the velocity of flow in each pipe\n", - "'''\n", - "\n", - "import math\n", + " import math\n", "\n", "# Variables\n", "d1 = 2 # ft\n", @@ -771,7 +759,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the time taken to lower the level of water\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -812,7 +800,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the time required to empty the overhead\n", "\n", "import math \n", "#initialisation of variables\n", @@ -866,7 +853,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the time taken \n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -909,7 +896,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find diameter of the pipe and efficiency of transmission.\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -955,7 +942,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the horse-powers of the jet.\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -1000,7 +987,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find volume of flow \n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -1043,7 +1030,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find maximum power transmitted by the jet\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -1087,7 +1074,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find height\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -1128,7 +1115,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find rise of pressure in the pipe\n", "\n", "import math \n", "#initialisation of variables\n", @@ -1170,7 +1156,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find economical diameter of pipe line\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", diff --git a/Hydraulics/Chapter_6.ipynb b/Hydraulics/Chapter_6.ipynb index b60e19b9..2ab32b0e 100644 --- a/Hydraulics/Chapter_6.ipynb +++ b/Hydraulics/Chapter_6.ipynb @@ -1,6 +1,7 @@ { "metadata": { - "name": "" + "name": "", + "signature": "sha256:a578101ccbcde1509a97d02129920a3db28366bac3115a1e48214601165df384" }, "nbformat": 3, "nbformat_minor": 0, @@ -27,7 +28,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the value of C and K\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -69,7 +70,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find value of C \n", "\n", "import math \n", "#initialisation of variables\n", @@ -115,7 +115,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -160,7 +160,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find the discharge of a channel\n", + "\n", "import math \n", "#initialisation of variables\n", "d = 3. \t\t\t#ft\n", @@ -200,7 +200,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find diameter\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -245,7 +245,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find depth of water\n", + "\n", "\n", "import math \n", "\n", @@ -297,7 +297,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find height of dam\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -342,7 +342,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find depth, bottom width and top width\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -389,7 +389,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find depth, bottom width, and top width\n", + "\n", "import math \n", "#initialisation of variables\n", "Q = 1100. \t\t\t#cuses\n", @@ -432,7 +432,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find depth of channel\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -473,7 +473,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find discharge\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -514,7 +514,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find specific energy\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -561,7 +561,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find slope of free water\n", "\n", "import math \n", "#initialisation of variables\n", @@ -606,7 +605,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find height required\n", "\n", "import math \n", "#Initialization of variables\n", @@ -654,7 +652,6 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find loss in energy\n", "\n", "import math \n", "#initialisation of variables\n", @@ -699,7 +696,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find downstream depth \n", + "\n", "import math \n", "#initialisation of variables\n", "d1 = 4. \t\t\t#ft\n", @@ -735,7 +732,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find approximate length\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -785,7 +782,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find discharge through the venturi flume \n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -826,7 +823,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# find discharge and depth of flow at the throat\n", + "\n", "\n", "import math \n", "#initialisation of variables\n", @@ -870,13 +867,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "'''\n", - "find\n", - "a) discharge\n", - "b) depth of water\n", - "c) height of standing wave\n", - "d) depth of water in channel\n", - "'''\n", + "\n", "import math \n", "#initialisation of variables\n", "h1 = 8. \t\t\t#ft\n", |