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| author | debashisdeb | 2014-06-20 15:42:42 +0530 |
|---|---|---|
| committer | debashisdeb | 2014-06-20 15:42:42 +0530 |
| commit | 83c1bfceb1b681b4bb7253b47491be2d8b2014a1 (patch) | |
| tree | f54eab21dd3d725d64a495fcd47c00d37abed004 /A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb | |
| parent | a78126bbe4443e9526a64df9d8245c4af8843044 (diff) | |
| download | Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.gz Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.tar.bz2 Python-Textbook-Companions-83c1bfceb1b681b4bb7253b47491be2d8b2014a1.zip | |
removing problem statements
Diffstat (limited to 'A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb')
| -rw-r--r-- | A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb | 2076 |
1 files changed, 1034 insertions, 1042 deletions
diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb index 53a08905..581d450b 100644 --- a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb @@ -1,1043 +1,1035 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "UNIT-5 Electricity"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.1,Page no:152"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate current flowing through a conductor\n",
- "\n",
- "#Variable declaration \n",
- "n=10**6 #no. of electrons\n",
- "e=1.6*10**-19 #charge on an electron in C\n",
- "\n",
- "#Calculation\n",
- "q=n*e #calculating total charge\n",
- "t=10**-3 #time in second\n",
- "I=q/t #calculating current\n",
- "\n",
- "#Result\n",
- "print\"Current flowing = \",I,\"Ampere\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current flowing = 1.6e-10 Ampere\n"
- ]
- }
- ],
- "prompt_number": 71
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.2,Page no:152"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#No of electrons passing through a lamp\n",
- "\n",
- "#Variable declaration \n",
- "I=300*10**-3 #current n Ampere\n",
- "t=60 #time in second\n",
- "e=1.6*10**-19 #chatge on electron in C\n",
- "\n",
- "#Calculation\n",
- "q=I*t #calculating charge\n",
- "n=q/e #calculating no of electrons\n",
- "\n",
- "#Result\n",
- "print\"No. of electrons = \",n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "No. of electrons = 1.125e+20\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.3,Page no:154"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Frequency of electrons across a conductor\n",
- "\n",
- "#Variable declaration \n",
- "V=200 #voltage in volt\n",
- "R=100 #resistance in Ohm\n",
- "e=1.6*10**-19 #charge on an electron in C\n",
- "\n",
- "#Calculation\n",
- "I=V/R #Ohm's law\n",
- "t=1 #time in second\n",
- "q=I*t #calculating charge\n",
- "n=q/e #calculating no of electrons\n",
- "\n",
- "#Result\n",
- "print\"No. of electrons = \",n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "No. of electrons = 1.25e+19\n"
- ]
- }
- ],
- "prompt_number": 72
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.4,Page no:156"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Resistivity of small wire\n",
- "\n",
- "#Variable declaration \n",
- "l=15 #length in m\n",
- "A=6*10**-7 #area in m square\n",
- "R=5 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "p=(A*R)/l #calculating resistivity\n",
- "\n",
- "#Result\n",
- "print\"Resistivity= \",p,\"Ohm metre\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistivity= 2e-07 Ohm metre\n"
- ]
- }
- ],
- "prompt_number": 73
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.5,Page no:157"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Resistivity of a normal wire\n",
- "\n",
- "#Variable declaration \n",
- "l=0.1 #length in m\n",
- "A=10**-4 #area in m square\n",
- "R=0.01 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "p=(A*R)/l #calculating resistivity\n",
- "\n",
- "#Result\n",
- "print\"Resistivity = \",p,\"Ohm metre\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistivity = 1e-05 Ohm metre\n"
- ]
- }
- ],
- "prompt_number": 74
