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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%Tutorial slides on Python.
%
% Author: FOSSEE
% Copyright (c) 2009, FOSSEE, IIT Bombay
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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% Taken from Fernando's slides.
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basicstyle=\ttfamily\bfseries,
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%%% This is from Fernando's setup.
% \usepackage{color}
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% showstringspaces=false,
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Title page
\title[]{Least Squares Fit\\Statistical Plotting}
\author[FOSSEE] {FOSSEE}
\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}
\date[] {31, October 2009\\Day 1, Session 3}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%\pgfdeclareimage[height=0.75cm]{iitmlogo}{iitmlogo}
%\logo{\pgfuseimage{iitmlogo}}
%% Delete this, if you do not want the table of contents to pop up at
%% the beginning of each subsection:
\AtBeginSubsection[]
{
\begin{frame}<beamer>
\frametitle{Outline}
\tableofcontents[currentsection,currentsubsection]
\end{frame}
}
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{
\begin{frame}<beamer>
\frametitle{Outline}
\tableofcontents[currentsection,currentsubsection]
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}
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% If you wish to uncover everything in a step-wise fashion, uncomment
% the following command:
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%\includeonlyframes{current,current1,current2,current3,current4,current5,current6}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% DOCUMENT STARTS
\begin{document}
\begin{frame}
\maketitle
\end{frame}
%% \begin{frame}
%% \frametitle{Outline}
%% \tableofcontents
%% % You might wish to add the option [pausesections]
%% \end{frame}
\begin{frame}
\frametitle{Statistical Analysis and Parsing}
Read the data supplied in \emph{sslc1.txt} and obtain the following statistics:
\begin{itemize}
\item Average total marks scored in each region
\item Subject wise average score of each region
\item \alert{??Subject wise average score for all regions combined??}
\item Find the subject wise standard deviation of scores for each region
\end{itemize}
\end{frame}
\begin{frame}
\frametitle{Statistical Analysis and Parsing \ldots}
Machinery Required -
\begin{itemize}
\item File reading and parsing
\item NumPy arrays - sum by rows and sum by coloumns
\item Dictionaries
\end{itemize}
\end{frame}
\begin{frame}
\frametitle{File reading and parsing}
Understanding the structure of sslc1.txt
\begin{itemize}
\item Each line in the file, i.e each row of a file is a single record.
\item Each record corresponds to a record of a single student
\item Each record consists of several fields separated by a ';'
\end{itemize}
\end{frame}
\begin{frame}
\frametitle{File reading and parsing \ldots}
Each record consists of:
\begin{itemize}
\item Region Code
\item Roll Number
\item Name
\item Marks of 5 subjects
\item Total marks
\item Pass (P)
\item Withdrawn (W)
\item Fail (F)
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{File reading and parsing \ldots}
\begin{lstlisting}
for record in open('sslc1.txt'):
fields = record.split(';')
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data}
\begin{itemize}
\item Let the parsed data be stored in dictionary \typ{data}
\item \begin{lstlisting}
data = {} # is an empty dictionary
\end{lstlisting}
\item Index of a dictionary is called a \emph{key}
\item \emph{Keys} of \typ{data} are strings - region codes
\item Value of a \emph{key} can be any Python object
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data...}
\begin{itemize}
\item In this problem let the value of a \emph{key} be another dictionary.
