From 83c1bfceb1b681b4bb7253b47491be2d8b2014a1 Mon Sep 17 00:00:00 2001 From: debashisdeb Date: Fri, 20 Jun 2014 15:42:42 +0530 Subject: removing problem statements --- .../Chapter5.ipynb | 2076 ++++++++++---------- 1 file changed, 1034 insertions(+), 1042 deletions(-) (limited to 'A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb') diff --git a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb index 53a08905..581d450b 100644 --- a/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb +++ b/A_Comprehensive_Textbook_Of_Applied_Physics_/Chapter5.ipynb @@ -1,1043 +1,1035 @@ -{ - "metadata": { - "name": "" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "UNIT-5 Electricity" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.1,Page no:152" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Calculate current flowing through a conductor\n", - "\n", - "#Variable declaration \n", - "n=10**6 #no. of electrons\n", - "e=1.6*10**-19 #charge on an electron in C\n", - "\n", - "#Calculation\n", - "q=n*e #calculating total charge\n", - "t=10**-3 #time in second\n", - "I=q/t #calculating current\n", - "\n", - "#Result\n", - "print\"Current flowing = \",I,\"Ampere\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Current flowing = 1.6e-10 Ampere\n" - ] - } - ], - "prompt_number": 71 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.2,Page no:152" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#No of electrons passing through a lamp\n", - "\n", - "#Variable declaration \n", - "I=300*10**-3 #current n Ampere\n", - "t=60 #time in second\n", - "e=1.6*10**-19 #chatge on electron in C\n", - "\n", - "#Calculation\n", - "q=I*t #calculating charge\n", - "n=q/e #calculating no of electrons\n", - "\n", - "#Result\n", - "print\"No. of electrons = \",n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "No. of electrons = 1.125e+20\n" - ] - } - ], - "prompt_number": 20 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.3,Page no:154" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Frequency of electrons across a conductor\n", - "\n", - "#Variable declaration \n", - "V=200 #voltage in volt\n", - "R=100 #resistance in Ohm\n", - "e=1.6*10**-19 #charge on an electron in C\n", - "\n", - "#Calculation\n", - "I=V/R #Ohm's law\n", - "t=1 #time in second\n", - "q=I*t #calculating charge\n", - "n=q/e #calculating no of electrons\n", - "\n", - "#Result\n", - "print\"No. of electrons = \",n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "No. of electrons = 1.25e+19\n" - ] - } - ], - "prompt_number": 72 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.4,Page no:156" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Resistivity of small wire\n", - "\n", - "#Variable declaration \n", - "l=15 #length in m\n", - "A=6*10**-7 #area in m square\n", - "R=5 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "p=(A*R)/l #calculating resistivity\n", - "\n", - "#Result\n", - "print\"Resistivity= \",p,\"Ohm metre\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resistivity= 2e-07 Ohm metre\n" - ] - } - ], - "prompt_number": 73 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.5,Page no:157" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Resistivity of a normal wire\n", - "\n", - "#Variable declaration \n", - "l=0.1 #length in m\n", - "A=10**-4 #area in m square\n", - "R=0.01 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "p=(A*R)/l #calculating resistivity\n", - "\n", - "#Result\n", - "print\"Resistivity = \",p,\"Ohm metre\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resistivity = 1e-05 Ohm metre\n" - ] - } - ], - "prompt_number": 74 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.6,Page no:157" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Resistivity of a long wire\n", - "\n", - "import math \n", - "\n", - "#Variable declaration\n", - "L=1 #length in m\n", - "r=0.2*10**-3 #radius in m\n", - "R=2 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "A=math.pi*(r)**2 #calculating area\n", - "P=(R*A)/L #calculating resistivity\n", - "\n", - "#Result\n", - "print\"Resistivity =%.2g\"%P,\"Ohm.metre\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resistivity =2.5e-07 Ohm.metre\n" - ] - } - ], - "prompt_number": 38 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.7,Page no:158" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#New resistance of a wire after drawn out\n", - "\n", - "#Variable declaration \n", - "R1=5 #resisitance in Ohm\n", - "\n", - "#Calculation\n", - "#A2=A/3\n", - "#R2/5=3l*3/A*A/l\n", - "#R2=9*5\n", - "\n", - "R2=9*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", - "print\"Resisitance = \",R2,\"Ohm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resisitance = 45 Ohm\n" - ] - } - ], - "prompt_number": 75 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.8,Page no:159" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Change in resistance of a wire\n", - "\n", - "#Variable declaration \n", - "R1=5 #resisitance in Ohm\n", - "\n", - "#Calculation\n", - "#A2=A/2\n", - "#R1=rho*l1/A1*R2\n", - "#R2=rho*l2/A2\n", - "#R2/R1=A1/l1\n", - "R2=4*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", - "\n", - "#Result\n", - "print\"Resisitance= \",R2,\"Ohm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resisitance= 20 Ohm\n" - ] - } - ], - "prompt_number": 70 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.9,Page no:162" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Total resistance in parallel\n", - "\n", - "#Variable declaration \n", - "R1=2 #resisitance in Ohm\n", - "R2=4 #resistance in Ohm\n", - "R3=5 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "R=(R1**-1)+(R2**-1)+(R3**-1) #calculating parallel resistance\n", - "Rp=(1/R) \n", - "\n", - "#Result\n", - "print\"Resisitance = \",Rp,\"Ohm\"\n", - "print\"\\nNOTE:Incorrect answer in book\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resisitance = 1.05263157895 Ohm\n", - "\n", - "NOTE:Incorrect answer in book\n" - ] - } - ], - "prompt_number": 39 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.10,Page no:163" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Series parallel combination resistance\n", - "\n", - "from scipy.optimize import fsolve \n", - "\n", - "#Variable declaration\n", - "Rs=40 #resisitance in Ohm\n", - "\n", - "#Calculation\n", - "#R1+R2=40\n", - "#R1*R2=256\n", - "#R1=256/R2\n", - "#Putting this value in eq 1:\n", - "#(256/R2)+R2=40\n", - "from sympy import solve, symbols, pprint\n", - "R2= symbols('R2')\n", - "a=1\n", - "b=-40\n", - "c=256\n", - "f = a*R2**2 + b*R2 + c\n", - "solution = solve(f, R2)\n", - "\n", - "#Result\n", - "print\"When R2=\",solution[0],\"Ohm R1=\",solution[1],\"Ohm\"\n", - "print\"When R2=\",solution[1],\"Ohm R1=\",solution[0],\"Ohm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "When R2= 8 Ohm R1= 32 Ohm\n", - "When R2= 32 Ohm R1= 8 Ohm\n" - ] - } - ], - "prompt_number": 24 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.11,Page no:164" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Find the valueof current in fig\n", - "\n", - "#Variable declaration \n", - "V=2.0 #in volts\n", - "R1=30.0 #resisitance in Ohm\n", - "R2=60.0 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", - "I=V/Rp #Ohm's law\n", - "\n", - "#Result\n", - "print\"Resisitance = \",Rp,\"Ohm\"\n", - "print\"Current = \",I,\"A\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resisitance = 20.0 Ohm\n", - "Current = 0.1 A\n" - ] - } - ], - "prompt_number": 26 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.12,Page no:165" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Combine resistance to get an equivalent resistance\n", - "\n", - "#Variable declaration \n", - "R1=2.0 #resisitance in Ohm\n", - "R2=3.0 #resistance in Ohm\n", - "R3=1.0 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", - "R=Rp+1.0 #1 Ohm in series\n", - "Rs=(R1+R2+R3) #series resistances\n", - "Rp=(1.0/R1)+(1.0/R2)+(1.0/R3) #calculating parallel resistance\n", - "\n", - "#Result\n", - "print\"(1)Equivalent Resisitance= \",R,\"Ohm\" \n", - "print\"(2)All resistances in series = \",Rs,\"Ohm\"\n", - "print\"(3)All in Parallel = \",(1/Rp),\"Ohm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(1)Equivalent