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.6,Page no:157"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Resistivity of a long wire\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "L=1 #length in m\n",
- "r=0.2*10**-3 #radius in m\n",
- "R=2 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "A=math.pi*(r)**2 #calculating area\n",
- "P=(R*A)/L #calculating resistivity\n",
- "\n",
- "#Result\n",
- "print\"Resistivity =%.2g\"%P,\"Ohm.metre\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistivity =2.5e-07 Ohm.metre\n"
- ]
- }
- ],
- "prompt_number": 38
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.7,Page no:158"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#New resistance of a wire after drawn out\n",
- "\n",
- "#Variable declaration \n",
- "R1=5 #resisitance in Ohm\n",
- "\n",
- "#Calculation\n",
- "#A2=A/3\n",
- "#R2/5=3l*3/A*A/l\n",
- "#R2=9*5\n",
- "\n",
- "R2=9*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n",
- "print\"Resisitance = \",R2,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resisitance = 45 Ohm\n"
- ]
- }
- ],
- "prompt_number": 75
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.8,Page no:159"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Change in resistance of a wire\n",
- "\n",
- "#Variable declaration \n",
- "R1=5 #resisitance in Ohm\n",
- "\n",
- "#Calculation\n",
- "#A2=A/2\n",
- "#R1=rho*l1/A1*R2\n",
- "#R2=rho*l2/A2\n",
- "#R2/R1=A1/l1\n",
- "R2=4*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n",
- "\n",
- "#Result\n",
- "print\"Resisitance= \",R2,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resisitance= 20 Ohm\n"
- ]
- }
- ],
- "prompt_number": 70
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.9,Page no:162"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Total resistance in parallel\n",
- "\n",
- "#Variable declaration \n",
- "R1=2 #resisitance in Ohm\n",
- "R2=4 #resistance in Ohm\n",
- "R3=5 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "R=(R1**-1)+(R2**-1)+(R3**-1) #calculating parallel resistance\n",
- "Rp=(1/R) \n",
- "\n",
- "#Result\n",
- "print\"Resisitance = \",Rp,\"Ohm\"\n",
- "print\"\\nNOTE:Incorrect answer in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resisitance = 1.05263157895 Ohm\n",
- "\n",
- "NOTE:Incorrect answer in book\n"
- ]
- }
- ],
- "prompt_number": 39
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.10,Page no:163"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Series parallel combination resistance\n",
- "\n",
- "from scipy.optimize import fsolve \n",
- "\n",
- "#Variable declaration\n",
- "Rs=40 #resisitance in Ohm\n",
- "\n",
- "#Calculation\n",
- "#R1+R2=40\n",
- "#R1*R2=256\n",
- "#R1=256/R2\n",
- "#Putting this value in eq 1:\n",
- "#(256/R2)+R2=40\n",
- "from sympy import solve, symbols, pprint\n",
- "R2= symbols('R2')\n",
- "a=1\n",
- "b=-40\n",
- "c=256\n",
- "f = a*R2**2 + b*R2 + c\n",
- "solution = solve(f, R2)\n",
- "\n",
- "#Result\n",
- "print\"When R2=\",solution[0],\"Ohm R1=\",solution[1],\"Ohm\"\n",
- "print\"When R2=\",solution[1],\"Ohm R1=\",solution[0],\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "When R2= 8 Ohm R1= 32 Ohm\n",
- "When R2= 32 Ohm R1= 8 Ohm\n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.11,Page no:164"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Find the valueof current in fig\n",
- "\n",
- "#Variable declaration \n",
- "V=2.0 #in volts\n",
- "R1=30.0 #resisitance in Ohm\n",
- "R2=60.0 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n",
- "I=V/Rp #Ohm's law\n",
- "\n",
- "#Result\n",
- "print\"Resisitance = \",Rp,\"Ohm\"\n",
- "print\"Current = \",I,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resisitance = 20.0 Ohm\n",
- "Current = 0.1 A\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.12,Page no:165"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Combine resistance to get an equivalent resistance\n",
- "\n",
- "#Variable declaration \n",
- "R1=2.0 #resisitance in Ohm\n",
- "R2=3.0 #resistance in Ohm\n",
- "R3=1.0 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n",
- "R=Rp+1.0 #1 Ohm in series\n",
- "Rs=(R1+R2+R3) #series resistances\n",
