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{
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 10: Pneumatic and Hydraulic Drives"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 10.1: Calculation_of_Hydraulic_Cylinder_Diameter_and_Standard_Rod_Size.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"clc;\n",
"clear;\n",
"mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-10.1 Page No.195\n');\n",
"P=100; //[lb/in^2] Hydraulic pressure\n",
"F=450; //[lb] Extension force\n",
"Fr=400; //[lb] Retraction force\n",
"A=F/P; //[in^2] Cross section area\n",
"D=sqrt(4*A/%pi); //[in] Bore of cylinder\n",
"mprintf('\n The bore of cylinder is %f in.',D);\n",
"//Use 2.5in bore cylinder\n",
"Dm=2.5; //[in] Bore of cylinder\n",
"Dr=1; //[in] Diameter of rod\n",
"A2=%pi*Dm^2/4-%pi*Dr^2/4; //[in^2]\n",
"F2=P*A2; //[lb] Force\n",
"if F2>=Fr then\n",
" mprintf('\n The diameter of rod is %f in.',Dr);\n",
"else \n",
" mprintf('\n This would not meet requirement');\n",
"end\n",
"//This would meet requirement\n",
"Ab=%pi*Dm^2/4; //[in^2] Cross section area\n",
"//Note-In the book V=180.7 is used instead of V=180.64158 \n",
"d=20; //[in] stroke\n",
"V=Ab*d+A2*d; //[in^3] Volume per cycle\n",
"t=2; //[s] Cycle time\n",
"FR=V/t; //[in^3/s] Flowrate\n",
"FR=FR*7.48*60/1728; //[gal/min] Flowrate\n",
"mprintf('\n Flow rate required is %f gal/min.',FR);"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 10.2: Pneumatic_Pop_Rivet_Gun.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"clc;\n",
"clear;\n",
"mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-10.2 Page No.198\n');\n",
"Pa=100; //[lb/in^2] Air pressure\n",
"Da=4; //[in] Diameter\n",
"Aa=%pi*Da^2/4; //[in^2] Cross section area\n",
"F1=Pa*Aa; //[lb] \n",
"Do=1; //[in] \n",
"Ao=%pi*Do^2/4; //[in] \n",
"Po=F1/Ao; //[lb/in^2]\n",
"mprintf('\n The oil pressure is %f lb/in^2.',Po);\n",
"D2o=3; //[in]\n",
"A2o=%pi*D2o^2/4; //[in^2]\n",
"F2=Po*A2o;\n",
"mprintf('\n Force F on piston rod is %f lb.',F2);\n",
"D=1; //[in]\n",
"d=4; //[in] \n",
"A=%pi*D^2/4; //[in^2]\n",
"V=A*d; //[in^3]\n",
"mprintf('\n The volume in 1-inch cylinder for the 4-inch travel is %f in^3.',V);\n",
"A3=%pi*3^2/4; //[in^2]\n",
"l3=V/A3; //[in]\n",
"mprintf('\n Travel for 3-inch cylinder is %f in.',l3);"
]
}
],
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"text": "MetaKernel Magics",
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