Resisitance= 2.2 Ohm\n", - "(2)All resistances in series = 6.0 Ohm\n", - "(3)All in Parallel = 0.545454545455 Ohm\n" - ] - } - ], - "prompt_number": 76 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.13,Page no:166" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Total resistor of combination\n", - "\n", - "#Variable declaration \n", - "V=20 #voltage in Volts\n", - "R1=2.0 #resisitance in Ohm\n", - "R2=4.0 #resistance in Ohm\n", - "R3=5.0 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "Rp=(1/R1)+(1/R2)+(1/R3) #calculating parallel resistance\n", - "R=1/Rp #Parallel\n", - "I1=V/R1 #calculating current through R1\n", - "I2=V/R2 #calculating current through R2\n", - "I3=V/R3 #calculating current through R3\n", - "I=V/R #calculating total current\n", - "\n", - "\n", - "#Result\n", - "print\"(a)Equivalent Resisitance = \",R,\"Ohm\"\n", - "print\"Current through R1 = \",I1,\"Ampere\"\n", - "print\"Current through R2 = \",I2,\"Ampere\" \n", - "print\"Total current = \",I,\"Ampere\" " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Equivalent Resisitance = 1.05263157895 Ohm\n", - "Current through R1 = 10.0 Ampere\n", - "Current through R2 = 5.0 Ampere\n", - "Total current = 19.0 Ampere\n" - ] - } - ], - "prompt_number": 30 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.14,Page no:166" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Calculate no of resistors form total resistor\n", - "\n", - "#Variable declaration\n", - "R=7 #Total resistanc of combination\n", - "\n", - "#Calculation\n", - "def f(n):\n", - " Rp = 6*(1/n) #resistance in parallel\n", - " return(R-Rp-5)\n", - "n=fsolve(f,1)\n", - "\n", - "#Result\n", - "print\"n=\",n[0]" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "n= 3.0\n" - ] - } - ], - "prompt_number": 33 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.15,Page no:173" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Voltage and current in figure\n", - "\n", - "#Variable declaration \n", - "R1=2 #resistance in Ohm\n", - "R2=6 #resistance in Ohm\n", - "R3=3 #resistance in Ohm\n", - "V=24 #voltage in volts\n", - "R=8 #resistance in Ohm\n", - "\n", - "#Calculation\n", - "I=V/R #Ohm's Law\n", - "V1=I*R1 #Ohm's Law\n", - "V2=I*R2 #Ohm's Law\n", - "V3=I*R3 #Ohm's Law\n", - "\n", - "#Result\n", - "print\"Current = \",I,\"Ampere\" \n", - "print\"Voltage drop across R1 = \",V1,\"Volts\"\n", - "print\"Voltage drop across R2 = \",V2,\"Volts\" \n", - "print\"Voltage drop across R3 = \",V3,\"Volts\"\n", - "print\"\\nNOTE:Wrong answer of R3 in book\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Current = 3 Ampere\n", - "Voltage drop across R1 = 6 Volts\n", - "Voltage drop across R2 = 18 Volts\n", - "Voltage drop across R3 = 9 Volts\n", - "\n", - "NOTE:Wrong answer of R3 in book\n" - ] - } - ], - "prompt_number": 36 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.16,Page no:173" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Current through branches of circuit\n", - "\n", - "#Variable declaration \n", - "R=15 #resistance in Ohm\n", - "print\"KVL: 16I1+15I2=6 (1)\" #KVL equation\n", - "I1=-1.66 #from(1)\n", - "I2=2.17 #from (1)\n", - "#Calculation\n", - "V=(I1+I2)*R #calculating potential difference\n", - "\n", - "#Result\n", - "print\"Potential difference= \",V,\"Volt\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "KVL: 16I1+15I2=6 (1)\n", - "Potential difference= 7.65 Volt\n" - ] - } - ], - "prompt_number": 37 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.17,Page no:174" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Determine current in wheatstone bridge\n", - "\n", - "print\"3I1-I2-1=0 (1)\" #KVL equation\n", - "print\"3I1-I2+2I=2 (2)\" #KVL equation\n", - "print\"3I1-I1+2I=2 (3)\" #KVL equation\n", - "\n", - "#Variable declaration\n", - "I1=4/17.0 #from (1)(2)(3)through AB \n", - "I2=-2/17.0 #from (1)(2)(3)through BD\n", - "I=3*I1+I2 #from (1)(2)(3)through main circuit\n", - "\n", - "#Calculation\n", - "Ibc=I1-I2 #calculating current in BC\n", - "Iad=I-I1 #calculating current in AD\n", - "Idc=I-I1+I2 #calculating