- "Rp=(1.0/R1)+(1.0/R2)+(1.0/R3) #calculating parallel resistance\n",
- "\n",
- "#Result\n",
- "print\"(1)Equivalent Resisitance= \",R,\"Ohm\" \n",
- "print\"(2)All resistances in series = \",Rs,\"Ohm\"\n",
- "print\"(3)All in Parallel = \",(1/Rp),\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(1)Equivalent Resisitance= 2.2 Ohm\n",
- "(2)All resistances in series = 6.0 Ohm\n",
- "(3)All in Parallel = 0.545454545455 Ohm\n"
- ]
- }
- ],
- "prompt_number": 76
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.13,Page no:166"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Total resistor of combination\n",
- "\n",
- "#Variable declaration \n",
- "V=20 #voltage in Volts\n",
- "R1=2.0 #resisitance in Ohm\n",
- "R2=4.0 #resistance in Ohm\n",
- "R3=5.0 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "Rp=(1/R1)+(1/R2)+(1/R3) #calculating parallel resistance\n",
- "R=1/Rp #Parallel\n",
- "I1=V/R1 #calculating current through R1\n",
- "I2=V/R2 #calculating current through R2\n",
- "I3=V/R3 #calculating current through R3\n",
- "I=V/R #calculating total current\n",
- "\n",
- "\n",
- "#Result\n",
- "print\"(a)Equivalent Resisitance = \",R,\"Ohm\"\n",
- "print\"Current through R1 = \",I1,\"Ampere\"\n",
- "print\"Current through R2 = \",I2,\"Ampere\" \n",
- "print\"Total current = \",I,\"Ampere\" "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a)Equivalent Resisitance = 1.05263157895 Ohm\n",
- "Current through R1 = 10.0 Ampere\n",
- "Current through R2 = 5.0 Ampere\n",
- "Total current = 19.0 Ampere\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.14,Page no:166"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate no of resistors form total resistor\n",
- "\n",
- "#Variable declaration\n",
- "R=7 #Total resistanc of combination\n",
- "\n",
- "#Calculation\n",
- "def f(n):\n",
- " Rp = 6*(1/n) #resistance in parallel\n",
- " return(R-Rp-5)\n",
- "n=fsolve(f,1)\n",
- "\n",
- "#Result\n",
- "print\"n=\",n[0]"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "n= 3.0\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.15,Page no:173"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Voltage and current in figure\n",
- "\n",
- "#Variable declaration \n",
- "R1=2 #resistance in Ohm\n",
- "R2=6 #resistance in Ohm\n",
- "R3=3 #resistance in Ohm\n",
- "V=24 #voltage in volts\n",
- "R=8 #resistance in Ohm\n",
- "\n",
- "#Calculation\n",
- "I=V/R #Ohm's Law\n",
- "V1=I*R1 #Ohm's Law\n",
- "V2=I*R2 #Ohm's Law\n",
- "V3=I*R3 #Ohm's Law\n",
- "\n",
- "#Result\n",
- "print\"Current = \",I,\"Ampere\" \n",
- "print\"Voltage drop across R1 = \",V1,\"Volts\"\n",
- "print\"Voltage drop across R2 = \",V2,\"Volts\" \n",
- "print\"Voltage drop across R3 = \",V3,\"Volts\"\n",
- "print\"\\nNOTE:Wrong answer of R3 in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current = 3 Ampere\n",
- "Voltage drop across R1 = 6 Volts\n",
- "Voltage drop across R2 = 18 Volts\n",
- "Voltage drop across R3 = 9 Volts\n",
- "\n",
- "NOTE:Wrong answer of R3 in book\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.16,Page no:173"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Current through branches of circuit\n",
- "\n",
- "#Variable declaration \n",
- "R=15 #resistance in Ohm\n",
- "print\"KVL: 16I1+15I2=6 (1)\" #KVL equation\n",
- "I1=-1.66 #from(1)\n",
- "I2=2.17 #from (1)\n",
- "#Calculation\n",
- "V=(I1+I2)*R #calculating potential difference\n",
- "\n",
- "#Result\n",
- "print\"Potential difference= \",V,\"Volt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "KVL: 16I1+15I2=6 (1)\n",
- "Potential difference= 7.65 Volt\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.17,Page no:174"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine current in wheatstone bridge\n",
- "\n",
- "print\"3I1-I2-1=0 (1)\" #KVL equation\n",
- "print\"3I1-I2+2I=2 (2)\" #KVL equation\n",
- "print\"3I1-I1+2I=2 (3)\" #KVL equation\n",
- "\n",
- "#Variable declaration\n",
- "I1=4/17.0 #from (1)(2)(3)through AB \n",
- "I2=-2/17.0 #from (1)(2)(3)through BD\n",
- "I=3*I1+I2 #from (1)(2)(3)through main circuit\n",
- "\n",