\item This dictionary contains:
\begin{itemize}
\item 'marks': A \emph{List} of \emph{Lists} containing all marks
\item 'total': A \emph{List} of total marks of each student
\item 'P': Number of passes
\item 'F': Number of failures
\item 'W': Number of withdrawls
\end{itemize}
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data \ldots}
\small
\begin{lstlisting}
data = {}
for record in open('sslc1.txt'):
fields = record.split(';')
if fields[0] not in data:
data[fields[0]] = {
'marks': [],
'total': [],
'P': 0,
'F': 0,
'W': 0
}
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data \ldots}
\begin{lstlisting}
marks = []
for field in fields[3:8]:
score_str = field.strip()
score = 0 if score_str == 'AA'
or score_str == 'AAA'
or score_str == ''
else int(score_str)
marks.append(score)
data[fields[0]]['marks'].append(marks)
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data \ldots}
\begin{lstlisting}
total = 0 if score_str == 'AA'
or score_str == 'AAA'
or score_str == ''
else int(fields[8])
data[fields[0]]['total'].append(total)
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dictionary - Building parsed data \ldots}
\begin{lstlisting}
pfw_key = fields[9]
or fields[10]
or 'F'
data[fields[0]][pfw_key] += 1
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{NumPy arrays}
\centerline{\alert{But I lied!?!?!?}}
\end{frame}
\begin{frame}[fragile]
\frametitle{Calculations}
\begin{lstlisting}
for k in data:
data[k]['marks'] = array(
data[k]['marks'])
data[k]['total'] = array(
data[k]['total'])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Calculations}
\small
\begin{lstlisting}
data[k]['avg'] = average(
data[k]['total'])
marks = data[k]['marks']
sub_avg = average(marks, axis=1)
sub_std = sqrt(sum(square(
sub_avg[:,newaxis] - marks), axis=0) /
len(marks))
data[k]['sub_avg'] = sub_avg
data[k]['sub_std'] = sub_std
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{New Concepts}
\begin{itemize}
\item Dictionaries
\item Slicing lists
\item New type of conditional
\item NumPy arrays
\item Slicing NumPy arrays
\item NumPy array functions - square, average, sqrt
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Dealing with data whole-sale}
\begin{lstlisting}
In []: for t in T:
....: Tsq.append(t*t)
\end{lstlisting}
\begin{itemize}
\item This is not very efficient
\item We are squaring element after element
\item We use arrays to make this efficient
\end{itemize}
\begin{lstlisting}
In []: L = array(L)
In []: T = array(T)
In []: Tsq = T*T
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Arrays}
\begin{itemize}
\item \typ{T} and \typ{L} are now arrays
\item arrays are very efficient and powerful
\item Very easy to perform element-wise operations
\item \typ{+, -, *, /, \%}
\item More about arrays later
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-Line.png}
\end{figure}
\end{frame}
\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit.png}
\end{figure}
\end{frame}
\begin{frame}
\frametitle{Least Square Fit Curve}
\begin{itemize}
\item $T^2$ and $L$ have a linear relationship
\item Hence, Least Square Fit Curve is a line
\item we shall use the \typ{lstsq} function
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{\typ{lstsq}}
\begin{itemize}
\item We need to fit a line through points for the equation $T^2 = m \cdot L+c$
\item The equation can be re-written as $T^2 = A \cdot p$
\item where A is
$\begin{bmatrix}
L_1 & 1 \\
L_2 & 1 \\
\vdots & \vdots\\
L_N & 1 \\
\end{bmatrix}$
and p is
$\begin{bmatrix}
m\\
c\\
\end{bmatrix}$
\item We need to find $p$ to plot the line
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Van der Monde Matrix}
\begin{itemize}
\item A is also called a Van der Monde matrix
\item It can be generated using \typ{vander}
\end{itemize}
Van der Monde matrix of order M
\begin{equation*}
\begin{bmatrix}
l_1^{M-1} & \ldots & l_1 & 1 \\
l_2^{M-1} & \ldots &l_2 & 1 \\
\vdots & \ldots & \vdots & \vdots\\
l_N^{M-1} & \ldots & l_N & 1 \\
\end{bmatrix}
\end{equation*}
\begin{lstlisting}
In []: A = vander(L,2)
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{\typ{lstsq} \ldots}
\begin{itemize}
\item Now use the \typ{lstsq} function
\item Along with a lot of things, it returns the least squares solution
\end{itemize}
\begin{lstlisting}
In []: coef, res, r, s = lstsq(A,Tsq)
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Least Square Fit Line \ldots}
We get the points of the line from \typ{coef}
\begin{lstlisting}
In []: Tline = coef[0]*L + coef[1]
\end{lstlisting}
\begin{itemize}
\item Now plot Tline vs. L, to get the Least squares fit line.
\end{itemize}
\begin{lstlisting}
In []: plot(L, Tline)
\end{lstlisting}
\end{frame}
\end{document}
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