current in DC\n", - "\n", - "#Result\n", - "print\"Current in branch BC = \",Ibc,\"Ampere\"\n", - "print\"NOTE:Calculation mistake in book while calculating for BC\"\n", - "print\"Current in branch AD = \",Iad,\"Ampere\"\n", - "print\"Current in branch DC = \",Idc,\"Ampere\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "3I1-I2-1=0 (1)\n", - "3I1-I2+2I=2 (2)\n", - "3I1-I1+2I=2 (3)\n", - "Current in branch BC = 0.352941176471 Ampere\n", - "NOTE:Calculation mistake in book while calculating for BC\n", - "Current in branch AD = 0.352941176471 Ampere\n", - "Current in branch DC = 0.235294117647 Ampere\n" - ] - } - ], - "prompt_number": 77 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.18,Page no:176" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Current through a galvanometer in wheatstone bridge\n", - "\n", - "#Variable declaration \n", - "P=10 #Ohm\n", - "Q=3 #Ohm\n", - "R=12 #Ohm\n", - "S=6 #Ohm\n", - "G=20 #Ohm\n", - "\n", - "\n", - "#Calculation\n", - "print\"-12I+22I1+IgG=0 (1)\" #KVL\n", - "print\"6I-9I1+29Ig=0 (2)\" #KVL\n", - "print\"13I1-3Ig=2 (3)\" #KVL\n", - "#From above equations\n", - "import numpy as np\n", - "a = np.array([[-12,22,20],[6,-9,29],[0,13,-3]]) \n", - "b = np.array([[0],[0],[2]])\n", - "np.linalg.solve(a,b)\n", - "\n", - "\n", - "#Result\n", - "print\"Current through Galvanometer = \",round(Ig*1000,2),\"mA\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "-12I+22I1+IgG=0 (1)\n", - "6I-9I1+29Ig=0 (2)\n", - "13I1-3Ig=2 (3)\n", - "Current through Galvanometer = 7.8 mA\n" - ] - } - ], - "prompt_number": 78 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.19,Page no:179" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#% drop in heat in bulb\n", - "\n", - "#Variable declaration \n", - "P=500 #power in Watts\n", - "V=200 #voltage in Volts\n", - "V1=160 #voltage in Volts\n", - "\n", - "#Calculation\n", - "R=(V**2)/P #using P=V**2*R\n", - "P1=(V1**2)/R #calculating power\n", - "Dp=500-P1 #drop in heat\n", - "D=(Dp*100)/500 #percentage drop\n", - "\n", - "#Result\n", - "print\"Resistance= \",R,\"Ohm\"\n", - "print\"% Drop in heat production = \",D,\"%\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resistance= 80 Ohm\n", - "% Drop in heat production = 36 %\n" - ] - } - ], - "prompt_number": 79 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.20,Page no:180" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Bulbs connected in parallel\n", - "\n", - "#Variable declaration\n", - "P1=100 #power in Watts\n", - "P2=500 #power in Watts\n", - "\n", - "#Calculation\n", - "P=P2/P1 #ratio\n", - "\n", - "#Result\n", - "print \"P=\",P\n", - "print\"P>0,I2=5I Therefore I2>I1\" " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "P= 5\n", - "P>0,I2=5I Therefore I2>I1\n" - ] - } - ], - "prompt_number": 80 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.21,Page no:181" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Heat and light energy produced by bulb on voltage drop\n", - "\n", - "#Variable declaration \n", - "t=1200 #time in second\n", - "P=100 #power in Watts\n", - "V=230 #voltage in Volts\n", - "\n", - "#Calculation\n", - "R=(V**2)/P #calculating resistance\n", - "V1=115 #supply voltage in Volts\n", - "E=((V1**2)*t)/R #calculating energy\n", - "\n", - "#Result\n", - "print\"Energy dissipated by bulb = \",E,\"J\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Energy dissipated by bulb = 30000 J\n" - ] - } - ], - "prompt_number": 81 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.22,Page no:181" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Calculate effeciency of transmission\n", - "\n", - "#Variable declaration\n", - "P=10**4 #power in Watts\n", - "V=250 #voltage in Volts\n", - "R=0.2 #resistance in ohm\n", - "\n", - "#Calculation\n", - "Pl=((P/V)*(P/V))*R #calculating power loss\n", - "print P1\n", - "E=P/(Pl+P) #calculating efficiency\n", - "\n", - "#Result\n", - "print\"Percent Efficiency = \",round(E*100),\"%\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "100\n", - "Percent Efficiency = 97.0 %\n" - ] - } - ], - "prompt_number": 56 