- "#Calculation\n",
- "Ibc=I1-I2 #calculating current in BC\n",
- "Iad=I-I1 #calculating current in AD\n",
- "Idc=I-I1+I2 #calculating current in DC\n",
- "\n",
- "#Result\n",
- "print\"Current in branch BC = \",Ibc,\"Ampere\"\n",
- "print\"NOTE:Calculation mistake in book while calculating for BC\"\n",
- "print\"Current in branch AD = \",Iad,\"Ampere\"\n",
- "print\"Current in branch DC = \",Idc,\"Ampere\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "3I1-I2-1=0 (1)\n",
- "3I1-I2+2I=2 (2)\n",
- "3I1-I1+2I=2 (3)\n",
- "Current in branch BC = 0.352941176471 Ampere\n",
- "NOTE:Calculation mistake in book while calculating for BC\n",
- "Current in branch AD = 0.352941176471 Ampere\n",
- "Current in branch DC = 0.235294117647 Ampere\n"
- ]
- }
- ],
- "prompt_number": 77
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.18,Page no:176"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Current through a galvanometer in wheatstone bridge\n",
- "\n",
- "#Variable declaration \n",
- "P=10 #Ohm\n",
- "Q=3 #Ohm\n",
- "R=12 #Ohm\n",
- "S=6 #Ohm\n",
- "G=20 #Ohm\n",
- "\n",
- "\n",
- "#Calculation\n",
- "print\"-12I+22I1+IgG=0 (1)\" #KVL\n",
- "print\"6I-9I1+29Ig=0 (2)\" #KVL\n",
- "print\"13I1-3Ig=2 (3)\" #KVL\n",
- "#From above equations\n",
- "import numpy as np\n",
- "a = np.array([[-12,22,20],[6,-9,29],[0,13,-3]]) \n",
- "b = np.array([[0],[0],[2]])\n",
- "np.linalg.solve(a,b)\n",
- "\n",
- "\n",
- "#Result\n",
- "print\"Current through Galvanometer = \",round(Ig*1000,2),\"mA\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "-12I+22I1+IgG=0 (1)\n",
- "6I-9I1+29Ig=0 (2)\n",
- "13I1-3Ig=2 (3)\n",
- "Current through Galvanometer = 7.8 mA\n"
- ]
- }
- ],
- "prompt_number": 78
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.19,Page no:179"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#% drop in heat in bulb\n",
- "\n",
- "#Variable declaration \n",
- "P=500 #power in Watts\n",
- "V=200 #voltage in Volts\n",
- "V1=160 #voltage in Volts\n",
- "\n",
- "#Calculation\n",
- "R=(V**2)/P #using P=V**2*R\n",
- "P1=(V1**2)/R #calculating power\n",
- "Dp=500-P1 #drop in heat\n",
- "D=(Dp*100)/500 #percentage drop\n",
- "\n",
- "#Result\n",
- "print\"Resistance= \",R,\"Ohm\"\n",
- "print\"% Drop in heat production = \",D,\"%\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance= 80 Ohm\n",
- "% Drop in heat production = 36 %\n"
- ]
- }
- ],
- "prompt_number": 79
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.20,Page no:180"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Bulbs connected in parallel\n",
- "\n",
- "#Variable declaration\n",
- "P1=100 #power in Watts\n",
- "P2=500 #power in Watts\n",
- "\n",
- "#Calculation\n",
- "P=P2/P1 #ratio\n",
- "\n",
- "#Result\n",
- "print \"P=\",P\n",
- "print\"P>0,I2=5I Therefore I2>I1\" "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "P= 5\n",
- "P>0,I2=5I Therefore I2>I1\n"
- ]
- }
- ],
- "prompt_number": 80
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.21,Page no:181"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Heat and light energy produced by bulb on voltage drop\n",
- "\n",
- "#Variable declaration \n",
- "t=1200 #time in second\n",
- "P=100 #power in Watts\n",
- "V=230 #voltage in Volts\n",
- "\n",
- "#Calculation\n",
- "R=(V**2)/P #calculating resistance\n",
- "V1=115 #supply voltage in Volts\n",
- "E=((V1**2)*t)/R #calculating energy\n",
- "\n",
- "#Result\n",
- "print\"Energy dissipated by bulb = \",E,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy dissipated by bulb = 30000 J\n"
- ]
- }
- ],
- "prompt_number": 81
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.22,Page no:181"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate effeciency of transmission\n",
- "\n",
- "#Variable declaration\n",
- "P=10**4 #power in Watts\n",
- "V=250 #voltage in Volts\n",
- "R=0.2 #resistance in ohm\n",
- "\n",
- "#Calculation\n",
- "Pl=((P/V)*(P/V))*R #calculating power loss\n",
- "print P1\n",
- "E=P/(Pl+P) #calculating efficiency\n",
- "\n",
- "#Result\n",
