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authorkinitrupti2017-05-12 18:40:35 +0530
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-{
- "metadata": {
- "name": "",
- "signature": "sha256:3e5d8c28d726b79a2c86b3cf54d87d3c39d0c9ab36d48d833fe93313ec8fd001"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5 : Thermodynamic Potentials and Maxwell Relation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1 Page No : 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#Given\n",
- "T = 293.0;#Consmath.tant temperature in K\n",
- "w_NH3 = 20/100.0;#weight of NH3 in an aqueous solution in Kg\n",
- "w_H2O = 80/100.0;#weight of H2O in an aqueous solution in Kg\n",
- "V = 40.0;#feed rate in Kg/min\n",
- "M_NH3 = 17.0;#Molecular weight of NH3\n",
- "M_H2O = 18.0;#Molecular weight of H20\n",
- "R = 1.98;#gas consmath.tant in Kcl/Kg mole K\n",
- "V_s = 62.0;#Rate of heating steam in Kg/min\n",
- "P1_H2O = 11.6;#Vapour pressure of water in feed in mm Hg\n",
- "P2_H2O = 17.5;#Vapour pressure of pure water in mm Hg\n",
- "P1_NH3 = 227.0;#Vapour pressure of NH3 in feed in mm Hg\n",
- "P2_NH3 = 6350.0;#Vapor pressure of pure NH3 in mm Hg\n",
- "#From steam tables:\n",
- "Hs = 666.4;#Enthalpy of steam at 160 deg celsius & 2Kgf/cm**2 in Kcal /Kg \n",
- "Ss = 1.75;#Entropy of steam at 160 deg celsius & 2Kgf/cm**2V in Kcal/Kg K\n",
- "Hl = 20.03;#Enthalpy of liquid water at 20 deg celsius in Kcal/Kg\n",
- "Sl = 0.0612;#Entropy of liquid water at 20 deg celsius in Kcal/Kg K\n",
- "\n",
- "#To Calculate the efficiency of the separation process \n",
- "#Material Balance:\n",
- "n_NH3 = (V*w_NH3)/M_NH3;#Kg moles of NH3 in feed(tops)\n",
- "n_H2O = (V*w_H2O)/M_H2O;#Kg moles of H20 in feed(bottoms)\n",
- "#del_F = del_F_NH3 +del_F_H2O;\n",
- "del_F = (R*T*n_NH3*math.log(P2_NH3/P1_NH3))+(R*T*n_H2O*math.log(P2_H2O/P1_H2O));#Theoretical minimum work done in Kcal\n",
- "#The available energy of the steam can be calculated from equation 4.14(page no 110)\n",
- "del_B = -V_s*((Hl-Hs)-T*(Sl-Ss));#Available energy of the steam in Kcal\n",
- "E = (del_F/del_B)*100;\n",
- "print \"The efficiency of the separation process is %f percent\"%(E);\n",
- "#end\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The efficiency of the separation process is 14.192424 percent\n"
- ]
- }
- ],
- "prompt_number": 2
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file