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.23,Page no:182" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Resistance and current capacity of a lamp\n", - "\n", - "#Variable declaration \n", - "P=100.0 #power in Watts\n", - "V=220.0 #voltage in Volts\n", - "\n", - "#Calculation\n", - "I=P/V #Current in Ampere\n", - "R=V/I #resistance\n", - "\n", - "#Result\n", - "print\"Current = \",round(I,3),\"A\" \n", - "print\"Resistance=\",R,\"Ohm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Current = 0.455 A\n", - "Resistance= 484.0 Ohm\n" - ] - } - ], - "prompt_number": 59 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:5.24,Page no:182" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Resistance of windings of electric motor\n", - "\n", - "#Variable declaration \n", - "V=50 #voltage in Volts\n", - "I=12 #Current in Ampere\n", - "\n", - "#Calculation\n", - "P=V*I #power\n", - "Pd=P*0.7 #power dissipated\n", - "R=(Pd/(I)**2) \n", - "\n", - "#Result\n", - "print\"Resistance = \",round(R,2),\"Ohm\" " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Resistance = 2.92 Ohm\n" - ] - } - ], - "prompt_number": 82 - } - ], - "metadata": {} - } - ] +{ + "metadata": { + "name": "", + "signature": "sha256:1f51544adf15fc8ba28e47ac7da1a371a1d8835331773ecfcfa211468f9b325d" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "UNIT-5 Electricity" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.1,Page no:152" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "n=10**6 #no. of electrons\n", + "e=1.6*10**-19 #charge on an electron in C\n", + "\n", + "#Calculation\n", + "q=n*e #calculating total charge\n", + "t=10**-3 #time in second\n", + "I=q/t #calculating current\n", + "\n", + "#Result\n", + "print\"Current flowing = \",I,\"Ampere\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current flowing = 1.6e-10 Ampere\n" + ] + } + ], + "prompt_number": 71 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.2,Page no:152" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "I=300*10**-3 #current n Ampere\n", + "t=60 #time in second\n", + "e=1.6*10**-19 #chatge on electron in C\n", + "\n", + "#Calculation\n", + "q=I*t #calculating charge\n", + "n=q/e #calculating no of electrons\n", + "\n", + "#Result\n", + "print\"No. of electrons = \",n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "No. of electrons = 1.125e+20\n" + ] + } + ], + "prompt_number": 20 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.3,Page no:154" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=200 #voltage in volt\n", + "R=100 #resistance in Ohm\n", + "e=1.6*10**-19 #charge on an electron in C\n", + "\n", + "#Calculation\n", + "I=V/R #Ohm's law\n", + "t=1 #time in second\n", + "q=I*t #calculating charge\n", + "n=q/e #calculating no of electrons\n", + "\n", + "#Result\n", + "print\"No. of electrons = \",n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "No. of electrons = 1.25e+19\n" + ] + } + ], + "prompt_number": 72 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.4,Page no:156" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "l=15 #length in m\n", + "A=6*10**-7 #area in m square\n", + "R=5 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "p=(A*R)/l #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity= \",p,\"Ohm metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity= 2e-07 Ohm metre\n" + ] + } + ], + "prompt_number": 73 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.5,Page no:157" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "l=0.1 #length in m\n", + "A=10**-4 #area in m square\n", + "R=0.01 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "p=(A*R)/l #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity = \",p,\"Ohm metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity = 1e-05 Ohm metre\n" + ] + } + ], + "prompt_number": 74 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.6,Page no:157" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\n", + "#Variable declaration\n", + "L=1 #length in m\n", + "r=0.2*10**-3 #radius in m\n", + "R=2 