- "print\"Percent Efficiency = \",round(E*100),\"%\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "100\n",
- "Percent Efficiency = 97.0 %\n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.23,Page no:182"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Resistance and current capacity of a lamp\n",
- "\n",
- "#Variable declaration \n",
- "P=100.0 #power in Watts\n",
- "V=220.0 #voltage in Volts\n",
- "\n",
- "#Calculation\n",
- "I=P/V #Current in Ampere\n",
- "R=V/I #resistance\n",
- "\n",
- "#Result\n",
- "print\"Current = \",round(I,3),\"A\" \n",
- "print\"Resistance=\",R,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current = 0.455 A\n",
- "Resistance= 484.0 Ohm\n"
- ]
- }
- ],
- "prompt_number": 59
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:5.24,Page no:182"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Resistance of windings of electric motor\n",
- "\n",
- "#Variable declaration \n",
- "V=50 #voltage in Volts\n",
- "I=12 #Current in Ampere\n",
- "\n",
- "#Calculation\n",
- "P=V*I #power\n",
- "Pd=P*0.7 #power dissipated\n",
- "R=(Pd/(I)**2) \n",
- "\n",
- "#Result\n",
- "print\"Resistance = \",round(R,2),\"Ohm\" "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance = 2.92 Ohm\n"
- ]
- }
- ],
- "prompt_number": 82
- }
- ],
- "metadata": {}
- }
- ]
+{ + "metadata": { + "name": "", + "signature": "sha256:1f51544adf15fc8ba28e47ac7da1a371a1d8835331773ecfcfa211468f9b325d" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "UNIT-5 Electricity" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.1,Page no:152" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "n=10**6 #no. of electrons\n", + "e=1.6*10**-19 #charge on an electron in C\n", + "\n", + "#Calculation\n", + "q=n*e #calculating total charge\n", + "t=10**-3 #time in second\n", + "I=q/t #calculating current\n", + "\n", + "#Result\n", + "print\"Current flowing = \",I,\"Ampere\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current flowing = 1.6e-10 Ampere\n" + ] + } + ], + "prompt_number": 71 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.2,Page no:152" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "I=300*10**-3 #current n Ampere\n", + "t=60 #time in second\n", + "e=1.6*10**-19 #chatge on electron in C\n", + "\n", + "#Calculation\n", + "q=I*t #calculating charge\n", + "n=q/e #calculating no of electrons\n", + "\n", + "#Result\n", + "print\"No. of electrons = \",n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "No. of electrons = 1.125e+20\n" + ] + } + ], + "prompt_number": 20 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.3,Page no:154" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=200 #voltage in volt\n", + "R=100 #resistance in Ohm\n", + "e=1.6*10**-19 #charge on an electron in C\n", + "\n", + "#Calculation\n", + "I=V/R #Ohm's law\n", + "t=1 #time in second\n", + "q=I*t #calculating charge\n", + "n=q/e #calculating no of electrons\n", + "\n", + "#Result\n", + "print\"No. of electrons = \",n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "No. of electrons = 1.25e+19\n" + ] + } + ], + "prompt_number": 72 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.4,Page no:156" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "l=15 #length in m\n", + "A=6*10**-7 #area in m square\n", + "R=5 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "p=(A*R)/l #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity= \",p,\"Ohm metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity= 2e-07 Ohm metre\n" + ] + } + ], + "prompt_number": 73 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.5,Page no:157" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "l=0.1 #length in m\n", + "A=10**-4 #area in m square\n", + "R=0.01 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "p=(A*R)/l #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity = \",p,\"Ohm metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity = 1e-05 Ohm metre\n" + ] + } + ], + "prompt_number": 74 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.6,Page no:157" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\n", + "#Variable