OSCAD/Examples/sedra_smith/chapter_3/example_3.3/bjt.lib


1
2
3
4
5
6

.model bjt NPN( Vtf=1.7 Cjc=7.306p Nc=2 Tr=46.91n Ne=1.307 
+ Cje=22.01p Isc=0 Xtb=1.5 Rb=10 Rc=1 
+ Tf=411.1p Xti=3 Ikr=0 Bf=50 Fc=.5 
+ Ise=14.34f Br=6.092 Ikf=.2847 Mje=.377 Mjc=.3416 
+ Vaf=74.03 Vjc=.2 Vje=.75 Xtf=3 Itf=.6 
+ Is=14.34f Eg=1.11 )