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "A=math.pi*(r)**2 #calculating area\n", + "P=(R*A)/L #calculating resistivity\n", + "\n", + "#Result\n", + "print\"Resistivity =%.2g\"%P,\"Ohm.metre\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistivity =2.5e-07 Ohm.metre\n" + ] + } + ], + "prompt_number": 38 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.7,Page no:158" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=5 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#A2=A/3\n", + "#R2/5=3l*3/A*A/l\n", + "#R2=9*5\n", + "\n", + "R2=9*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", + "print\"Resisitance = \",R2,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 45 Ohm\n" + ] + } + ], + "prompt_number": 75 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.8,Page no:159" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=5 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#A2=A/2\n", + "#R1=rho*l1/A1*R2\n", + "#R2=rho*l2/A2\n", + "#R2/R1=A1/l1\n", + "R2=4*R1 #calculating using R2/A1=(l2/A2)*(A1/l1)\n", + "\n", + "#Result\n", + "print\"Resisitance= \",R2,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance= 20 Ohm\n" + ] + } + ], + "prompt_number": 70 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.9,Page no:162" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2 #resisitance in Ohm\n", + "R2=4 #resistance in Ohm\n", + "R3=5 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "R=(R1**-1)+(R2**-1)+(R3**-1) #calculating parallel resistance\n", + "Rp=(1/R) \n", + "\n", + "#Result\n", + "print\"Resisitance = \",Rp,\"Ohm\"\n", + "print\"\\nNOTE:Incorrect answer in book\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 1.05263157895 Ohm\n", + "\n", + "NOTE:Incorrect answer in book\n" + ] + } + ], + "prompt_number": 39 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.10,Page no:163" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from scipy.optimize import fsolve \n", + "\n", + "#Variable declaration\n", + "Rs=40 #resisitance in Ohm\n", + "\n", + "#Calculation\n", + "#R1+R2=40\n", + "#R1*R2=256\n", + "#R1=256/R2\n", + "#Putting this value in eq 1:\n", + "#(256/R2)+R2=40\n", + "from sympy import solve, symbols, pprint\n", + "R2= symbols('R2')\n", + "a=1\n", + "b=-40\n", + "c=256\n", + "f = a*R2**2 + b*R2 + c\n", + "solution = solve(f, R2)\n", + "\n", + "#Result\n", + "print\"When R2=\",solution[0],\"Ohm R1=\",solution[1],\"Ohm\"\n", + "print\"When R2=\",solution[1],\"Ohm R1=\",solution[0],\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "When R2= 8 Ohm R1= 32 Ohm\n", + "When R2= 32 Ohm R1= 8 Ohm\n" + ] + } + ], + "prompt_number": 24 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.11,Page no:164" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=2.0 #in volts\n", + "R1=30.0 #resisitance in Ohm\n", + "R2=60.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", + "I=V/Rp #Ohm's law\n", + "\n", + "#Result\n", + "print\"Resisitance = \",Rp,\"Ohm\"\n", + "print\"Current = \",I,\"A\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resisitance = 20.0 Ohm\n", + "Current = 0.1 A\n" + ] + } + ], + "prompt_number": 26 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.12,Page no:165" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2.0 #resisitance in Ohm\n", + "R2=3.0 #resistance in Ohm\n", + "R3=1.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(R1*R2)/(R1+R2) #calculating parallel resistance\n", + "R=Rp+1.0 #1 Ohm in series\n", + "Rs=(R1+R2+R3) #series resistances\n", + "Rp=(1.0/R1)+(1.0/R2)+(1.0/R3) #calculating parallel resistance\n", + "\n", + "#Result\n", + "print\"(1)Equivalent Resisitance= \",R,\"Ohm\" \n", + "print\"(2)All resistances in series = \",Rs,\"Ohm\"\n", + "print\"(3)All in Parallel = \",(1/Rp),\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(1)Equivalent Resisitance= 2.2 Ohm\n", + "(2)All resistances in series = 6.0 Ohm\n", + "(3)All in Parallel = 0.545454545455 Ohm\n" + ] + } + ], + "prompt_number": 76 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.13,Page no:166" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=20 #voltage in Volts\n", + "R1=2.0 #resisitance in Ohm\n", + "R2=4.0 #resistance in Ohm\n", + "R3=5.0 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "Rp=(1/R1)+(1/R2)+(1/R3) #calculating parallel resistance\n", + "R=1/Rp #Parallel\n", + "I1=V/R1 #calculating current through R1\n", + "I2=V/R2 #calculating current through R2\n", + "I3=V/R3 #calculating current through R3\n", + "I=V/R #calculating total current\n", + "\n", + "\n", + "#Result\n", + "print\"(a)Equivalent Resisitance = \",R,\"Ohm\"\n", + "print\"Current through R1 = \",I1,\"Ampere\"\n", + "print\"Current through R2 = \",I2,\"Ampere\" \n", + "print\"Total current = \",I,\"Ampere\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(a)Equivalent Resisitance = 1.05263157895 Ohm\n", + "Current through R1 = 10.0 Ampere\n", + "Current through R2 = 5.0 Ampere\n", + "Total current = 19.0 Ampere\n" + ] + } + ], + "prompt_number": 30 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.14,Page no:166" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "R=7 #Total resistanc of combination\n", + "\n", + "#Calculation\n", + "def f(n):\n", + " Rp = 6*(1/n) #resistance in parallel\n", + " return(R-Rp-5)\n", + "n=fsolve(f,1)\n", + "\n", + "#Result\n", + "print\"n=\",n[0]" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "n= 3.0\n" + ] + } + ], + "prompt_number": 33 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.15,Page no:173" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R1=2 #resistance in Ohm\n", + "R2=6 #resistance in Ohm\n", + "R3=3 #resistance in Ohm\n", + "V=24 #voltage in volts\n", + "R=8 #resistance in Ohm\n", + "\n", + "#Calculation\n", + "I=V/R #Ohm's Law\n", + "V1=I*R1 #Ohm's Law\n", + "V2=I*R2 #Ohm's Law\n", + "V3=I*R3 #Ohm's Law\n", + "\n", + "#Result\n", + "print\"Current = \",I,\"Ampere\" \n", + "print\"Voltage drop across R1 = \",V1,\"Volts\"\n", + "print\"Voltage drop across R2 = \",V2,\"Volts\" \n", + "print\"Voltage drop across R3 = \",V3,\"Volts\"\n", + "print\"\\nNOTE:Wrong answer of R3 in book\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current = 3 Ampere\n", + "Voltage drop across R1 = 6 Volts\n", + "Voltage drop across R2 = 18 Volts\n", + "Voltage drop across R3 = 9 Volts\n", + "\n", + "NOTE:Wrong answer of R3 in book\n" + ] + } + ], + "prompt_number": 36 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.16,Page no:173" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "R=15 #resistance in Ohm\n", + "print\"KVL: 16I1+15I2=6 (1)\" #KVL equation\n", + "I1=-1.66 #from(1)\n", + "I2=2.17 #from (1)\n", + "#Calculation\n", + "V=(I1+I2)*R #calculating potential difference\n", + "\n", + "#Result\n", + "print\"Potential difference= \",V,\"Volt\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "KVL: 16I1+15I2=6 (1)\n", + "Potential difference= 7.65 Volt\n" + ] + } + ], + "prompt_number": 37 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.17,Page no:174" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "print\"3I1-I2-1=0 (1)\" #KVL equation\n", + "print\"3I1-I2+2I=2 (2)\" #KVL equation\n", + "print\"3I1-I1+2I=2 (3)\" #KVL equation\n", + "\n", + "#Variable declaration\n", + "I1=4/17.0 #from (1)(2)(3)through AB \n", + "I2=-2/17.0 #from (1)(2)(3)through BD\n", + "I=3*I1+I2 #from (1)(2)(3)through main circuit\n", + "\n", + "#Calculation\n", + "Ibc=I1-I2 #calculating current in BC\n", + "Iad=I-I1 #calculating current in AD\n", + "Idc=I-I1+I2 #calculating current in DC\n", + "\n", + "#Result\n", + "print\"Current in branch BC = \",Ibc,\"Ampere\"\n", + "print\"NOTE:Calculation mistake in book while calculating for BC\"\n", + "print\"Current in branch AD = \",Iad,\"Ampere\"\n", + "print\"Current in branch DC = \",Idc,\"Ampere\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "3I1-I2-1=0 (1)\n", + "3I1-I2+2I=2 (2)\n", + "3I1-I1+2I=2 (3)\n", + "Current in branch BC = 0.352941176471 Ampere\n", + "NOTE:Calculation mistake in book while calculating for BC\n", + "Current in branch AD = 0.352941176471 Ampere\n", + "Current in branch DC = 0.235294117647 Ampere\n" + ] + } + ], + "prompt_number": 77 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.18,Page