declaration\n", + "L=1 #length in m\n", + "r=0.2*10**-3 #radius in m\n", + "R=2 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "A=math.pi*(r)**2 #calculating area\n", + "P=(R*A)/L #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity =%.2g\"%P,\"Ohm.metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity =2.5e-07 Ohm.metre\n" + ] + } + ], + "prompt_number": 38 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.7,Page no:158" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=5 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#A2=A/3\n", + "#R2/5=3l*3/A*A/l\n", + "#R2=9*5\n", + "\n", + "R2=9*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", + "print\"Resisitance = \",R2,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 45 Ohm\n" + ] + } + ], + "prompt_number": 75 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.8,Page no:159" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=5 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#A2=A/2\n", + "#R1=rho*l1/A1*R2\n", + "#R2=rho*l2/A2\n", + "#R2/R1=A1/l1\n", + "R2=4*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", + "\n", + "#Result\n", + "print\"Resisitance= \",R2,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance= 20 Ohm\n" + ] + } + ], + "prompt_number": 70 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.9,Page no:162" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2 #resisitance in Ohm\n", + "R2=4 #resistance in Ohm\n", + "R3=5 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "R=(R1**-1)+(R2**-1)+(R3**-1) #calculating parallel resistance\n", + "Rp=(1/R) \n", + "\n", + "#Result\n", + "print\"Resisitance = \",Rp,\"Ohm\"\n", + "print\"\\nNOTE:Incorrect answer in book\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 1.05263157895 Ohm\n", + "\n", + "NOTE:Incorrect answer in book\n" + ] + } + ], + "prompt_number": 39 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.10,Page no:163" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from scipy.optimize import fsolve \n", + "\n", + "#Variable declaration\n", + "Rs=40 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#R1+R2=40\n", + "#R1*R2=256\n", + "#R1=256/R2\n", + "#Putting this value in eq 1:\n", + "#(256/R2)+R2=40\n", + "from sympy import solve, symbols, pprint\n", + "R2= symbols('R2')\n", + "a=1\n", + "b=-40\n", + "c=256\n", + "f = a*R2**2 + b*R2 + c\n", + "solution = solve(f, R2)\n", + "\n", + "#Result\n", + "print\"When R2=\",solution[0],\"Ohm R1=\",solution[1],\"Ohm\"\n", + "print\"When R2=\",solution[1],\"Ohm R1=\",solution[0],\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "When R2= 8 Ohm R1= 32 Ohm\n", + "When R2= 32 Ohm R1= 8 Ohm\n" + ] + } + ], + "prompt_number": 24 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.11,Page no:164" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=2.0 #in volts\n", + "R1=30.0 #resisitance in Ohm\n", + "R2=60.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", + "I=V/Rp #Ohm's law\n", + "\n", + "#Result\n", + "print\"Resisitance = \",Rp,\"Ohm\"\n", + "print\"Current = \",I,\"A\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 20.0 Ohm\n", + "Current = 0.1 A\n" + ] + } + ], + "prompt_number": 26 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.12,Page no:165" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2.0 #resisitance in Ohm\n", + "R2=3.0 #resistance in Ohm\n", + "R3=1.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", + "R=Rp+1.0 #1 Ohm in series\n", + "Rs=(R1+R2+R3) #series resistances\n", + "Rp=(1.0/R1)+(1.0/R2)+(1.0/R3) #calculating parallel resistance\n", + "\n", + "#Result\n", + "print\"(1)Equivalent Resisitance= \",R,\"Ohm\" \n", + "print\"(2)All resistances in series = \",Rs,\"Ohm\"\n", + "print\"(3)All in Parallel = \",(1/Rp),\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(1)Equivalent Resisitance= 2.2 Ohm\n", + "(2)All resistances in series = 6.0 Ohm\n", + "(3)All in Parallel = 0.545454545455 Ohm\n" + ] + } + ], + "prompt_number": 76 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.13,Page no:166" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=20 #voltage in Volts\n", + "R1=2.0 #resisitance in Ohm\n", + "R2=4.0 #resistance in Ohm\n", + "R3=5.