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+// Check for the infeasible problem
+C = [0.9501 0.7620 0.6153 0.4057
+ 0.2311 0.4564 0.7919 0.9354
+ 0.6068 0.0185 0.9218 0.9169
+ 0.4859 0.8214 0.7382 0.4102
+ 0.8912 0.4447 0.1762 0.8936];
+d = [0.0578
+ 0.3528
+ 0.8131
+ 0.0098
+ 0.1388];
+Aeq = [-1 0 0 0; 0 -1 0 0; 1 1 0 0 ];
+beq = [-6 -6 11];
+
+//Converged to a point of local infeasibility.
+// lambda =
+//
+// lower: [0x0 constant]
+// upper: [0x0 constant]
+// eqlin: [0x0 constant]
+// ineqlin: [0x0 constant]
+// output =
+//
+// Iterations: 0
+// exitflag =
+//
+// 5
+// residual =
+//
+// 0.0578
+// 0.3528
+// 0.8131
+// 0.0098
+// 0.1388
+// resnorm =
+//
+// 0.8083018
+// xopt =
+//
+// []
+
+[xopt,resnorm,residual,exitflag,output,lambda] = lsqlin(C,d,[],[],Aeq,beq)
+