no:176" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "P=10 #Ohm\n", + "Q=3 #Ohm\n", + "R=12 #Ohm\n", + "S=6 #Ohm\n", + "G=20 #Ohm\n", + "\n", + "\n", + "#Calculation\n", + "print\"-12I+22I1+IgG=0 (1)\" #KVL\n", + "print\"6I-9I1+29Ig=0 (2)\" #KVL\n", + "print\"13I1-3Ig=2 (3)\" #KVL\n", + "#From above equations\n", + "import numpy as np\n", + "a = np.array([[-12,22,20],[6,-9,29],[0,13,-3]]) \n", + "b = np.array([[0],[0],[2]])\n", + "np.linalg.solve(a,b)\n", + "\n", + "\n", + "#Result\n", + "print\"Current through Galvanometer = \",round(Ig*1000,2),\"mA\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "-12I+22I1+IgG=0 (1)\n", + "6I-9I1+29Ig=0 (2)\n", + "13I1-3Ig=2 (3)\n", + "Current through Galvanometer = 7.8 mA\n" + ] + } + ], + "prompt_number": 78 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.19,Page no:179" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "P=500 #power in Watts\n", + "V=200 #voltage in Volts\n", + "V1=160 #voltage in Volts\n", + "\n", + "#Calculation\n", + "R=(V**2)/P #using P=V**2*R\n", + "P1=(V1**2)/R #calculating power\n", + "Dp=500-P1 #drop in heat\n", + "D=(Dp*100)/500 #percentage drop\n", + "\n", + "#Result\n", + "print\"Resistance= \",R,\"Ohm\"\n", + "print\"% Drop in heat production = \",D,\"%\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistance= 80 Ohm\n", + "% Drop in heat production = 36 %\n" + ] + } + ], + "prompt_number": 79 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.20,Page no:180" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "P1=100 #power in Watts\n", + "P2=500 #power in Watts\n", + "\n", + "#Calculation\n", + "P=P2/P1 #ratio\n", + "\n", + "#Result\n", + "print \"P=\",P\n", + "print\"P>0,I2=5I Therefore I2>I1\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "P= 5\n", + "P>0,I2=5I Therefore I2>I1\n" + ] + } + ], + "prompt_number": 80 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.21,Page no:181" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "t=1200 #time in second\n", + "P=100 #power in Watts\n", + "V=230 #voltage in Volts\n", + "\n", + "#Calculation\n", + "R=(V**2)/P #calculating resistance\n", + "V1=115 #supply voltage in Volts\n", + "E=((V1**2)*t)/R #calculating energy\n", + "\n", + "#Result\n", + "print\"Energy dissipated by bulb = \",E,\"J\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Energy dissipated by bulb = 30000 J\n" + ] + } + ], + "prompt_number": 81 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.22,Page no:181" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration\n", + "P=10**4 #power in Watts\n", + "V=250 #voltage in Volts\n", + "R=0.2 #resistance in ohm\n", + "\n", + "#Calculation\n", + "Pl=((P/V)*(P/V))*R #calculating power loss\n", + "print P1\n", + "E=P/(Pl+P) #calculating efficiency\n", + "\n", + "#Result\n", + "print\"Percent Efficiency = \",round(E*100),\"%\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "100\n", + "Percent Efficiency = 97.0 %\n" + ] + } + ], + "prompt_number": 56 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.23,Page no:182" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Variable declaration \n", + "P=100.0 #power in Watts\n", + "V=220.0 #voltage in Volts\n", + "\n", + "#Calculation\n", + "I=P/V #Current in Ampere\n", + "R=V/I #resistance\n", + "\n", + "#Result\n", + "print\"Current = \",round(I,3),\"A\" \n", + "print\"Resistance=\",R,\"Ohm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current = 0.455 A\n", + "Resistance= 484.0 Ohm\n" + ] + } + ], + "prompt_number": 59 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example no:5.24,Page no:182" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "#Variable declaration \n", + "V=50 #voltage in Volts\n", + "I=12 #Current in Ampere\n", + "\n", + "#Calculation\n", + "P=V*I #power\n", + "Pd=P*0.7 #power dissipated\n", + "R=(Pd/(I)**2) \n", + "\n", + "#Result\n", + "print\"Resistance = \",round(R,2),\"Ohm\" " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Resistance = 2.92 Ohm\n" + ] + } + ], + "prompt_number": 82 + } + ], + "metadata": {} + } + ] } \ No newline at end of file -- cgit