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authorkinitrupti2017-05-12 18:40:35 +0530
committerkinitrupti2017-05-12 18:40:35 +0530
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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 5: Surface Tension"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Exa 5.1"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Work (dyn cm or erg) = 5.03e+04\n",
+ "press enter key to exit\n"
+ ]
+ },
+ {
+ "data": {
+ "text/plain": [
+ "''"
+ ]
+ },
+ "execution_count": 1,
+ "metadata": {},
+ "output_type": "execute_result"
+ }
+ ],
+ "source": [
+ "#If the surface tension of a soap bubble is 0.4 N/m, what work is required to\n",
+ "#increase the diameter from 5 to 15 cm?\n",
+ "import math\n",
+ "#initialisation of variables\n",
+ "St= 0.04 \t\t\t\t\t\t\t\t\t\t\t\t\t\t\t#N/m\n",
+ "d1= 5. \t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t#cm\n",
+ "d2= 15. \t\t\t\t\t\t\t\t\t\t\t\t\t\t\t#cm\n",
+ "#CALCULATIONS\n",
+ "W= St*1000.*2*4*math.pi*(math.pow((d2/2),2)-math.pow((d1/2),2))\t\t#Work\n",
+ "#RESULTS\n",
+ "print '%s %.2e' % ('Work (dyn cm or erg) = ',W)\n",
+ "raw_input('press enter key to exit')"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Exa 5.2"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Presuure difference (lbf/ft^2) = 14.12\n",
+ "press enter key to exit\n"
+ ]
+ },
+ {
+ "data": {
+ "text/plain": [
+ "''"
+ ]
+ },
+ "execution_count": 2,
+ "metadata": {},
+ "output_type": "execute_result"
+ }
+ ],
+ "source": [
+ "#By much does the pressure inside a 0.017 in droplet of water at 20C\n",
+ "#exceed the outside pressure.\n",
+ "import math\n",
+ "#initialisation of variables\n",
+ "R= 0.017 \t\t\t\t\t\t\t\t\t\t\t\t#in\n",
+ "sigma= 72.8 \t\t\t\t\t\t\t\t\t\t\t#m N/m\n",
+ "#CALCULATIONS\n",
+ "P= (2*sigma*0.005*0.017)/(72.8*R*7.08*math.pow(10,-4))\t#Presuure difference\n",
+ "#RESULTS\n",
+ "print '%s %.2f' % ('Presuure difference (lbf/ft^2) = ',P)\n",
+ "raw_input('press enter key to exit')"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Exa 5.3"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Difference in mercury level (cm (depression)) = -2.48\n",
+ "press enter key to exit\n"
+ ]
+ },
+ {
+ "data": {
+ "text/plain": [
+ "''"
+ ]
+ },
+ "execution_count": 3,
+ "metadata": {},
+ "output_type": "execute_result"
+ }
+ ],
+ "source": [
+ "#A 0.4 mm diameter glass tube stands vertically in a dish of mercury at 20C.\n",
+ "#Determine the difference between the level of mercury in the dish and in\n",
+ "#the tube. The specific gravity for mercury is 13.6 and the contact angle \n",
+ "#with glass is 130C\n",
+ "import math\n",
+ "#initialisation of variables\n",
+ "d= 13.6 \t\t\t\t\t\t\t#gm/cm^3\n",
+ "g= 980 \t\t\t\t\t\t\t\t#cm/s^2\n",
+ "D= 0.4 \t\t\t\t\t\t\t\t#mm\n",
+ "angle= 130*math.pi/180. \t\t\t#radians\n",
+ "s= 514. \t\t\t\t\t\t\t#dyn/cm\n",
+ "#CALCULATIONS\n",
+ "h= (4*s*10*math.cos(angle))/(d*g*D)\t#Depression in mercury level\n",
+ "#RESULTS\n",
+ "print '%s %.2f' % (' Difference in mercury level (cm (depression)) = ',h)\n",
+ "raw_input('press enter key to exit')"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.6"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}