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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 1: Measurement"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1.1: Sample_Problem_1.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Given that\n",
"velocityP = 23 //rides per h\n",
"c1 = 4 //from ride to stadia\n",
"c2 = 6 //from stadia to plethra\n",
"c3 = 30.8 //from plethra to meter\n",
"c4 = 10^-3 //from meter to kilometer\n",
"c5 = 60 * 60 //from h to sec\n",
"\n",
"//Sample Problem 1-1\n",
"printf('**Sample Problem 1-1**\n')\n",
"velocityC = velocityP * c1 * c2 * c3 * c4 / c5\n",
"printf('The speed is %e km/s', velocityC)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1.2: Sample_Problem_2.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Given that\n",
"conv1 = 170.474 //conversion from crans to liters\n",
"conv2 = 48.26 //from covido to cm\n",
"V1 = 1255 //in crans\n",
"\n",
"//Sample Problem 1-2\n",
"printf('**Sample Problem 1-2**\n')\n",
"VC = V1 * conv1 * 10^3 / (conv2^3)\n",
"printf('The required declaration is %e cubic covidos', VC)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1.3: Sample_Problem_3.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Given that\n",
"//the crossection to be approximately squre\n",
"Radius = 2 //in meter\n",
"side = 4 * 10^-3 //converted from mm to meter\n",
"\n",
"//Sample Problem 1-3\n",
"printf('**Sample Problem 1-3**\n')\n",
"//making the volume equal\n",
"Length = 4/3 * %pi * Radius^3 / side^2\n",
"L_km = Length/10^3\n",
"order = round(log(L_km)/log(10)) //will give us order of magnitude\n",
"printf('The order of length of string is 10^%d km', order)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1.4: Sample_Problem_4.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Given that\n",
"height = 1.70 //in meter\n",
"elapsed_time = 11.1 //in sec\n",
"\n",
"//Sample Problem 1-4\n",
"printf('**Sample Problem 1-4**\n')\n",
"//the angle between the two radius is\n",
"theta = elapsed_time / (24 * 3600) * %pi*2 //in radians\n",
"//we also have d^2 = 2 * r *h\n",
"//as d is very small hence can be considered as a arc\n",
"//d = r * theta\n",
"//=> r * theta^2 = 2 * h\n",
"radius = 2 * height /theta^2\n",
"printf('The radius of earth is %e m', radius)"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
