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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 23: Electric Fields"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 23.2: Sample_Problem_2.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"exec('degree_rad.sci', -1)\n",
"\n",
"//Given that\n",
"Q = 1 //(say)\n",
"q1 = +2*Q\n",
"q2 = -2*Q\n",
"q3 = -4*Q\n",
"d = 1 //(say)\n",
"theta = dtor(30)\n",
"\n",
"//Sample Problem 23-2\n",
"printf('**Sample Problem 23-2**\n')\n",
"E1 = coulomb(q1, 1, d)*[cos(theta), sin(theta)]\n",
"E2 = coulomb(q2, 1, d)*[-cos(theta), sin(theta)]\n",
"E3 = coulomb(q3, 1, d)*[-cos(theta), -sin(theta)]\n",
"E = E1 + E2 + E3\n",
"printf('The net electric field at origin is equal to %eQ/d^2 N/C', norm(E))"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 23.3: Sample_Problem_3.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('electrostatics.sci', -1)\n",
"exec('degree_rad.sci', -1)\n",
"\n",
"//Given that\n",
"Q = 1 //(say)\n",
"A = dtor(120)\n",
"r = 1 //(say)\n",
"\n",
"//Sample Problem 23-3\n",
"printf('**Sample Problem 23-3**\n')\n",
"Eunit_angle = coulomb(Q/A, 1, r)\n",
"//overall only x-component will survive\n",
"E = integrate('Eunit_angle*cos(theta)', 'theta', -A/2, A/2)\n",
"printf('The electric field due to arc at point P is equal to %eQ/r^2 N/C', E)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 23.4: Sample_Problem_4.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Given that\n",
"m = 1.3*10^-10 //in kg\n",
"Q = 1.5*10^-13 //in C\n",
"Vx = 18 //in m/s\n",
"L = 1.6*10^-2 //in meter\n",
"E = 1.4*10^6 //in N/C\n",
"\n",
"//Sample Problem 23-4\n",
"printf('**Sample Problem 23-4**\n')\n",
"a = E*Q/m\n",
"t = L/Vx\n",
"dv = 0.5*a*t^2 //vertical drop\n",
"printf('The vertical drop of the drop is equal to %fmm', dv*10^3)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 23.5: Sample_Problem_5.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"exec('degree_rad.sci', -1)\n",
"\n",
"//Given that\n",
"P = 6.2*10^-30 //in C.m\n",
"\n",
"//Sample Problem 23-5a\n",
"printf('**Sample Problem 23-5a**\n')\n",
"q = 10*e\n",
"l = P/q\n",
"printf('The effective ditance between the positive & negative center is %em\n', l)\n",
"\n",
"//Sample Problem 23-5b\n",
"printf('\n**Sample Problem 23-5b**\n')\n",
"E = 1.5*10^4 //in N/C\n",
"T = 2*E*q*l/2\n",
"printf('The net torque on the dipole is %eN.m\n', T)\n",
"\n",
"//Sample Problem 23-5c\n",
"printf('\n**Sample Problem 23-5c**\n')\n",
"W = -(P*E*(cos(dtor(180)) - cos(0)))\n",
"printf('The work done by the external agent is equal to %eJ', W)"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
