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-{

- "metadata": {

-  "name": "",

-  "signature": "sha256:6310b6690e48041fd88dd8277353623ea538798dfeeeb9a3819409de065b2175"

- },

- "nbformat": 3,

- "nbformat_minor": 0,

- "worksheets": [

-  {

-   "cells": [

-    {

-     "cell_type": "heading",

-     "level": 1,

-     "metadata": {},

-     "source": [

-      "Chapter10:IRREVERSIBILITY AND AVAILABILITY"

-     ]

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Ex10.1:pg-386"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#example 1\n",

-      "#Calculating reversible work\n",

-      "\n",

-      "#Form the Steam Tables,the inlet and the exit state properties are \n",

-      "hi=171.95 #initial specific heat of enthalpy in kJ/kg\n",

-      "si=0.5705 #initial specific entropy in kJ/kg-K\n",

-      "se=2.1341 #final specific entropy in kJ/kg-K\n",

-      "he=765.34 #final specific heat of enthalpy in kJ/kg-K\n",

-      "m=5 #mass flow rate of feedwater in kg/s\n",

-      "q1=900/m #heat added by one of the sources in kJ/kg\n",

-      "q2=he-hi-q1 #second heat transfer in kJ/kg\n",

-      "To=25+273.3 #Temp. of the surroundings in K\n",

-      "T1=100+273.2 #temp. of reservoir of one of the source in K\n",

-      "T2=200+273.2 #temp. of reservoir of second source in K\n",

-      "wrev=To*(se-si)-(he-hi)+q1*(1-To/T1)+q2*(1-To/T2) #reversible work in kJ/kg\n",

-      "print\"\\n Hence, the irreversibility is\",round(wrev,1),\"kJ/kg\"\n"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "\n",

-        " Hence, the irreversibility is 62.0 kJ/kg\n"

-       ]

-      }

-     ],

-     "prompt_number": 1

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Ex10.2:pg-387"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#example 2\n",

-      "#Calculating reversible work\n",

-      "import math\n",

-      "#Form the Steam Tables,the inlet and the exit state properties are\n",

-      "hi=298.6 #initial specific heat of enthalpy in kJ/kg\n",

-      "si=6.8631 #initial specific entropy in kJ/kg-K\n",

-      "se=7.4664 #final specific entropy in kJ/kg-K\n",

-      "he=544.7 #final specific heat of enthalpy in kJ/kg-K\n",

-      "q=-50 #heat lost to surroundings in kJ/kg\n",

-      "w=hi-he+q #work in kJ/kg\n",

-      "To=25+273.2 #Temp. of the surroundings in K\n",

-      "P1=100 #Pressure of ambient air in kPa\n",

-      "P2=1000 #Final pressure of air after compression in kPa\n",

-      "R=0.287 #Universal gas constant in kJ/kg-K\n",

-      "wrev=To*(se-si-R*math.log(P2/P1))-(he-hi)+q*(1-To/To)#reversible work for the given change of state in kJ/kg\n",

-      "i=wrev-w #irreversibility in kJ/kg\n",

-      "print\"\\n Hence, the irreversibility is\",round(i,1),\"kJ/kg\"\n"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "\n",

-        " Hence, the irreversibility is 32.8 kJ/kg\n"

-       ]

-      }

-     ],

-     "prompt_number": 3

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Ex10.3:pg-390"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#example 3\n",

-      "#Calculating reversible work and irreversibility\n",

-      "\n",

-      "#Form the Steam Tables at state 1\n",

-      "u1=1243.5 #initial specific internal energy in kJ/kg\n",

-      "s1=4.4819 #initial specific entropy in kJ/kg-K\n",

-      "v1=28.895 #initial specific volume in m^3/kg\n",

-      "v2=2*v1 #final specific volume in kg/m^3\n",

-      "u2=u1 #initial specific internal energy in kJ/kg\n",

-      "#These two independent properties, v2 and u2 , fix state 2.The final temp. is calculated by interplotation using the data for T2=5C and v2,x=0/3928 and u=948.5 kJ/kg. For T2=10C and v2, x=0.5433 and u=1317 kJ/kg\n",

-      "T2=9.1+273.2 #final temp. in K\n",

-      "x2=0.513 #quality in final state\n",

-      "s2=4.644 #final specific entropy in kJ/kg\n",

-      "V1=1 #volume of part of A in m^3\n",

-      "m=V1/v1  #mass flow rate in kg/s\n",

-      "To=20+273.2 #Room temperature in K\n",

-      "Wrev=To*m*(s2-s1) #reversible work in kJ\n",

-      "I=Wrev #irreversibility of the process\n",

-      "print\"\\n The irreversibility is \",round(I,3),\"kJ\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "\n",

-        " The irreversibility is  1.645 kJ\n"

-       ]

-      }

-     ],

-     "prompt_number": 5

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [],

-     "language": "python",

-     "metadata": {},

-     "outputs": []

-    }

-   ],

-   "metadata": {}

-  }

- ]

-}
\ No newline at end of file