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-rw-r--r--Hydraulics/Chapter_3.ipynb41
1 files changed, 14 insertions, 27 deletions
diff --git a/Hydraulics/Chapter_3.ipynb b/Hydraulics/Chapter_3.ipynb
index 52d98bab..6b36939a 100644
--- a/Hydraulics/Chapter_3.ipynb
+++ b/Hydraulics/Chapter_3.ipynb
@@ -1,6 +1,7 @@
{
"metadata": {
- "name": ""
+ "name": "",
+ "signature": "sha256:97f449fad397b42ecb1501f787392dc6e0950fafed8997a70fb14e2a9c19a198"
},
"nbformat": 3,
"nbformat_minor": 0,
@@ -27,7 +28,6 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find the hydraulic co-efficients.\n",
"\n",
"\n",
"#initialisation of variables\n",
@@ -81,7 +81,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# Determine coefficients of velocity and contraction and discharge of the jet.\n",
+ "\n",
"\n",
"import math \n",
"\n",
@@ -137,12 +137,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "'''\n",
- "find\n",
- "a) Head lost due to shock\n",
- "b) pressure in the larger part of pipe\n",
- "c) work done in forcing the water through the enlargement.\n",
- "'''\n",
+ "\n",
"\n",
"#initialisation of variables\n",
"\n",
@@ -192,12 +187,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "'''\n",
- "find\n",
- "a) discharge in cusecs\n",
- "b) co-efficient of discharge\n",
- "c) absolute pressure \n",
- "'''\n",
+ "\n",
"\n",
"#initialisation of variables\n",
"\n",
@@ -245,9 +235,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#find discharge per second\n",
"\n",
- "#initialisation of variables\n",
"\n",
"import math \n",
"H = 4. \t\t\t#ft\n",
@@ -284,7 +272,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find the rate of discharge in gpm\n",
+ "\n",
"\n",
"import math \n",
"\n",
@@ -333,7 +321,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# Find time required to lower the water level\n",
+ "\n",
"\n",
"import math \n",
"\n",
@@ -380,7 +368,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find the time required to empty.\n",
+ "\n",
"import math \n",
"#initialisation of variables\n",
"D = 10. \t\t\t#ft\n",
@@ -421,7 +409,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find minutes will the mouthpiece empty the boiler\n",
+ "\n",
"\n",
"import math \n",
"\n",
@@ -461,7 +449,6 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find the time of emptying the bath when co-efficient \n",
"\n",
"import math \n",
"\n",
@@ -504,7 +491,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find time required to reduce the difference of water levels\n",
+ "\n",
"import math \n",
"#initialisation of variables\n",
"H1 = 9. \t\t\t#ft\n",
@@ -544,7 +531,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Determine the size of a square orifice placed below the tail water level.\n",
+ "\n",
"\n",
"#initialisation of variables\n",
"import math \n",
@@ -584,7 +571,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find How much water will escape through the orifice d\n",
+ "\n",
"\n",
"#initialisation of variables\n",
"import math \n",
@@ -631,7 +618,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find the discharge in cu\n",
+ "\n",
"\n",
"import math \n",
"#initialisation of variables\n",
@@ -672,7 +659,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "# find appropriate discharge in cu ft/sec.\n",
+ "\n",
"\n",
"import math \n",
"#initialisation of variables\n",