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(1/R1)+(1/R2)+(1/R3) #calculating parallel resistance\n", + "R=1/Rp #Parallel\n", + "I1=V/R1 #calculating current through R1\n", + "I2=V/R2 #calculating current through R2\n", + "I3=V/R3 #calculating current through R3\n", + "I=V/R #calculating total current\n", + "\n", + "\n", + "#Result\n", + "print\"(a)Equivalent Resisitance = \",R,\"Ohm\"\n", + "print\"Current through R1 = \",I1,\"Ampere\"\n", + "print\"Current through R2 = \",I2,\"Ampere\" \n", + "print\"Total current = \",I,\"Ampere\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(a)Equivalent Resisitance = 1.05263157895 Ohm\n", + "Current through R1 = 10.0 Ampere\n", + "Current through R2 = 5.0 Ampere\n", + "Total current = 19.0 Ampere\n" + ] + } + ], + "prompt_number": 30 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.14,Page no:166" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "R=7 #Total resistanc of combination\n", + "\n", + "#Calculation\n", + "def f(n):\n", + " Rp = 6*(1/n) #resistance in parallel\n", + " return(R-Rp-5)\n", + "n=fsolve(f,1)\n", + "\n", + "#Result\n", + "print\"n=\",n[0]" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "n= 3.0\n" + ] + } + ], + "prompt_number": 33 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.15,Page no:173" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2 #resistance in Ohm\n", + "R2=6 #resistance in Ohm\n", + "R3=3 #resistance in Ohm\n", + "V=24 #voltage in volts\n", + "R=8 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "I=V/R #Ohm's Law\n", + "V1=I*R1 #Ohm's Law\n", + "V2=I*R2 #Ohm's Law\n", + "V3=I*R3 #Ohm's Law\n", + "\n", + "#Result\n", + "print\"Current = \",I,\"Ampere\" \n", + "print\"Voltage drop across R1 = \",V1,\"Volts\"\n", + "print\"Voltage drop across R2 = \",V2,\"Volts\" \n", + "print\"Voltage drop across R3 = \",V3,\"Volts\"\n", + "print\"\\nNOTE:Wrong answer of R3 in book\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current = 3 Ampere\n", + "Voltage drop across R1 = 6 Volts\n", + "Voltage drop across R2 = 18 Volts\n", + "Voltage drop across R3 = 9 Volts\n", + "\n", + "NOTE:Wrong answer of R3 in book\n" + ] + } + ], + "prompt_number": 36 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.16,Page no:173" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R=15 #resistance in Ohm\n", + "print\"KVL: 16I1+15I2=6 (1)\" #KVL equation\n", + "I1=-1.66 #from(1)\n", + "I2=2.17 #from (1)\n", + "#Calculation\n", + "V=(I1+I2)*R #calculating potential difference\n", + "\n", + "#Result\n", + "print\"Potential difference= \",V,\"Volt\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "KVL: 16I1+15I2=6 (1)\n", + "Potential difference= 7.65 Volt\n" + ] + } + ], + "prompt_number": 37 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.17,Page no:174" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "print\"3I1-I2-1=0 (1)\" #KVL equation\n", + "print\"3I1-I2+2I=2 (2)\" #KVL equation\n", + "print\"3I1-I1+2I=2 (3)\" #KVL equation\n", + "\n", + "#Variable declaration\n", + "I1=4/17.0 #from (1)(2)(3)through AB \n", + "I2=-2/17.0 #from (1)(2)(3)through BD\n", + "I=3*I1+I2 #from (1)(2)(3)through main circuit\n", + "\n", + "#Calculation\n", + "Ibc=I1-I2 #calculating current in BC\n", + "Iad=I-I1 #calculating current in AD\n", + "Idc=I-I1+I2 #calculating current in DC\n", + "\n", + "#Result\n", + "print\"Current in branch BC = \",Ibc,\"Ampere\"\n", + "print\"NOTE:Calculation mistake in book while calculating for BC\"\n", + "print\"Current in branch AD = \",Iad,\"Ampere\"\n", + "print\"Current in branch DC = \",Idc,\"Ampere\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "3I1-I2-1=0 (1)\n", + "3I1-I2+2I=2 (2)\n", + "3I1-I1+2I=2 (3)\n", + "Current in branch BC = 0.352941176471 Ampere\n", + "NOTE:Calculation mistake in book while calculating for BC\n", + "Current in branch AD = 0.352941176471 Ampere\n", + "Current in branch DC = 0.235294117647 Ampere\n" + ] + } + ], + "prompt_number": 