From 41f1f72e9502f5c3de6ca16b303803dfcf1df594 Mon Sep 17 00:00:00 2001
From: Thomas Stephen Lee
Date: Fri, 4 Sep 2015 22:04:10 +0530
Subject: add/remove/update books

---
 Fundamentals_Of_Thermodynamics/Chapter10.ipynb | 164 -------------------------
 1 file changed, 164 deletions(-)
 delete mode 100755 Fundamentals_Of_Thermodynamics/Chapter10.ipynb

(limited to 'Fundamentals_Of_Thermodynamics/Chapter10.ipynb')

diff --git a/Fundamentals_Of_Thermodynamics/Chapter10.ipynb b/Fundamentals_Of_Thermodynamics/Chapter10.ipynb
deleted file mode 100755
index 59bbb80a..00000000
--- a/Fundamentals_Of_Thermodynamics/Chapter10.ipynb
+++ /dev/null
@@ -1,164 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:6310b6690e48041fd88dd8277353623ea538798dfeeeb9a3819409de065b2175"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10:IRREVERSIBILITY AND AVAILABILITY"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10.1:pg-386"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#example 1\n",
-      "#Calculating reversible work\n",
-      "\n",
-      "#Form the Steam Tables,the inlet and the exit state properties are \n",
-      "hi=171.95 #initial specific heat of enthalpy in kJ/kg\n",
-      "si=0.5705 #initial specific entropy in kJ/kg-K\n",
-      "se=2.1341 #final specific entropy in kJ/kg-K\n",
-      "he=765.34 #final specific heat of enthalpy in kJ/kg-K\n",
-      "m=5 #mass flow rate of feedwater in kg/s\n",
-      "q1=900/m #heat added by one of the sources in kJ/kg\n",
-      "q2=he-hi-q1 #second heat transfer in kJ/kg\n",
-      "To=25+273.3 #Temp. of the surroundings in K\n",
-      "T1=100+273.2 #temp. of reservoir of one of the source in K\n",
-      "T2=200+273.2 #temp. of reservoir of second source in K\n",
-      "wrev=To*(se-si)-(he-hi)+q1*(1-To/T1)+q2*(1-To/T2) #reversible work in kJ/kg\n",
-      "print\"\\n Hence, the irreversibility is\",round(wrev,1),\"kJ/kg\"\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        " Hence, the irreversibility is 62.0 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10.2:pg-387"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#example 2\n",
-      "#Calculating reversible work\n",
-      "import math\n",
-      "#Form the Steam Tables,the inlet and the exit state properties are\n",
-      "hi=298.6 #initial specific heat of enthalpy in kJ/kg\n",
-      "si=6.8631 #initial specific entropy in kJ/kg-K\n",
-      "se=7.4664 #final specific entropy in kJ/kg-K\n",
-      "he=544.7 #final specific heat of enthalpy in kJ/kg-K\n",
-      "q=-50 #heat lost to surroundings in kJ/kg\n",
-      "w=hi-he+q #work in kJ/kg\n",
-      "To=25+273.2 #Temp. of the surroundings in K\n",
-      "P1=100 #Pressure of ambient air in kPa\n",
-      "P2=1000 #Final pressure of air after compression in kPa\n",
-      "R=0.287 #Universal gas constant in kJ/kg-K\n",
-      "wrev=To*(se-si-R*math.log(P2/P1))-(he-hi)+q*(1-To/To)#reversible work for the given change of state in kJ/kg\n",
-      "i=wrev-w #irreversibility in kJ/kg\n",
-      "print\"\\n Hence, the irreversibility is\",round(i,1),\"kJ/kg\"\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        " Hence, the irreversibility is 32.8 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10.3:pg-390"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#example 3\n",
-      "#Calculating reversible work and irreversibility\n",
-      "\n",
-      "#Form the Steam Tables at state 1\n",
-      "u1=1243.5 #initial specific internal energy in kJ/kg\n",
-      "s1=4.4819 #initial specific entropy in kJ/kg-K\n",
-      "v1=28.895 #initial specific volume in m^3/kg\n",
-      "v2=2*v1 #final specific volume in kg/m^3\n",
-      "u2=u1 #initial specific internal energy in kJ/kg\n",
-      "#These two independent properties, v2 and u2 , fix state 2.The final temp. is calculated by interplotation using the data for T2=5C and v2,x=0/3928 and u=948.5 kJ/kg. For T2=10C and v2, x=0.5433 and u=1317 kJ/kg\n",
-      "T2=9.1+273.2 #final temp. in K\n",
-      "x2=0.513 #quality in final state\n",
-      "s2=4.644 #final specific entropy in kJ/kg\n",
-      "V1=1 #volume of part of A in m^3\n",
-      "m=V1/v1  #mass flow rate in kg/s\n",
-      "To=20+273.2 #Room temperature in K\n",
-      "Wrev=To*m*(s2-s1) #reversible work in kJ\n",
-      "I=Wrev #irreversibility of the process\n",
-      "print\"\\n The irreversibility is \",round(I,3),\"kJ\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        " The irreversibility is  1.645 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [],
-     "language": "python",
-     "metadata": {},
-     "outputs": []
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
\ No newline at end of file
-- 
cgit