77 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.18,Page no:176" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "P=10 #Ohm\n", + "Q=3 #Ohm\n", + "R=12 #Ohm\n", + "S=6 #Ohm\n", + "G=20 #Ohm\n", + "\n", + "\n", + "#Calculation\n", + "print\"-12I+22I1+IgG=0 (1)\" #KVL\n", + "print\"6I-9I1+29Ig=0 (2)\" #KVL\n", + "print\"13I1-3Ig=2 (3)\" #KVL\n", + "#From above equations\n", + "import numpy as np\n", + "a = np.array([[-12,22,20],[6,-9,29],[0,13,-3]]) \n", + "b = np.array([[0],[0],[2]])\n", + "np.linalg.solve(a,b)\n", + "\n", + "\n", + "#Result\n", + "print\"Current through Galvanometer = \",round(Ig*1000,2),\"mA\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "-12I+22I1+IgG=0 (1)\n", + "6I-9I1+29Ig=0 (2)\n", + "13I1-3Ig=2 (3)\n", + "Current through Galvanometer = 7.8 mA\n" + ] + } + ], + "prompt_number": 78 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.19,Page no:179" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "P=500 #power in Watts\n", + "V=200 #voltage in Volts\n", + "V1=160 #voltage in Volts\n", + "\n", + "#Calculation\n", + "R=(V**2)/P #using P=V**2*R\n", + "P1=(V1**2)/R #calculating power\n", + "Dp=500-P1 #drop in heat\n", + "D=(Dp*100)/500 #percentage drop\n", + "\n", + "#Result\n", + "print\"Resistance= \",R,\"Ohm\"\n", + "print\"% Drop in heat production = \",D,\"%\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistance= 80 Ohm\n", + "% Drop in heat production = 36 %\n" + ] + } + ], + "prompt_number": 79 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.20,Page no:180" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "P1=100 #power in Watts\n", + "P2=500 #power in Watts\n", + "\n", + "#Calculation\n", + "P=P2/P1 #ratio\n", + "\n", + "#Result\n", + "print \"P=\",P\n", + "print\"P>0,I2=5I Therefore I2>I1\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "P= 5\n", + "P>0,I2=5I Therefore I2>I1\n" + ] + } + ], + "prompt_number": 80 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.21,Page no:181" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "t=1200 #time in second\n", + "P=100 #power in Watts\n", + "V=230 #voltage in Volts\n", + "\n", + "#Calculation\n", + "R=(V**2)/P #calculating resistance\n", + "V1=115 #supply voltage in Volts\n", + "E=((V1**2)*t)/R #calculating energy\n", + "\n", + "#Result\n", + "print\"Energy dissipated by bulb = \",E,\"J\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Energy dissipated by bulb = 30000 J\n" + ] + } + ], + "prompt_number": 81 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.22,Page no:181" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "P=10**4 #power in Watts\n", + "V=250 #voltage in Volts\n", + "R=0.2 #resistance in ohm\n", + "\n", + "#Calculation\n", + "Pl=((P/V)*(P/V))*R #calculating power loss\n", + "print P1\n", + "E=P/(Pl+P) #calculating efficiency\n", + "\n", + "#Result\n", + "print\"Percent Efficiency = \",round(E*100),\"%\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "100\n", + "Percent Efficiency = 97.0 %\n" + ] + } + ], + "prompt_number": 56 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.23,Page no:182" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "P=100.0 #power in Watts\n", + "V=220.0 #voltage in Volts\n", + "\n", + "#Calculation\n", + "I=P/V #Current in Ampere\n", + "R=V/I #resistance\n", + "\n", + "#Result\n", + "print\"Current = \",round(I,3),\"A\" \n", + "print\"Resistance=\",R,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current = 0.455 A\n", + "Resistance= 484.0 Ohm\n" + ] + } + ], + "prompt_number": 59 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.24,Page no:182" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=50 #voltage in Volts\n", + "I=12 #Current in Ampere\n", + "\n", + "#Calculation\n", + "P=V*I #power\n", + "Pd=P*0.7 #power dissipated\n", + "R=(Pd/(I)**2) \n", + "\n", + "#Result\n", + "print\"Resistance = \",round(R,2),\"Ohm\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistance = 2.92 Ohm\n" + ] + } + ], + "prompt_number": 82 + } + ], + "metadata": {} + } + ] }
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